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Derivatives · Derivatives

Rate of Change and Derivative of a Function at a Point

Before you start, make sure you know: Average rate of change of a function (High School Year 2 (semesters 3 and 4))
Before you start, make sure you know: Definition of the derivative of a function at a point (High School Year 2 (semesters 3 and 4))

You are riding the Metrobús along Insurgentes. When you reach the station, what does the speedometer read at that instant? Your phone says you took 30 minutes to go 12 km, but that is an average. Going from the average to the value "right now" is the central idea of differential calculus. From Archimedes and Zeno to Newton and Leibniz, humanity has tried to capture the "instant": here we manage it with a limit.

Average rate of change

Graph of a function with a secant line joining two points A and B of the curve; its slope is the average rate of change. A(a, f(a)) B(b, f(b)) secant: slope = ARC[a, b]
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Calculate the average rate of change (ARC) of the function $f(x) = x^2 - 4x + 5$ on the interval $[1, 4]$. Explain graphically what the value obtained represents in…

Calculate the average rate of change (ARC) of the function $f(x) = x^2 - 4x + 5$ on the interval $[1, 4]$. Explain graphically what the value obtained represents in relation to the secant line that passes through the points $A$ and $B$ of the curve corresponding to the endpoints of that interval (they are marked in the figure).

Graph of the parabola f(x) = x² − 4x + 5 between x = 0 and x = 4, with the points A and B of abscissas 1 and 4 and the secant line passing through themxyABfSecant0123412345
Solve
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A Year 13 student trains for the 100-meter sprint. The distance covered (in meters) as a function of time (in seconds) is given by the expression $s(t) = 0.5t^2 + 2t$.…

A Year 13 student trains for the 100-meter sprint. The distance covered (in meters) as a function of time (in seconds) is given by the expression $s(t) = 0.5t^2 + 2t$.

Calculate the average speed of the athlete between $t = 2$ s and $t = 6$ s. Which mathematical concept does this value correspond to?

Solve
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The growth in followers of a new account on a popular social network follows the function $S(t) = t^2 + 4t + 100$, where $t$ is the time in days since its creation and…

The growth in followers of a new account on a popular social network follows the function $S(t) = t^2 + 4t + 100$, where $t$ is the time in days since its creation and $S(t)$ is the number of followers. The figure shows the graph of $S$ and the lines joining the points of the curve corresponding to $t=0$, $t=5$ and $t=10$.

  1. a) Calculate the average rate of change (ARC) of the number of followers over the intervals $[0, 5]$ and $[5, 10]$.
  2. b) Explain the meaning of the results you obtained in the context of the account's growth. In which interval has the growth been faster?
Graph of the parabola S(t) with the points at t = 0, 5 and 10 joined by two secant lines 0 5 10 50 100 150 200 250 Time t (days) Followers S(t) S(t) = t² + 4t + 100 Interval [0, 5] Interval [5, 10]
Solve

From the secant to the tangent: the derivative

To find out what happens at an instant, we move point $B$ closer to point $A$: the interval shrinks and the secants rotate until they become the tangent line.

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Given the function $f(x) = 3x^2 - 1$, use the definition of derivative at a point via the limit: $$f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$$ to find the value of…

Given the function $f(x) = 3x^2 - 1$, use the definition of derivative at a point via the limit:

$$f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$$

to find the value of the derivative at the point with x-coordinate $x = 2$.

Solve
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Consider the rational function $f(x) = \frac{2}{x}$. Show, applying the definition of derivative as a limit, that the value of the instantaneous rate of change at…

Consider the rational function $f(x) = \frac{2}{x}$.

Show, applying the definition of derivative as a limit, that the value of the instantaneous rate of change at $x = 1$ is $f'(1) = -2$. Interpret the sign of the result obtained.

Solve
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Calculate the derivative of the function $f(x) = \dfrac{3}{x + 1}$ at the point with x-coordinate $x = 2$ using strictly the definition of derivative via the limit:…

Calculate the derivative of the function $f(x) = \dfrac{3}{x + 1}$ at the point with x-coordinate $x = 2$ using strictly the definition of derivative via the limit:

$$f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$$
Solve

The derivative as the instantaneous rate of change

If $s(t)$ is position, $s'(t)$ is the instantaneous velocity (what the speedometer reads). If $S(t)$ is the number of followers, $S'(t)$ is followers per day at that instant. The sign tells you whether it is increasing ($f'>0$) or decreasing ($f'<0$); the units are those of $y$ divided by those of $x$.

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Observe the following graph of a function $f(x)$. Without performing calculations, order the following values from smallest to largest, justifying your answer based on…

Observe the following graph of a function $f(x)$. Without performing calculations, order the following values from smallest to largest, justifying your answer based on the steepness of the lines:

  • The average rate of change in the interval $[1, 3]$.

  • The derivative of the function at the point $x = 1$.

  • The derivative of the function at the point $x = 3$.

1 3 x y f(x) f'(1) = ? ARC[1.3]= ? f'(3) = ?
Solve
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The number of subscribers of a new YouTube channel evolves according to the function $S(t) = t^2 + 10t + 100$, where $t$ is the time in days since its creation. a)…

The number of subscribers of a new YouTube channel evolves according to the function $S(t) = t^2 + 10t + 100$, where $t$ is the time in days since its creation.

  1. a) Calculate the average rate of change of subscribers between day $t = 0$ and day $t = 10$.
  2. b) What is the instantaneous growth of subscribers on exactly day $t = 5$? (Calculate $S'(5)$ using the definition).
Solve
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The temperature of a metal plate (in degrees Celsius) varies with time $t$ (in minutes) following the model $T(t) = 20 + 4t - 0.1t^2$. Calculate the instantaneous rate…

The temperature of a metal plate (in degrees Celsius) varies with time $t$ (in minutes) following the model $T(t) = 20 + 4t - 0.1t^2$.

Calculate the instantaneous rate of change of the temperature at time $t = 10$ minutes. State the units of measurement of the result and explain whether the plate is heating up or cooling down at that moment.

Solve
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A skater moves along a track whose position (in meters) with respect to the start is given by the expression $e(t) = \sqrt{4t + 9}$, where $t$ is the time in seconds. a)…

A skater moves along a track whose position (in meters) with respect to the start is given by the expression $e(t) = \sqrt{4t + 9}$, where $t$ is the time in seconds.

  1. a) Calculate the average velocity of the skater between $t = 0$ and $t = 4$ seconds.
  2. b) Find the instantaneous velocity at $t = 4$ seconds using the definition of derivative.
Solve
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A forest surveillance drone follows an approach trajectory whose altitude $h$ (in meters) with respect to time $t$ (in seconds) is given by the function: $$h(t) =…

A forest surveillance drone follows an approach trajectory whose altitude $h$ (in meters) with respect to time $t$ (in seconds) is given by the function:

$$h(t) = \sqrt{t^2 + 144} - 10$$

Find:

  1. Calculate the average rate of change of the height in the interval $[0, 5]$. Explain its physical meaning.

  2. Using the definition of a derivative at a point, obtain the instantaneous rate of ascent at time $t = 5$ seconds.

  3. Check whether there is any time $t > 0$ at which the instantaneous rate of ascent matches exactly the average rate of change calculated in part 1.

Solve

Some useful derivatives for recognizing limits

Sometimes the limit you are asked for is really a derivative in disguise. If you recognize the function and the point, all you need to do is differentiate. For that you need five results that you will see in detail on the page about differentiation rules; here we use them as a tool:

Why do they work? The limit $\displaystyle\lim_{h\to0}\frac{f(a+h)-f(a)}{h}$ is exactly $f'(a)$: if you identify $f$ and $a$, you can compute the derivative with these rules instead of simplifying by hand.

Is there a point where the instantaneous rate equals the average rate?

If the secant between $A$ and $B$ has a certain slope, sometimes there is a point $c$ between $a$ and $b$ where the tangent is parallel to that secant, that is, $f'(c)=\text{ARC}[a,b]$. To find it: compute the ARC, differentiate, and solve $f'(c)=\text{ARC}$, checking that $c$ lies inside the interval.

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Given the function $f(x) = \dfrac{x^2}{x - 1}$: a) Calculate the average rate of change in the interval $[2, 4]$. b) Determine whether there is any point $c$ within the…

Given the function $f(x) = \dfrac{x^2}{x - 1}$:

  1. a) Calculate the average rate of change in the interval $[2, 4]$.
  2. b) Determine whether there is any point $c$ within the interval $(2, 4)$ such that the instantaneous derivative $f'(c)$ coincides with the average rate of change calculated in the previous part.
Solve
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The temperature of an electronic component during the first hours of operation follows the function $T(t) = 20 + t \times e^{-t}$, where $T$ is the temperature in…

The temperature of an electronic component during the first hours of operation follows the function $T(t) = 20 + t \times e^{-t}$, where $T$ is the temperature in degrees Celsius and $t$ is the time in hours.

Calculate the instantaneous rate of change of temperature when exactly 1 hour has elapsed ($t = 1$). Is the temperature increasing, decreasing, or neither at that instant? Justify your answer based on the sign of the derivative.

Solve
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Calculate, using exclusively the definition of a derivative as the limit of the difference quotient, the value of the following limit: $$\lim_{h \to 0}…

Calculate, using exclusively the definition of a derivative as the limit of the difference quotient, the value of the following limit:

$$\lim_{h \to 0} \frac{\sin^2\left(\frac{\pi}{4} + h\right) - \frac{1}{2}}{h}$$

Hint: Identify this limit with the derivative of a known function at a given point and solve using standard differentiation rules to verify your result.

x y 0 f(x) = sin²(x) P Q π/4 π/4 + h 1/2 h sin²(π/4 + h) - 1/2 h → 0
Solve

Tangent line and normal line

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Determine the gradient of the tangent line to the graph of the function $f(x) = \sqrt{x+1}$ at the point where $x = 3$, applying the limit of the instantaneous rate of…

Determine the gradient of the tangent line to the graph of the function $f(x) = \sqrt{x+1}$ at the point where $x = 3$, applying the limit of the instantaneous rate of change:

$$f'(3) = \lim_{x \to 3} \frac{f(x) - f(3)}{x - 3}$$ X Y 0 x → 3 3 x f(3) f(x) (3, f(3)) (x, f(x)) x - 3 f(x) - f(3) f(x) Tangent Secant
Solve
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Consider the function $f(x) = x^2 - 6x + 5$. Determine the point on the graph where the tangent line has a gradient of $m = 2$. Once the point has been found, write the…

Consider the function $f(x) = x^2 - 6x + 5$. Determine the point on the graph where the tangent line has a gradient of $m = 2$. Once the point has been found, write the complete equation of this tangent line in point-slope form.

Solve
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Find the equation of the tangent line and of the normal line to the curve $f(x) = x^3 - 3x^2 + 2$ at the point where the graph crosses the y-axis ($OY$).

Find the equation of the tangent line and of the normal line to the curve $f(x) = x^3 - 3x^2 + 2$ at the point where the graph crosses the y-axis ($OY$).

Graph of the curve f(x) = x³ − 3x² + 2 with the coordinate axes012312−1−2xyf(x) = x³ − 3x² + 2
Solve
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Find the equations of the tangent lines to the curve $y = x^2 - 4x + 5$ that pass through the external point $A(0, 0)$ (the figure shows only one of them). Note: Note…

Find the equations of the tangent lines to the curve $y = x^2 - 4x + 5$ that pass through the external point $A(0, 0)$ (the figure shows only one of them).

Note: Note that point A does not lie on the curve. You will need to set the gradient of the tangent at a general point $(a, f(a))$ equal to the gradient of the line joining that point to the origin.

X Y y = x² - 4x + 5 a f(a) f'(a) = f(a)/a P(a, f(a)) A(0,0)
Solve

Continuity, differentiability, and one-sided derivatives

When the graph has a corner, there is no single tangent. To detect this we use the limits from each side: $f'(a^-)$ and $f'(a^+)$ (here it is enough to mention them).

Graph of a piecewise function joined smoothly at x = a: the two branches meet at the same point and with the same tangent. x = a (joining point) continuity: equal one-sided limits differentiability: f'(a⁻) = f'(a⁺)
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Given the piecewise function: $$f(x) = \begin{cases} x^2 + ax + b & \text{if } x < 1 \\ \ln(x) & \text{if } x \geq 1 \end{cases}$$ Calculate the values of $a$ and $b$ so…

Given the piecewise function:

$$f(x) = \begin{cases} x^2 + ax + b & \text{if } x < 1 \\ \ln(x) & \text{if } x \geq 1 \end{cases}$$

Calculate the values of $a$ and $b$ so that the function is differentiable at the point $x = 1$. Remember that for a function to be differentiable, it must first be continuous.

Solve
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Given the function $f(x) = x \times |x - 3|$, study its differentiability at the point $x = 3$. To do this: 1. Express the function as a piecewise function. 2. Calculate…

Given the function $f(x) = x \times |x - 3|$, study its differentiability at the point $x = 3$.

To do this:

  1. Express the function as a piecewise function.

  2. Calculate the one-sided derivatives $f'(3^-)$ and $f'(3^+)$ using the limit of the difference quotient.

  3. Interpret the result geometrically: does the graph have a sharp point (corner) or a smooth tangent at $x=3$? Justify your answer.

Solve
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Consider the piecewise function: $$f(x) = \begin{cases} a \times e^{x-2} + b \times x & \text{if } x \le 2 \\ \frac{x^2 - 4}{x-2} + \ln(x-1) & \text{if } x > 2…

Consider the piecewise function:

$$f(x) = \begin{cases} a \times e^{x-2} + b \times x & \text{if } x \le 2 \\ \frac{x^2 - 4}{x-2} + \ln(x-1) & \text{if } x > 2 \end{cases}$$

Determine the values of the real parameters $a$ and $b$ so that the function is differentiable at the point $x = 2$. To do this, you must first ensure continuity and then the existence of equal, finite one-sided derivatives at that point using the definition of derivative.

Solve
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Consider the function $f(x) = \sqrt[3]{x^2}$. 1. Study the continuity of the function at the origin ($x=0$). 2. Analyse differentiability at $x=0$ by calculating the…

Consider the function $f(x) = \sqrt[3]{x^2}$.

  1. Study the continuity of the function at the origin ($x=0$).

  2. Analyse differentiability at $x=0$ by calculating the limit of the difference quotient.

  3. If the limit tends to infinity, what type of tangent line does the function have at that point? Describe the visual behavior of the graph near the origin.

Solve

The derivative function and parallel tangents

If in the definition we leave $a$ free, the result is a function $f'(x)$ that gives the slope at each point.

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Let $f(x) = \frac{1}{x+1}$ be the function. Prove, applying the definition of derivative, that its derivative function is $f'(x) = \frac{-1}{(x+1)^2}$ for any value of…

Let $f(x) = \frac{1}{x+1}$ be the function. Prove, applying the definition of derivative, that its derivative function is $f'(x) = \frac{-1}{(x+1)^2}$ for any value of $x$ belonging to its domain.

From this result, determine the coordinates of the points on the graph where the tangent line is parallel to the line $y = -x$ (the bisector of the second quadrant).

Solve
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In a biotechnology laboratory, the population of a bacterial colony (in millions) is modelled by the function: $$P(t) = \frac{40t}{t^2 + 4} + 5, \quad t \ge 0$$ where…

In a biotechnology laboratory, the population of a bacterial colony (in millions) is modelled by the function:

$$P(t) = \frac{40t}{t^2 + 4} + 5, \quad t \ge 0$$

where $t$ is the time in hours.

  1. Find the instantaneous rate of change of the population at $t = 1$ hour and at $t = 4$ hours.

  2. Determine at which of these two times the population is growing faster.

  3. Is there any time at which the rate of growth is zero? If so, calculate that value of $t$ and interpret what happens to the population at that moment.

t (hours) P(t) (millions) 5 10 15 P(t) = 40t/(t²+4) + 5 t=1 Rate of change = ? t=4 Rate of change = ? t=? Rate of change = 0 Fastest growth?
Solve

Summary

Go back to the beginning: the speedometer at the Metrobús station is the derivative of position, the limit of the average velocities as the interval shrinks.

See all the exercises in this section