Back to homeBiology II · High School Year 3 · Physics-Math · Change subject
Start for free
Prep 3 Tech · Biology II
Molecular genetics · From DNA to protein

Gene Regulation and Genomes

Having a gene in your DNA does not mean it is always expressed, or expressed in every cell. Cells turn genes on and off according to their needs and their cell type, using mechanisms that act at different points along the path DNA → mRNA → protein. Here we will see how gene expression is regulated, using the bacterial lac operon as a model, and how information is organized in genomes of very different sizes.

Gene Expression Is Differential

A neuron transmits electrical impulses and a muscle cell contracts with force, yet both come from the same zygote and have the same DNA: how can two cells with the same instructions be so different?

Three cell types with the same DNA: all express the constitutive genes, but each one activates only its own regulated genes and none expresses the hemoglobin gene. neuron muscle cell skin cell genes basic metabolism constitutive neurotransmitters regulated contractile proteins regulated keratin regulated hemoglobin regulated active gene silenced gene
Practice★☆☆Not started
All the cells in your body possess the same DNA, yet a neuron and a muscle cell are very different. Explain what causes this difference with reference to gene expression.

All the cells in your body possess the same DNA, yet a neuron and a muscle cell are very different. Explain what causes this difference with reference to gene expression.

Solve
Practice★☆☆Not started
What is a constitutive gene and what is a regulated gene? Give an example of each type and explain why it is advantageous for the cell to regulate some of its genes.

What is a constitutive gene and what is a regulated gene? Give an example of each type and explain why it is advantageous for the cell to regulate some of its genes.

Solve

The lac Operon: A Model of Bacterial Regulation

In the diagram, panel A shows the situation without lactose and panel B the situation with lactose. The ellipse below the promoter is RNA polymerase.

Lac operon. Panel A, without lactose: the repressor occupies the operator and blocks RNA polymerase. Panel B, with lactose: the repressor comes off and RNA polymerase transcribes Z, Y, and A. A. no lactose P O Z — Y — A repressor RNA polymerase ? B. with lactose lactose repressor P O Z — Y — A (transcribed)
Practice★★☆Not started
The diagram represents the lac operon of Escherichia coli in two situations (A and B). State in which of them lactose is present in the medium, name the elements…

The diagram represents the lac operon of Escherichia coli in two situations (A and B). State in which of them lactose is present in the medium, name the elements labelled (P, O, Z-Y-A and ?), and explain what happens to the expression of the structural genes in each situation.

A P O Z Y A ? B P O Z Y A
Solve
Practice★★★Not started
In a laboratory, a mutant strain of Escherichia coli* displaying a complete deletion in the regulatory gene lacI* (I⁻* phenotype) is studied. A student predicts that…

In a laboratory, a mutant strain of Escherichia coli displaying a complete deletion in the regulatory gene lacI (I⁻ phenotype) is studied. A student predicts that this bacterium will maximally transcribe the structural genes of the lac operon under any circumstance, since the repressor will never bind to the operator.

To test their hypothesis, the strain is cultured in three media with equivalent concentrations of basic nutrients:

  • Medium A: glucose as the sole carbon source.

  • Medium B: simultaneous presence of glucose and lactose.

  • Medium C: lactose as the sole carbon source.

  1. a) Evaluate whether the student's prediction is correct. Justify what level of operon transcription (null, very low basal, or high) will be observed in each of the three media, detailing the molecular mechanism involved (role of the CAP-cAMP complex and adenylyl cyclase).
  2. b) Predict with reasoning what would happen to transcription in Medium C if the strain were to acquire a second mutation that inactivated the CAP protein gene.
Solve

Regulation in Eukaryotic Cells

In bacteria, transcription is turned on or off right next to the promoter, but in our cells a sequence tens of thousands of base pairs away can switch a gene on: how is that activation coordinated across the chromatin?

Top, an enhancer far from the promoter on stretched-out DNA. Bottom, the chromatin forms a loop that brings the enhancer, with its transcription factor, close to the promoter where RNA polymerase sits. 1. In the linear sequence the enhancer is far from the promoter enhancer promoter gene 2. The chromatin folds into a loop and brings them together transcription factor RNA polymerase enhancer
Practice★★☆Not started
What is a promoter and what role does it play in the regulation of transcription? Explain what may happen if a mutation disables the promoter of a gene.

What is a promoter and what role does it play in the regulation of transcription? Explain what may happen if a mutation disables the promoter of a gene.

Solve
Practice★★☆Not started
In eukaryotic cells, DNA is packaged bound to histones forming chromatin. Explain how the degree of chromatin compaction influences gene expression.

In eukaryotic cells, DNA is packaged bound to histones forming chromatin. Explain how the degree of chromatin compaction influences gene expression.

Solve

Epigenetics and Cell Differentiation

Fragment of double-stranded DNA with methyl groups (CH₃) attached to cytosines, which silence the gene without changing the base sequence. gene silenced by DNA methylation CH₃ CH₃ CH₃ the base sequence does not change; the gene stops being expressed
Practice★★★Not started
In a colorectal carcinoma biopsy, it is detected that the tumor suppressor gene MLH1* is completely silenced, which prevents DNA mismatch repair. When sequencing the…

In a colorectal carcinoma biopsy, it is detected that the tumor suppressor gene MLH1 is completely silenced, which prevents DNA mismatch repair. When sequencing the gene in the tumor, its nucleotide sequence is identical to that of healthy tissue; however, molecular analysis reveals dense hypermethylation of cytosines in CpG islands of its promoter region. When the tumor cells are cultured with 5-azacytidine (a DNA methyltransferase inhibitor), MLH1 expression resumes.

  1. a) Based on these data, justify why the silencing of MLH1 in this tumor constitutes an epigenetic event and not a genetic mutation.
  2. b) Explain the physical-molecular mechanism by which the presence of methyl groups on promoter cytosines prevents gene transcription, referring to the binding of transcription factors and chromatin remodeling.
  3. c) When these 5-azacytidine-treated tumor cells divide in a drug-free medium, new cell generations can inherit the methylation pattern and silence the gene again. Justify how DNA methylation is maintained and transmitted during cell replication by maintenance methyltransferases.
Solve

Genome Organization

The onion (Allium cepa) has about $16{,}000$ million base pairs of DNA, five times more than a human ($3{,}000$ million): does that mean an onion needs a biological instruction manual five times more complex than ours?

Bar representing the human genome: only about 1.5 % codes for proteins and the rest is noncoding DNA. rest: introns, regulatory sequences, repeats ≈1.5 % coding
Practice★☆☆Not started
Name two general differences between the genome of a prokaryotic cell and that of a eukaryotic cell (location, DNA shape, presence of introns).

Name two general differences between the genome of a prokaryotic cell and that of a eukaryotic cell (location, DNA shape, presence of introns).

Solve
Practice★★★Not started
Analyze the following table with genomic data from three representative organisms: | Organism | Genome size (bp) | Estimated no. of genes | Proportion of non-coding DNA…

Analyze the following table with genomic data from three representative organisms:

Organism Genome size (bp) Estimated no. of genes Proportion of non-coding DNA
Escherichia coli (bacterium) 4.6 × 10⁶ 4,300 ~12 %
Homo sapiens (human) 3.2 × 10⁹ 21,000 ~98.5 %
Paris japonica (plant) 1.5 × 10¹¹ ~30,000 >99 %
  1. a) A student claims that, since Paris japonica has a genome nearly 50 times larger than the human genome, it must possess a proportionally higher biological and anatomical complexity. Refute their claim using the data and explain what the C-value paradox consists of.
  2. b) In light of the data in the table, explain which types of sequences make up the vast majority of non-coding DNA in eukaryotes and why a bacterium cannot tolerate such a high proportion of non-coding DNA.
Solve

Back to the beginning: the onion has more DNA than we do, but almost all of it is noncoding DNA; genome size does not measure complexity.

Summary

See all the exercises in this section