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Molecular genetics · From DNA to protein

Gene Expression

A blue corn tortilla has the color it has because the cells of the kernel make pigments thanks to specific proteins. But the DNA in those cells never leaves the nucleus, and proteins are assembled in the cytoplasm. How does the information travel from a gene to the place where the protein is made? This use of the gene is called gene expression, and it happens in two stages, transcription and translation, which make up the so-called central dogma of molecular biology: DNA → RNA → protein.

Transcription: from gene to messenger RNA

In eukaryotic cells, DNA stays inside the nucleus, but proteins are made in the cytoplasm. The cell's solution is to make a portable copy of the gene: messenger RNA.

Transcription in a eukaryotic cell: inside the nucleus, RNA polymerase opens the DNA double helix, travels along the template strand in the 3'→5' direction, and synthesizes a complementary mRNA in the 5'→3' direction; the finished mRNA leaves through a nuclear pore into the cytoplasm, where it binds to a ribosome. nucleus cytoplasm 3' 5' 5' 3' coding strand DNA: template strand (read 3'→5') promoter RNA polymerase moves mRNA: copy (5'→3') 5' 3' finished mRNA exits to the cytoplasm mRNA 5' ribosome nuclear pore nuclear membrane
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Define transcription and translation and state where in the eukaryotic cell each of these processes takes place.

Define transcription and translation and state where in the eukaryotic cell each of these processes takes place.

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From the DNA template strand 3'-TACGGAACT-5', obtain the resulting mRNA sequence indicating its polarity, and state the maximum number of amino acids this fragment can…

From the DNA template strand 3'-TACGGAACT-5', obtain the resulting mRNA sequence indicating its polarity, and state the maximum number of amino acids this fragment can encode.

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The genetic code

Diagram of the genetic code: the AUG codon of the mRNA, made of the bases A, U, and G, codes for the amino acid methionine and signals the start; there are 64 codons for 20 amino acids, so the code is degenerate. A U G AUG codon (start) methionine 64 codons 20 amino acids → degenerate code
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What is a codon? State how many nucleotides make it up, how many distinct codons exist, and how many different amino acids they encode in total.

What is a codon? State how many nucleotides make it up, how many distinct codons exist, and how many different amino acids they encode in total.

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Look at the diagram of the flow of genetic information. State which molecules are labelled A, B and C, which processes occur at arrows 1 and 2, and what the area…

Look at the diagram of the flow of genetic information. State which molecules are labelled A, B and C, which processes occur at arrows 1 and 2, and what the area surrounded by the dashed line represents.

A 1 B 2 C
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Consider the following fragment of the coding sequence of an mRNA that is translated into a cytoplasmic protein: $5'\text{--- AUG - UCU - UCC - UCA - UCG --- } 3'$…

Consider the following fragment of the coding sequence of an mRNA that is translated into a cytoplasmic protein:

$5'\text{--- AUG - UCU - UCC - UCA - UCG --- } 3'$

(Note: the four codons following the AUG start codon all code for the amino acid serine).

  1. a) Based on this specific case, justify why the genetic code is degenerate and demonstrate that this property is not equivalent to saying that the code is "ambiguous".
  2. b) Suppose that two independent point mutations are introduced: Mutant 1 changes the second codon from UCU to UCC; Mutant 2 changes the third codon from UCC to UAC (which codes for tyrosine). Compare the impact of both mutations on the amino acid sequence of the protein and classify each mutation according to its functional effect.
  3. c) Reason what adaptive advantage is conferred by the fact that the degeneracy of the genetic code is almost always concentrated at the third base of each triplet (wobble hypothesis) rather than at the first or second, in the face of spontaneous point mutations.
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Translation: from mRNA to protein

mRNA uses only 4 nucleotides (A, U, G, C), but proteins have 20 different amino acids. How does the cell convert a four-letter text into a chain of amino acids?

Animation of translation: a tRNA brings an amino acid from the right to the codon of the mRNA, the amino acid joins the chain, the tRNA leaves, the mRNA advances one codon, and the polypeptide grows. chain of amino acids = protein ribosome mRNA read codon by codon

The three types of RNA work together: mRNA carries the message (the sequence of codons), tRNA carries each amino acid and places it according to its anticodon, and rRNA is the structural and catalytic component of the ribosome.

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Based on the following genetic code table: | Codon | Amino acid | | :---: | :---: | | AUG | Methionine (Met) | | CCU | Proline (Pro) | | GCU | Alanine (Ala) | | UAA |…

Based on the following genetic code table:

Codon Amino acid
AUG Methionine (Met)
CCU Proline (Pro)
GCU Alanine (Ala)
UAA Stop (Fin)
UAU Tyrosine (Tyr)
  1. a) Translate the following $\text{mRNA}$: $5'\text{-AUGGCUUAA-}3'$, and indicate the resulting amino acid sequence.
  2. b) Explain what role the first and the last codon of the fragment play.
Solve
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Differentiate the functions of mRNA, tRNA and rRNA in protein synthesis, indicating what each type of RNA contributes to the process.

Differentiate the functions of mRNA, tRNA and rRNA in protein synthesis, indicating what each type of RNA contributes to the process.

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Following a tRNA through the ribosome

The ribosome has three sites. A charged tRNA delivers its amino acid to the A site; the P site holds the tRNA attached to the growing peptide; the E site lets the uncharged tRNA exit. The initiator tRNA is the exception: it enters directly into P. The ribosome moves along the mRNA from 5' to 3'.

Ribosome reading the mRNA from 5′ to 3′, with a tRNA in each site: aminoacyl-tRNA entering at A, peptidyl-tRNA with the growing peptide at P, and uncharged tRNA leaving through E. ribosome movement (reading 5′ → 3′) enters aminoacyl-tRNA tRNA leaves uncharged growing peptide C 5′ 3′ mRNA N E P A
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The following diagram represents a functional ribosome during the elongation phase of translation: a) Justify and deduce the polarity ($5'$ and $3'$ ends) of the mRNA…

The following diagram represents a functional ribosome during the elongation phase of translation:

mRNA AUG GCU UAA UAC ? stop codon
  1. a) Justify and deduce the polarity ($5'$ and $3'$ ends) of the mRNA strand and the direction in which the ribosome will move along it.
  2. b) Write the sequence of the anticodon of the tRNA marked with a question mark (?), mandatory specifying its $5'\to 3'$ polarity, and reason which amino acid it carries knowing that the GCU codon codes for alanine.
  3. c) In a mutant strain, a suppressor tRNA is produced that is capable of recognizing the UAA codon by inserting the amino acid tyrosine. Predict what will happen to translation and to the length of the resulting protein when the ribosome reaches the position marked with the stop codon compared to the wild-type cell.
Solve

Processing of mRNA in eukaryotes

If you compare the RNA just transcribed in the nucleus with the mRNA that reaches the ribosome, the latter is often much shorter. Where do the missing pieces go?

Diagram of splicing in eukaryotes: the primary mRNA, with three exons and interspersed introns, loses the introns and leaves a mature mRNA made only of the joined exons. Exon 1 Intron 1 Exon 2 Intron 2 Exon 3 Primary mRNA: exons (color) + introns (gray) splicing Exon 1 Exon 2 Exon 3 Mature mRNA: only joined exons
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In the human genome, the fibronectin gene contains numerous exons and introns. In fibroblasts, it gives rise to an insoluble protein isoform that forms part of the…

In the human genome, the fibronectin gene contains numerous exons and introns. In fibroblasts, it gives rise to an insoluble protein isoform that forms part of the extracellular matrix, whereas in hepatocytes it originates a soluble isoform that circulates in the blood plasma.

  1. a) Justify the molecular mechanism by which a single genomic DNA sequence can give rise to these two proteins with such different functions and locations.
  2. b) A patient presents a point mutation consisting of a transition (G to A) at the splicing acceptor site of intron 4 of this gene. Predict two possible alterations in the structure of the resulting mature mRNA and their consequences for the synthesized protein.
  3. c) If we clone this intact human gene (with all its introns and exons) into a plasmid and introduce it into Escherichia coli, reason whether the bacterium will synthesize functional human fibronectin.
Solve

Gene expression in bacteria and in eukaryotes

Comparison of gene expression: in the bacterium, which has no nucleus, ribosomes translate the mRNA while RNA polymerase is still transcribing it; in the eukaryotic cell, the pre-mRNA is transcribed and matured by splicing in the nucleus, leaves through a nuclear pore, and is translated later in the cytoplasm. Bacterium: no nucleus DNA RNA polymerase movement ribosomes mRNA 5' polypeptide cytoplasm Coupled: ribosomes translate the mRNA while RNA polymerase is still transcribing it. Eukaryote: with a nucleus nucleus pre-mRNA introns splicing mature mRNA nuclear envelope nuclear pore cytoplasm ribosomes 5' 3' polypeptides Separated: transcription and maturation in the nucleus; translation occurs later, in the cytoplasm.

Back to the beginning: the DNA does not leave the nucleus, but its message does. RNA polymerase copies the gene into an mRNA, which is processed, leaves through the nuclear pores, and in the cytoplasm the ribosomes translate it codon by codon. That is how the blue corn cells make their pigments.

Summary

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