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Exercises: Gene regulation and genomes

Practice★☆☆
All the cells in your body possess the same DNA, yet a neuron and a muscle cell are very different. Explain what causes this difference with reference to gene expression.

All the cells in your body possess the same DNA, yet a neuron and a muscle cell are very different. Explain what causes this difference with reference to gene expression.

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Practice★☆☆
What is a constitutive gene and what is a regulated gene? Give an example of each type and explain why it is advantageous for the cell to regulate some of its genes.

What is a constitutive gene and what is a regulated gene? Give an example of each type and explain why it is advantageous for the cell to regulate some of its genes.

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Practice★☆☆
Name two general differences between the genome of a prokaryotic cell and that of a eukaryotic cell (location, DNA shape, presence of introns).

Name two general differences between the genome of a prokaryotic cell and that of a eukaryotic cell (location, DNA shape, presence of introns).

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The diagram represents the lac operon of Escherichia coli in two situations (A and B). State in which of them lactose is present in the medium, name the elements…

The diagram represents the lac operon of Escherichia coli in two situations (A and B). State in which of them lactose is present in the medium, name the elements labelled (P, O, Z-Y-A and ?), and explain what happens to the expression of the structural genes in each situation.

A P O Z Y A ? B P O Z Y A
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Practice★★☆
What is a promoter and what role does it play in the regulation of transcription? Explain what may happen if a mutation disables the promoter of a gene.

What is a promoter and what role does it play in the regulation of transcription? Explain what may happen if a mutation disables the promoter of a gene.

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Practice★★☆
In eukaryotic cells, DNA is packaged bound to histones forming chromatin. Explain how the degree of chromatin compaction influences gene expression.

In eukaryotic cells, DNA is packaged bound to histones forming chromatin. Explain how the degree of chromatin compaction influences gene expression.

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Practice★★★
In a colorectal carcinoma biopsy, it is detected that the tumor suppressor gene MLH1* is completely silenced, which prevents DNA mismatch repair. When sequencing the…

In a colorectal carcinoma biopsy, it is detected that the tumor suppressor gene MLH1 is completely silenced, which prevents DNA mismatch repair. When sequencing the gene in the tumor, its nucleotide sequence is identical to that of healthy tissue; however, molecular analysis reveals dense hypermethylation of cytosines in CpG islands of its promoter region. When the tumor cells are cultured with 5-azacytidine (a DNA methyltransferase inhibitor), MLH1 expression resumes.

  1. a) Based on these data, justify why the silencing of MLH1 in this tumor constitutes an epigenetic event and not a genetic mutation.
  2. b) Explain the physical-molecular mechanism by which the presence of methyl groups on promoter cytosines prevents gene transcription, referring to the binding of transcription factors and chromatin remodeling.
  3. c) When these 5-azacytidine-treated tumor cells divide in a drug-free medium, new cell generations can inherit the methylation pattern and silence the gene again. Justify how DNA methylation is maintained and transmitted during cell replication by maintenance methyltransferases.
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Practice★★★
Analyze the following table with genomic data from three representative organisms: | Organism | Genome size (bp) | Estimated no. of genes | Proportion of non-coding DNA…

Analyze the following table with genomic data from three representative organisms:

Organism Genome size (bp) Estimated no. of genes Proportion of non-coding DNA
Escherichia coli (bacterium) 4.6 × 10⁶ 4,300 ~12 %
Homo sapiens (human) 3.2 × 10⁹ 21,000 ~98.5 %
Paris japonica (plant) 1.5 × 10¹¹ ~30,000 >99 %
  1. a) A student claims that, since Paris japonica has a genome nearly 50 times larger than the human genome, it must possess a proportionally higher biological and anatomical complexity. Refute their claim using the data and explain what the C-value paradox consists of.
  2. b) In light of the data in the table, explain which types of sequences make up the vast majority of non-coding DNA in eukaryotes and why a bacterium cannot tolerate such a high proportion of non-coding DNA.
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Practice★★★
In a laboratory, a mutant strain of Escherichia coli* displaying a complete deletion in the regulatory gene lacI* (I⁻* phenotype) is studied. A student predicts that…

In a laboratory, a mutant strain of Escherichia coli displaying a complete deletion in the regulatory gene lacI (I⁻ phenotype) is studied. A student predicts that this bacterium will maximally transcribe the structural genes of the lac operon under any circumstance, since the repressor will never bind to the operator.

To test their hypothesis, the strain is cultured in three media with equivalent concentrations of basic nutrients:

  • Medium A: glucose as the sole carbon source.

  • Medium B: simultaneous presence of glucose and lactose.

  • Medium C: lactose as the sole carbon source.

  1. a) Evaluate whether the student's prediction is correct. Justify what level of operon transcription (null, very low basal, or high) will be observed in each of the three media, detailing the molecular mechanism involved (role of the CAP-cAMP complex and adenylyl cyclase).
  2. b) Predict with reasoning what would happen to transcription in Medium C if the strain were to acquire a second mutation that inactivated the CAP protein gene.
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