Back to homeMathematics · 3rd Year · Change subject
Start for free
3rd Year · Mathematics
Geometry and Trigonometry · Similarity

Right-angled triangles

Before you start, make sure you know: Similar triangles (2nd Year, Junior Cycle)

How could you find the height of a floodlight pylon at a GAA pitch without climbing it? Similar triangles [Theorem 13] are the basis of real techniques for measuring things you cannot reach with a tape measure, from the height of a pylon to the width of a river. You already know similar triangles and Pythagoras' Theorem; here you will apply them in context, and you will answer the pylon question in the mirror method.

Quick revision: similar right-angled triangles

Practice★☆☆Not started
In a gable roof that forms a right angle at its apex, the altitude drawn from that vertex divides the base (hypotenuse) into two segments of $2\text{ m}$ and…

In a gable roof that forms a right angle at its apex, the altitude drawn from that vertex divides the base (hypotenuse) into two segments of $2\text{ m}$ and $8\text{ m}$. Apply the altitude theorem to calculate the maximum height of the roof.

Solve
Practice★☆☆Not started
A skate ramp has a right-angled triangle profile resting on its hypotenuse. The horizontal base (hypotenuse) measures $10\text{ m}$ and the projection of the upward…

A skate ramp has a right-angled triangle profile resting on its hypotenuse. The horizontal base (hypotenuse) measures $10\text{ m}$ and the projection of the upward slope onto the base is $3.6\text{ m}$. Use the cathetus theorem to calculate the length of the upward slope.

Solve
Practice★☆☆Not started
In a technical drawing class, a student draws a right-angled triangle with a hypotenuse of $13\text{ cm}$ and legs of $5\text{ cm}$ and $12\text{ cm}$. Then, they draw…

In a technical drawing class, a student draws a right-angled triangle with a hypotenuse of $13\text{ cm}$ and legs of $5\text{ cm}$ and $12\text{ cm}$. Then, they draw the altitude to the hypotenuse. Use the leg theorem to calculate the lengths of both projections of the legs onto the hypotenuse.

You can do it on paper and send a photo with your answer.

Solve

Finding the altitude: area and quadratic equations

There are two ways to find the altitude $h$ when the projections are not both known. If you know the sides, use areas: the area of a right-angled triangle is half of leg × leg and also half of hypotenuse × altitude, so $\text{hypotenuse} \times h = \text{leg} \times \text{leg}$. If you only know how the projections are related, write $h^2 = m \times n$ (or a leg theorem) as a quadratic equation and solve it.

If the projections are in the ratio $9 : 16$, write them as $9t$ and $16t$. Then $h^2 = 9t \times 16t = 144t^2$.

Practice★★☆Not started
The façade of a modern building has a right-angled triangular window resting on its hypotenuse. The height of the window relative to the base is $4.8\text{ m}$ and the…

The façade of a modern building has a right-angled triangular window resting on its hypotenuse. The height of the window relative to the base is $4.8\text{ m}$ and the projection of the shorter side onto the base is $3.6\text{ m}$. Calculate the lengths of both legs and the hypotenuse.

3.6 m n = ? h = 4.8 m
Solve
Practice★★☆Not started
A plot of farmland is in the shape of a right-angled triangle. The projection of one leg onto the hypotenuse is $4\text{ dam}$ longer than the projection of the other…

A plot of farmland is in the shape of a right-angled triangle. The projection of one leg onto the hypotenuse is $4\text{ dam}$ longer than the projection of the other leg. If the altitude to the hypotenuse is $4.8\text{ dam}$, set up a quadratic equation and calculate the total length of the hypotenuse.

Solve
Practice★★★Not started
In an architectural design, the profile of a roof is a right-angled triangle resting on its hypotenuse. The altitude drawn from the vertex of the right angle divides the…

In an architectural design, the profile of a roof is a right-angled triangle resting on its hypotenuse. The altitude drawn from the vertex of the right angle divides the hypotenuse into two segments in the ratio $9:16$. If the altitude measures $6\text{ m}$, calculate the total perimeter of the triangle that forms the roof.

9k 16k h = 6 m
Solve

Scale factors for areas and volumes

If two figures or solids are similar with scale factor $k$, lengths are multiplied by $k$, areas by $k^2$ and volumes by $k^3$. Why? An area is length × length, so $k$ appears twice; a volume has three lengths.

Practice★☆☆Not started
Two right-angled triangular road signs are similar. The shorter leg of the small sign measures $30\text{ cm}$ and its area is $600\text{ cm}^2$. If the shorter leg of…

Two right-angled triangular road signs are similar. The shorter leg of the small sign measures $30\text{ cm}$ and its area is $600\text{ cm}^2$. If the shorter leg of the large sign measures $60\text{ cm}$, what is the area of the large sign?

Solve
Practice★★★Not started
A right pyramid with a square base is cut by a plane parallel to the base at one-third of its height (measured from the apex). If the area of the cross-section obtained…

A right pyramid with a square base is cut by a plane parallel to the base at one-third of its height (measured from the apex). If the area of the cross-section obtained is $15\text{ cm}^2$, what is the volume of the original pyramid if its total height is $18\text{ cm}$?

Solve

Checking whether two right-angled triangles are similar

For two right-angled triangles to be similar, it is enough for both legs to be proportional, or for a leg and the hypotenuse to be proportional: the right angle is already shared.

Two right-angled triangles with dimensions, used to compare whether their legs and hypotenuse are proportional. 15 20 40 50 (hyp.) 30
Practice★☆☆Not started
A carpenter cuts two wooden wedges in the shape of a right-angled triangle. The first has legs of $15\text{ cm}$ and $20\text{ cm}$. The second has a hypotenuse of…

A carpenter cuts two wooden wedges in the shape of a right-angled triangle. The first has legs of $15\text{ cm}$ and $20\text{ cm}$. The second has a hypotenuse of $50\text{ cm}$ and a leg of $30\text{ cm}$. Check mathematically whether both wedges are similar.

Solve
Practice★☆☆Not started
The two main ropes that secure the central pole of a tent from the top to the ground form a right angle with each other. The pole is $4\text{ m}$ high and one of the…

The two main ropes that secure the central pole of a tent from the top to the ground form a right angle with each other. The pole is $4\text{ m}$ high and one of the ropes is anchored $3.2\text{ m}$ from the base of the pole. At what distance from the base is the other rope anchored?

Solve

The mirror method

A flat mirror on the ground reflects angles just as they arrive: the angle of incidence equals the angle of reflection. This creates two similar right-angled triangles —the one formed by your eyes and the mirror, and the one formed by the object and the mirror— which let you calculate heights you cannot reach without climbing anything.

Diagram of the mirror method for measuring an inaccessible height using two similar right-angled triangles with the same angle of reflection. mirror 1.6 m 1.5 m h ? 12 m
Practice★★☆Not started
To measure the height of a wind turbine, an engineer places a flat mirror on the ground $12\text{ m}$ from the base of the tower. She steps back $1.5\text{ m}$ from the…

To measure the height of a wind turbine, an engineer places a flat mirror on the ground $12\text{ m}$ from the base of the tower. She steps back $1.5\text{ m}$ from the mirror until she sees the top of the wind turbine reflected exactly in the centre of the mirror. If the engineer's eye level is $1.6\text{ m}$ above the ground, calculate the height of the wind turbine.

Solve
Practice★☆☆Not started
In your schoolyard, you want to measure the height of the basketball hoop using the mirror method (based on the fact that the angle of incidence and the angle of…

In your schoolyard, you want to measure the height of the basketball hoop using the mirror method (based on the fact that the angle of incidence and the angle of reflection of light are identical, generating similar right-angled triangles). You place a horizontal flat mirror on the ground $2.25\text{ m}$ from the base of the hoop post. You walk backwards in a straight line and stand $1.20\text{ m}$ from the mirror, at which point you see the rim accurately reflected. Your eyes are $1.60\text{ m}$ above the ground.

  1. a) Before doing any algebraic calculations, observe the relationship between the distance from the mirror to the hoop ($2.25\text{ m}$) and the distance from the mirror to you ($1.20\text{ m}$). Estimate whether the height of the hoop will be greater than, less than, or equal to twice your eye level height ($3.20\text{ m}$), justifying your intuitive estimate.
  2. b) Set up the formal similarity proportion between the two right-angled triangles, calculate the exact value of the height of the hoop, and evaluate whether the obtained result confirms your previous estimate and whether it is consistent with the actual dimensions of a regulation basketball hoop.
Solve

Overlapping triangles: billiards and inscribed squares

When a figure hides two right-angled triangles that share an angle (and are therefore similar), the proportion between their sides solves problems that at first sight do not look like similarity problems.

Path of a billiard ball bouncing towards a pocket, split into two similar right-angled triangles. 20 60 100 cm x
Practice★★☆Not started
On a billiard table, a ball must hit the cushion and bounce towards a pocket, forming two similar right-angled triangles. The ball is $20\text{ cm}$ from the cushion and…

On a billiard table, a ball must hit the cushion and bounce towards a pocket, forming two similar right-angled triangles. The ball is $20\text{ cm}$ from the cushion and the pocket is $60\text{ cm}$ from the same cushion. If the horizontal distance parallel to the cushion between the ball and the pocket is $100\text{ cm}$, at what horizontal distance from the initial position of the ball must the impact on the cushion occur?

20 60 100 cm x
Solve
Practice★★☆Not started
In a piece of jewellery, a square of side length $x$ is inscribed inside a right-angled triangle with legs $6\text{ mm}$ and $8\text{ mm}$, such that the vertex of the…

In a piece of jewellery, a square of side length $x$ is inscribed inside a right-angled triangle with legs $6\text{ mm}$ and $8\text{ mm}$, such that the vertex of the triangle's right angle coincides with a vertex of the square and the opposite vertex of the square lies on the hypotenuse. Calculate the value of $x$ using similar triangles.

Solve
Practice★★★Not started
A rectangular sheet of paper $8\text{ cm}$ wide and $15\text{ cm}$ long is folded so that two opposite vertices coincide. The crease formed is a straight line. Calculate…

A rectangular sheet of paper $8\text{ cm}$ wide and $15\text{ cm}$ long is folded so that two opposite vertices coincide. The crease formed is a straight line. Calculate the length of this crease based on the similarity of the right-angled triangles formed.

Solve

Measuring an inaccessible width: the marker-pole method

To measure the width of a river without crossing it, you use two similar right-angled triangles built with marker poles on one bank only: a large one (up to the tree on the other bank) and a small one that you can measure entirely.

Diagram of the marker-pole method for measuring the width of a river using two similar right-angled triangles that are vertically opposite. tree A observer 30 m 6 m 4 m pole
Practice★★★Not started
A surveyor wants to calculate the width of a river. To do so, he stands on one bank and sights a tree on the opposite bank. He walks $30\text{ m}$ along the bank…

A surveyor wants to calculate the width of a river. To do so, he stands on one bank and sights a tree on the opposite bank. He walks $30\text{ m}$ along the bank (perpendicular to the initial line of sight) and places a marker post. He then walks another $6\text{ m}$ in the same direction, turns $90^\circ$ away from the river, and walks $4\text{ m}$ until he sees the marker post aligned with the tree. What is the width of the river?

Solve
Practice★★☆Not started
In an area of the Parque Nacional de Ordesa y Monte Perdido (Huesca), a group of forest rangers needs to estimate the width of an inaccessible ravine through which a…

In an area of the Parque Nacional de Ordesa y Monte Perdido (Huesca), a group of forest rangers needs to estimate the width of an inaccessible ravine through which a torrential river flows. On the opposite bank, there is a vertical beacon $R$ fixed to the rock. To apply the ranging pole method from their accessible bank, they make the following marks in a straight line along the edge:

  • They drive a pole $A$ right in front of the beacon $R$, so that the line of sight $RA$ is perpendicular to the bank.

  • They walk $15\text{ m}$ along the bank and drive a pole $B$.

  • They keep walking $5\text{ m}$ more in the same direction and mark point $C$.

  • From $C$, they move inland perpendicularly to the bank until they find a point $D$ from which the pole $B$ and the beacon $R$ are perfectly aligned. They measure the distance traveled: $CD = 8\text{ m}$.

  1. a) Formally prove which criterion guarantees that the right-angled triangles $\triangle RAB$ and $\triangle DCB$ are similar.
  2. b) Translate the situation into a geometric proportion and calculate the width of the ravine ($RA$).
  3. c) If, due to a lack of space on the bank, they had placed pole $B$ $10\text{ m}$ from $A$ and another $10\text{ m}$ from $C$, how many metres would they have had to walk inland from $C$ to align the line of sight? Explain what technical or precision advantage is gained by choosing different distances instead of equal ones.
Solve

Summary

See all the exercises in this section