Simplifying Surds
A square vegetable garden in Galway has an area of $72$ m². Its side is $\sqrt{72}$ m… but how much is that? With a calculator, $8.485\ldots$, but there is an exact and much more useful way of writing it: $6\sqrt{2}$. In this section you will learn to simplify surds by taking out of the root everything that can be taken out.
Higher Level only: simplifying surds is part of the Higher Level course.
Taking factors out of a root
Since $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$, if there is a perfect square multiplying inside the root of a surd, it can come out:
$$\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}$$To extract factors from a root, we group the repeated factors of the radicand as indicated by the index: in a square root (index $2$), each group of $2$ equal factors…
To extract factors from a root, we group the repeated factors of the radicand as indicated by the index: in a square root (index $2$), each group of $2$ equal factors comes out as a single factor; in a cube root (index $3$), each group of $3$ comes out.
Look at the following diagram representing $\sqrt[3]{x^4}$. As $x^4 = x^3 \times x$, the group of $3$ comes out as a single $x$ and the remaining factor stays inside.
Following this logic, extract all possible factors from the following roots:
- a) $\sqrt{x^3}$
- b) $\sqrt{a^5}$
- c) $\sqrt[3]{m^4}$
- d) $\sqrt[4]{y^5}$
Many times we find numbers that are not factorised. The first step must always be to decompose the number into prime factors. For example, to simplify $\sqrt{12}$, we…
Many times we find numbers that are not factorised. The first step must always be to decompose the number into prime factors.
For example, to simplify $\sqrt{12}$, we first think that $12 = 2^2 \times 3$. As $2$ is squared, it can "escape" from the square root.
Decompose into prime factors and extract as much as you can from these square roots:
- a) $\sqrt{18}$
- b) $\sqrt{50}$
- c) $\sqrt{20}$
- d) $\sqrt{75}$
We have a square plot of land. We know that its area is $72 \text{ m}^2$, but we want to know exactly how long its side is, expressed in the simplest possible form (by…
We have a square plot of land. We know that its area is $72 \text{ m}^2$, but we want to know exactly how long its side is, expressed in the simplest possible form (by extracting factors).
Remember that if the Area of a square is $l^2$, then the side is $l = \sqrt{\text{Area}}$.
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Factorise the number 72.
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Write $\sqrt{72}$ using those factors.
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Extract the numbers that are squared.
Extract all possible factors from the following numerical radicals. To do this, you must first find the prime factor decomposition of the numbers inside the root. a)…
Extract all possible factors from the following numerical radicals. To do this, you must first find the prime factor decomposition of the numbers inside the root.
- a) $\sqrt{216}$
- b) $\sqrt[3]{5000}$
- c) $\sqrt[4]{162}$
Variables and fractions inside the root
With letters we also have to look at the sign: $\sqrt{x^2} = |x|$, because the principal root cannot be negative. For example, if $x = -3$, $\sqrt{x^2} = 3$, not $-3$. For roots with an odd index the sign is preserved: $\sqrt[3]{x^3} = x$.
In the example $\sqrt{50x^3/9}$, the real domain requires $x \ge 0$. For instance, $\sqrt{180a^5} = 6a^2\sqrt{5a}$ for $a \ge 0$. That is why here we can take the factors out without absolute values. In a fraction, we work separately with the numerator and the denominator, checking that the denominator is not zero.
$$\sqrt{\frac{50\,x^{3}}{9}} = \frac{\sqrt{2 \cdot 5^{2} \cdot x^{2} \cdot x}}{\sqrt{3^{2}}} = \frac{5x\sqrt{2x}}{3}$$Sometimes we have numbers and letters mixed inside a root. The procedure is the same: we work with the number on one side and with each letter on the other. Simplify the…
Sometimes we have numbers and letters mixed inside a root. The procedure is the same: we work with the number on one side and with each letter on the other.
Simplify the following radicals by extracting all possible factors:
- a) $\sqrt{8x^3}$
- b) $\sqrt{27a^2}$
- c) $\sqrt{16y^5}$
- d) $\sqrt{25z^3}$
We can not only extract factors from the numerator, but also from the denominator if we have fractions inside the root. If we have $\sqrt{\frac{a^3}{b^2}}$, we can take…
We can not only extract factors from the numerator, but also from the denominator if we have fractions inside the root.
If we have $\sqrt{\frac{a^3}{b^2}}$, we can take factors out from top and bottom independently. In this example, $b^2$ comes out as $b$ in the denominator, and from $a^3$ we take out an $a$ in the numerator: $\frac{a}{b}\sqrt{a}$.
Try to simplify these expressions:
- a) $\sqrt{\frac{50}{9}}$
- b) $\sqrt{\frac{x^3}{4}}$
- c) $\sqrt{\frac{1}{27}}$ (Hint: factorise 27 and leave it in the denominator)
Simplify the following radicals containing variables. Remember that to be able to extract a variable, its exponent must be equal to or greater than the index of the…
Simplify the following radicals containing variables. Remember that to be able to extract a variable, its exponent must be equal to or greater than the index of the root.
- a) $\sqrt[3]{x^4 \times y^7 \times z^{10}}$
- b) $\sqrt{25a^3 b^5 c}$
- c) $\sqrt[5]{\frac{m^7}{n^{10}}}$
Putting factors in
This is the reverse process: a non-negative factor that is outside goes in raised to the power of the index. With an odd index, a negative factor can also go in. With an even index, the negative sign stays outside: $-3\sqrt{5} = -\sqrt{45}$, not $\sqrt{45}$.
$$3\sqrt{5} = \sqrt{3^{2} \cdot 5} = \sqrt{45} \qquad\qquad 2\sqrt[3]{4} = \sqrt[3]{2^{3} \cdot 4} = \sqrt[3]{32}$$It is useful, for example, for comparing surds: which is larger, $3\sqrt{5}$ or $4\sqrt{3}$? Putting the factors inside: $\sqrt{45}$ versus $\sqrt{48}$. $4\sqrt{3}$ wins.
Let's play the inverse process to check if you have understood extraction. If I have a factor outside the root and I want to put it inside, I have to raise it to the…
Let's play the inverse process to check if you have understood extraction. If I have a factor outside the root and I want to put it inside, I have to raise it to the index of the root.
For example: $3\sqrt{2} = \sqrt{3^2 \times 2} = \sqrt{9 \times 2} = \sqrt{18}$.
In your exercise book, match each simplified expression on the left with its original root on the right (you don't need to calculate, just reason which number came out):
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$2\sqrt{2}$ --- A. $\sqrt{12}$
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$3\sqrt{2}$ --- B. $\sqrt{20}$
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$2\sqrt{3}$ --- C. $\sqrt{8}$
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$2\sqrt{5}$ --- D. $\sqrt{18}$
State whether the following equalities are true or false by carrying out the necessary factor extraction: a) $\sqrt{a^2 + b^2} = a + b$ b) $\sqrt{16 \times x^6} = 4x^3$…
State whether the following equalities are true or false by carrying out the necessary factor extraction:
- a) $\sqrt{a^2 + b^2} = a + b$
- b) $\sqrt{16 \times x^6} = 4x^3$
- c) $\sqrt[3]{8 + 27} = 5$
- d) $\sqrt{\frac{x^2}{4}} = \frac{x}{2}$
Harder cases
When the expression under the root is awkward, tidy it first, then take factors out.
In many scientific formulas, very large or very small powers of 10 appear inside roots. Simplify the following expressions by extracting powers of 10 from the radical:…
In many scientific formulas, very large or very small powers of 10 appear inside roots. Simplify the following expressions by extracting powers of 10 from the radical:
- a) $\sqrt{1.44 \times 10^7}$
- b) $\sqrt[3]{2 \times 10^{14}}$
- c) $\sqrt{0.00003}$ (Hint: express it first as $3 \times 10^{-5}$)
Calculate and simplify the following radical by decomposing the radicand into prime factors. Be careful, as the radicand is a negative number and the index is odd, so…
Calculate and simplify the following radical by decomposing the radicand into prime factors. Be careful, as the radicand is a negative number and the index is odd, so the result exists in real numbers. Extract all possible factors from the root.
$$ \sqrt[3]{-54000} $$Simplify the following nested radical. First, convert the expression into a single root by multiplying the indices and express the radicand as a power. Finally, extract…
Simplify the following nested radical. First, convert the expression into a single root by multiplying the indices and express the radicand as a power. Finally, extract all possible factors.
$$ \sqrt{\sqrt[3]{64 \times a^{13} \times b^7}} $$Using surds
Exact answers matter in geometry, and you can always check them by estimating between two perfect squares.
Back to the start: the garden with area $72$ m² has side $6\sqrt{2}$ m. Since $64 < 72 < 81$, the side is between $8$ m and $9$ m, which matches $8.485\ldots$ m.
We have a cubic water tank. We know that its total volume is $686 \text{ m}^3$. Calculate the length of the edge of the tank, expressing the result using a simplified…
We have a cubic water tank. We know that its total volume is $686 \text{ m}^3$. Calculate the length of the edge of the tank, expressing the result using a simplified radical (by extracting factors).
Calculate the length of the hypotenuse of a right-angled triangle whose legs measure $10 \text{ cm}$ and $5 \text{ cm}$. Apply Pythagoras' theorem and express the final…
Calculate the length of the hypotenuse of a right-angled triangle whose legs measure $10 \text{ cm}$ and $5 \text{ cm}$. Apply Pythagoras' theorem and express the final result by extracting all possible factors from the root.
We have a square plot of land with an area of $720 \text{ m}^2$. We want to install an irrigation pipe crossing the land diagonally. Calculate the exact length of the…
We have a square plot of land with an area of $720 \text{ m}^2$. We want to install an irrigation pipe crossing the land diagonally. Calculate the exact length of the pipe, expressing the result as a simplified radical (extracting the maximum number of factors).
Like surds
Two surds are like surds if, after taking factors out, they have the same index and the same radicand. $\sqrt{8}$, $\sqrt{18}$ and $\sqrt{50}$ look different, but:
$$\sqrt{8} = 2\sqrt{2}, \qquad \sqrt{18} = 3\sqrt{2}, \qquad \sqrt{50} = 5\sqrt{2}$$All three are "multiples of $\sqrt{2}$". That is why they can be added: $\sqrt{8} + \sqrt{18} - \sqrt{50} = (2 + 3 - 5)\sqrt{2} = 0$. You will see this in depth in the next section.
In order to add or subtract radicals, they must be like radicals. At first glance, the following radicals appear different. Extract factors from each of them to check…
In order to add or subtract radicals, they must be like radicals. At first glance, the following radicals appear different. Extract factors from each of them to check whether their radical parts are the same and, if so, express them in simplified form:
- a) $\sqrt{80}$
- b) $\sqrt{125}$
- c) $2\sqrt{45}$
Simplify the following fractions containing radicals by extracting factors from both the numerator and the denominator. If possible, simplify the resulting fraction: a)…
Simplify the following fractions containing radicals by extracting factors from both the numerator and the denominator. If possible, simplify the resulting fraction:
- a) $\sqrt{\frac{98}{75}}$
- b) $\sqrt[3]{\frac{16a^4}{27b^3}}$