Back to homePhysics and Chemistry · 2nd ESO · Change subject
Start for free
ESO Y2 · Physics and Chemistry
Interaction · Motion

Speed

A runner covers 100 m in 20 s. A cyclist covers 30 km in 2 h. Who is faster? To compare them, you need a single quantity that relates the distance they cover to the time they take: speed.

Before you start, make sure you know: First-degree equations (1st ESO)
Before you start, make sure you know: Direct proportion (1st ESO)

What speed is

Two swimmers train in a pool: the first swims 50 m in 25 s and the second swims 100 m in 60 s; how can we tell for certain which one swims faster if they have covered different distances in different times?

Straight path of 100 metres covered in 20 seconds, with the calculation of the resulting average speed of 5 metres per second. d = 100 m t = 0 s t = 20 s v = 100 m ÷ 20 s = 5 m/s
Practice★☆☆Not started
A runner covers $100\ \text{m}$ in $20\ \text{s}$. Calculate their average speed in $\text{m/s}$.

A runner covers $100\ \text{m}$ in $20\ \text{s}$. Calculate their average speed in $\text{m/s}$.

Solve
Practice★☆☆Not started
State which of these expressions are units of speed and which are not, and explain why: a) $\text{m/s}$ b) $\text{km}$ c) $\text{km/h}$ d) $\text{s}$

State which of these expressions are units of speed and which are not, and explain why:

  1. a) $\text{m/s}$
  2. b) $\text{km}$
  3. c) $\text{km/h}$
  4. d) $\text{s}$
Solve
Practice★☆☆Not started
Who travels faster: Alma, who covers $60\ \text{m}$ in $12\ \text{s}$, or Bruno, who covers $40\ \text{m}$ in $10\ \text{s}$? Calculate the speed of each and compare…

Who travels faster: Alma, who covers $60\ \text{m}$ in $12\ \text{s}$, or Bruno, who covers $40\ \text{m}$ in $10\ \text{s}$? Calculate the speed of each and compare them.

Solve

Changing units: m/s and km/h

Diagram of the conversion factor between kilometres per hour and metres per second, dividing or multiplying by 3,6. km/h m/s ÷ 3,6 × 3,6 72 km/h ÷ 3,6 = 20 m/s 15 m/s × 3,6 = 54 km/h
Practice★★☆Not started
A car travels along a motorway at $90\ \text{km/h}$. Express its speed in $\text{m/s}$. Remember: $1\ \text{km} = 1000\ \text{m}$ and $1\ \text{h} = 3600\ \text{s}$.

A car travels along a motorway at $90\ \text{km/h}$. Express its speed in $\text{m/s}$. Remember: $1\ \text{km} = 1000\ \text{m}$ and $1\ \text{h} = 3600\ \text{s}$.

Solve
Practice★★☆Not started
A greyhound runs at $20\ \text{m/s}$. Express its speed in $\text{km/h}$.

A greyhound runs at $20\ \text{m/s}$. Express its speed in $\text{km/h}$.

Solve
Practice★★★Not started
The distance from the Earth to the Moon is $3,84\cdot10^{8}\ \text{m}$ and light travels at $3\cdot10^{8}\ \text{m/s}$. How long does it take for moonlight to reach us?…

The distance from the Earth to the Moon is $3,84\cdot10^{8}\ \text{m}$ and light travels at $3\cdot10^{8}\ \text{m/s}$. How long does it take for moonlight to reach us? Give the answer in seconds, to two decimal places.

Solve

Comparing speeds

A car at 72 km/h, equivalent to 20 m/s, and a cyclist at 15 m/s, with arrows whose lengths are proportional to their speeds: the car's arrow is longer. 72 km/h ÷ 3,6 20 m/s now in m/s 15 m/s 20 m/s > 15 m/s
Practice★★☆Not started
Who is faster: a car travelling at $72\ \text{km/h}$ or a cyclist going downhill at $15\ \text{m/s}$? Convert both speeds to the same unit to compare them.

Who is faster: a car travelling at $72\ \text{km/h}$ or a cyclist going downhill at $15\ \text{m/s}$? Convert both speeds to the same unit to compare them.

Solve
Practice★★☆Not started
Order the following speeds from lowest to highest, expressing them all in $\text{m/s}$ first: a) $18\ \text{km/h}$ b) $10\ \text{m/s}$ c) $900\ \text{m/min}$

Order the following speeds from lowest to highest, expressing them all in $\text{m/s}$ first:

  1. a) $18\ \text{km/h}$
  2. b) $10\ \text{m/s}$
  3. c) $900\ \text{m/min}$
Solve

Average speed on journeys with several stages

You set off on a trip and drive for 1 hour along a motorway at 120 km/h, but then you are stuck in a traffic jam for 2 hours at 20 km/h: what has your overall average speed been, and why does it not match the simple average of the two figures?

To see why, first look at a different journey, with two stages of the same distance (60 km each); we will come back to the traffic jam at the end.

Journey in two stages of 60 km: the first at 120 km/h for 0,5 h and the second at 60 km/h for 1 h; in total 120 km in 1,5 h, that is, an average of 80 km/h. Stage 1: 60 km at 120 km/h (0,5 h) Stage 2: 60 km at 60 km/h (1 h) 0,5 h 120 km in 1,5 h → average of 80 km/h
Practice★★☆Not started
A swimmer crosses a $25\ \text{m}$ pool in $10\ \text{s}$ and returns to the starting point in $15\ \text{s}$, as shown in the figure. a) What is the total distance…

A swimmer crosses a $25\ \text{m}$ pool in $10\ \text{s}$ and returns to the starting point in $15\ \text{s}$, as shown in the figure.

25 m outward trip: 10 s return: 15 s
  1. a) What is the total distance covered and how much time did it take?
  2. b) What is her average speed for the whole journey?
  3. c) What was her total displacement? Explain the difference between displacement and distance.
Solve
Practice★★★Not started
A car travels $60\ \text{km}$ at $120\ \text{km/h}$ and another $60\ \text{km}$ at $60\ \text{km/h}$, as shown in the figure. a) Calculate the time taken for each…

A car travels $60\ \text{km}$ at $120\ \text{km/h}$ and another $60\ \text{km}$ at $60\ \text{km/h}$, as shown in the figure.

60 km 120 km/h 60 km 60 km/h
  1. a) Calculate the time taken for each section.
  2. b) Calculate the average speed for the whole trip.
  3. c) Explain why the average speed is not $90\ \text{km/h}$, the mean of the two speeds.
Solve
Practice★★★Not started
A cyclist covers $3\ \text{km}$ in $10\ \text{min}$ with a tailwind and takes $15\ \text{min}$ to return along the same route. a) Calculate her speed on the outward and…

A cyclist covers $3\ \text{km}$ in $10\ \text{min}$ with a tailwind and takes $15\ \text{min}$ to return along the same route.

  1. a) Calculate her speed on the outward and return journeys, in $\text{km/h}$.
  2. b) Calculate her average speed for the complete trip.
  3. c) Is the average speed equal to the mean of the two speeds from part a)? Reason your answer.
Solve

Back to the beginning: The runner has a speed of $5\text{ m/s}$ ($18\text{ km/h}$) and the cyclist $15\text{ km/h}$ ($30\text{ km} \div 2\text{ h}$); therefore, the runner is faster. And in the traffic-jam trip you cover $120 + 40 = 160\text{ km}$ in $3\text{ h}$, an average of about $53\text{ km/h}$, not $70\text{ km/h}$.

Summary

See all the exercises in this section