Law of Definite Proportions (Proust)
If you analyze tap water from your home in Santiago and spring water from the Cordillera Central, will they have the same proportion of hydrogen and oxygen? The answer is yes, always, and that simple fact is one of the most useful laws in chemistry.
Proust's discovery
At the end of the 18th century, the French chemist Joseph Louis Proust analyzed the same compound obtained from very different sources (natural minerals, laboratory reactions...) and found something surprising: the ratio between the elements that made it up was always identical.
Complete the law in your own words and check it with water from two different origins.
Complete the sentence with the missing words: "When two or more elements combine to form a specific $\dots$, they always do so in the same proportion by $\dots$,…
Complete the sentence with the missing words: "When two or more elements combine to form a specific $\dots$, they always do so in the same proportion by $\dots$, regardless of the amount of $\dots$ or its origin."
We analyse distilled water from a laboratory and collected, purified rainwater. In what ratio do hydrogen and oxygen combine in each? What does Proust's law say about…
We analyse distilled water from a laboratory and collected, purified rainwater. In what ratio do hydrogen and oxygen combine in each? What does Proust's law say about the origin of the samples?
Calculating with a fixed ratio
If you know the ratio of a compound, you can calculate the mass of one element from the mass of the other, just as you would with a cooking recipe: if you double the rice, you double the water.
Notice that the more hydrogen you add, the more oxygen you need to keep exactly the same $1:8$ ratio.
In water, hydrogen and oxygen combine in the ratio of $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen. How many grams of oxygen will combine with…
In water, hydrogen and oxygen combine in the ratio of $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen. How many grams of oxygen will combine with $4\ \text{g}$ of hydrogen?
To form carbon dioxide, carbon and oxygen combine in the ratio of $3\ \text{g}$ of carbon for every $8\ \text{g}$ of oxygen. What mass of oxygen do you need to…
To form carbon dioxide, carbon and oxygen combine in the ratio of $3\ \text{g}$ of carbon for every $8\ \text{g}$ of oxygen. What mass of oxygen do you need to completely burn $9\ \text{g}$ of carbon?
If $1\ \text{g}$ of hydrogen reacts exactly with $8\ \text{g}$ of oxygen, what mass of water is formed? What other law of chemical reactions did you need besides…
If $1\ \text{g}$ of hydrogen reacts exactly with $8\ \text{g}$ of oxygen, what mass of water is formed? What other law of chemical reactions did you need besides Proust's law?
Calcium and oxygen combine in the ratio $5:2$ to form quicklime (calcium oxide). a) What mass of calcium combines with $16\ \text{g}$ of oxygen? b) What mass of…
Calcium and oxygen combine in the ratio $5:2$ to form quicklime (calcium oxide).
- a) What mass of calcium combines with $16\ \text{g}$ of oxygen?
- b) What mass of quicklime is obtained?
We completely decompose $90\ \text{g}$ of water into its elements (ratio $1:8$ between hydrogen and oxygen). What mass of hydrogen and what mass of oxygen are obtained?
We completely decompose $90\ \text{g}$ of water into its elements (ratio $1:8$ between hydrogen and oxygen). What mass of hydrogen and what mass of oxygen are obtained?
In ammonia, nitrogen and hydrogen combine in the ratio $14:3$. a) What mass of hydrogen combines exactly with $28\ \text{g}$ of nitrogen? b) What mass of ammonia is…
In ammonia, nitrogen and hydrogen combine in the ratio $14:3$.
- a) What mass of hydrogen combines exactly with $28\ \text{g}$ of nitrogen?
- b) What mass of ammonia is formed?
Magnesium and oxygen combine in the ratio $3:2$ when forming magnesium oxide. If we analyse $20\ \text{g}$ of magnesium oxide, what mass of magnesium and what mass of…
Magnesium and oxygen combine in the ratio $3:2$ when forming magnesium oxide. If we analyse $20\ \text{g}$ of magnesium oxide, what mass of magnesium and what mass of oxygen does it contain?
In a first experiment, $4\ \text{g}$ of copper combine exactly with $1\ \text{g}$ of oxygen. In a second experiment, we start with twice as much copper. a) What mass of…
In a first experiment, $4\ \text{g}$ of copper combine exactly with $1\ \text{g}$ of oxygen. In a second experiment, we start with twice as much copper.
- a) What mass of oxygen will combine with $8\ \text{g}$ of copper?
- b) What mass of oxide is obtained in each experiment?
- c) Does the combination ratio depend on the amount of sample used? Justify your answer.
Are they the same compound?
Proust's law also works in reverse: if you are given two samples with different masses of the same elements, you can check whether they are compatible with the same compound by calculating the ratio of each one.
One water sample contains $2\ \text{g}$ of hydrogen and $16\ \text{g}$ of oxygen; another sample contains $5\ \text{g}$ of hydrogen and $40\ \text{g}$ of oxygen. The…
One water sample contains $2\ \text{g}$ of hydrogen and $16\ \text{g}$ of oxygen; another sample contains $5\ \text{g}$ of hydrogen and $40\ \text{g}$ of oxygen. The figure compares the composition of the two samples.
Calculate the ratio between hydrogen and oxygen in each sample and reason whether they could be the same compound.
One sample contains $3\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen, and another contains $3\ \text{g}$ of carbon and $4\ \text{g}$ of oxygen. Could they be the same…
One sample contains $3\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen, and another contains $3\ \text{g}$ of carbon and $4\ \text{g}$ of oxygen. Could they be the same compound? Justify your answer using Proust's law.
A laboratory analyses two samples of an iron oxide. Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B contains $21\ \text{g}$ of iron and…
A laboratory analyses two samples of an iron oxide. Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B contains $21\ \text{g}$ of iron and $9\ \text{g}$ of oxygen. Calculate the ratio for each and decide if they are the same compound.
In a first experiment, we form water by combining $2\ \text{g}$ of hydrogen with $16\ \text{g}$ of oxygen. In another experiment, we decompose $9\ \text{g}$ of water and…
In a first experiment, we form water by combining $2\ \text{g}$ of hydrogen with $16\ \text{g}$ of oxygen. In another experiment, we decompose $9\ \text{g}$ of water and obtain $1\ \text{g}$ of hydrogen and $8\ \text{g}$ of oxygen.
- a) Verify that both results comply with the law of definite proportions.
- b) Explain the difference between the two experiments (synthesis and analysis) and reason why the ratio is the same in both.
A class measures the composition of water and obtains $10.2\ \text{g}$ of hydrogen and $79.8\ \text{g}$ of oxygen. a) Calculate the oxygen/hydrogen ratio (to one decimal…
A class measures the composition of water and obtains $10.2\ \text{g}$ of hydrogen and $79.8\ \text{g}$ of oxygen.
- a) Calculate the oxygen/hydrogen ratio (to one decimal place) and compare it with the theoretical ratio $8:1$.
- b) Should we conclude that Proust's law fails? Reason your answer.
- c) Point out two possible causes for the slight discrepancy with the theoretical value.
A laboratory receives $250\ \text{g}$ of a white mineral that the supplier claims is pure calcium oxide (calcium:oxygen ratio $5:2$). Analysis reveals $175\ \text{g}$ of…
A laboratory receives $250\ \text{g}$ of a white mineral that the supplier claims is pure calcium oxide (calcium:oxygen ratio $5:2$). Analysis reveals $175\ \text{g}$ of calcium and $75\ \text{g}$ of oxygen.
- a) Check whether the mineral could be pure calcium oxide.
- b) What mass of oxygen should accompany $175\ \text{g}$ of calcium if it were?
- c) Propose an explanation for the result of the analysis.
Two elements, more than one compound
Sometimes two elements combine in more than one fixed ratio, and each ratio gives rise to a different compound with different properties.
Will $6\ \text{g}$ of carbon combine completely with $16\ \text{g}$ of oxygen to form carbon dioxide, with nothing left over? What mass of carbon dioxide will form?…
Will $6\ \text{g}$ of carbon combine completely with $16\ \text{g}$ of oxygen to form carbon dioxide, with nothing left over? What mass of carbon dioxide will form? (Remember: the ratio is $3\ \text{g}$ of carbon for every $8\ \text{g}$ of oxygen.)
Copper can form two different oxides. In one sample, $8\ \text{g}$ of copper combine with $2\ \text{g}$ of oxygen; in another sample, $8\ \text{g}$ of copper combine…
Copper can form two different oxides. In one sample, $8\ \text{g}$ of copper combine with $2\ \text{g}$ of oxygen; in another sample, $8\ \text{g}$ of copper combine with $1\ \text{g}$ of oxygen. The figure compares the composition of the two samples.
Is it the same oxide? How do you know?
We analyse three samples of "iron oxide". Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B, $14\ \text{g}$ of iron and $4\ \text{g}$ of…
We analyse three samples of "iron oxide". Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B, $14\ \text{g}$ of iron and $4\ \text{g}$ of oxygen; sample C, $21\ \text{g}$ of iron and $9\ \text{g}$ of oxygen.
- a) Calculate the iron:oxygen ratio for each sample.
- b) Which of them are the same compound?
- c) Explain why iron can give rise to more than one different oxide.
Carbon and oxygen can form two different gases. In sample A, there are $6\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen; in sample B, there are $6\ \text{g}$ of…
Carbon and oxygen can form two different gases. In sample A, there are $6\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen; in sample B, there are $6\ \text{g}$ of carbon and $16\ \text{g}$ of oxygen. The figure shows the model of each molecule.
- a) Calculate the carbon:oxygen ratio for each sample.
- b) Are they the same compound?
- c) Given that one of the gases is carbon monoxide (highly toxic) and the other is carbon dioxide, explain why Proust's law allows us to distinguish between them even though they are made of the same elements.
When a reactant is left over
If you mix two elements without respecting their exact ratio, not everything reacts: the one in excess is left over without combining.
In a sealed container, we place $10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen and cause them to react (the combination ratio is $1:8$). The figure shows the…
In a sealed container, we place $10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen and cause them to react (the combination ratio is $1:8$). The figure shows the container before the reaction.
- a) Does all the hydrogen react?
- b) What mass of water is formed?
- c) Is there any gas left over? What mass?
We burn $12\ \text{g}$ of carbon with $40\ \text{g}$ of oxygen (the combination ratio is $3:8$). a) How much oxygen is consumed? b) What mass of carbon dioxide is…
We burn $12\ \text{g}$ of carbon with $40\ \text{g}$ of oxygen (the combination ratio is $3:8$).
- a) How much oxygen is consumed?
- b) What mass of carbon dioxide is formed?
- c) What mass of oxygen remains unreacted?
We mix $16\ \text{g}$ of hydrogen with $100\ \text{g}$ of oxygen and trigger the reaction (ratio $1:8$). a) What mass of each gas reacts? b) What mass of water is…
We mix $16\ \text{g}$ of hydrogen with $100\ \text{g}$ of oxygen and trigger the reaction (ratio $1:8$).
- a) What mass of each gas reacts?
- b) What mass of water is formed?
- c) What mass of hydrogen is left over?
A student claims: "If I add twice as much oxygen, the water that forms will contain twice as much oxygen." To test this, we combine $4\ \text{g}$ of hydrogen with…
A student claims: "If I add twice as much oxygen, the water that forms will contain twice as much oxygen." To test this, we combine $4\ \text{g}$ of hydrogen with $64\ \text{g}$ of oxygen (twice as much as necessary).
- a) Calculate the mass of water formed and the mass of oxygen left over.
- b) Use Proust's law to explain why the student is mistaken.
Go back to the beginning: tap water in Santiago and spring water have the same ratio, $1\ \text{g}$ of H for every $8\ \text{g}$ of O, because it is the same substance.