Forces and Deformations: Hooke's Law
At the market in Santiago, the orange seller hangs a sack from a spring scale and the pointer moves down. If she hangs two identical sacks, the pointer moves down twice as far. What rule does that stretching follow, and why can we use it to measure forces?
A spring stretches in proportion to the force
If you hang weights of $1\ \text{N}$, $2\ \text{N}$, and $3\ \text{N}$ from the same spring, you find that it stretches $1.5\ \text{cm}$, $3.0\ \text{cm}$, and $4.5\ \text{cm}$: each newton you add always produces the same stretch. What formula relates the applied force to how much the spring stretches?
Complete the sentence: "Hooke's law states that the extension of a spring is $\dots$ proportional to the $\dots$ applied to it." Then write the formula $F = k \times x$…
Complete the sentence: "Hooke's law states that the extension of a spring is $\dots$ proportional to the $\dots$ applied to it." Then write the formula $F = k \times x$ and state the meaning and unit of each letter.
A spring has a spring constant $k = 10\ \text{N/cm}$, as shown in the figure. Calculate the force that must be applied to stretch it by $3\ \text{cm}$. Remember Hooke's…
A spring has a spring constant $k = 10\ \text{N/cm}$, as shown in the figure.
Calculate the force that must be applied to stretch it by $3\ \text{cm}$. Remember Hooke's law: $F = k \times x$.
A force of $20\ \text{N}$ is applied to a spring with constant $k = 5\ \text{N/cm}$. How many centimeters does it extend by?
A force of $20\ \text{N}$ is applied to a spring with constant $k = 5\ \text{N/cm}$. How many centimeters does it extend by?
When the units don't match
Often the problem gives $k$ in $\text{N/m}$ and the elongation in $\text{cm}$, or the other way around. First you convert, then you calculate. Remember: $1\ \text{m} = 100\ \text{cm}$.
And when you are given the length of the spring instead of the elongation, subtract: $x = l - l_0$. A spring that is $20\ \text{cm}$ at rest and measures $30\ \text{cm}$ with a weight stretched $10\ \text{cm} = 0.1\ \text{m}$.
A spring has a spring constant of $k = 200\ \text{N/m}$ and extends by $5\ \text{cm}$. a) Express the extension in meters. b) Calculate the applied force.
A spring has a spring constant of $k = 200\ \text{N/m}$ and extends by $5\ \text{cm}$.
- a) Express the extension in meters.
- b) Calculate the applied force.
The spring constant of a spring is $k = 2\ \text{N/cm}$. a) Express it in $\text{N/m}$. b) Calculate the force required to stretch the spring by $0.1\ \text{m}$.
The spring constant of a spring is $k = 2\ \text{N/cm}$.
- a) Express it in $\text{N/m}$.
- b) Calculate the force required to stretch the spring by $0.1\ \text{m}$.
A spring measures $10\ \text{cm}$ at rest and its constant is $k = 5\ \text{N/cm}$. When a weight is hung from it, the spring length becomes $14\ \text{cm}$, as shown in…
A spring measures $10\ \text{cm}$ at rest and its constant is $k = 5\ \text{N/cm}$. When a weight is hung from it, the spring length becomes $14\ \text{cm}$, as shown in the figure.
- a) How much has it extended?
- b) What is the value of the weight?
A spring with constant $k = 50\ \text{N/m}$ measures $20\ \text{cm}$ at rest. We hang a weight from it and the spring length becomes $30\ \text{cm}$. a) Express the…
A spring with constant $k = 50\ \text{N/m}$ measures $20\ \text{cm}$ at rest. We hang a weight from it and the spring length becomes $30\ \text{cm}$.
- a) Express the extension in meters.
- b) Calculate the weight of the weight hanging from it.
- c) If we hung twice as much weight, what length would the spring measure?
The spring constant: "stiff" and "soft" springs
If you hang the same $5\ \text{N}$ weight from the thin spring of a retractable pen and from the thick spring of an engine's suspension, the first one deforms by several centimeters and the second one barely moves. What quantity measures that resistance to deformation?
Spring A has a spring constant of $k = 2\ \text{N/cm}$ and spring B has $k = 8\ \text{N/cm}$. Without performing calculations: a) Which one is "stiffer", that is, which…
Spring A has a spring constant of $k = 2\ \text{N/cm}$ and spring B has $k = 8\ \text{N/cm}$. Without performing calculations:
- a) Which one is "stiffer", that is, which one is harder to stretch?
- b) Which one will extend more if we apply the same force to both?
A spring extends by $4\ \text{cm}$ when a force of $2\ \text{N}$ is applied to it. Without doing detailed calculations, and considering Hooke's law: how much will it…
A spring extends by $4\ \text{cm}$ when a force of $2\ \text{N}$ is applied to it. Without doing detailed calculations, and considering Hooke's law: how much will it extend with $4\ \text{N}$? And with $1\ \text{N}$? Justify your answers.
When a weight of $8\ \text{N}$ is hung from a spring, it extends by $2\ \text{cm}$, as shown in the figure. Calculate the spring constant of the spring, in $\text{N/cm}$.
When a weight of $8\ \text{N}$ is hung from a spring, it extends by $2\ \text{cm}$, as shown in the figure.
Calculate the spring constant of the spring, in $\text{N/cm}$.
When a force of $10\ \text{N}$ is applied to a spring, it extends by $5\ \text{cm}$. a) Calculate its spring constant. b) What force will be required to extend it by…
When a force of $10\ \text{N}$ is applied to a spring, it extends by $5\ \text{cm}$.
- a) Calculate its spring constant.
- b) What force will be required to extend it by $8\ \text{cm}$?
When a weight of $6\ \text{N}$ is hung from a spring, it extends by $3\ \text{cm}$. a) What is its spring constant? b) How much will it extend if we hang a weight of…
When a weight of $6\ \text{N}$ is hung from a spring, it extends by $3\ \text{cm}$.
- a) What is its spring constant?
- b) How much will it extend if we hang a weight of $10\ \text{N}$?
For spring A, we know that with $6\ \text{N}$ it extends by $2\ \text{cm}$; for spring B, with the same $6\ \text{N}$ it extends by $6\ \text{cm}$. a) Calculate the…
For spring A, we know that with $6\ \text{N}$ it extends by $2\ \text{cm}$; for spring B, with the same $6\ \text{N}$ it extends by $6\ \text{cm}$.
- a) Calculate the spring constant of each spring.
- b) Which of the two is stiffer?
We hang the same weight from spring A and it extends by $2\ \text{cm}$; from spring B and it extends by $6\ \text{cm}$. a) Which of the two springs has a larger spring…
We hang the same weight from spring A and it extends by $2\ \text{cm}$; from spring B and it extends by $6\ \text{cm}$.
- a) Which of the two springs has a larger spring constant?
- b) How many times larger?
- c) If we hang a weight from spring B that weighs half as much, how much will it extend?
The force–extension graph of a spring is a straight line passing through the origin and through the point corresponding to an extension of $4\ \text{cm}$ and a force of…
The force–extension graph of a spring is a straight line passing through the origin and through the point corresponding to an extension of $4\ \text{cm}$ and a force of $12\ \text{N}$, as shown in the figure.
- a) What force corresponds to an extension of $1\ \text{cm}$?
- b) What is the spring constant of the spring?
- c) What extension corresponds to a force of $15\ \text{N}$?
The dynamometer: a spring for measuring forces
When you hang a motionless object, the dynamometer measures its weight. The stretched spring pulls the bag upward with a force equal to its weight, and the bag pulls the spring downward: that is why it stretches.
What is a newton meter? What quantity does it measure and in which unit? What is the main part inside it?
What is a newton meter? What quantity does it measure and in which unit? What is the main part inside it?
We hang a bag of oranges from a newton meter and it reads $15\ \text{N}$, as shown in the figure. a) What force is the newton meter measuring? b) The bag is stationary:…
We hang a bag of oranges from a newton meter and it reads $15\ \text{N}$, as shown in the figure.
- a) What force is the newton meter measuring?
- b) The bag is stationary: what force does the newton meter exert on the bag?
You want to build a homemade newton meter using a spring with constant $k = 0.5\ \text{N/cm}$ capable of measuring forces up to $10\ \text{N}$. a) How much will the…
You want to build a homemade newton meter using a spring with constant $k = 0.5\ \text{N/cm}$ capable of measuring forces up to $10\ \text{N}$.
- a) How much will the spring extend under the maximum force?
- b) What minimum length must the ruler where you draw the scale have?
- c) What distance will there be between the $1\ \text{N}$ mark and the $2\ \text{N}$ mark?
You have two springs: spring A, with $k = 10\ \text{N/cm}$, and spring B, with $k = 0.5\ \text{N/cm}$. You want to measure small forces, of around $2\ \text{N}$, using a…
You have two springs: spring A, with $k = 10\ \text{N/cm}$, and spring B, with $k = 0.5\ \text{N/cm}$. You want to measure small forces, of around $2\ \text{N}$, using a school ruler.
- a) Calculate how much each spring extends with $2\ \text{N}$.
- b) Which one should you use to clearly read the measurement? Give reasons for your answer.
How far the law holds: the elastic limit
Hooke's law doesn't hold forever. If you stretch a spring too far, when you let go it no longer returns to its original length: it stays deformed permanently. The point where that happens is the elastic limit.
Before the limit, the spring is elastic (it recovers its shape) and the force-elongation graph is a straight line through the origin. After it, the graph curves: the spring stretches more than $F = k \cdot x$ predicts and the deformation is permanent.
In the laboratory we measure the extension of a spring with different forces: with $1\ \text{N}$ it extends by $2\ \text{cm}$; with $2\ \text{N}$, $4\ \text{cm}$; and…
In the laboratory we measure the extension of a spring with different forces: with $1\ \text{N}$ it extends by $2\ \text{cm}$; with $2\ \text{N}$, $4\ \text{cm}$; and with $3\ \text{N}$, $6\ \text{cm}$.
- a) Calculate the spring constant for each pair of data.
- b) Does this spring satisfy Hooke's law? Justify your answer.
We stretch a spring with increasingly larger forces and, beyond a certain point, when released it no longer returns to its original length: it remains deformed. a) What…
We stretch a spring with increasingly larger forces and, beyond a certain point, when released it no longer returns to its original length: it remains deformed.
- a) What is the name of the point beyond which this happens?
- b) Is Hooke's law satisfied before or after this point?
- c) Why must we not exceed it when using a newton meter?
When stretching a spring with different forces we obtain these extensions: with $2\ \text{N}$, $1\ \text{cm}$; with $4\ \text{N}$, $2\ \text{cm}$; with $6\ \text{N}$,…
When stretching a spring with different forces we obtain these extensions: with $2\ \text{N}$, $1\ \text{cm}$; with $4\ \text{N}$, $2\ \text{cm}$; with $6\ \text{N}$, $3\ \text{cm}$; and with $8\ \text{N}$, $4.5\ \text{cm}$. The data are represented in the graph:
- a) Calculate the spring constant of the spring in the region where Hooke's law is satisfied.
- b) Above what force is Hooke's law no longer satisfied?
- c) What is happening to the spring beyond that point?
A spring scale at a market stall uses a spring with $k = 20\ \text{N/cm}$ that must not extend by more than $5\ \text{cm}$ to avoid damage. a) What is the maximum force…
A spring scale at a market stall uses a spring with $k = 20\ \text{N/cm}$ that must not extend by more than $5\ \text{cm}$ to avoid damage.
- a) What is the maximum force the scale can measure?
- b) Can a bag of oranges weighing $120\ \text{N}$ be weighed on it? Justify your answer.
- c) What will happen to the spring if someone insists on weighing the bag?
A spring extends by $2\ \text{cm}$ when a force of $5\ \text{N}$ is applied to it. a) Calculate its spring constant. b) Predict the extension for $12\ \text{N}$ assuming…
A spring extends by $2\ \text{cm}$ when a force of $5\ \text{N}$ is applied to it.
- a) Calculate its spring constant.
- b) Predict the extension for $12\ \text{N}$ assuming Hooke's law is satisfied.
- c) When tested in the laboratory with $12\ \text{N}$, the spring extends by $6\ \text{cm}$ instead of the predicted amount. Give two possible explanations for the difference.
Back to the beginning: the pointer on the market scale moves down twice as far with twice the weight because its spring obeys Hooke's law, as long as it doesn't go past the elastic limit.