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Chemical reactions · Types of reactions

Stoichiometry in Industrial Processes

A cement plant, a steel mill, or a fertilizer plant doesn't work with grams, but with tons. They also never have "exact" reactants: the ore arrives mixed with rock, one reactant is left over and another runs short, and the equation promises $100\ \text{t}$ of product but the plant collects $92\ \text{t}$. Where do the missing $8\ \text{t}$ go, if atoms are not destroyed? To answer, you need to combine three ideas you already know (purity, limiting reactant, and mole ratio) with a new one: yield.

From moles to tons: stoichiometry at large scale

The method doesn't change when you go from the lab to the factory: mass → mol → mol → mass. The only thing that changes is the scale of the units. The coefficients of the balanced equation tell how many moles react, and that ratio holds equally for $1\ \text{mol}$ as for $1{,}000\ \text{mol}$.

Look at the Haber process for making ammonia, the basis of nitrogen fertilizers:

$$\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$$

It reads like this: $1\ \text{mol}$ of $\text{N}_2$ reacts with $3\ \text{mol}$ of $\text{H}_2$ and produces $2\ \text{mol}$ of $\text{NH}_3$.

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A fertiliser plant synthesises ammonia via the Haber process: $\text{N}2 + 3\ \text{H}2 \rightarrow 2\ \text{NH}3$. a) How many moles of ammonia are obtained, at most,…

A fertiliser plant synthesises ammonia via the Haber process: $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$.

  1. a) How many moles of ammonia are obtained, at most, from $5\ \text{mol}$ of nitrogen?
  2. b) How many moles of hydrogen are consumed in that case?
Solve
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In the Haber process, $\text{N}2 + 3\ \text{H}2 \rightarrow 2\ \text{NH}3$, the molar masses are $M(\text{N}2) = 28\ \text{g/mol}$, $M(\text{H}2) = 2\ \text{g/mol}$ and…

In the Haber process, $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$, the molar masses are $M(\text{N}_2) = 28\ \text{g/mol}$, $M(\text{H}_2) = 2\ \text{g/mol}$ and $M(\text{NH}_3) = 17\ \text{g/mol}$.

  1. a) Calculate the mass of ammonia obtained from $28\ \text{g}$ of nitrogen with sufficient hydrogen.
  2. b) Calculate the mass of hydrogen consumed and check that the law of conservation of mass is satisfied.
Solve
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In the blast furnace, the main ore reduction reaction is $\text{Fe}2\text{O}3 + 3\ \text{CO} \rightarrow 2\ \text{Fe} + 3\ \text{CO}2$. a) How many moles of iron are…

In the blast furnace, the main ore reduction reaction is $\text{Fe}_2\text{O}_3 + 3\ \text{CO} \rightarrow 2\ \text{Fe} + 3\ \text{CO}_2$.

  1. a) How many moles of iron are obtained from $2\ \text{mol}$ of iron(III) oxide?
  2. b) Given that $M(\text{Fe}) = 56\ \text{g/mol}$, calculate the mass of iron obtained from $1\ \text{mol}$ of iron(III) oxide.
Solve

Kilomoles and tons

In industry, the kilomole is used ($1\ \text{kmol} = 1{,}000\ \text{mol}$). Its advantage: if the molar mass is $28\ \text{g/mol}$, then it is $28\ \text{kg/kmol}$. The numbers are the same, but the mass is in kilograms and the amount in kilomoles. With tons it works the same way: $28\ \text{t}$ of $\text{N}_2$ are $1{,}000\ \text{kmol}$, or $1\ \text{t-mol}$ if you work with tons and "ton-moles" (units that are consistent with each other).

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A cement plant decomposes limestone in its kiln: $\text{CaCO}3 \rightarrow \text{CaO} + \text{CO}2$, with molar masses $M(\text{CaCO}3) = 100\ \text{g/mol}$,…

A cement plant decomposes limestone in its kiln: $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$, with molar masses $M(\text{CaCO}_3) = 100\ \text{g/mol}$, $M(\text{CaO}) = 56\ \text{g/mol}$ and $M(\text{CO}_2) = 44\ \text{g/mol}$. $100\ \text{g}$ of pure calcium carbonate is loaded.

  1. a) Calculate the mass of quicklime ($\text{CaO}$) obtained.
  2. b) Calculate the mass of carbon dioxide released.
  3. c) Check that the sum of the masses of the products equals the mass of the reactant.
Solve
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In industry, the kilomole ($1\ \text{kmol} = 1000\ \text{mol}$) is often used: the mass of one kilomole in kilograms is numerically equal to the molar mass in…

In industry, the kilomole ($1\ \text{kmol} = 1000\ \text{mol}$) is often used: the mass of one kilomole in kilograms is numerically equal to the molar mass in $\text{g/mol}$. For the Haber process, $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$, we have $M(\text{N}_2) = 28\ \text{kg/kmol}$, $M(\text{H}_2) = 2\ \text{kg/kmol}$ and $M(\text{NH}_3) = 17\ \text{kg/kmol}$. A plant consumes $140\ \text{t}$ of nitrogen per day.

  1. a) Express that mass of nitrogen in kmol.
  2. b) Calculate the metric tons of ammonia that the plant produces per day.
  3. c) Calculate the metric tons of hydrogen it needs daily.
Solve

Multistep processes

Many industrial products, such as sulfuric acid, are not made in a single step. The output of one stage is the input of the next. The trick is to follow one atom (sulfur, for example) through all the equations and see how many moles of final product come out for each mole of the starting reactant.

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In the manufacture of sulphuric acid, the key stage is the oxidation of sulphur dioxide: $2\ \text{SO}2 + \text{O}2 \rightarrow 2\ \text{SO}3$. a) How many moles of…

In the manufacture of sulphuric acid, the key stage is the oxidation of sulphur dioxide: $2\ \text{SO}_2 + \text{O}_2 \rightarrow 2\ \text{SO}_3$.

  1. a) How many moles of sulphur trioxide are obtained from $4\ \text{mol}$ of sulphur dioxide?
  2. b) How many moles of oxygen are consumed in that transformation?
Solve
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The manufacture of sulphuric acid from sulphur occurs in three stages: $\text{S} + \text{O}2 \rightarrow \text{SO}2$;…

The manufacture of sulphuric acid from sulphur occurs in three stages: $\text{S} + \text{O}_2 \rightarrow \text{SO}_2$; $2\ \text{SO}_2 + \text{O}_2 \rightarrow 2\ \text{SO}_3$; $\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4$. The sequence of transformations is shown schematically in the figure:

S SO₂ SO₃ H₂SO₄ + O₂ + O₂ + H₂O
  1. a) By following the sulphur atoms through the three equations, deduce how many moles of sulphuric acid are obtained per mole of initial sulphur.
  2. b) With $M(\text{S}) = 32\ \text{kg/kmol}$ and $M(\text{H}_2\text{SO}_4) = 98\ \text{kg/kmol}$, calculate the metric tons of acid produced by a plant from $32\ \text{t}$ of sulphur.
Solve
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Many sulphuric acid plants start from pyrite, an ore of $\text{FeS}2$. The first stage is roasting:…

Many sulphuric acid plants start from pyrite, an ore of $\text{FeS}_2$. The first stage is roasting: $4\ \text{FeS}_2 + 11\ \text{O}_2 \rightarrow 2\ \text{Fe}_2\text{O}_3 + 8\ \text{SO}_2$; then, $\text{SO}_2$ is oxidised to $\text{SO}_3$ and this is hydrated to $\text{H}_2\text{SO}_4$ ($M(\text{FeS}_2) = 120\ \text{kg/kmol}$; $M(\text{H}_2\text{SO}_4) = 98\ \text{kg/kmol}$; $M(\text{Fe}) = 56\ \text{kg/kmol}$). $1000\ \text{kg}$ of ore with $60\ \%$ pyrite content is processed.

  1. a) Calculate the kmol of $\text{FeS}_2$ processed.
  2. b) Using the sulphur atoms, verify that each mole of $\text{FeS}_2$ leads to $2\ \text{mol}$ of $\text{H}_2\text{SO}_4$, and calculate the mass of acid obtained.
  3. c) The iron(III) oxide generated during roasting can be sent to a blast furnace: calculate the mass of recoverable iron and comment on the economic and environmental advantage of integrating two processes in this way.
Solve

The limiting reactant

If you mix $24\ \text{g}$ of magnesium with $32\ \text{g}$ of oxygen to form magnesium oxide, $2\ \text{Mg} + \text{O}_2 \rightarrow 2\ \text{MgO}$, the reaction stops, leaving $16\ \text{g}$ of oxygen unused. Why does it stop if there is still a reactant left in the container?

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On a trip you prepare sandwiches: each one has exactly $2$ slices of bread and $1$ slice of ham. You have $10$ slices of bread and $4$ slices of ham. The available…

On a trip you prepare sandwiches: each one has exactly $2$ slices of bread and $1$ slice of ham. You have $10$ slices of bread and $4$ slices of ham. The available ingredients are shown in the figure.

10 slices of bread 4 slices of ham 1 sandwich: 2 bread + 1 ham ?
  1. a) How many complete sandwiches can you prepare?
  2. b) Which ingredient is left over and in what quantity?
  3. c) In chemistry, the reactant that is used up first and limits the amount of product is called the limiting reactant: state which ingredient plays that role here.
Solve
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Industry obtains hydrochloric acid by direct synthesis from the elements: $\text{H}2 + \text{Cl}2 \rightarrow 2\ \text{HCl}$. A reactor is loaded with $3\ \text{mol}$ of…

Industry obtains hydrochloric acid by direct synthesis from the elements: $\text{H}_2 + \text{Cl}_2 \rightarrow 2\ \text{HCl}$. A reactor is loaded with $3\ \text{mol}$ of hydrogen and $2\ \text{mol}$ of chlorine. The reactor feed is represented using the particle model:

reactor 3 mol H₂ 2 mol Cl₂ ?
  1. a) Determine which reactant is the limiting reactant, justifying your answer using stoichiometry.
  2. b) Calculate the moles of $\text{HCl}$ formed.
  3. c) Calculate the moles of excess reactant remaining unreacted and the mass of $\text{HCl}$ obtained ($M(\text{HCl}) = 36.5\ \text{g/mol}$).
Solve
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Titanium for the aerospace industry is obtained via the Kroll process: $\text{TiCl}4 + 2\ \text{Mg} \rightarrow \text{Ti} + 2\ \text{MgCl}2$, with molar masses…

Titanium for the aerospace industry is obtained via the Kroll process: $\text{TiCl}_4 + 2\ \text{Mg} \rightarrow \text{Ti} + 2\ \text{MgCl}_2$, with molar masses $M(\text{TiCl}_4) = 190\ \text{g/mol}$, $M(\text{Mg}) = 24\ \text{g/mol}$ and $M(\text{Ti}) = 48\ \text{g/mol}$. A reactor is loaded with $190\ \text{g}$ of titanium tetrachloride and $36\ \text{g}$ of magnesium.

  1. a) Determine the limiting reactant.
  2. b) Calculate the mass of titanium obtained.
  3. c) Calculate the moles of excess reactant remaining unreacted.
Solve

Impure raw materials: purity

Ores are not pure compounds. An iron ore contains iron(III) oxide mixed with gangue, rock that does not react. Only the pure part goes into the stoichiometric calculations.

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A steelworks receives an iron ore with $80\ \%$ by mass of iron(III) oxide; the rest is inert gangue that does not react. In the blast furnace:…

A steelworks receives an iron ore with $80\ \%$ by mass of iron(III) oxide; the rest is inert gangue that does not react. In the blast furnace: $\text{Fe}_2\text{O}_3 + 3\ \text{CO} \rightarrow 2\ \text{Fe} + 3\ \text{CO}_2$, with $M(\text{Fe}_2\text{O}_3) = 160\ \text{kg/kmol}$ and $M(\text{Fe}) = 56\ \text{kg/kmol}$. $1000\ \text{kg}$ of ore is loaded.

  1. a) Calculate the mass of iron(III) oxide that actually enters the furnace.
  2. b) Calculate the maximum mass of iron that could be obtained.
  3. c) State what mass of gangue must be removed as waste.
Solve

The yield of a real process

When you heat $100\ \text{g}$ of pure calcium carbonate, $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$, stoichiometry predicts $56\ \text{g}$ of quicklime ($M(\text{CaCO}_3)=100\ \text{g/mol}$, $M(\text{CaO})=56\ \text{g/mol}$). In the furnace only $50.4\ \text{g}$ are collected. Where do the missing grams go?

Comparison between an expected theoretical mass of 100 tons and an actual mass obtained of 92 tons, which defines a yield of 92 %. 100 t theoretical 92 t actual yield = 92/100 · 100 = 92 %

Go back to the start: the $5.6\ \text{g}$ difference is not destroyed. Part of the product is lost or does not form (in this case, yield $\dfrac{50.4}{56}\times 100 = 90\ \%$), but the atoms are still somewhere in the system.

Another real fact about plants: in the ammonia reactor only part of the gas is converted on each pass. What comes out unreacted is separated from the ammonia and recycled to the reactor. That way, the overall utilization is much greater than that of a single pass.

Practice★☆☆Not started
A cement plant calculates that, according to stoichiometry, its kiln should produce $100\ \text{t}$ of lime per day, but the actual production is $92\ \text{t}$. a)…

A cement plant calculates that, according to stoichiometry, its kiln should produce $100\ \text{t}$ of lime per day, but the actual production is $92\ \text{t}$.

  1. a) Calculate the yield of the kiln, as a percentage.
  2. b) State two reasons why a real industrial process might not reach the theoretical yield of $100\ \%$.
Solve
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A lime kiln decomposes $200\ \text{g}$ of pure calcium carbonate: $\text{CaCO}3 \rightarrow \text{CaO} + \text{CO}2$, with $M(\text{CaCO}3) = 100\ \text{g/mol}$ and…

A lime kiln decomposes $200\ \text{g}$ of pure calcium carbonate: $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$, with $M(\text{CaCO}_3) = 100\ \text{g/mol}$ and $M(\text{CaO}) = 56\ \text{g/mol}$.

  1. a) Calculate the theoretical mass of quicklime that should be obtained.
  2. b) If the actual yield of the kiln is $90\ \%$, calculate the mass of lime obtained in practice.
  3. c) Suggest a reason why the kiln does not reach the theoretical yield.
Solve
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In the Haber process, $\text{N}2 + 3\ \text{H}2 \rightarrow 2\ \text{NH}3$, only part of the gas is converted on each pass through the reactor. $10\ \text{mol}$ of…

In the Haber process, $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$, only part of the gas is converted on each pass through the reactor. $10\ \text{mol}$ of nitrogen is introduced with excess hydrogen, and the conversion per pass is $40\ \%$ ($M(\text{NH}_3) = 17\ \text{g/mol}$).

  1. a) Calculate the theoretical mass of ammonia if all the nitrogen reacted.
  2. b) Calculate the mass of ammonia actually obtained on one pass.
  3. c) Explain what is done industrially with the gas that leaves the reactor unreacted and why this decision improves the overall utilization of nitrogen.
Solve

Combining purity, limiting reactant, and yield

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An ammonia plant, $\text{N}2 + 3\ \text{H}2 \rightarrow 2\ \text{NH}3$, daily has $28\ \text{t}$ of nitrogen and $8\ \text{t}$ of hydrogen available, and operates with a…

An ammonia plant, $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$, daily has $28\ \text{t}$ of nitrogen and $8\ \text{t}$ of hydrogen available, and operates with a yield of $95\ \%$ ($M(\text{N}_2) = 28\ \text{kg/kmol}$; $M(\text{H}_2) = 2\ \text{kg/kmol}$; $M(\text{NH}_3) = 17\ \text{kg/kmol}$).

  1. a) Express both masses in kmol.
  2. b) Determine the limiting reactant.
  3. c) Calculate the theoretical daily production of ammonia, in metric tons.
  4. d) Calculate the actual production with the specified yield.
  5. e) Calculate the metric tons of hydrogen left over each day and explain what should be done with them in the plant.
Solve
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A blast furnace processes $1000\ \text{kg}$ of ore with $80\ \%$ of $\text{Fe}2\text{O}3$ according to…

A blast furnace processes $1000\ \text{kg}$ of ore with $80\ \%$ of $\text{Fe}_2\text{O}_3$ according to $\text{Fe}_2\text{O}_3 + 3\ \text{CO} \rightarrow 2\ \text{Fe} + 3\ \text{CO}_2$, with a yield of $90\ \%$ ($M(\text{Fe}_2\text{O}_3) = 160\ \text{kg/kmol}$; $M(\text{Fe}) = 56\ \text{kg/kmol}$; $M(\text{CO}_2) = 44\ \text{kg/kmol}$).

  1. a) Calculate the mass of iron(III) oxide contained in the feed.
  2. b) Calculate the theoretical mass of iron.
  3. c) Calculate the actual mass of iron with the furnace's yield.
  4. d) Calculate the mass of carbon dioxide generated by the reduction reaction.
  5. e) The process also uses coke (carbon) as a fuel and as a source of $\text{CO}$: explain why total emissions per metric ton of steel are higher than calculated in d) and cite a technological pathway to reduce them.
Solve
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A cement plant loads $1000\ \text{kg}$ of limestone with $90\ \%$ of $\text{CaCO}3$ (the rest being inert impurities) into its kiln. The reaction is…

A cement plant loads $1000\ \text{kg}$ of limestone with $90\ \%$ of $\text{CaCO}_3$ (the rest being inert impurities) into its kiln. The reaction is $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$, with $M(\text{CaCO}_3) = 100\ \text{kg/kmol}$, $M(\text{CaO}) = 56\ \text{kg/kmol}$ and $M(\text{CO}_2) = 44\ \text{kg/kmol}$, and the yield of the kiln is $95\ \%$.

  1. a) Calculate the mass of calcium carbonate contained in the feed.
  2. b) Calculate the theoretical mass and actual mass of quicklime obtained.
  3. c) Calculate the mass of carbon dioxide generated by the reaction.
  4. d) Propose two technological measures to reduce the carbon footprint of cement manufacturing and briefly justify each one.
Solve

Working with a reactant in excess on purpose

Sometimes the excess is not an oversight: it is a decision. If one reactant is cheap and the other is expensive or hard to recover, more of the cheap one is loaded to make sure the expensive one is completely consumed. An excess is also used to push the reaction toward the products.

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A plant wants to produce $480\ \text{kg}$ of titanium via the Kroll process: $\text{TiCl}4 + 2\ \text{Mg} \rightarrow \text{Ti} + 2\ \text{MgCl}2$ (…

A plant wants to produce $480\ \text{kg}$ of titanium via the Kroll process: $\text{TiCl}_4 + 2\ \text{Mg} \rightarrow \text{Ti} + 2\ \text{MgCl}_2$ ($M(\text{TiCl}_4) = 190\ \text{kg/kmol}$; $M(\text{Mg}) = 24\ \text{kg/kmol}$; $M(\text{Ti}) = 48\ \text{kg/kmol}$).

  1. a) Calculate the mass of titanium tetrachloride required.
  2. b) Calculate the theoretical mass of magnesium and the mass that must be loaded if working with an excess of $25\ \%$.
  3. c) Explain why it is advantageous to work with excess magnesium even if it increases the cost of the process, and why the plant subsequently electrolyses the $\text{MgCl}_2$ obtained to recover the magnesium.
Solve

Atom economy

Even with a $100\ \%$ yield, a route can still generate a lot of waste, because the equation itself produces byproducts. Atom economy measures that.

A bar represents the mass of calcium carbonate, 100 units: 56 form the desired quicklime and 44 the carbon dioxide, so the atom economy is 56 %. CaCO₃ → CaO + CO₂ CaO (56) CO₂ (44) atom economy = 56/100 · 100 = 56 % desired product: CaO
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Copper can be obtained via two routes: A) $\text{CuO} + \text{H}2 \rightarrow \text{Cu} + \text{H}2\text{O}$; B)…

Copper can be obtained via two routes: A) $\text{CuO} + \text{H}_2 \rightarrow \text{Cu} + \text{H}_2\text{O}$; B) $\text{Fe} + \text{CuSO}_4 \rightarrow \text{Cu} + \text{FeSO}_4$ ($M(\text{CuO}) = 80\ \text{g/mol}$; $M(\text{H}_2) = 2\ \text{g/mol}$; $M(\text{CuSO}_4) = 160\ \text{g/mol}$; $M(\text{Fe}) = 56\ \text{g/mol}$; $M(\text{Cu}) = 64\ \text{g/mol}$). The atom economy of a route is the percentage represented by the mass of the desired product over the total mass of the reactants.

  1. a) Calculate the atom economy of each route.
  2. b) Decide which is "greener" according to that criterion and justify your answer.
  3. c) State two additional factors (economic, energetic or environmental) that a company would consider before choosing a route and comment on why the less atom-efficient route might end up being used.
Solve

Environmental impact of the chemical industry

Stoichiometry is also useful for estimating emissions. If you know how many moles of $\text{CO}_2$ a reaction produces, you know how many tons reach the atmosphere. This matters in Mexico: cement plants, steel mills, and fertilizer plants are major emitters of $\text{CO}_2$.

$\text{CO}_2$ is a greenhouse gas: it traps heat in the atmosphere and contributes to global warming and climate change.

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Major chemical processes have an environmental impact: blast furnaces and cement manufacturing emit $\text{CO}2$, and the hydrogen consumed in the Haber process is…

Major chemical processes have an environmental impact: blast furnaces and cement manufacturing emit $\text{CO}_2$, and the hydrogen consumed in the Haber process is usually obtained today from natural gas.

  1. a) Explain what global environmental problem is associated with carbon dioxide emissions.
  2. b) Explain why manufacturing hydrogen by water electrolysis powered by renewable energy ("green hydrogen") would reduce the environmental footprint of ammonia.
Solve
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The calcination of limestone in cement manufacturing is $\text{CaCO}3 \rightarrow \text{CaO} + \text{CO}2$, with $M(\text{CaCO}3) = 100\ \text{kg/kmol}$ and…

The calcination of limestone in cement manufacturing is $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$, with $M(\text{CaCO}_3) = 100\ \text{kg/kmol}$ and $M(\text{CO}_2) = 44\ \text{kg/kmol}$. A cement plant calcines $1000\ \text{kg}$ of pure limestone per day.

  1. a) Calculate the mass of carbon dioxide generated each day by the chemical reaction itself.
  2. b) Calculate the metric tons emitted per year if the plant operates for $300$ days.
  3. c) The kiln is heated by burning fuel: explain why the plant's actual carbon footprint exceeds the calculated value and why cement is listed among the highest-emitting materials.
Solve
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The hydrogen consumed by the Haber process is mostly obtained from methane; the overall process can be written as…

The hydrogen consumed by the Haber process is mostly obtained from methane; the overall process can be written as $\text{CH}_4 + 2\ \text{H}_2\text{O} \rightarrow \text{CO}_2 + 4\ \text{H}_2$ ($M(\text{CO}_2) = 44\ \text{g/mol}$; $M(\text{NH}_3) = 17\ \text{g/mol}$). In the synthesis, $\text{N}_2 + 3\ \text{H}_2 \rightarrow 2\ \text{NH}_3$.

  1. a) Calculate the moles of hydrogen required for each mole of ammonia.
  2. b) Calculate the moles of carbon dioxide emitted in obtaining that hydrogen per mole of ammonia.
  3. c) Calculate the kilograms of $\text{CO}_2$ emitted per kilogram of ammonia manufactured using this "gray hydrogen".
  4. d) With green hydrogen (water electrolysis using renewable electricity), state what that direct emission would be and comment on what other indirect emissions might still exist in ammonia manufacturing.
Solve

What's still left to learn: rate and equilibrium

Stoichiometry answers how much product you can expect at most. It doesn't say how fast it forms or how far the reaction goes. In the factory, those two questions decide the cost.

  • Rate (kinetics): a reaction can be extremely fast or very slow depending on temperature, concentration, contact surface, or a catalyst. It is studied under reaction rate and collision theory.

  • How far it goes (equilibrium): many reactions are reversible and stop while reactants are still present. This explains why the per-pass yield of ammonia is partial. It is studied with the constant $K_c$ and Le Chatelier's principle.

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In a Haber plant operating at high pressure and about $450\ \celsius$, only $15\ \%$ of the nitrogen reacts on each pass through the reactor. $100\ \text{kmol}$ of…

In a Haber plant operating at high pressure and about $450\ \celsius$, only $15\ \%$ of the nitrogen reacts on each pass through the reactor. $100\ \text{kmol}$ of $\text{N}_2$ enters with sufficient hydrogen ($M(\text{NH}_3) = 17\ \text{kg/kmol}$).

  1. a) Calculate the kmol of ammonia obtained in one pass and its mass.
  2. b) The unreacted gas is recirculated to the reactor: explain why, as a result, the overall nitrogen utilisation approaches $100\ \%$ even though the conversion per pass is low.
  3. c) Relate recirculation to the economic and environmental efficiency of the process (raw material and energy per metric ton of product).
  4. d) The process is exothermic but requires compressing the gases and maintaining the temperature: comment on what these conditions mean for the plant's energy consumption and why industry seeks more effective catalysts.
Solve

Summary

See all the exercises in this section