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Chemical reactions · Gases and solutions

Solutions and Their Properties

Before you start, make sure you know: Solutions (High School Year 1 (semesters 1 and 2))

You make hibiscus tea (agua de jamaica) at home: how do you know whether yours came out more concentrated than your friend's? In the lab, saying "really strong" is not enough: you have to measure. And what matters almost always is not how many grams there are, but how many particles (molecules or ions), because they are the ones that react, the ones that cross a membrane, or the ones that lower the freezing temperature of the water in a car's radiator. That is why concentration is mostly expressed in moles per liter: molarity.

Ways to Express Concentration

A solution has a solute and a solvent. Concentration tells how much solute there is in a given amount of solution. You already know one way: mass percent.

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To rehydrate an athlete, a drink is prepared by dissolving $20\ \text{g}$ of glucose in $180\ \text{g}$ of water. a) What is the total mass of the solution? b) Calculate…

To rehydrate an athlete, a drink is prepared by dissolving $20\ \text{g}$ of glucose in $180\ \text{g}$ of water.

  1. a) What is the total mass of the solution?
  2. b) Calculate its percentage by mass of glucose.
Solve
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Physiological saline used in hospitals is a $0.9\ \%$ by mass sodium chloride solution. a) How many grams of salt are contained in a $500\ \text{g}$ bag of saline? b)…

Physiological saline used in hospitals is a $0.9\ \%$ by mass sodium chloride solution.

  1. a) How many grams of salt are contained in a $500\ \text{g}$ bag of saline?
  2. b) How many grams of water?
Solve
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A pharmacy dilutes $50\ \text{g}$ of a concentrated salt solution at $20\ \%$ by mass with $150\ \text{g}$ of water to prepare mouthwashes. a) How many grams of salt are…

A pharmacy dilutes $50\ \text{g}$ of a concentrated salt solution at $20\ \%$ by mass with $150\ \text{g}$ of water to prepare mouthwashes.

  1. a) How many grams of salt are provided by the concentrated solution?
  2. b) What is the total mass of the mixture?
  3. c) Calculate the new percentage by mass.
Solve

Molarity: Concentration in Moles per Liter

If you dissolve $58.5\ \text{g}$ of table salt (NaCl) in one glass and $180\ \text{g}$ of glucose ($\text{C}_6\text{H}_{12}\text{O}_6$) in another, the masses are very different, but each glass has $1\ \text{mol}$ of substance: 1 mol of NaCl units (which separate when dissolved into 1 mol of $\text{Na}^+$ and 1 mol of $\text{Cl}^-$, that is, 2 mol of ions) and 1 mol of glucose molecules. How can you compare the amount of substance per liter and not just the mass?

Volumetric flask with one liter of solution filled to the mark and four solute dots, each representing 1 mol, illustrating molarity as moles per liter. Molarity: moles of solute per liter 4 solute dots in 1 L (each dot represents 1 mol) 1 L fill mark 1 dot = 1 mol M = 4 mol / 1 L = 4 mol/L
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In the laboratory, $0.5\ \text{mol}$ of sodium chloride is dissolved in water to make $2\ \text{L}$ of solution. a) Write down the formula for molarity. b) Calculate the…

In the laboratory, $0.5\ \text{mol}$ of sodium chloride is dissolved in water to make $2\ \text{L}$ of solution.

  1. a) Write down the formula for molarity.
  2. b) Calculate the molarity of the solution.
Solve
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A solution of sodium hydroxide, $\text{NaOH}$, is $0.4\ \text{M}$. Data: molar mass of $\text{NaOH}$, $40\ \text{g/mol}$. a) How many moles of $\text{NaOH}$ are in…

A solution of sodium hydroxide, $\text{NaOH}$, is $0.4\ \text{M}$. Data: molar mass of $\text{NaOH}$, $40\ \text{g/mol}$.

  1. a) How many moles of $\text{NaOH}$ are in $250\ \text{mL}$ of that solution?
  2. b) How many grams of $\text{NaOH}$ is this?
Solve
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State whether each statement is true or false and justify your answer: a) If half of a solution is transferred to another beaker, the molarity in each beaker is half of…

State whether each statement is true or false and justify your answer:

  1. a) If half of a solution is transferred to another beaker, the molarity in each beaker is half of what it was at the beginning.
  2. b) If the volume of a solution is halved by evaporating water, its molarity doubles.
  3. c) Two solutions of different solutes can have the same molarity and, at the same time, different masses of solute per liter.
Solve
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$20\ \text{g}$ of sodium hydroxide, $\text{NaOH}$, are dissolved in water to make up $500\ \text{mL}$ of solution. Given: molar mass of $\text{NaOH}$,…

$20\ \text{g}$ of sodium hydroxide, $\text{NaOH}$, are dissolved in water to make up $500\ \text{mL}$ of solution. Given: molar mass of $\text{NaOH}$, $40\ \text{g/mol}$.

  1. a) How many moles are the $20\ \text{g}$ of $\text{NaOH}$?
  2. b) Express the volume in liters and calculate the molarity of the solution.
Solve

Preparing Solutions and Converting Between Units

With molarity you can go back and forth between moles, mass, and volume. The two relationships you need are $n = M \times V$ and $n = m / M_{\text{molar}}$.

When the concentration is given as mass percent and you are given the density, use $1\ \text{L} = 1000\ \text{mL}$ of solution as a basis.

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To prepare $100\ \text{mL}$ of a $0.5\ \text{M}$ sodium carbonate solution, $5.3\ \text{g}$ of solute must be weighed out. Put the following laboratory procedure steps…

To prepare $100\ \text{mL}$ of a $0.5\ \text{M}$ sodium carbonate solution, $5.3\ \text{g}$ of solute must be weighed out. Put the following laboratory procedure steps in order (they are currently mixed up) and explain what is done in each step:

  1. a) Make up to the mark on the neck of the flask with distilled water.
  2. b) Weigh the solute using the balance.
  3. c) Dissolve the solute in a beaker with a small amount of water.
  4. d) Transfer to the $100\ \text{mL}$ volumetric flask and add water almost up to the mark.

In addition, explain what "making up to the mark" means and why the volumetric flask is the appropriate piece of equipment. The figure shows the volumetric flask and, magnified, the detail of making up to the mark on the neck.

100 mL graduation mark mark meniscus
Solve
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You are asked to prepare $200\ \text{mL}$ of a $1\ \text{M}$ solution of potassium chloride, $\text{KCl}$. Given: molar mass of $\text{KCl}$, $74.5\ \text{g/mol}$. a)…

You are asked to prepare $200\ \text{mL}$ of a $1\ \text{M}$ solution of potassium chloride, $\text{KCl}$. Given: molar mass of $\text{KCl}$, $74.5\ \text{g/mol}$.

  1. a) How many moles of $\text{KCl}$ do you need?
  2. b) What mass should you weigh?
  3. c) Describe the complete laboratory procedure, naming the apparatus (balance, beaker, volumetric flask…) and the moment when it is made up to the mark.
Solve
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A patient needs to receive $0.05\ \text{mol}$ of glucose intravenously and a $0.5\ \text{M}$ glucose solution is available. Given: molar mass of glucose,…

A patient needs to receive $0.05\ \text{mol}$ of glucose intravenously and a $0.5\ \text{M}$ glucose solution is available. Given: molar mass of glucose, $180\ \text{g/mol}$.

  1. a) What volume of solution, in liters, contains that amount of glucose? Express it in milliliters as well.
  2. b) How many grams of glucose does the patient receive?
Solve
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A glucose solution has a density of $1.08\ \text{g/mL}$ and a concentration of $5\ \%$ by mass. Given: molar mass of glucose, $180\ \text{g/mol}$. a) Calculate the mass…

A glucose solution has a density of $1.08\ \text{g/mL}$ and a concentration of $5\ \%$ by mass. Given: molar mass of glucose, $180\ \text{g/mol}$.

  1. a) Calculate the mass of $1\ \text{L}$ of solution.
  2. b) How many grams of glucose does that liter contain?
  3. c) Calculate the molarity of the solution.
Solve

Parts per Million: Very Small Concentrations

One kilogram of water, equal to one million milligrams, shown as a bar; a very thin strip at the end represents 1 mg of solute, that is, 1 ppm. 1 kg of water (= 1,000,000 mg) 1 mg of solute = 1 ppm 1 ppm = 1 mg per kg of solution
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The legal limit of nitrates in drinking water is $50\ \text{ppm}$, i.e. $50\ \text{mg}$ of nitrate per kilogram of water. a) How many milligrams of nitrate, at most, can…

The legal limit of nitrates in drinking water is $50\ \text{ppm}$, i.e. $50\ \text{mg}$ of nitrate per kilogram of water.

  1. a) How many milligrams of nitrate, at most, can a container with $5\ \text{kg}$ of water contain?
  2. b) In the laboratory, $50\ \text{ppm}$ is often taken as $50\ \text{mg/L}$: explain what is being assumed about the density of water for both ways of expressing it to coincide.
Solve
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Analysis of a spring finds $30\ \text{mg}$ of dissolved fluoride per $2\ \text{kg}$ of water. The recommended limit for drinking water is $1.5\ \text{ppm}$. a) Express…

Analysis of a spring finds $30\ \text{mg}$ of dissolved fluoride per $2\ \text{kg}$ of water. The recommended limit for drinking water is $1.5\ \text{ppm}$.

  1. a) Express the fluoride concentration of the spring in ppm.
  2. b) Does it exceed the limit? How many times does it exceed it?
Solve

Diluting and Mixing Solutions

Commercial hydrochloric acid is very concentrated (≈ 12 M), but in lab work $0.1\ \text{M}$ or $0.5\ \text{M}$ is used. How much concentrated acid do you have to measure out, and to what volume do you fill it?

Dilution of 10 mL of 2 M HCl: in a volumetric flask, 90 mL of water is added up to the 100 mL mark, giving 0.2 M HCl with the same 0.02 mol of solute. State 1 Concentrated HCl State 2 Diluted HCl M₁ = 2 M V₁ = 10 mL + 90 mL of water bring to 100 mL volume mark M₂ = 0.2 M V₂ = 100 mL total volume solute particles (the same in both containers) n = M₁·V₁ = 2 M · 0.010 L = 0.02 mol = M₂·V₂
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$10\ \text{mL}$ of a hydrochloric acid solution, $\text{HCl}$, $2\ \text{M}$ are taken and water is added to make up $100\ \text{mL}$ of solution. Observe the diagram of…

$10\ \text{mL}$ of a hydrochloric acid solution, $\text{HCl}$, $2\ \text{M}$ are taken and water is added to make up $100\ \text{mL}$ of solution. Observe the diagram of the dilution.

10 mL HCl 2 M + water 100 mL M₂ = ?
  1. a) How many moles of $\text{HCl}$ did the initial $10\ \text{mL}$ contain?
  2. b) Calculate the molarity of the diluted solution.
  3. c) Verify that the relationship $M_1\times V_1=M_2\times V_2$ is satisfied and explain which quantity is conserved in a dilution.
Solve
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A laboratory has nitric acid, $\text{HNO}3$, $4\ \text{M}$ and needs to prepare $500\ \text{mL}$ of $0.8\ \text{M}$ solution. a) Apply the relationship…

A laboratory has nitric acid, $\text{HNO}_3$, $4\ \text{M}$ and needs to prepare $500\ \text{mL}$ of $0.8\ \text{M}$ solution.

  1. a) Apply the relationship $M_1\times V_1=M_2\times V_2$ to calculate the volume of concentrated acid that needs to be measured.
  2. b) Describe how to safely prepare the dilution: what apparatus is used and why the acid is added to the water and not the other way round.
Solve
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Commercial hydrochloric acid used in the laboratory has a concentration of $37\ \%$ by mass and a density of $1.19\ \text{g/mL}$. Given: molar mass of $\text{HCl}$,…

Commercial hydrochloric acid used in the laboratory has a concentration of $37\ \%$ by mass and a density of $1.19\ \text{g/mL}$. Given: molar mass of $\text{HCl}$, $36.5\ \text{g/mol}$.

  1. a) Calculate the mass of $1\ \text{L}$ of commercial acid.
  2. b) How many grams of pure $\text{HCl}$ does that liter contain?
  3. c) Calculate the molarity of the commercial acid, to one decimal place.
  4. d) Calculate, to one decimal place, what volume of this acid must be measured to prepare $500\ \text{mL}$ of $1\ \text{M}$ solution, and describe the dilution procedure safely.
Solve
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In an analytical laboratory, $100\ \text{mL}$ of $0.5\ \text{M}$ $\text{NaCl}$ solution are mixed with $300\ \text{mL}$ of $1.5\ \text{M}$ $\text{NaCl}$ solution. Assume…

In an analytical laboratory, $100\ \text{mL}$ of $0.5\ \text{M}$ $\text{NaCl}$ solution are mixed with $300\ \text{mL}$ of $1.5\ \text{M}$ $\text{NaCl}$ solution. Assume that the volumes are additive. The diagram shows the mixture.

100 mL NaCl 0.5 M + 300 mL NaCl 1.5 M 400 mL M = ?
  1. a) Calculate the moles of salt provided by each solution.
  2. b) Calculate the molarity of the resulting mixture.
  3. c) Explain why the result is not $1\ \text{M}$, the mean of the two initial concentrations.
Solve

Conservation of Solute When Evaporating

When you evaporate water from a broth, the salt does not leave: what is conserved is the mass of solute, and that is why the percentage goes up.

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A pot contains $2\ \text{kg}$ of broth with $1\ \%$ by mass of salt. a) How many grams of salt are in the broth? b) Upon boiling, water evaporates until the broth weighs…

A pot contains $2\ \text{kg}$ of broth with $1\ \%$ by mass of salt.

  1. a) How many grams of salt are in the broth?
  2. b) Upon boiling, water evaporates until the broth weighs $500\ \text{g}$: what is the percentage by mass of salt now?
  3. c) A chef wants the broth to have $2\ \%$ salt: to what total mass must it be reduced?
  4. d) Explain why the concentration increases even though not a single gram of salt has been added: which quantity is conserved?
Solve

Colligative Properties: What Matters Is How Many Particles There Are

You add salt to the ice in a homemade ice cream maker and the mixture cools below $0\ °\text{C}$. Why?

Freezing temperature scale: pure water freezes at 0 °C, the 0.5 M salt solution freezes lower, and the 1 M salt solution freezes lower still. Freezing temperature T 0 °C pure water 0.5 M salt 1 M salt freezes at 0 °C freezes lower freezes lower still
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The colligative properties of solutions depend on the number of dissolved solute particles and not on their nature. a) Order from lowest to highest freezing point: pure…

The colligative properties of solutions depend on the number of dissolved solute particles and not on their nature.

  1. a) Order from lowest to highest freezing point: pure water, $0.5\ \text{M}$ salt solution, and $1\ \text{M}$ salt solution. Explain your answer.
  2. b) Order those same three samples from lowest to highest boiling point.
  3. c) Does it affect these orderings whether the solute is salt or sugar? Explain what it means for them to be colligative properties.
Solve
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In winter, road services spread salt on ice and snow. a) What happens to the freezing point of water when a salt is dissolved? b) Explain why the mixture of water and…

In winter, road services spread salt on ice and snow.

  1. a) What happens to the freezing point of water when a salt is dissolved?
  2. b) Explain why the mixture of water and salt can remain liquid at $-5\ \celsius$ even though pure water would be frozen.
  3. c) Reason why this method loses effectiveness when it is very cold, for example at $-20\ \celsius$: what do you think happens when the temperature drops too low, no matter how much salt is added?
  4. d) Relate this method to car antifreeze: which colligative property do both make use of?
Solve
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Car antifreeze is a solution of ethylene glycol in water. a) Which colligative property does it make use of to protect the engine in winter? Explain how it works at…

Car antifreeze is a solution of ethylene glycol in water.

  1. a) Which colligative property does it make use of to protect the engine in winter? Explain how it works at $-15\ \celsius$.
  2. b) The same solution also raises the boiling point of the coolant water: explain why this is useful in summer.
  3. c) A garage prepares the mixture at $30\ \%$ by mass of ethylene glycol: calculate how many kilograms of ethylene glycol and water are needed to obtain $10\ \text{kg}$ of antifreeze.
  4. d) If the cooling system of a car contains $6\ \text{kg}$ of that mixture, what mass of ethylene glycol does it contain?
Solve

Osmosis and Osmotic Pressure

With $0.1\ \text{M}$ glucose on one side and $1\ \text{M}$ on the other, water moves toward the $1\ \text{M}$ side: its level rises and the other drops, until the pressure difference of the liquid offsets the tendency to move.

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Two compartments are separated by a semipermeable membrane, which allows water to pass through but not glucose. In one there is a $0.1\ \text{M}$ glucose solution and in…

Two compartments are separated by a semipermeable membrane, which allows water to pass through but not glucose. In one there is a $0.1\ \text{M}$ glucose solution and in the other a $1\ \text{M}$ solution. The diagram shows the initial situation.

net flow of water: ? water glucose semipermeable membrane 0.1 M glucose 1 M glucose
  1. a) Explain what osmosis is.
  2. b) Predict which way the water will pass through the membrane and justify your answer.
  3. c) What difference will be observed between the two compartments over time?
  4. d) What is osmotic pressure? State what would need to be done to prevent this flow of water.
Solve
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A desalination plant obtains drinking water from the sea by reverse osmosis. The diagram shows the process. a) Explain what reverse osmosis consists of and what is…

A desalination plant obtains drinking water from the sea by reverse osmosis. The diagram shows the process.

seawater pure water membrane pressure
  1. a) Explain what reverse osmosis consists of and what is achieved by applying a pressure higher than its osmotic pressure to seawater.
  2. b) What characteristic must the membrane have for the process to work?
  3. c) Brackish water, less concentrated in salts than seawater, requires less pressure to desalinate: relate this to the dependence of osmotic pressure on concentration.
  4. d) Point out an advantage and a disadvantage of the process considering the energy required.
Solve
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Red blood cells are surrounded by a semipermeable membrane and contain an aqueous medium with dissolved salts and proteins. a) Explain why saline or intravenous fluid…

Red blood cells are surrounded by a semipermeable membrane and contain an aqueous medium with dissolved salts and proteins.

  1. a) Explain why saline or intravenous fluid injected into a vein must be isotonic, that is, have a solute concentration similar to that of blood. Which colligative phenomenon is involved?
  2. b) Predict what would happen to red blood cells if the IV fluid were much more dilute than blood: which way would water flow and what risk would there be?
  3. c) What if it were much more concentrated? Justify your answer in the same way.
Solve

Back to the beginning: two hibiscus teas are compared by concentration (mass percent or mol/L), and properties such as freezing temperature depend only on how many particles are dissolved.

Summary

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