Back to homeChemistry · High School Year 2 · Physics-Math · Change subject
Start for free
Prep 2 Tech · Chemistry
Chemical change · Chemical reactions of interest

Neutralization Reactions

Before you start, make sure you know: Chemical equations and balancing (Secondary Year 3)
Before you start, make sure you know: Solutions and concentration (Secondary Year 3)

After a few too many tacos, heartburn is relieved with an antacid; the lime used to cook corn for nixtamal is a base; and a wasp sting is soothed with a little vinegar. All three cases are the same type of reaction: an acid meets a base and they "cancel" each other out, in a proportion that stoichiometry lets us calculate.

Acids, bases, and the pH scale

Lemon juice is sour and attacks marble; hand soap is slippery. How can we sort out these differences with a single numerical scale?

pH scale ranging from 0 to 14: acidic zone below 7, neutral point at 7, and basic zone above 7, with an arrow showing the direction in which pH increases. neutral acidic pH < 7 basic pH > 7 0 7 14 pH the lower, the more acidic the higher, the more basic

Besides pH, salts are the compounds that result when the metal of a base joins with the rest of an acid: $\text{NaCl}$, $\text{KNO}_3$, $\text{CaSO}_4$.

Practice★☆☆Not started
Classify each of these substances as an acid, a base or a salt: a) $HNO_3$ (nitric acid) b) $KOH$ (potassium hydroxide) c) $NaCl$ (sodium chloride) d) $H_2SO_4$…

Classify each of these substances as an acid, a base or a salt:

  1. a) $HNO_3$ (nitric acid)
  2. b) $KOH$ (potassium hydroxide)
  3. c) $NaCl$ (sodium chloride)
  4. d) $H_2SO_4$ (sulfuric acid)
  5. e) $Ca(OH)_2$ (calcium hydroxide)
Solve
Practice★☆☆Not started
pH measures how acidic or basic a solution is. These are the positions of the four solutions on the pH scale: State whether each of these solutions is acidic, neutral or…

pH measures how acidic or basic a solution is. These are the positions of the four solutions on the pH scale:

pH 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 lemon juice crushed tomato pure water hand soap

State whether each of these solutions is acidic, neutral or basic:

  1. a) lemon juice, $pH = 2.5$
  2. b) pure water, $pH = 7$
  3. c) hand soap, $pH = 10$
  4. d) crushed tomato, $pH = 4.5$
Solve

The heart of neutralization: H⁺ + OH⁻ → H₂O

When hydrochloric acid and caustic soda, two very corrosive substances, are mixed, the result is water with table salt, giving off heat. What happens at the particle level for both to lose their aggressiveness?

An H⁺ ion and a hydroxide ion OH⁻ combine and form a water molecule H₂O, neutral, with the oxygen bonded to two hydrogens at an angle of about 104.5 degrees. + H⁺ + O H OH⁻ O H H H₂O neutral, pH = 7

One practical way to detect this is litmus paper: red in an acidic medium and blue in a basic medium. In a complete neutralization neither one is left in excess, and the paper no longer indicates acid or base.

Practice★☆☆Not started
Complete the general scheme of a neutralisation reaction with the missing words: "An $\dots$ reacts with a $\dots$ to form a $\dots$ and $\dots$". Then give an example…

Complete the general scheme of a neutralisation reaction with the missing words: "An $\dots$ reacts with a $\dots$ to form a $\dots$ and $\dots$". Then give an example using the reaction between hydrochloric acid and sodium hydroxide.

Solve
Practice★☆☆Not started
In the laboratory, hydrochloric acid ($HCl$) is mixed with sodium hydroxide ($NaOH$) to form sodium chloride ($NaCl$), common salt, and water. Write the reaction…

In the laboratory, hydrochloric acid ($HCl$) is mixed with sodium hydroxide ($NaOH$) to form sodium chloride ($NaCl$), common salt, and water. Write the reaction equation and check by counting atoms that it is balanced.

Solve
Practice★☆☆Not started
Litmus paper turns red in acidic conditions and blue in basic conditions. a) What color will it turn in a solution of $HCl$? b) And in a solution of $NaOH$? c) We mix…

Litmus paper turns red in acidic conditions and blue in basic conditions.

  1. a) What color will it turn in a solution of $HCl$?
  2. b) And in a solution of $NaOH$?
  3. c) We mix the two solutions in exact amounts for complete neutralization: explain why the litmus paper no longer indicates acid or base in the resulting mixture.
Solve
Practice★★☆Not started
The core of any neutralisation is the combination of the $H^+$ ion from the acid with the $OH^-$ ion from the base to form water: $H^+ + OH^- \rightarrow H_2O$, as shown…

The core of any neutralisation is the combination of the $H^+$ ion from the acid with the $OH^-$ ion from the base to form water: $H^+ + OH^- \rightarrow H_2O$, as shown in the diagram.

H ion H+ + O H ion OH− O H H H₂O
  1. a) Check that this ionic equation is balanced in terms of atoms and electrical charge.
  2. b) Using this idea, explain what these two reactions have in common: $HCl + NaOH \rightarrow NaCl + H_2O$ and $HNO_3 + KOH \rightarrow KNO_3 + H_2O$.
Solve

Balancing neutralizations and naming the salt

The salt always combines the metal of the base with the rest of the acid. If the acid supplies more than one $\text{H}^+$, or the base more than one $\text{OH}^-$, you have to balance carefully so that every ion finds a partner. Rule of thumb: first the metal and the rest of the acid; H and O last.

To name the salt, use the name of the acid's anion and that of the metal: $\text{HCl}$ (hydrochloric acid) with $\text{KOH}$ gives potassium chloride; $\text{HNO}_3$ (nitric) gives nitrate; $\text{H}_2\text{SO}_4$ (sulfuric) gives sulfate.

Practice★☆☆Not started
Write the formula and name of the salt formed in each neutralization reaction: a) Hydrochloric acid ($HCl$) with potassium hydroxide ($KOH$). b) Nitric acid ($HNO_3$)…

Write the formula and name of the salt formed in each neutralization reaction:

  1. a) Hydrochloric acid ($HCl$) with potassium hydroxide ($KOH$).
  2. b) Nitric acid ($HNO_3$) with sodium hydroxide ($NaOH$).
Solve
Practice★★☆Not started
Sulfuric acid ($H_2SO_4$) reacts with calcium hydroxide ($Ca(OH)2$) to form calcium sulfate ($CaSO_4$) and water. Write the equation and balance it; pay close attention…

Sulfuric acid ($H_2SO_4$) reacts with calcium hydroxide ($Ca(OH)_2$) to form calcium sulfate ($CaSO_4$) and water. Write the equation and balance it; pay close attention to how many water molecules are formed for each calcium sulfate.

Solve
Practice★★☆Not started
Write and balance the equation for the neutralisation between hydrochloric acid ($HCl$) and calcium hydroxide ($Ca(OH)2$), forming calcium chloride ($CaCl_2$) and water.

Write and balance the equation for the neutralisation between hydrochloric acid ($HCl$) and calcium hydroxide ($Ca(OH)_2$), forming calcium chloride ($CaCl_2$) and water.

Solve
Practice★★☆Not started
Write and balance the equation for the neutralisation of sulfuric acid ($H_2SO_4$) with sodium hydroxide ($NaOH$), forming sodium sulfate ($Na_2SO_4$) and water.

Write and balance the equation for the neutralisation of sulfuric acid ($H_2SO_4$) with sodium hydroxide ($NaOH$), forming sodium sulfate ($Na_2SO_4$) and water.

Solve
Practice★★☆Not started
Three beakers contain dissolved salts left behind after three complete neutralisations: potassium chloride ($KCl$), sodium nitrate ($NaNO_3$) and calcium sulphate…

Three beakers contain dissolved salts left behind after three complete neutralisations: potassium chloride ($KCl$), sodium nitrate ($NaNO_3$) and calcium sulphate ($CaSO_4$). Deduce which acid and which base have neutralised each other in each beaker and write the balanced equation for each reaction.

Solve
Practice★★★Not started
Phosphoric acid ($H_3PO_4$), present in some cola soft drinks, reacts with calcium hydroxide to form calcium phosphate ($Ca_3(PO_4)2$) and water. a) Write and balance…

Phosphoric acid ($H_3PO_4$), present in some cola soft drinks, reacts with calcium hydroxide to form calcium phosphate ($Ca_3(PO_4)_2$) and water.

  1. a) Write and balance the equation (you will need the coefficients $2$, $3$ and $6$).
  2. b) How many moles of water are formed per mole of phosphoric acid?
  3. c) Explain why, when balancing this equation, it is not enough to look at a single element, and why it is advisable to start by balancing calcium and phosphorus before hydrogen and oxygen.
Solve

Neutralization in everyday life: pH and antacids

Front view of a stomach, with the esophagus at the top and the duodenum at the bottom left. Gastric juice with hydrochloric acid collects in its lower part. An antacid arrives through the esophagus, reacts in the juice, gives off CO₂ bubbles, and neutralizes the excess acid. + antacid CO₂ H⁺ H⁺ H⁺ gastric acid (HCl) esophagus duodenum stomach the excess acid is neutralized

Gastric juice contains hydrochloric acid. An antacid containing a base, such as magnesium hydroxide (milk of magnesia), neutralizes it: acid + base → salt + water. When the pH rises from 3 to near 7, the acidity disappears.

The same thing happens with lime in farming: an acidic soil (low pH) is corrected with calcium hydroxide, which raises the pH. If too much is added, the soil becomes basic and is no good for crops either. And acid rain dissolves marble ($\text{CaCO}_3$) because the acid reacts with the carbonate, just like the antacid; granite, which has no carbonates, resists better.

Ammonia $\text{NH}_3$ is a special case: it neutralizes $\text{HCl}$ ($\text{NH}_3 + \text{HCl} \rightarrow \text{NH}_4\text{Cl}$) without forming water because it has no $\text{OH}^-$; in the modern definition a base is any substance that accepts $\text{H}^+$, and the nitrogen in $\text{NH}_3$ accepts it to form $\text{NH}_4^+$.

Back to the beginning: nixtamal uses lime (a base) to change the pH of the corn; the antacid neutralizes the $\text{HCl}$ in the stomach; and vinegar soothes the wasp sting, which is basic. All three cases are $\text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O}$.

Practice★☆☆Not started
We have a beaker with dilute vinegar at $pH = 3$ and we gradually add a solution of sodium bicarbonate, which is a base. a) Does the pH in the beaker rise or fall when…

We have a beaker with dilute vinegar at $pH = 3$ and we gradually add a solution of sodium bicarbonate, which is a base.

  1. a) Does the pH in the beaker rise or fall when adding the bicarbonate?
  2. b) If we add just the right amount to neutralise all the acid, around what value will the pH be?

Give reasons for your answers.

Solve
Practice★☆☆Not started
Gastric juice in the stomach contains hydrochloric acid. In cases of heartburn, antacids from the pharmacy, which contain bases such as magnesium hydroxide, relieve it.…

Gastric juice in the stomach contains hydrochloric acid. In cases of heartburn, antacids from the pharmacy, which contain bases such as magnesium hydroxide, relieve it. Explain, using the concept of neutralisation, how an antacid works in the stomach.

Solve
Practice★★☆Not started
An effervescent antacid contains sodium bicarbonate ($NaHCO_3$), which reacts with hydrochloric acid as follows: $NaHCO_3 + HCl \rightarrow NaCl + H_2O + CO_2$. a) Check…

An effervescent antacid contains sodium bicarbonate ($NaHCO_3$), which reacts with hydrochloric acid as follows: $NaHCO_3 + HCl \rightarrow NaCl + H_2O + CO_2$.

  1. a) Check by counting atoms that the equation is balanced.
  2. b) Why do bubbles form when the tablet is dropped into a glass with acid?
  3. c) How does this reaction differ from a "classic" neutralisation such as that of $NaOH$ with $HCl$?
Solve
Practice★★☆Not started
The soil in a vegetable garden has $pH = 5$, and tomatoes grow best with a pH between $6$ and $7$. a) Is it an acidic or basic soil? b) Farmers add "lime" (calcium…

The soil in a vegetable garden has $pH = 5$, and tomatoes grow best with a pH between $6$ and $7$.

  1. a) Is it an acidic or basic soil?
  2. b) Farmers add "lime" (calcium hydroxide) to acidic soils. Assuming the acidity of the soil were due to hydrochloric acid, write the balanced equation for what the lime does in the soil.
  3. c) What would happen to the pH of the soil if too much lime were added? Would it be good for tomatoes?
Solve
Practice★★★Not started
Ammonia ($NH_3$) in cleaning products is not a hydroxide, but it reacts with hydrochloric acid as follows: $NH_3 + HCl \rightarrow NH_4Cl$. a) Check that the equation is…

Ammonia ($NH_3$) in cleaning products is not a hydroxide, but it reacts with hydrochloric acid as follows: $NH_3 + HCl \rightarrow NH_4Cl$.

  1. a) Check that the equation is balanced.
  2. b) Why does water not appear among the products, unlike what happens in neutralisations with hydroxides?
  3. c) The modern definition states that a base is any substance capable of accepting $H^+$ ions. Using this definition, explain why ammonia is indeed a base and what has happened to its nitrogen atom upon forming $NH_4Cl$.
Solve
Practice★★★Not started
A bee sting injects an acid (methanoic acid) and a wasp sting, a basic substance. In the first-aid kit, there is vinegar (dilute acetic acid) and a sodium hydrogen…

A bee sting injects an acid (methanoic acid) and a wasp sting, a basic substance. In the first-aid kit, there is vinegar (dilute acetic acid) and a sodium hydrogen carbonate paste.

  1. a) Which of the two remedies would you apply to each sting? Justify your answer using the concept of neutralisation.
  2. b) A friend claims that "vinegar works for all stings". Explain to them why they are wrong and what would happen if vinegar were applied to a bee sting.
Solve

Calculating with neutralizations

Two beakers: on the left 0.1 mol of HCl dissolved, with H⁺ and Cl⁻ ions; on the right 0.05 mol of Mg(OH)₂, with Mg²⁺ and OH⁻ ions. An arrow labeled «÷ 2» indicates that half as many moles of base as of acid are needed. 0.1 mol HCl ÷ 2 0.05 mol Mg(OH)₂ H⁺ Cl⁻ Mg²⁺ OH⁻

The balanced equation is read in moles: $\text{Mg(OH)}_2 + 2\ \text{HCl} \rightarrow \text{MgCl}_2 + 2\ \text{H}_2\text{O}$ says that $1$ mol of base neutralizes $2$ mol of acid. With that you calculate as in any stoichiometry problem: moles of one reactant × (desired coefficient / given coefficient).

Practice★★☆Not started
Milk of magnesia is a suspension of magnesium hydroxide ($Mg(OH)2$) taken for heartburn. Its reaction with stomach acid is…

Milk of magnesia is a suspension of magnesium hydroxide ($Mg(OH)_2$) taken for heartburn. Its reaction with stomach acid is $Mg(OH)_2 + 2\ HCl \rightarrow MgCl_2 + 2\ H_2O$.

  1. a) How many moles of $HCl$ does $1\ \text{mol}$ of $Mg(OH)_2$ neutralise?
  2. b) If the stomach has an excess of $0.1\ \text{mol}$ of $HCl$, how many moles of $Mg(OH)_2$ are needed to neutralise it?
Solve
Practice★★★Not started
Which antacid makes the best use of every gram? These are the reactions of three antacids with stomach acid: a) magnesium hydroxide ($58\ \text{g/mol}$):…

Which antacid makes the best use of every gram? These are the reactions of three antacids with stomach acid:

  1. a) magnesium hydroxide ($58\ \text{g/mol}$): $Mg(OH)_2 + 2\ HCl \rightarrow MgCl_2 + 2\ H_2O$
  2. b) calcium carbonate ($100\ \text{g/mol}$): $CaCO_3 + 2\ HCl \rightarrow CaCl_2 + H_2O + CO_2$
  3. c) sodium hydrogen carbonate ($84\ \text{g/mol}$): $NaHCO_3 + HCl \rightarrow NaCl + H_2O + CO_2$

Calculate the moles of $HCl$ neutralised by $1\ \text{g}$ of each antacid (you can give your answer as a fraction or rounded to three decimal places), order them from highest to lowest capacity per gram and explain why calcium carbonate neutralises less acid per gram than magnesium hydroxide, even though both neutralise the same amount of acid per mole.

Solve
Practice★★★Not started
In a laboratory flask, there are $0.2\ \text{mol}$ of sulphuric acid ($H_2SO_4$). a) Write the balanced equation for its neutralisation with sodium hydroxide ($NaOH$),…

In a laboratory flask, there are $0.2\ \text{mol}$ of sulphuric acid ($H_2SO_4$).

  1. a) Write the balanced equation for its neutralisation with sodium hydroxide ($NaOH$), which produces sodium sulphate ($Na_2SO_4$) and water.
  2. b) Calculate how many moles of $NaOH$ are needed to neutralise all the acid.
  3. c) If we were to add only $0.2\ \text{mol}$ of $NaOH$, would the solution be acidic, neutral or basic? Justify your answer using stoichiometry.
Solve
Practice★★★Not started
We mix $0.1\ \text{mol}$ of sulphuric acid ($H_2SO_4$) with $0.1\ \text{mol}$ of sodium hydroxide ($NaOH$). a) Write the balanced equation for the neutralisation, which…

We mix $0.1\ \text{mol}$ of sulphuric acid ($H_2SO_4$) with $0.1\ \text{mol}$ of sodium hydroxide ($NaOH$).

  1. a) Write the balanced equation for the neutralisation, which produces sodium sulphate ($Na_2SO_4$) and water.
  2. b) Reason which of the two reactants is used up first and how many moles of the other remain unreacted.
  3. c) Will the final pH be acidic, basic or neutral? What if we mix $0.1\ \text{mol}$ of $H_2SO_4$ with $0.2\ \text{mol}$ of $NaOH$? Justify both answers.
Solve
Practice★★★Not started
Marble facades and statues (calcium carbonate, $CaCO_3$) deteriorate with acid rain, which contains sulphuric acid ($H_2SO_4$). a) Write and balance the equation for the…

Marble facades and statues (calcium carbonate, $CaCO_3$) deteriorate with acid rain, which contains sulphuric acid ($H_2SO_4$).

  1. a) Write and balance the equation for the reaction between sulphuric acid and calcium carbonate, in which calcium sulphate ($CaSO_4$), water and carbon dioxide are formed.
  2. b) Explain why this reaction gradually "eats away at" statues.
  3. c) Granite does not contain carbonates: reason why granite buildings withstand acid rain better than marble ones.
Solve

The titration curve

In a titration, a base is added little by little to an acid while the pH is measured. Why does the pH barely change at first and then suddenly "jump"?

Graph of an acid-base titration curve showing how the pH changes with the volume of base added, highlighting the vertical jump at the equivalence point. V equivalence pH V (mL)
Practice★★★Not started
In the laboratory, a solution of $NaOH$ is added slowly to $25\ \text{mL}$ of a solution of $HCl$ while measuring the pH, as shown in the diagram. This is what is…

In the laboratory, a solution of $NaOH$ is added slowly to $25\ \text{mL}$ of a solution of $HCl$ while measuring the pH, as shown in the diagram.

NaOH HCl 25 mL pH

This is what is observed: at first, the pH is $1$ and hardly increases during the first $20\ \text{mL}$ added; between $24$ and $26\ \text{mL}$, the pH jumps from $3$ to $11$; from then on, it rises slowly, approaching $13$.

  1. a) Draw in your notebook the graph of pH against the volume of $NaOH$ added, marking those three sections.
  2. b) For what added volume is the neutralisation exactly complete? What is the pH of the solution at that point?
  3. c) Explain, using the reaction $H^+ + OH^- \rightarrow H_2O$, why the pH changes so rapidly around that exact point.

You can do it on paper and send a photo with your answer.

Solve

Summary

See all the exercises in this section