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5th Year HL · Physics
Interaction · Dynamics

Everyday forces

A book does not sink into the table, a lamp hangs motionless from a cable, a lift makes the scales read too much as it starts to move, and dragging a wardrobe across the bedroom floor is harder at the start than afterwards. These are different situations, but they are all solved with the same set of five forces: weight, normal reaction, friction, tension and upthrust.

Weight: the force of gravity

You drop your pencil case in the school corridor and it falls to the floor, accelerating, but if you hold it in your hand you feel it pulling downwards: what invisible force attracts all bodies towards the centre of the Earth?

Block of mass m with the weight vector W pointing vertically downwards. m W = mg
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Calculate the weight of a rucksack of $5\ \text{kg}$ (take $g = 9.8\ \text{m/s}^2$) and indicate the direction in which this force acts.

Calculate the weight of a rucksack of $5\ \text{kg}$ (take $g = 9.8\ \text{m/s}^2$) and indicate the direction in which this force acts.

Solve
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A pair of bathroom scales reads $60\ \text{kg}$. a) What do the scales actually measure: mass or weight? b) What is this person's weight in newtons (take…

A pair of bathroom scales reads $60\ \text{kg}$.

  1. a) What do the scales actually measure: mass or weight?
  2. b) What is this person's weight in newtons (take $g = 9.8\ \text{m/s}^2$)?
  3. c) What would the scales read on the Moon, where gravity is weaker? Reason your answer.
Solve
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An astronaut has a mass of $80\ \text{kg}$. a) Calculate their weight on Earth ($g = 9.8\ \text{m/s}^2$). b) Calculate their weight on the Moon, where…

An astronaut has a mass of $80\ \text{kg}$.

  1. a) Calculate their weight on Earth ($g = 9.8\ \text{m/s}^2$).
  2. b) Calculate their weight on the Moon, where $g = 1.6\ \text{m/s}^2$.
  3. c) Has their mass changed upon going to the Moon? What about their weight? Explain the difference between the two concepts.
Solve

The normal reaction: the perpendicular reaction of a surface

If you put a pile of heavy books on your desk, the table does not break and the books do not fall: what force does a surface exert to support the objects resting on it?

Block resting on a horizontal table: the weight W acts downwards from the centre of the block and the normal reaction R acts upwards, perpendicular to the surface, with the same magnitude. Surface Body R W R = W (at rest)
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A book of $2\ \text{kg}$ is at rest on a table (take $g = 9.8\ \text{m/s}^2$). a) Draw the forces acting on the book in your exercise book. b) Calculate the weight of…

A book of $2\ \text{kg}$ is at rest on a table (take $g = 9.8\ \text{m/s}^2$).

  1. a) Draw the forces acting on the book in your exercise book.
  2. b) Calculate the weight of the book and the normal reaction force exerted by the table.

You can do it on paper and send a photo with your answer.

Solve
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A cup is resting on the kitchen worktop. Which object exerts the normal force on the cup? In which direction does it point? Why do you think it is called a "normal"…

A cup is resting on the kitchen worktop. Which object exerts the normal force on the cup? In which direction does it point? Why do you think it is called a "normal" force?

Solve
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On a book resting on a table, the weight and the normal force act, having the same magnitude and opposite directions. A student claims: "since they are equal and…

On a book resting on a table, the weight and the normal force act, having the same magnitude and opposite directions. A student claims: "since they are equal and opposite, they are an action-reaction pair". Explain why the student is mistaken, stating which object each of these forces acts upon and what the true "partner" force of each one is according to Newton's third law.

Solve
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A person of $60\ \text{kg}$ is standing on bathroom scales inside a lift, and the scales read $660\ \text{N}$ (take $g = 10\ \text{m/s}^2$). a) Calculate the person's…

A person of $60\ \text{kg}$ is standing on bathroom scales inside a lift, and the scales read $660\ \text{N}$ (take $g = 10\ \text{m/s}^2$).

  1. a) Calculate the person's real weight.
  2. b) Calculate the net force acting on them.
  3. c) Deduce the magnitude and direction of the lift's acceleration.
Solve

Friction: proportional to the normal reaction

You push gently on a wardrobe in your bedroom and it does not move; you push harder and, once it starts to slide, it takes quite a bit less effort to keep it going: how does the resistance between two surfaces in contact behave?

Block resting on the ground with four forces: applied force to the right, friction to the left, normal reaction upwards and weight downwards. Applied F F = μR R W

Air resistance and terminal velocity

A resistant force such as air resistance also opposes motion, but it grows as the speed grows. A skydiver or parachutist speeds up while weight is greater than air resistance. As speed rises, air resistance rises until it equals the weight. Then $F_{net} = 0$, so $a = 0$ and the speed stays constant: this is the terminal velocity.

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A crate of $20\ \text{kg}$ is pulled along a floor for which the friction force is given by $F_r = \mu \times N$, with $\mu = 0.3$ (take $g = 10\ \text{m/s}^2$). a)…

A crate of $20\ \text{kg}$ is pulled along a floor for which the friction force is given by $F_r = \mu \times N$, with $\mu = 0.3$ (take $g = 10\ \text{m/s}^2$).

  1. a) Calculate the normal force on the crate.
  2. b) Calculate the friction force.
  3. c) What is the minimum horizontal force that must be applied for the crate to move forward at a constant speed? Justify your answer.
Solve
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A worker pulls a crate of $10\ \text{kg}$ along a horizontal floor with a force of $60\ \text{N}$, and the friction is $30\ \text{N}$ (take $g = 10\ \text{m/s}^2$). The…

A worker pulls a crate of $10\ \text{kg}$ along a horizontal floor with a force of $60\ \text{N}$, and the friction is $30\ \text{N}$ (take $g = 10\ \text{m/s}^2$). The diagram shows the forces acting on the crate.

m = 10 kg F = 60 N Fr = 30 N N = ? P = ?
  1. a) Calculate the weight of the crate and the normal force from the floor.
  2. b) Calculate the net horizontal force and the acceleration of the crate.
Solve
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A student pushes a piece of furniture with increasing force: with $10\ \text{N}$ it does not move, with $20\ \text{N}$ it does not move, with $30\ \text{N}$ it does not…

A student pushes a piece of furniture with increasing force: with $10\ \text{N}$ it does not move, with $20\ \text{N}$ it does not move, with $30\ \text{N}$ it does not move and with $35\ \text{N}$ it starts to slide.

  1. a) What was the friction force in each of the first three cases? Justify your answer using Newton's second law.
  2. b) What is the maximum value of static friction between the piece of furniture and the floor?
  3. c) Once in motion, do you expect the friction to remain the same? Reason your answer using what you know about static and dynamic friction.
Solve
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A lorry travels along a motorway at constant speed and its engine exerts a force of $2000\ \text{N}$. a) What is the total friction force (air resistance and tyres)…

A lorry travels along a motorway at constant speed and its engine exerts a force of $2000\ \text{N}$.

  1. a) What is the total friction force (air resistance and tyres) under these conditions? Justify your answer using Newton's second law.
  2. b) If the engine increases its force to $2600\ \text{N}$ and the friction remains the same, calculate the net force and explain what happens to the lorry's speed.
  3. c) Air resistance increases with speed: using this information, explain why the lorry cannot exceed a certain maximum speed no matter how hard the accelerator is pressed.
Solve
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A parachutist of $70\ \text{kg}$ descends with an open parachute at a constant speed of $5\ \text{m/s}$ (take $g = 10\ \text{m/s}^2$). a) What is the magnitude of the…

A parachutist of $70\ \text{kg}$ descends with an open parachute at a constant speed of $5\ \text{m/s}$ (take $g = 10\ \text{m/s}^2$).

  1. a) What is the magnitude of the air resistance force on the parachute? Justify your answer using Newton's second law.
  2. b) Before the parachute opened, the parachutist was also falling at a constant speed, of $50\ \text{m/s}$. Was the air resistance then greater, smaller or equal to that with the open parachute? Reason your answer.
  3. c) Explain what happens to the net force at the instant the parachute opens and why the parachutist slows down until reaching a new constant speed.
Solve

Tension: the force of ropes and cables

Body hanging from a rope with the tension vector pointing upwards and the weight vector pointing downwards. m T W

Connected bodies

When a locomotive pulls rail cars, the whole train has the same acceleration. Find it first by treating the train as one body: $a = F_{net}/m_{total}$. Then find the tension in a coupling by applying $F_{net} = ma$ to the part of the train behind that coupling: the coupling is the only forward force on it.

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A lamp of $3\ \text{kg}$ hangs from the ceiling suspended by a cable (take $g = 9.8\ \text{m/s}^2$). a) What forces act on the lamp and what exerts them? b) Calculate…

A lamp of $3\ \text{kg}$ hangs from the ceiling suspended by a cable (take $g = 9.8\ \text{m/s}^2$).

  1. a) What forces act on the lamp and what exerts them?
  2. b) Calculate the tension in the cable.
Solve
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Two teams pull on a rope in opposite directions, each with a force of $350\ \text{N}$, and the rope does not move, as shown in the diagram. a) What is the tension at any…

Two teams pull on a rope in opposite directions, each with a force of $350\ \text{N}$, and the rope does not move, as shown in the diagram.

350 N Team A 350 N Team B T = ?
  1. a) What is the tension at any point in the rope? (Be careful: it is not the sum of the two forces; explain why.)
  2. b) If one of the teams lets go of the rope, what happens to the tension and to the movement of the rope? Explain it.
Solve
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A locomotive of $2000\ \text{kg}$ pulls two identical rail cars of $2000\ \text{kg}$ each with a force of $6000\ \text{N}$ (consider friction negligible). a) Calculate…

A locomotive of $2000\ \text{kg}$ pulls two identical rail cars of $2000\ \text{kg}$ each with a force of $6000\ \text{N}$ (consider friction negligible).

Diagram of the locomotive pulling two rail cars with their respective forces and tensions a = ? Rail car 2 2000 kg T2 = ? Rail car 1 2000 kg T1 = ? Locomotive 2000 kg F = 6000 N
  1. a) Calculate the acceleration of the system.
  2. b) Calculate the tension in the coupling between the locomotive and the first rail car.
  3. c) Calculate the tension in the coupling between the two rail cars and explain why it is smaller than the previous one.
Solve

Upthrust: the force of fluids

Try the diagram below: a weight W of 30 N pulls down and an upthrust U of 45 N pushes up. Their resultant $F_{net}$ shows the net force, which points upwards, so the body rises.

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When you submerge a beach ball in a swimming pool and let go of it, it shoots upwards. What force, besides weight, acts on the ball while it is submerged? What exerts it…

When you submerge a beach ball in a swimming pool and let go of it, it shoots upwards. What force, besides weight, acts on the ball while it is submerged? What exerts it and in which direction does it point?

Solve
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A stone weighs $10\ \text{N}$ in air, and when suspended from a force meter and submerged in water, the device reads $6\ \text{N}$, as shown in the diagram. a) What is…

A stone weighs $10\ \text{N}$ in air, and when suspended from a force meter and submerged in water, the device reads $6\ \text{N}$, as shown in the diagram.

6 N force meter water stone T = 6 N E = ? P = 10 N
  1. a) What is the upthrust exerted by the water on the stone?
  2. b) In which direction does this force point?
  3. c) If the stone were released underwater, would it sink or float? Reason your answer by comparing the weight with the upthrust.
Solve
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A steel ship of $50000\ \text{kg}$ floats in the harbour, while a steel bolt of $50\ \text{g}$ sinks to the bottom (take $g = 10\ \text{m/s}^2$), as shown in the…

A steel ship of $50000\ \text{kg}$ floats in the harbour, while a steel bolt of $50\ \text{g}$ sinks to the bottom (take $g = 10\ \text{m/s}^2$), as shown in the diagram.

water m = 50000 kg ship P = ? E = ? bolt m = 50 g P E
  1. a) Calculate the weight of each one (be careful with the mass units).
  2. b) If the ship floats in equilibrium, what is the upthrust exerted by the water on it?
  3. c) Explaining in terms of the volume of water displaced by each, how is it possible for the ship to generate such a large upthrust while the bolt does not, given that both are made of steel?
Solve
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Unit challenge. How do forces interact in everyday real situations? Design a technical report investigating the forces acting on a canned food or plastic container in…

Unit challenge. How do forces interact in everyday real situations? Design a technical report investigating the forces acting on a canned food or plastic container in your own home.

  1. Equilibrium and buoyant force: Measure the mass of the empty container and its volume ($m \pm 0.001\text{ kg}$). Submerge it closed (with air inside) and fully in water, tethered to the bottom with a string; numerically determine the buoyant force $\vec{E}$, the tension $\vec{T}$, and the weight $\vec{P}$, drawing the vector diagram at equilibrium to scale.

  2. Dynamic friction: Add 4 different masses of rice or water to the container. Pull it horizontally at constant velocity along a table using a previously calibrated elastic band. Record the value of the normal force $\vec{N}$ and the frictional force $\vec{F}_r$ in a table, including their associated uncertainties.

  3. Processing and prediction: Plot $F_r$ versus $N$, deduce the coefficient of friction $\mu$ from the slope, and apply Newton's second law ($\sum \vec{F} = m \vec{a}$) to calculate the acceleration of the container if a constant horizontal force of $2.0\text{ N}$ were applied to it with one of the loads from part 2 (state which), first checking whether this force exceeds friction.

  4. Report: Write a reasoned proposal summarizing the vector analysis, the graph, and your conclusions.

Evaluation criteria:

  • Precise identification, vector resolution, and calculation of $\vec{P}$, $\vec{N}$, $\vec{F}_r$, $\vec{T}$, and $\vec{E}$.

  • Experimental quality in taking measurements, estimating uncertainties, and graphical plotting.

  • Correct application of the fundamental principle of dynamics ($\sum \vec{F} = m \vec{a}$).

  • Structure, consistency, and scientific justification of the final report.

Solve

The complete force diagram

To solve any dynamics problem, the first step is always the same: draw all the forces acting on the body, identifying who exerts each one, and resolve them along the horizontal and vertical axes. Use $F_{net} = ma$ along each axis.

Free-body diagram of a box pushed along a surface: applied force and friction F horizontally, normal reaction R upwards and weight W downwards. box applied force F = μR R W
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A plant pot is resting on a windowsill, at rest. List the forces acting on it, stating which object exerts each one, and draw the force diagram in your exercise book.…

A plant pot is resting on a windowsill, at rest. List the forces acting on it, stating which object exerts each one, and draw the force diagram in your exercise book.

You can do it on paper and send a photo with your answer.

Solve
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A rugby player slides across the grass after a tackle. Draw the player sliding to the right in your exercise book and represent the friction force on him: in which…

A rugby player slides across the grass after a tackle. Draw the player sliding to the right in your exercise book and represent the friction force on him: in which direction does it point and why?

You can do it on paper and send a photo with your answer.

Solve
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A goods lift raises a load of $60\ \text{kg}$ with an acceleration of $2\ \text{m/s}^2$ (take $g = 10\ \text{m/s}^2$). a) Draw the forces acting on the load in your…

A goods lift raises a load of $60\ \text{kg}$ with an acceleration of $2\ \text{m/s}^2$ (take $g = 10\ \text{m/s}^2$).

  1. a) Draw the forces acting on the load in your exercise book.
  2. b) Calculate its weight.
  3. c) Apply Newton's second law to calculate the tension in the cable.

You can do it on paper and send a photo with your answer.

Solve
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A crate of $5\ \text{kg}$ is on a horizontal floor and is pushed with a horizontal force of $40\ \text{N}$; the friction is $20\ \text{N}$ (take $g = 10\ \text{m/s}^2$).…

A crate of $5\ \text{kg}$ is on a horizontal floor and is pushed with a horizontal force of $40\ \text{N}$; the friction is $20\ \text{N}$ (take $g = 10\ \text{m/s}^2$).

  1. a) Draw the four forces acting on the crate in your exercise book, naming each one and the object that exerts it.
  2. b) Calculate the magnitude of all four forces.
  3. c) Calculate the net force on the crate and its acceleration.

You can do it on paper and send a photo with your answer.

Solve
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A student claims: "the normal force is always equal to the weight". To test this, a crate of $10\ \text{kg}$ is placed on the floor and pulled upwards with a rope…

A student claims: "the normal force is always equal to the weight". To test this, a crate of $10\ \text{kg}$ is placed on the floor and pulled upwards with a rope exerting $30\ \text{N}$, without actually lifting it (take $g = 10\ \text{m/s}^2$).

  1. a) Draw the three vertical forces acting on the crate in your exercise book.
  2. b) Since the crate is at rest, calculate the magnitude of the normal force.
  3. c) Explain why the student's statement is false in general and state in which specific case it would be true.

You can do it on paper and send a photo with your answer.

Solve

Back to the beginning: The book does not sink because the normal reaction balances its weight, the lamp does not fall because the tension supports its weight, the scales read more as the lift starts because $R = m \cdot (g + a)$, and dragging the furniture is harder at the start because the maximum static friction is greater than the dynamic friction ($\mu_e > \mu_d$).

Summary

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