Uniformly accelerated linear motion

A car starts with an acceleration of $2\ \text{m/s}^2$.

1. a) Explain in your own words what this piece of data means: by how much does its speed increase each second?
2. b) If it starts from rest, what speed will it have after $5\ \text{s}$?

A bicycle starts from rest and accelerates at $3\ \text{m/s}^2$ for $4\ \text{s}$. Calculate its final speed using $v = v_0 + a \times t$.

A motorcycle travels at $5\ \text{m/s}$ and accelerates at $2\ \text{m/s}^2$ for $6\ \text{s}$. What speed does it reach?

A car travelling at $20\ \text{m/s}$ brakes with an acceleration of $-4\ \text{m/s}^2$.

1. a) Why is the acceleration negative?
2. b) How long does it take to come to a complete stop?

A bus reduces its speed from $25\ \text{m/s}$ to $15\ \text{m/s}$ in $5\ \text{s}$.

1. a) Calculate its acceleration.
2. b) Explain the meaning of the sign of the result.

A high-speed train accelerates from rest to $50\ \text{m/s}$ in $100\ \text{s}$. Calculate its acceleration and express the result in $\text{m/s}^2$.

A cyclist starts from rest and accelerates at $0.5\ \text{m/s}^2$ for $10\ \text{s}$.

1. a) Calculate the speed reached.
2. b) Calculate the distance covered using $x = x_0 + v_0 \times t + \frac{1}{2} a \times t^2$.

A car travels at $10\ \text{m/s}$ and accelerates at $2\ \text{m/s}^2$ for $5\ \text{s}$. Calculate the distance it covers in that time.

The position of an object, in International System units, is given by $x = 3 + 2 \times t + t^2$. By comparing with $x = x_0 + v_0 \times t + \frac{1}{2} a \times t^2$:

1. a) Determine its initial position $x_0$, its initial velocity $v_0$ and its acceleration $a$.
2. b) Calculate its velocity when $t = 4\ \text{s}$.
3. c) Calculate its position at that same instant.

A bicycle starts from rest at a traffic light and accelerates at $1.5\ \text{m/s}^2$ for $8\ \text{s}$.

1. a) What is its speed at the end of the acceleration?
2. b) What distance has it covered in those $8\ \text{s}$?

A train starts from rest and accelerates at $0.5\ \text{m/s}^2$ for $60\ \text{s}$; then it maintains the speed reached for $300\ \text{s}$. The $v$-$t$ graph for the journey is shown in the figure.

1. a) What speed does it reach at the end of the acceleration?
2. b) What distance does it cover in each of the two stages?
3. c) What is the total distance?
4. d) Calculate the average speed for the whole journey, in $\text{m/s}$.

We want to test whether "doubling the speed doubles the braking distance" is true. Consider a car that brakes with $a = -5\ \text{m/s}^2$.

1. a) Calculate the braking time and braking distance if it travels at $20\ \text{m/s}$.
2. b) Repeat the calculation if it travels at $40\ \text{m/s}$.
3. c) How many times larger is the braking distance when the speed is doubled? Was the statement true?
4. d) Explain the result, taking into account that doubling the speed doubles both the braking time and the average speed during braking.

A car goes from $0$ to $90\ \text{km/h}$ in $10\ \text{s}$ with constant acceleration.

1. a) Express the final speed in $\text{m/s}$.
2. b) Calculate the acceleration.
3. c) Calculate the distance covered while starting off.

A car travelling at $72\ \text{km/h}$ brakes with an acceleration of $-5\ \text{m/s}^2$ until it stops. The $v$-$t$ graph of the braking is shown in the figure.

1. a) Express the initial speed in $\text{m/s}$.
2. b) How long does the braking last?
3. c) What distance does it cover while braking?

A car travels at $90\ \text{km/h}$ when the driver sees an obstacle. It takes $0.8\ \text{s}$ to react (reaction time) and then brakes with $a = -6.25\ \text{m/s}^2$. The two stages of stopping are shown in the figure.

1. a) Express the speed in $\text{m/s}$ and calculate the distance covered during the reaction time.
2. b) Calculate the braking time and the braking distance.
3. c) What is the total stopping distance from the moment the driver sees the obstacle?
4. d) Based on the results, explain why using a mobile phone while driving is so dangerous.

A train travelling at $30\ \text{m/s}$ must stop at the next station by braking with an acceleration of $-0.5\ \text{m/s}^2$.

1. a) How long will the braking last?
2. b) What distance will it cover while braking?
3. c) At what distance from the station must the train driver start braking?
4. d) Explain why this distance is so large even though the acceleration is small.

Two cars travel at $30\ \text{m/s}$ and perform an emergency stop: the first with $a = -5\ \text{m/s}^2$ and the second with $a = -6\ \text{m/s}^2$.

1. a) Calculate the braking time and braking distance for each car.
2. b) If there is an obstacle $80\ \text{m}$ from the point where they start braking, which of the two hits it? Justify your answer with calculations.
3. c) Explain what quality of a car the braking distance describes and why it matters in road safety.

A car travels at a constant speed of $20\ \text{m/s}$ and, as it passes a stationary police car, the police car starts off and pursues it with a constant acceleration of $2\ \text{m/s}^2$.

1. a) Write the position equations for both cars, taking the overtaking point as the origin.
2. b) Calculate the instant at which the police car catches up with the other car. You will obtain two mathematical solutions: explain why one of them is discarded.
3. c) At what distance from the origin does it catch up?
4. d) Calculate the speed of the police car at that instant and compare it with that of the other car.

A cyclist travels at $10\ \text{m/s}$ and, at the moment they pass a stationary moped, the moped starts off and pursues them with an acceleration of $4\ \text{m/s}^2$.

1. a) Write the position equations for both vehicles.
2. b) Solve the resulting quadratic equation to find the time when the moped catches up.
3. c) At what distance from the starting point does this occur?
4. d) What speed is the moped travelling at that moment?

In a training session, runner A passes the starting line at a constant speed of $6\ \text{m/s}$ at the exact instant runner B starts from rest with $a = 1\ \text{m/s}^2$.

1. a) Who is ahead when $t = 8\ \text{s}$? Calculate the position of each runner.
2. b) Calculate the instant when B catches up with A, and the position of the overtake.
3. c) What speed is B travelling at that instant?
4. d) Explain why B, despite starting off slower, ends up catching up with A.