Vector composition of forces
Two tugboats pull on a barge in Dublin Port with cables that are not parallel; a crane cable holds a beam at some angle; three volunteers pull on a stranded net on a beach clean-up in Co. Clare, each from a different direction. In none of these cases is it enough to add or subtract numbers: forces are vectors, and to predict what will happen to the body we have to add them using the rules of vector addition.
Force: magnitude, direction and sense
If you push a trolley forwards with $50\ \text{N}$ it moves, but if you apply the same $50\ \text{N}$ downwards you just press it against the floor: why is the numerical value not enough to describe what a force does? In Leaving Cert Physics you will use the symbol $F_{net}$ for the resultant force.
A problem states: "the wind pushes the sail of a windsurf board with a force of $120\ \text{N}$ towards the north-east." a) State the magnitude, direction and sense of…
A problem states: "the wind pushes the sail of a windsurf board with a force of $120\ \text{N}$ towards the north-east."
- a) State the magnitude, direction and sense of this force.
- b) Explain why force is a vector quantity: what information would be lost if we only gave its magnitude?
Forces in the same direction and graphical addition: the parallelogram
When two or more forces act along the same line, the resultant is obtained with an algebraic sum, giving a positive sign to one sense and a negative sign to the opposite one. When they are not aligned, we need the graphical construction of the parallelogram.
The two auxiliary thrusters of a space probe ignite simultaneously and push in the same direction and sense with forces of $250\ \text{N}$ and $400\ \text{N}$. Calculate…
The two auxiliary thrusters of a space probe ignite simultaneously and push in the same direction and sense with forces of $250\ \text{N}$ and $400\ \text{N}$. Calculate the resultant force on the probe and draw a diagram in your notebook representing the two forces and the resultant.
In a tug-of-war game at a local festival, the home team pulls to the left with a force of $380\ \text{N}$ and the visiting team pulls to the right with $350\ \text{N}$.…
In a tug-of-war game at a local festival, the home team pulls to the left with a force of $380\ \text{N}$ and the visiting team pulls to the right with $350\ \text{N}$. The situation is shown in the figure.
- a) Calculate the magnitude of the resultant force on the rope.
- b) State which team the rope will start moving towards and justify your answer.
Two forces of $4\ \text{N}$ and $3\ \text{N}$ act on the same point at an angle of $90^\circ$ to each other. Draw the situation in your notebook using a scale of…
Two forces of $4\ \text{N}$ and $3\ \text{N}$ act on the same point at an angle of $90^\circ$ to each other. Draw the situation in your notebook using a scale of $1\ \text{cm}$ per newton, apply the parallelogram rule and measure the diagonal to obtain the magnitude of the resultant. Then check the result with the Pythagorean theorem and compare both values.
You can do it on paper and send a photo with your answer.
Resolving a force into components
To add forces at any angle to each other, the general method is the analytical one: resolve each force into its horizontal component ($F_x$) and vertical component ($F_y$).
Weight on a slope
On a slope at angle $\theta$ to the horizontal, it is handy to resolve the weight $mg$ into a component parallel to the slope and one perpendicular to it. The angle between the weight and the perpendicular to the slope is also $\theta$, so: $$mg\sin\theta \text{ (parallel)} \qquad mg\cos\theta \text{ (perpendicular)}$$ The parallel component tends to make the object slide down; the perpendicular one presses it against the surface (the normal reaction $R$ balances it).
Two people pull a moving crate with ropes perpendicular to each other, one with a force of $60\ \text{N}$ and the other with $80\ \text{N}$. Draw the situation in your…
Two people pull a moving crate with ropes perpendicular to each other, one with a force of $60\ \text{N}$ and the other with $80\ \text{N}$. Draw the situation in your notebook and calculate the magnitude of the resultant force on the crate using Pythagoras' theorem.
You can do it on paper and send a photo with your answer.
The two motors of a competition robot push such that the components of the total force on the robot are $F_x = 12\ \text{N}$ and $F_y = 5\ \text{N}$. Calculate the…
The two motors of a competition robot push such that the components of the total force on the robot are $F_x = 12\ \text{N}$ and $F_y = 5\ \text{N}$. Calculate the magnitude of the resultant force.
The cable of a construction crane pulls a beam with a force of $400\ \text{N}$ making an angle of $60^\circ$ with the horizontal, as shown in the figure. Using…
The cable of a construction crane pulls a beam with a force of $400\ \text{N}$ making an angle of $60^\circ$ with the horizontal, as shown in the figure.
Using $\sen 60^\circ \approx 0.87$ and $\cos 60^\circ = 0.5$:
- a) Calculate the horizontal and vertical components of the force.
- b) State which of the two components lifts the beam.
A worker leaves a pallet of $60\ \text{kg}$ at rest on a loading ramp that forms an angle of $37^\circ$ with the horizontal, as shown in the figure. Take…
A worker leaves a pallet of $60\ \text{kg}$ at rest on a loading ramp that forms an angle of $37^\circ$ with the horizontal, as shown in the figure.
Take $g \approx 10\ \text{m/s}^2$ and use $\sen 37^\circ \approx 0.6$ and $\cos 37^\circ \approx 0.8$.
- a) Calculate the weight of the pallet.
- b) Calculate the component of the weight parallel to the ramp and the component perpendicular to it.
- c) State which of the two components tends to make the pallet slide down the ramp.
Resultant of several forces using components
The components method is essential when there are three or more forces at different angles, or when the question already gives the components and asks you to reconstruct the magnitude and the angle.
Finding the angle: inverse trig and angles beyond 90°
The angle of the resultant can be found with any inverse ratio: $\sin\alpha = R_y/R$, $\cos\alpha = R_x/R$ or $\tan\alpha = R_y/R_x$. Use the absolute values of the components to get an acute angle $\alpha$ from the horizontal, then use the signs of $R_x$ and $R_y$ to decide the quadrant: if $Rx<0$ and $R_y>0$ the force points up and to the left, so its angle from the positive $x$-axis is $180^\circ-\alpha$. For forces at angles above $90^\circ$, the formulas $Fx=F\cos\theta$ and $Fy=F\sin\theta$ still work if $\theta$ is measured from the positive $x$-axis: the calculator gives the negative signs automatically (e.g. $\cos 120^\circ=-0.5$).
The components of the force exerted by the wind on a weather vane are $F_x = -8\ \text{N}$ and $F_y = 6\ \text{N}$. a) Calculate the magnitude of the resultant force. b)…
The components of the force exerted by the wind on a weather vane are $F_x = -8\ \text{N}$ and $F_y = 6\ \text{N}$.
- a) Calculate the magnitude of the resultant force.
- b) Calculate the angle formed by the resultant with the horizontal using $\arcsen$ (note that $\arcsen 0.6 \approx 37^\circ$).
Two rescuers pull an emergency stretcher using two ropes. The forces they exert, in components, are $\vec{F}1 = (30,\ 40)\ \text{N}$ and…
Two rescuers pull an emergency stretcher using two ropes. The forces they exert, in components, are $\vec{F}_1 = (30,\ 40)\ \text{N}$ and $\vec{F}_2 = (-30,\ 40)\ \text{N}$.
- a) Calculate the components of the resultant force on the stretcher.
- b) Calculate the magnitude of the resultant.
- c) Explain why the horizontal components cancel out and what advantage this symmetrical arrangement provides for transport.
Two elastic cords pull on the eyelet of a truck tarpaulin: one with $30\ \text{N}$ towards the east and another with $40\ \text{N}$ towards the north. a) Calculate the…
Two elastic cords pull on the eyelet of a truck tarpaulin: one with $30\ \text{N}$ towards the east and another with $40\ \text{N}$ towards the north.
- a) Calculate the magnitude of the resultant of these two forces.
- b) Deduce the magnitude and direction of the force that a third cord must exert so that the eyelet is in equilibrium.
- c) Calculate the angle formed by this third force with the westward direction (use $\arcsen 0.8 \approx 53^\circ$).
Three forces with components $\vec{F}1 = (6,\ 0)\ \text{N}$, $\vec{F}2 = (0,\ 8)\ \text{N}$ and $\vec{F}3 = (-6,\ -8)\ \text{N}$ act on a ring. a) Draw the three forces…
Three forces with components $\vec{F}_1 = (6,\ 0)\ \text{N}$, $\vec{F}_2 = (0,\ 8)\ \text{N}$ and $\vec{F}_3 = (-6,\ -8)\ \text{N}$ act on a ring.
- a) Draw the three forces head-to-tail in your notebook (polygon rule) and describe what happens to the polygon of forces.
- b) Check numerically that $\sum \vec{F} = 0$ by summing the components along each axis.
- c) State the mechanical state of the ring.
You can do it on paper and send a photo with your answer.
The propulsion system of a delivery drone exerts a force with components $(9,\ 12)\ \text{N}$ on it. a) Calculate the magnitude of the total thrust. b) Calculate the…
The propulsion system of a delivery drone exerts a force with components $(9,\ 12)\ \text{N}$ on it.
- a) Calculate the magnitude of the total thrust.
- b) Calculate the angle formed by the thrust with the horizontal using $\arcsen$ (note that $\arcsen 0.8 \approx 53^\circ$).
- c) Draw the thrust vector and its two components in your notebook.
You can do it on paper and send a photo with your answer.
Three forces with components $\vec{F}1 = (8,\ 6)\ \text{N}$, $\vec{F}2 = (-3,\ 2)\ \text{N}$ and $\vec{F}3 = (-5,\ -8)\ \text{N}$ act on the central ring of a force…
Three forces with components $\vec{F}_1 = (8,\ 6)\ \text{N}$, $\vec{F}_2 = (-3,\ 2)\ \text{N}$ and $\vec{F}_3 = (-5,\ -8)\ \text{N}$ act on the central ring of a force table in the laboratory.
- a) Add the components of the three forces along each axis and check that the ring is in equilibrium.
- b) If force $\vec{F}_3$ is suddenly removed, calculate the components of the resultant force remaining on the ring.
- c) Predict which direction the ring will start moving in that case and justify your answer.
Three volunteers pull on a stranded net during a beach clean-up day, each with a force of $120\ \text{N}$, and the three ropes form angles of $120^\circ$ with each…
Three volunteers pull on a stranded net during a beach clean-up day, each with a force of $120\ \text{N}$, and the three ropes form angles of $120^\circ$ with each other, as shown in the figure.
- a) Taking one of the forces in the direction of the $x$-axis, write the components of the three forces (use $\cos 120^\circ = -0.5$ and $\sen 120^\circ \approx 0.87$).
- b) Add the components and verify that the resultant is practically zero. Does the net move?
- c) If one of the volunteers lets go of their rope, calculate the resultant force remaining on the net and predict what will happen.
Two tugboats pull a barge along a canal using symmetrical cables that form an angle of $37^\circ$ with the canal axis, each pulling with a force of $5000\ \text{N}$, as…
Two tugboats pull a barge along a canal using symmetrical cables that form an angle of $37^\circ$ with the canal axis, each pulling with a force of $5000\ \text{N}$, as shown in the figure.
Use $\sen 37^\circ \approx 0.6$ and $\cos 37^\circ \approx 0.8$.
- a) Calculate the component of each force along the canal and the resultant force on the barge.
- b) Explain why the sideways components cancel out and what advantage having symmetrical cables provides.
- c) If one of the tugboats lets go of its cable, calculate the sideways component that appears and predict what will happen to the trajectory of the barge.
Equilibrium of a particle
In a tug-of-war at a school sports day the central flag stays still if both teams pull with the same force, but if several cables pull in different directions, what exact mathematical condition predicts whether or not the object will start to move?
A painting hangs stationary on a museum wall. a) What is the vector sum of all the forces acting on it? Give reasons for your answer. b) What would happen to the…
A painting hangs stationary on a museum wall.
- a) What is the vector sum of all the forces acting on it? Give reasons for your answer.
- b) What would happen to the painting if this sum were no longer zero?
A flowerpot of $1.2\ \text{kg}$ hangs at rest from a rope on the porch of a house. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the weight of the flowerpot. b) What…
A flowerpot of $1.2\ \text{kg}$ hangs at rest from a rope on the porch of a house. Take $g \approx 10\ \text{m/s}^2$.
- a) Calculate the weight of the flowerpot.
- b) What force does the rope exert on the flowerpot? Justify your answer by applying the equilibrium condition for a particle, $\sum \vec{F} = 0$.
A kite flies in equilibrium held by a string pulling on it with a tension of $50\ \text{N}$ at an angle of $37^\circ$ to the horizontal, in the direction towards the…
A kite flies in equilibrium held by a string pulling on it with a tension of $50\ \text{N}$ at an angle of $37^\circ$ to the horizontal, in the direction towards the hand holding it (that is, downwards and forwards), as shown in the figure.
Use $\sin 37^\circ \approx 0.6$ and $\cos 37^\circ \approx 0.8$.
- a) Calculate the horizontal and vertical components of the tension on the kite.
- b) If the kite weighs $20\ \text{N}$, calculate the vertical force that the wind must exert on it to keep it in equilibrium, applying $\sum \vec{F} = 0$ in the vertical direction.
A lamp of $4\ \text{kg}$ hangs in equilibrium from the ceiling of a porch, supported by two symmetrical cables that make an angle of $30^\circ$ with the ceiling, as…
A lamp of $4\ \text{kg}$ hangs in equilibrium from the ceiling of a porch, supported by two symmetrical cables that make an angle of $30^\circ$ with the ceiling, as shown in the figure.
Take $g \approx 10\ \text{m/s}^2$ and use $\sin 30^\circ = 0.5$.
- a) Draw the forces acting on the lamp in your notebook.
- b) Apply the equilibrium condition in the vertical direction and calculate the tension in each cable.
- c) Compare the tension with the weight of the lamp and explain what would happen to the tensions if the angle with the ceiling were smaller. Could the cables ever be perfectly horizontal? Justify your answer.
You can do it on paper and send a photo with your answer.
A shop sign weighing $100\ \text{N}$ hangs from a knot from which two ropes extend: one horizontal, attached to the wall, and another going up to the ceiling making an…
A shop sign weighing $100\ \text{N}$ hangs from a knot from which two ropes extend: one horizontal, attached to the wall, and another going up to the ceiling making an angle of $30^\circ$ with the horizontal. Use $\sen 30^\circ = 0.5$ and $\cos 30^\circ \approx 0.87$.
- a) Draw the force diagram acting on the knot in your notebook.
- b) Apply the equilibrium condition in the vertical direction and calculate the tension in the inclined rope.
- c) Apply the equilibrium condition in the horizontal direction and calculate the tension in the horizontal rope.
You can do it on paper and send a photo with your answer.
You pull a sledge with a rope making an angle of $37^\circ$ with the horizontal, exerting a force of $250\ \text{N}$, and the sledge moves across the snow at constant…
You pull a sledge with a rope making an angle of $37^\circ$ with the horizontal, exerting a force of $250\ \text{N}$, and the sledge moves across the snow at constant velocity, as shown in the figure.
Use $\sen 37^\circ \approx 0.6$ and $\cos 37^\circ \approx 0.8$.
- a) Calculate the horizontal and vertical components of your force.
- b) Calculate the friction force acting on the sledge, applying the equilibrium condition in the horizontal direction.
- c) The sledge is moving and yet you claim it is in equilibrium. Resolve this apparent contradiction using Newton's first law.
A block of $50\ \text{kg}$ is at rest on a ramp inclined at $37^\circ$, held by a rope parallel to the ramp. Take $g \approx 10\ \text{m/s}^2$ and use…
A block of $50\ \text{kg}$ is at rest on a ramp inclined at $37^\circ$, held by a rope parallel to the ramp. Take $g \approx 10\ \text{m/s}^2$ and use $\sen 37^\circ \approx 0.6$ and $\cos 37^\circ \approx 0.8$. Friction is negligible.
- a) Calculate the weight of the block and resolve it into components parallel and perpendicular to the ramp.
- b) Apply the equilibrium condition in the parallel direction and calculate the tension in the rope.
- c) Calculate the normal force exerted by the ramp. If the ramp were steeper, reason how the required tension and the normal force would change.
On a laboratory force table, a ring is held by two cords passing over pulleys: a mass of $300\ \text{g}$ hangs from one cord in the eastward direction and a mass of…
On a laboratory force table, a ring is held by two cords passing over pulleys: a mass of $300\ \text{g}$ hangs from one cord in the eastward direction and a mass of $400\ \text{g}$ from the other in the northward direction. The set-up is shown in the figure (top view).
Take $g \approx 10\ \text{m/s}^2$.
- a) Calculate the tension in each cord (remember that the tension equals the weight of the hanging mass).
- b) Calculate the magnitude of the resultant of the two tensions on the ring.
- c) Deduce what mass must be hung from a third pulley and in which direction it must be placed so that the ring remains in equilibrium at the centre of the table (use $\arcsen 0.8 \approx 53^\circ$).
Verifying the addition of forces in the lab
In the lab you can verify the law of addition of vectors with a force board (force table). Hang masses from two cords over pulleys, so the tensions are $T = mg$. In 1D, two forces along the same line add or subtract: check that the reading of one newton balance matches $F_1 \pm F_2$. In 2D, place two forces at $90^\circ$ and use a third force to bring the ring to the centre of the board: this third force is the equilibrant, equal in magnitude and opposite in sense to the resultant.
Back to the start: (a different case from the exercise). If two tugboats in Dublin Port each pull with $3000\ \text{N}$ and the angle between their cables is $60^\circ$ ($30^\circ$ to the line of travel), the useful forward force is not $6000\ \text{N}$ but $2 \cdot 3000 \cdot \cos 30^\circ \approx 5200\ \text{N}$.