Equations and graphs of motion
A story: "you leave home for school at a steady pace, speed up when you realise you are late for the bus, and slow down at the school gate". That story can be drawn without a single word, using a graph. And from a graph — of position, velocity or acceleration — you can read what type of motion there is in each stage, without knowing the equation beforehand.
x-t graph: the gradient is the velocity
At a school sports day in Athlone, a stopwatch times two runners: one covers $10\ \mathrm{m}$ every $2\ \mathrm{s}$ and the other $18\ \mathrm{m}$ in the same interval. How can we compare at a glance, on a pair of coordinate axes, who is moving faster?
On the $x(t)$ graph, look at how steep the line is; on the $v(t)$ graph, check that it is a horizontal line, because the velocity does not change.
The $x$-$t$ graph of a moving object is a horizontal line at $x = 5\ \text{m}$ for $10\ \text{s}$. It is shown in the figure. a) What is the state of the object during…
The $x$-$t$ graph of a moving object is a horizontal line at $x = 5\ \text{m}$ for $10\ \text{s}$. It is shown in the figure.
- a) What is the state of the object during this time?
- b) What is its velocity? Justify your answer using the gradient of the graph.
Complete the following sentences about motion graphs: a) The gradient of a $x$-$t$ graph represents the $\dots$ b) The gradient of a $v$-$t$ graph represents the $\dots$…
Complete the following sentences about motion graphs:
- a) The gradient of a $x$-$t$ graph represents the $\dots$
- b) The gradient of a $v$-$t$ graph represents the $\dots$
- c) The area under a $v$-$t$ graph represents the distance $\dots$ travelled.
The $x$-$t$ graph of a pedestrian is a straight line passing through the points $(0, 2)$ and $(4, 10)$, with $x$ in metres and $t$ in seconds. It is shown in the figure.…
The $x$-$t$ graph of a pedestrian is a straight line passing through the points $(0, 2)$ and $(4, 10)$, with $x$ in metres and $t$ in seconds. It is shown in the figure.
- a) Calculate the gradient of the line and state what physical quantity it represents.
- b) Write the position equation for the pedestrian.
A classmate shows you two $x$-$t$ graphs: in the first, the position increases along a sloped straight line; in the second, the position increases along a curve that…
A classmate shows you two $x$-$t$ graphs: in the first, the position increases along a sloped straight line; in the second, the position increases along a curve that gets steeper and steeper. They are shown in the figure.
- a) Which one corresponds to uniform motion and which to accelerated motion?
- b) Explain what happens to the velocity in each case.
v-t graph: the gradient is the acceleration
Two cars on the M50 show $100\ \mathrm{km\,h^{-1}}$ on their dashboards: one is travelling in a straight line at a fixed velocity and the other has just put its foot down to overtake. How do we show in a graph the difference between maintaining velocity and gaining it second by second?
Since $a \neq 0$, the $v(t)$ graph is no longer horizontal: it is a sloping line, and the $x(t)$ graph curves.
The $v$-$t$ graph of a car is a straight line joining the points $(0, 0)$ and $(4, 12)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure. a)…
The $v$-$t$ graph of a car is a straight line joining the points $(0, 0)$ and $(4, 12)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure.
- a) Calculate the gradient of the line and state what physical quantity it represents.
- b) What is its value along with its unit?
The $v$-$t$ graph of a car is a straight line joining the points $(0, 20)$ and $(5, 0)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure. a) Is…
The $v$-$t$ graph of a car is a straight line joining the points $(0, 20)$ and $(5, 0)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure.
- a) Is the car accelerating or braking? Justify your answer.
- b) Calculate its acceleration from the gradient.
The $v$-$t$ graph of a car is a straight line joining the points $(0, 5)$ and $(6, 17)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure. a)…
The $v$-$t$ graph of a car is a straight line joining the points $(0, 5)$ and $(6, 17)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure.
- a) Calculate the acceleration.
- b) Write the velocity equation and calculate $v$ when $t = 3\ \text{s}$.
- c) Calculate the distance travelled in $6\ \text{s}$ by dividing the area under the graph into a rectangle and a triangle.
Signed area: displacement; absolute areas: distance travelled
If $v<0$, the area contributes a negative displacement. For the distance travelled, add the absolute values of the areas, separating the stages in which the sign of $v$ changes. For example, $v=4\ \mathrm{m\,s^{-1}}$ for $3\ \mathrm{s}$ and $v=-2\ \mathrm{m\,s^{-1}}$ for $2\ \mathrm{s}$ give $\Delta x=12-4=8\ \text{m}$, but $d=12+4=16\ \text{m}$. In the following examples the velocities are positive, which is why distance travelled and displacement coincide.
The $v$-$t$ graph of a cyclist is a horizontal line at $v = 6\ \text{m/s}$ from $t = 0$ to $t = 5\ \text{s}$. It is shown in the figure. a) What type of motion does it…
The $v$-$t$ graph of a cyclist is a horizontal line at $v = 6\ \text{m/s}$ from $t = 0$ to $t = 5\ \text{s}$. It is shown in the figure.
- a) What type of motion does it describe?
- b) Calculate the distance travelled using the area under the graph.
The $v$-$t$ graph of a car has three sections: from $(0, 0)$ to $(10, 20)$, from $(10, 20)$ to $(30, 20)$, and from $(30, 20)$ to $(40, 0)$, with $v$ in $\text{m/s}$ and…
The $v$-$t$ graph of a car has three sections: from $(0, 0)$ to $(10, 20)$, from $(10, 20)$ to $(30, 20)$, and from $(30, 20)$ to $(40, 0)$, with $v$ in $\text{m/s}$ and $t$ in seconds. It is shown in the figure.
- a) Calculate the acceleration for each section.
- b) Calculate the distance travelled in each section using the areas (triangles and rectangle) under the graph.
- c) What is the total distance?
The $v$-$t$ graph of a cyclist has three straight sections connecting the points $(0, 0)$, $(5, 10)$, $(15, 10)$ and $(20, 0)$, with $v$ in $\text{m/s}$ and $t$ in…
The $v$-$t$ graph of a cyclist has three straight sections connecting the points $(0, 0)$, $(5, 10)$, $(15, 10)$ and $(20, 0)$, with $v$ in $\text{m/s}$ and $t$ in seconds.
- a) Describe in words what the cyclist does in each section.
- b) Calculate the total distance travelled using the areas under the graph.
The $v$-$t$ graph of a metro train between two stations is: it accelerates from $0$ to $15\ \text{m/s}$ in $30\ \text{s}$, maintains $15\ \text{m/s}$ for $60\ \text{s}$…
The $v$-$t$ graph of a metro train between two stations is: it accelerates from $0$ to $15\ \text{m/s}$ in $30\ \text{s}$, maintains $15\ \text{m/s}$ for $60\ \text{s}$ and brakes to a stop at $15\ \text{s}$. It is shown in the figure.
- a) Calculate the acceleration for each section.
- b) Calculate the distance of each section and the total distance between the stations.
- c) Calculate the average speed for the journey, rounded to one decimal place.
The $v$-$t$ graph of an object has two sections: a straight line from $(0, 0)$ to $(4, 8)$ and a horizontal line at $v = 8\ \text{m/s}$ from $t = 4\ \text{s}$ to…
The $v$-$t$ graph of an object has two sections: a straight line from $(0, 0)$ to $(4, 8)$ and a horizontal line at $v = 8\ \text{m/s}$ from $t = 4\ \text{s}$ to $t = 10\ \text{s}$, with $v$ in $\text{m/s}$.
- a) Calculate the distance travelled in each section.
- b) Calculate the position at $t = 2\ \text{s}$, $t = 4\ \text{s}$ and $t = 10\ \text{s}$ (take the origin as the initial position).
- c) Using these values, describe the shape of the $x$-$t$ graph: which section is curved and which section is straight? Justify your answer.
a-t graph: the area is the change in velocity
An Irish Rail train sets off with a constant acceleration of $0.8\ \mathrm{m\,s^{-2}}$ for $20\ \mathrm{s}$ and then the acceleration drops to zero. How do we work out the final velocity reached from the drawing of its acceleration against time?
The $a$-$t$ graph of a moving object is a horizontal line at $a = 2\ \text{m/s}^2$ from $t = 0$ to $t = 6\ \text{s}$, as shown in the figure. If the object starts from…
The $a$-$t$ graph of a moving object is a horizontal line at $a = 2\ \text{m/s}^2$ from $t = 0$ to $t = 6\ \text{s}$, as shown in the figure.
If the object starts from rest, calculate its velocity after $6\ \text{s}$ using the area under the $a$-$t$ graph.
The $a$-$t$ graph of an object starting from rest is: $a = 3\ \text{m/s}^2$ from $t = 0$ to $t = 4\ \text{s}$, and $a = 0$ from $t = 4\ \text{s}$ to $t = 10\ \text{s}$.…
The $a$-$t$ graph of an object starting from rest is: $a = 3\ \text{m/s}^2$ from $t = 0$ to $t = 4\ \text{s}$, and $a = 0$ from $t = 4\ \text{s}$ to $t = 10\ \text{s}$. It is shown in the figure.
- a) Calculate the velocity at $4\ \text{s}$ using the area under the $a$-$t$ graph.
- b) What is its velocity at $10\ \text{s}$? Justify your answer.
- c) Draw the corresponding $v$-$t$ graph in your notebook.
You can do it on paper and send a photo with your answer.
An object starts from rest. Its $a$-$t$ graph is: $a = 4\ \text{m/s}^2$ from $t = 0$ to $t = 5\ \text{s}$, and $a = -2\ \text{m/s}^2$ from $t = 5\ \text{s}$ to…
An object starts from rest. Its $a$-$t$ graph is: $a = 4\ \text{m/s}^2$ from $t = 0$ to $t = 5\ \text{s}$, and $a = -2\ \text{m/s}^2$ from $t = 5\ \text{s}$ to $t = 15\ \text{s}$. It is shown in the figure.
- a) Calculate the maximum velocity it reaches and at what time.
- b) Calculate the velocity at $15\ \text{s}$.
- c) Draw the $v$-$t$ graph in your notebook and calculate the total distance travelled using its area.
- d) Describe the complete motion in words.
You can do it on paper and send a photo with your answer.
Combined stages: rest, constant velocity and constant acceleration on one graph
The $x$-$t$ graph of a walking trip has three straight sections: from $(0, 0)$ to $(10, 50)$, from $(10, 50)$ to $(15, 50)$, and from $(15, 50)$ to $(25, 0)$, with $x$…
The $x$-$t$ graph of a walking trip has three straight sections: from $(0, 0)$ to $(10, 50)$, from $(10, 50)$ to $(15, 50)$, and from $(15, 50)$ to $(25, 0)$, with $x$ in metres and $t$ in seconds. It is shown in the figure.
- a) Calculate the speed for each section.
- b) Interpret each section: what are the walkers doing in each one?
- c) How long does the entire trip last?
The $x$-$t$ graph of an object is a straight line connecting the points $(0, 50)$ and $(10, 0)$, with $x$ in metres and $t$ in seconds. It is shown in the figure. a)…
The $x$-$t$ graph of an object is a straight line connecting the points $(0, 50)$ and $(10, 0)$, with $x$ in metres and $t$ in seconds. It is shown in the figure.
- a) Write its position equation.
- b) Explain what the initial position and the sign of the gradient mean.
- c) Calculate the position when $t = 14\ \text{s}$ and explain the physical meaning of it being negative.
- d) At what time is it at $x = -50\ \text{m}$?
The $x$-$t$ graph of a walk is: a straight line from $(0, 0)$ to $(4, 40)$ and another from $(4, 40)$ to $(8, 0)$, with $x$ in metres and $t$ in seconds. It is shown in…
The $x$-$t$ graph of a walk is: a straight line from $(0, 0)$ to $(4, 40)$ and another from $(4, 40)$ to $(8, 0)$, with $x$ in metres and $t$ in seconds. It is shown in the figure.
- a) Calculate the velocity for each section.
- b) Calculate the total distance travelled and the total displacement.
- c) Calculate the average velocity (displacement divided by time) and the average speed (distance divided by time).
- d) Explain why one of them comes out as zero and the other does not.
A classmate draws a $x$-$t$ graph in which one section is a vertical line and claims that it represents an instantaneous change in position. a) Explain why a $x$-$t$…
A classmate draws a $x$-$t$ graph in which one section is a vertical line and claims that it represents an instantaneous change in position.
- a) Explain why a $x$-$t$ graph cannot have a vertical section: what would this imply about the position of the object at a single instant and about its velocity?
- b) For the same reason, explain whether the $x$-$t$ graph can "go backwards" to the left on the time axis.
- c) Draw a correct $x$-$t$ graph in your notebook for this situation: a person leaves home, stops for a while to talk to a neighbour, and returns home. Justify the shape of each section.
You can do it on paper and send a photo with your answer.
Working out the equation from data or from a graph
Two straight-line graphs meet where their equations give the same $x$ at the same $t$. For example, if $x_A = 3t$ and $x_B = 12 + t$, set $3t = 12 + t$, so $t = 6\ \mathrm{s}$ and $x = 18\ \mathrm{m}$: that point is where the two objects are at the same place at the same time.
Measuring the position of a laboratory trolley gives these data: at $t = 0\ \text{s}$, $x = 3\ \text{m}$; at $t = 1\ \text{s}$, $x = 5\ \text{m}$; at $t = 2\ \text{s}$,…
Measuring the position of a laboratory trolley gives these data: at $t = 0\ \text{s}$, $x = 3\ \text{m}$; at $t = 1\ \text{s}$, $x = 5\ \text{m}$; at $t = 2\ \text{s}$, $x = 7\ \text{m}$; at $t = 3\ \text{s}$, $x = 9\ \text{m}$.
- a) Plot the points on a $x$-$t$ graph in your notebook and check that they lie on a straight line.
- b) Deduce the position equation for the trolley.
- c) Predict its position when $t = 10\ \text{s}$.
You can do it on paper and send a photo with your answer.
The position of a moving object, in SI units, is $x = 10 - 3 \times t$. a) Calculate its position at $t = 0\ \text{s}$, $t = 1\ \text{s}$ and $t = 2\ \text{s}$. b)…
The position of a moving object, in SI units, is $x = 10 - 3 \times t$.
- a) Calculate its position at $t = 0\ \text{s}$, $t = 1\ \text{s}$ and $t = 2\ \text{s}$.
- b) Describe the $x$-$t$ graph: is it sloping upwards or downwards? What does the negative gradient indicate?
- c) Calculate the time at which it passes through the origin, rounding to one decimal place.
In a joint $x$-$t$ graph, object A follows the straight line $x_A = 4 \times t$ and object B follows the straight line $x_B = 20 + t$, in International System units. a)…
In a joint $x$-$t$ graph, object A follows the straight line $x_A = 4 \times t$ and object B follows the straight line $x_B = 20 + t$, in International System units.
- a) Draw the two straight lines in your notebook.
- b) What does the point where they intersect mean?
- c) Calculate the time and position of intersection, rounded to one decimal place.
You can do it on paper and send a photo with your answer.
Measuring the position of a trolley going down an inclined plane gives: at $t = 0\ \text{s}$, $x = 0\ \text{m}$; at $t = 1\ \text{s}$, $x = 1\ \text{m}$; at…
Measuring the position of a trolley going down an inclined plane gives: at $t = 0\ \text{s}$, $x = 0\ \text{m}$; at $t = 1\ \text{s}$, $x = 1\ \text{m}$; at $t = 2\ \text{s}$, $x = 4\ \text{m}$; at $t = 3\ \text{s}$, $x = 9\ \text{m}$.
- a) Verify that the data satisfy the relation $x = t^2$ and, by comparing it with $x = \frac{1}{2} a \times t^2$, deduce the acceleration of the trolley.
- b) Predict its position when $t = 5\ \text{s}$.
- c) Calculate how far it moves in each second ($0$-$1\ \text{s}$, $1$-$2\ \text{s}$, $2$-$3\ \text{s}$) and explain, from these values, why the $x$-$t$ graph is a curve and not a straight line.
Investigating with data and estimating uncertainty
Put forward the hypothesis "the trolley keeps a constant velocity". Film a slow movement on a stable table, with a visible scale and a fixed camera perpendicular to the path. Share out the tasks of measuring, recording and checking; do not film faces or publish personal data. You can also export positions from a simulation, identifying them as simulated data. In the lab you could instead use a ticker-timer or light gates and a data logger.
In a spreadsheet, put $t$ in column A and $x$ in column B; in C3 type =(B3-B2)/(A3-A2) and copy it downwards. Plot the x-t points, draw a line of best fit and check the differences between the measurements and the prediction. State the units, resolution, repetitions and possible systematic errors. The relative uncertainty of $v=(0.29\pm0.02)\ \mathrm{m\,s^{-1}}$ is approximately $0.02/0.29\times100=7\%$; it is not a known true error.
Some key ideas for handling data. A random error varies unpredictably from one measurement to the next (for example, reaction time with a stopwatch); repeating and averaging reduces it. A systematic error shifts every reading the same way (for example, a wrongly set zero); repeating does not remove it. Accuracy is how close a result is to the true value; precision is how close repeated readings are to each other, so you can be precise but not accurate. Give answers to a sensible number of significant figures, no more than your least precise measurement allows: $0.29\ \mathrm{m\,s^{-1}}$ has 2 significant figures, so do not quote $0.2933\ \mathrm{m\,s^{-1}}$. A line of best fit is drawn so that the points are spread evenly above and below it; its gradient gives the velocity on an $x$-$t$ graph, and a point far from it is a possible anomalous value to investigate.
Check your interpretation against a source identified by author, date and procedure. Present the data, the conclusion and the limitations; a discordant point is investigated, not deleted to improve the fit.
Now test the model and compare it with your data:
For the free-fall report (DIFICIL-09): time 5 drops from a fixed height $h$, find the mean time $\bar{t}$ and its uncertainty (half the range), then use $h = \frac12 g t^2$, so $g = 2h/\bar{t}^2$, and compare with $9.8\ \mathrm{m\,s^{-2}}$.
Unit challenge. Design a kinematics report integrating motions from your daily environment: 1. Free fall: Measure a fixed height ($h \approx 2.00 \pm 0.01\text{ m}$) and…
Unit challenge. Design a kinematics report integrating motions from your daily environment:
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Free fall: Measure a fixed height ($h \approx 2.00 \pm 0.01\text{ m}$) and time $5$ drops of a small object. Tabulate the times, find the mean and uncertainty ($\bar{t} \pm \Delta t$), experimentally calculate the value of $g$ using $h = \frac{1}{2}gt^2$, and plot the $y-t$ graph predicted by the model $y = h - \frac{1}{2}gt^2$ with your value of $g$.
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UFM and braking (UAM): Measure on Google Maps the distance of a journey you usually make by bike or scooter. Model an intermediate section at constant speed $v$ (UFM) and a final deceleration to a complete stop with acceleration $a$ (UAM). Write their equations of motion $x(t)$ and $v(t)$.
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Rotation (UCM): For the wheels ($R = 0.32\text{ m}$) spinning at that speed $v$, determine the angular velocity $\omega$, the period $T$, and the centripetal acceleration $a_c$.
Present the results in a short report with your data, calculations, and graphs.
Evaluation criteria:
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Rigor in taking home measurements, estimating uncertainty, and plotting graphs.
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Correctness in formulating the equations and SI units for UFM, UAM, free fall, and UCM.
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Critical analysis of possible sources of error and clarity in the conclusions.
Back to the beginning: on a $v$-$t$ graph, walking to school at a steady pace is drawn as a horizontal line, speeding up for the bus as a rising straight line and slowing down at the school gate as a falling straight line until it touches the time axis ($v=0$).