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Rates of Reactions, Materials and Living Systems · Rates of chemical reactions

Factors affecting reaction rate

A rusty gate in Galway takes years to fall apart, but a firework burns out in seconds. Both are chemical reactions. Why are some reactions slow and others fast, and how can we speed one up or slow another down? By the end of this page you will be able to explain it using particles and collisions.

Rate and collisions

The rate of reaction tells you how fast reactants are used up or products are formed. A fast reaction finishes in a short time. A slow reaction takes a long time.

For two particles to react they must collide. Not every collision works. The particles must hit each other with enough energy to break bonds. The minimum energy needed is called the activation energy.

So there are two ideas to remember:

  • more collisions per second means a faster reaction (higher frequency of collisions);

  • collisions with more energy are more likely to be successful.

Every factor on this page changes one or both of these.

We can measure the rate in two common ways:

$$\text{rate} = \frac{1}{\text{time}} \qquad\text{or}\qquad \text{average rate} = \frac{\text{change in amount of product}}{\text{time taken}}$$

The first is used when you time how long something takes to finish (for example, a mark disappearing). The second is used when you collect a gas. A shorter time means a bigger rate.

Practice★☆☆Not started
Name four factors that can change the rate of a chemical reaction. For each factor, state whether increasing it (or adding it) normally makes a reaction faster or slower.

Name four factors that can change the rate of a chemical reaction. For each factor, state whether increasing it (or adding it) normally makes a reaction faster or slower.

Solve

Concentration and surface area

Concentration

Concentration is how much solute is dissolved in a given volume, for example in $\text{mol/dm}^3$. In a more concentrated acid there are more acid particles in the same space. Particles are closer together, so they collide more often. More collisions per second means a faster reaction.

Look at the results of a magnesium and acid experiment:

Concentration ($\text{mol/dm}^3$) Time for magnesium to disappear (s)
0.5 120
1.0 60
2.0 30

Doubling the concentration halves the time, so it doubles the rate. This pattern (the rate is proportional to the concentration) is true for many simple reactions, but not all.

Surface area

Only particles at the surface of a solid can be hit by the particles in the liquid or gas. If you break a solid into smaller pieces, you expose more surface. More of the solid is in contact with the other reactant, so there are more collisions per second.

A large lump of solid with a small exposed surface compared with the same solid crushed into many small pieces with a large exposed surface One large lump Small surface area Many small pieces Large surface area

A marble chip (calcium carbonate) reacts slowly with acid, but the same mass of marble powder reacts much faster. The total mass is the same, but the powder has a far larger surface area.

Practice★☆☆Not started
A student in a school in Galway adds a whole marble chip (calcium carbonate) to dilute hydrochloric acid in one beaker. In a second beaker she adds the same mass of…

A student in a school in Galway adds a whole marble chip (calcium carbonate) to dilute hydrochloric acid in one beaker. In a second beaker she adds the same mass of marble powder to the same volume of the same acid at the same temperature.

  1. a) In which beaker will the reaction be faster?
  1. b) Explain your answer using the idea of surface area.
Solve
Practice★★☆Not started
A student in Cork measures the time taken for a piece of magnesium ribbon to disappear completely in $50\ \text{cm}^3$ of hydrochloric acid at different concentrations.…

A student in Cork measures the time taken for a piece of magnesium ribbon to disappear completely in $50\ \text{cm}^3$ of hydrochloric acid at different concentrations. The temperature is kept constant.

Concentration of acid ($\text{mol/dm}^3$) Time (s)
0.5 160
1.0 80
2.0 40
  1. a) State the relationship between concentration and the time taken.
  1. b) Predict the time for a concentration of $4.0\ \text{mol/dm}^3$.
  1. c) Explain, using particles and collisions, why a higher concentration gives a faster reaction.
Solve

Temperature

Think of food in a fridge and food left on the counter. Cold slows down the chemical reactions that make food go off.

When you heat a mixture, the particles gain kinetic energy and move faster. This has two effects:

  1. They collide more often.

  2. A greater fraction of collisions has energy equal to or above the activation energy, so more collisions are successful.

The second effect is the bigger one. That is why a small rise in temperature can make a big difference.

A common investigation uses sodium thiosulfate and acid. A cloudy yellow precipitate of sulfur forms, and you time how long it takes for a cross under the flask to disappear.

Temperature (°C) Time (s) Rate $= \dfrac{1}{\text{time}}$ ($\text{s}^{-1}$)
20 80 0.0125
30 40 0.025
40 20 0.05

Each rise of 10 °C halves the time. As a rough rule, many reactions double in rate for every 10 °C rise.

Practice★★☆Not started
Sodium thiosulfate solution reacts with acid to form a cloudy yellow precipitate of sulfur. A student places the flask over a cross marked on paper and times how long it…

Sodium thiosulfate solution reacts with acid to form a cloudy yellow precipitate of sulfur. A student places the flask over a cross marked on paper and times how long it takes for the cross to disappear. The results are:

Temperature (°C) Time for cross to disappear (s)
15 96
25 48
35 24
45 12
  1. a) What is the effect of increasing the temperature by $10\ °\text{C}$ on the time taken?
  1. b) Calculate the rate as $\dfrac{1}{\text{time}}$ in $\text{s}^{-1}$ at $25\ °\text{C}$ and at $45\ °\text{C}$.
  1. c) Explain why particles react faster at a higher temperature.
Solve

Catalysts

A catalyst is a substance that speeds up a chemical reaction but is not used up in it. It is chemically the same at the end as at the start.

A catalyst provides an alternative pathway with a lower activation energy. More collisions now have enough energy to react, so the rate goes up. The temperature does not change.

Energy profile showing a high activation energy without a catalyst and a lower activation energy with a catalyst Energy Progress of reaction Without catalyst With catalyst Ea Ea Reactants Products Ea = activation energy

Examples:

  • manganese(IV) oxide, $\text{MnO}_2$, speeds up the breakdown of hydrogen peroxide;

  • the catalytic converter in a car uses metals such as platinum to turn harmful exhaust gases into less harmful ones;

  • enzymes are biological catalysts, such as the amylase in your saliva.

Hydrogen peroxide decomposes slowly:

$$\text{hydrogen peroxide} \rightarrow \text{water} + \text{oxygen}$$

With $\text{MnO}_2$ it fizzes quickly. The $\text{MnO}_2$ can be filtered off, dried and weighed. Its mass is unchanged, which shows it was not used up. The oxygen relights a glowing splint.

Practice★☆☆Not started
Explain in your own words what a catalyst is. Does a catalyst get used up in the reaction? Give one example of a catalyst used in everyday life or in industry.

Explain in your own words what a catalyst is. Does a catalyst get used up in the reaction? Give one example of a catalyst used in everyday life or in industry.

Solve
Practice★★☆Not started
Hydrogen peroxide, $\text{H}2\text{O}2$, decomposes slowly into water and oxygen. When a small amount of manganese(IV) oxide, $\text{MnO}2$, is added, bubbles of gas…

Hydrogen peroxide, $\text{H}_2\text{O}_2$, decomposes slowly into water and oxygen. When a small amount of manganese(IV) oxide, $\text{MnO}_2$, is added, bubbles of gas form rapidly. After the reaction, the $\text{MnO}_2$ is filtered off, dried and found to have the same mass as at the start.

  1. a) Write a word equation for the decomposition.
  1. b) Name the role of $\text{MnO}_2$ and explain how the mass result supports your answer.
  1. c) Describe a test to identify the gas produced.
Solve

Following a reaction over time

When a reaction produces a gas, you can collect it in a gas syringe and record the volume at regular times. Plotting volume against time gives a curve.

Time (s) Volume of gas ($\text{cm}^3$)
0 0
20 24
40 36
60 42
80 44
100 44

The curve is steepest at the start and then flattens:

  • Steep at the start: reactants are at their highest concentration, so collisions are most frequent and the rate is greatest.

  • Getting less steep: reactants are being used up, so collisions become less frequent and the rate falls.

  • Flat: one reactant has been completely used up. The reaction has stopped, and no more product forms.

The average rate between two times is the change in volume divided by the change in time.

When a metal reacts with an acid, the products are a salt and hydrogen gas:

$$\text{metal} + \text{acid} \rightarrow \text{salt} + \text{hydrogen}$$

For example, zinc + sulfuric acid → zinc sulfate + hydrogen, or $\text{Zn} + \text{H}_2\text{SO}_4 \rightarrow \text{ZnSO}_4 + \text{H}_2$. The equation is balanced because each side has 1 Zn, 2 H, 1 S and 4 O. Test for hydrogen: a lighted splint makes a squeaky pop.

A final volume that is the same in two experiments means the same amount of limiting reactant was used (the limiting reactant is the one that runs out first, so it decides how much product can form). Faster conditions (higher temperature, more concentrated acid, powder) change how quickly you get there, not how much gas you finally get. A smaller amount of the limiting reactant, for example a more dilute acid that runs out, gives a smaller final volume.

Practice★★★Not started
A student investigates the reaction between calcium carbonate and excess hydrochloric acid by measuring the volume of carbon dioxide collected in a gas syringe. | Time…

A student investigates the reaction between calcium carbonate and excess hydrochloric acid by measuring the volume of carbon dioxide collected in a gas syringe.

Time (s) Volume of $\text{CO}_2$ ($\text{cm}^3$)
0 0
30 30
60 50
90 62
120 68
150 70
180 70
  1. a) Calculate the average rate of reaction (in $\text{cm}^3/\text{s}$) during the first $30\ \text{s}$ and between $90\ \text{s}$ and $120\ \text{s}$.
  1. b) Explain why the rate decreases as the reaction proceeds.
  1. c) Explain why the volume stops changing after $150\ \text{s}$.
  1. d) The experiment is repeated with the same mass of calcium carbonate but using powder instead of chips. Sketch in words how the curve would differ and state what would be the final volume. Justify your answer.
Solve
Practice★★★Not started
A factory in Cork Harbour uses a solid catalyst in the form of a fine mesh rather than in large lumps, and operates the reaction at a temperature of $450\ °\text{C}$…

A factory in Cork Harbour uses a solid catalyst in the form of a fine mesh rather than in large lumps, and operates the reaction at a temperature of $450\ °\text{C}$ rather than at room temperature.

  1. a) Explain why a fine mesh of catalyst is more effective than large lumps.
  1. b) Explain, using the idea of activation energy, how a catalyst increases the rate without being used up.
  1. c) Suggest one reason why a company might choose not to raise the temperature much further, even though this would increase the rate.
Solve
Practice★★★Not started
Two experiments are carried out with $1.0\ \text{g}$ of zinc and excess dilute sulfuric acid. In experiment A the acid concentration is $1.0\ \text{mol/dm}^3$ at…

Two experiments are carried out with $1.0\ \text{g}$ of zinc and excess dilute sulfuric acid. In experiment A the acid concentration is $1.0\ \text{mol/dm}^3$ at $20\ °\text{C}$. In experiment B the acid concentration is $1.0\ \text{mol/dm}^3$ at $40\ °\text{C}$.

  1. a) Name the gas produced and write a balanced chemical equation.
  1. b) Which experiment finishes first? Explain using collision theory, mentioning both the frequency and the energy of collisions.
  1. c) Both experiments produce the same total volume of gas. Explain why.
  1. d) Experiment C uses $1.0\ \text{g}$ of zinc with $0.5\ \text{mol/dm}^3$ acid at $20\ °\text{C}$ and the same volume of acid, still in excess. Predict how the initial rate compares with A and justify.
Solve

Summary

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