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Materials and manufacturing · Internal structure of materials

Internal structure and properties

No property of a material is a coincidence: a metal conducts electricity and a ceramic does not, and diamond is the hardest known material while graphite is used as a lubricant, even though both are pure carbon. The reason always lies in how their atoms are bonded and arranged.

Before you start, make sure you know: Classification of materials (1st Bachillerato)
Before you start, make sure you know: The properties of materials (1st ESO)

The three atomic bonds

Every macroscopic property of an engineering material (conductivity, hardness, melting point, brittleness) originates in the type of bond between its atoms.

Three atomic lattices: ionic (alternating ions of opposite charge), covalent (atoms joined by shared pairs of electrons) and metallic (cations surrounded by a sea of free electrons). ionic covalent metallic ++ ++ ++ ++ −− −− −− −− +++ +++ +++ fixed ions hard, brittle does not conduct e⁻ pairs highly variable diamond ↔ polymer sea of e⁻ ductile conducts well
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Explain what the three main types of atomic bonding (ionic, covalent and metallic) consist of and give a representative material example for each, indicating a property…

Explain what the three main types of atomic bonding (ionic, covalent and metallic) consist of and give a representative material example for each, indicating a property of that material that is explained by its bonding.

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Copper conducts electric current and polyethylene does not. Explain this difference using the "sea of electrons" model of metallic bonding and the structure of polymers.

Copper conducts electric current and polyethylene does not. Explain this difference using the "sea of electrons" model of metallic bonding and the structure of polymers.

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Predict, reasoning from the type of bonding, the behaviour of these three materials: common salt (NaCl), copper (Cu) and quartz (SiO₂). For each one, state whether you…

Predict, reasoning from the type of bonding, the behaviour of these three materials: common salt (NaCl), copper (Cu) and quartz (SiO₂). For each one, state whether you expect it to conduct electric current in the solid state, whether it will have a high or low melting point, and whether it will be brittle or ductile.

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Crystal lattices of metals

A metal is not a disordered heap of atoms: it is organised into a crystal lattice that repeats in all three directions of space.

Unit cells of the body-centred cubic (BCC) lattice, with one atom at the centre, and the face-centred cubic (FCC) lattice, with one atom at the centre of each face. BCC (α-iron) FCC (aluminium, copper) centre
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The figure shows the unit cell of a crystalline metal: there are atoms at the eight vertices of the cube and an additional atom inside it. State the name of this crystal…

The figure shows the unit cell of a crystalline metal: there are atoms at the eight vertices of the cube and an additional atom inside it. State the name of this crystal lattice and explain, based on it, why metals are usually dense and deformable.

? lattice name unit cell of a metal (for example, iron at room temperature)
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Explain using the crystal lattice model why a metal can be rolled into thin sheets without breaking while an ionic crystal (such as salt) shatters when struck: what…

Explain using the crystal lattice model why a metal can be rolled into thin sheets without breaking while an ionic crystal (such as salt) shatters when struck: what happens to the atomic planes and the charges in each case?

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Qualitatively compare body-centred cubic (BCC) and face-centred cubic (FCC) lattices: how many atoms each atom touches (coordination number) and which typical metals…

Qualitatively compare body-centred cubic (BCC) and face-centred cubic (FCC) lattices: how many atoms each atom touches (coordination number) and which typical metals crystallise in each (iron at room temperature versus aluminium or copper).

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Crystalline versus amorphous: the case of carbon and silica

Two materials with the same chemical composition can behave in completely different ways if their internal structure is different.

Diamond and graphite, both pure carbon: on the left, the diamond cell, in which each carbon atom is bonded to four neighbours in a tetrahedron forming a rigid three-dimensional covalent lattice; on the right, graphite, with flat layers of carbon hexagons stacked on top of each other, held together by weak forces, so that they can slide. Diamond three-dimensional covalent lattice each C bonded to 4 C (tetrahedron) rigid, ordered lattice: hardest natural material Graphite flat stacked layers the layers slide bonds covalent strong forces weak weak bond between layers: lubricant and pencil leads
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Explain the difference in internal structure between a thermoplastic polymer (independent chains) and a thermosetting polymer (cross-linked chains), and reason why the…

Explain the difference in internal structure between a thermoplastic polymer (independent chains) and a thermosetting polymer (cross-linked chains), and reason why the former can be recycled by melting while the latter cannot.

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Diamond and graphite are both composed solely of carbon atoms, yet the former is the hardest natural material and the latter is used as a lubricant and in pencil leads.…

Diamond and graphite are both composed solely of carbon atoms, yet the former is the hardest natural material and the latter is used as a lubricant and in pencil leads. Explain this difference based on how the carbon atoms are bonded and arranged in each structure.

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A glass bottle and a quartz crystal have very similar chemical compositions (both silica-based), but glass is amorphous while quartz is crystalline. Explain what these…

A glass bottle and a quartz crystal have very similar chemical compositions (both silica-based), but glass is amorphous while quartz is crystalline. Explain what these two terms mean and reason why glass breaks into irregular fragments whereas quartz exhibits flat faces.

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Alloys: dislocations and hardening

Adding different atoms to a pure metallic lattice radically changes its mechanical behaviour.

Animation of slip by dislocation: in the pure metal the dislocation (purple atom) moves freely to the right; in the alloy, the atoms in the slip row move forward a little, slow down and shake, stuck between the large solute atoms. Then the cycle restarts. pure metal: easy slip alloy: different atoms slow down the slip
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Distinguish between a substitutional alloy and an interstitial alloy at the atomic level: what relative size the added atoms must have in each case, and a real example…

Distinguish between a substitutional alloy and an interstitial alloy at the atomic level: what relative size the added atoms must have in each case, and a real example of each type (bronze with tin versus steel with carbon).

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Steel is iron with up to $2\,\%$ carbon. Explain qualitatively what ferrite and cementite (iron carbide) are in its microstructure and reason why steel with a higher…

Steel is iron with up to $2\,\%$ carbon. Explain qualitatively what ferrite and cementite (iron carbide) are in its microstructure and reason why steel with a higher carbon content is harder but less weldable.

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For the manufacture of friction bushings subjected to load, a quality report shows that Cu-Sn bronze (10 wt% Sn) exhibits a significantly higher yield strength than…

For the manufacture of friction bushings subjected to load, a quality report shows that Cu-Sn bronze (10 wt% Sn) exhibits a significantly higher yield strength than annealed pure copper. An operator proposes replacing tin with zinc in the same proportion (Cu-Zn brass at 10 wt% Zn), claiming that the strengthening will be exactly the same because both are substitutional solid solutions.

  1. a) Given the atomic radii ($r_{\text{Cu}} = 128\ \text{pm}$, $r_{\text{Zn}} = 133\ \text{pm}$, $r_{\text{Sn}} = 151\ \text{pm}$), justify using crystal lattice distortion theory and elastic stress fields why the operator's claim is incorrect, predicting which of the two alloys will offer greater resistance to dislocation movement.
  2. b) Explain how the ductility and electrical conductivity of copper are affected when adding these solutes, relating both changes to electron scattering and the pinning of dislocation motion.
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Composites, semiconductors and degradation

Combining materials from different families, or slightly modifying a pure covalent material, opens up behaviours that no single simple material can offer on its own.

Energy band diagrams of an insulator (quartz), a semiconductor (doped silicon) and a conductor (copper): conductivity increases as the gap to the conduction band shrinks. energy insulator quartz semiconductor doped Si conductor copper conduction band valence band dopant level electron increasing conductivity
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Three covalent material wafers are analyzed to design a resistive temperature sensor over a range from 150 °C to 350 °C: diamond ($E_g \approx 5,5\ \text{eV}$), silicon…

Three covalent material wafers are analyzed to design a resistive temperature sensor over a range from 150 °C to 350 °C: diamond ($E_g \approx 5,5\ \text{eV}$), silicon ($E_g \approx 1,1\ \text{eV}$), and germanium ($E_g \approx 0,67\ \text{eV}$).

  1. a) A technician suggests using germanium doped with phosphorus ($10^{16}\ \text{atoms/cm}^3$). Interpret using the band model why, when raising the temperature above a certain threshold, the intrinsic carrier concentration exceeds that provided by the dopants (intrinsic regime), causing the conductivity to go out of control and invalidating the sensor calibration.
  2. b) Predict with reasoning which of the three base materials would offer the greatest stability against uncontrolled thermal generation of electron-hole pairs in this temperature range, and argue whether diamond would behave as a semiconductor or as an insulator at 350 °C considering its bandgap width.
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On a coastal pedestrian footbridge, structural carbon steel beams were joined using stainless steel bolts and aluminium alloy rivets. After two years of service, two…

On a coastal pedestrian footbridge, structural carbon steel beams were joined using stainless steel bolts and aluminium alloy rivets. After two years of service, two severe pathologies are observed: the aluminium rivets have disintegrated due to galvanic corrosion, while the steel beams show intense localized pitting at the points where the protective paint layer suffered scratches during assembly.

  1. a) Using the galvanic series of potentials and the surface area balance (anode/cathode area ratio), justify the rapid destruction of the aluminium rivets in contact with stainless steel in a saline atmosphere, explaining why their natural alumina ($\text{Al}_2\text{O}_3$) passivation layer was not sufficient to prevent the attack.
  2. b) Refute the suitability of the paint coating compared to hot-dip galvanizing (zinc coating). Justify electrochemically why a scratch in the paint accelerates localized corrosion of the base steel, whereas on galvanized sheet the steel remains protected even if the coating suffers a similar gouge.
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The structural frame for a lightweight rescue drone is being designed. It must maximize flight endurance, ensure stiffness against wind gusts, and absorb impacts in…

The structural frame for a lightweight rescue drone is being designed. It must maximize flight endurance, ensure stiffness against wind gusts, and absorb impacts in forced landings without catastrophic failure. Three candidate materials are presented:

  • Candidate A (Polyamide 66 with 30% short glass fibre): $\rho = 1,35\ \text{g/cm}^3$, $E = 8,5\ \text{GPa}$, Izod impact strength $= 11\ \text{kJ/m}^2$, low cost, recyclable by thermoforming.

  • Candidate B (Forged AZ91D magnesium alloy): $\rho = 1,81\ \text{g/cm}^3$, $E = 45\ \text{GPa}$, yield strength $\sigma_y = 160\ \text{MPa}$, fracture toughness $K_{1c} = 17\ \text{MPa}\cdot\text{m}^{1/2}$, medium cost, recyclable by casting.

  • Candidate C (Unidirectional continuous carbon fibre epoxy laminate / CFRP): $\rho = 1,55\ \text{g/cm}^3$, $E = 135\ \text{GPa}$ (in the longitudinal direction), brittle under transverse point impacts, very high cost, not thermally recyclable.

  1. a) Calculate the specific stiffness ($E/\rho$) of the three candidates and interpret which one best optimizes the ratio between structural stiffness and mass in flight.
  2. b) If the drone must operate in rocky environments with a high risk of accidental collision, justify which material you would select, reasoning the microstructural pros and cons of candidates B and C (ductility and plastic deformation versus elastic-brittle behaviour with delamination). Argue which priority criterion would force you to discard Candidate A despite its lower density and cost.
Solve

Back to the beginning: Diamond is extremely hard and graphite lubricates because the former arranges its carbon atoms in a rigid 3D covalent lattice, whereas the latter forms 2D layers that slide over one another; metals conduct because their electrons form a free sea, unlike in ceramics, where the ions are fixed in the lattice.

Summary

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