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Secondary 3 · Mathematics
Powers and roots · Roots

Operations with radicals

Before you start, make sure you know: Powers (Secondary Year 2 (first cycle))
Before you start, make sure you know: Operations with monomials (Secondary Year 2 (first cycle))

Wilkin wants to put up a guy wire to support a pole in the school yard. Using Pythagoras, he gets $\sqrt{20}$ meters. How many meters of wire does he buy? Before reaching for the calculator, learn to operate with radicals so you can always give the exact value. The rules are very similar to those in algebra.

Adding and subtracting radicals

You can only add like radicals (same index and same radicand). It works just like with letters: $2x + 5x = 7x$, and $2\sqrt{3} + 5\sqrt{3} = 7\sqrt{3}$.

Sum of like radicals versus unlike radicals, and the need to pull out factors before adding. 2√3 + 5√3 − √3 = 6√3 (like 2x + 5x − x = 6x) √3 + √2= ?? are not like radicals: it stays as is √12 + √27 = 2√3 + 3√3 = 5√3 pull out factors first
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We are going to simplify expressions by grouping like radicals. Imagine that $\sqrt{3}$ is like an "x" or an "apple". Carry out the following additions and subtractions:…

We are going to simplify expressions by grouping like radicals. Imagine that $\sqrt{3}$ is like an "x" or an "apple". Carry out the following additions and subtractions:

  1. $5\sqrt{2} + 3\sqrt{2} - 2\sqrt{2}$

  2. $7\sqrt[3]{5} - 2\sqrt[3]{5}$

  3. $4\sqrt{6} + \sqrt{6} - 8\sqrt{6}$

Solve
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To add and subtract radicals, they must be like radicals (same index and same radicand). Simplify the following radicals by expressing the numbers as products of prime…

To add and subtract radicals, they must be like radicals (same index and same radicand). Simplify the following radicals by expressing the numbers as products of prime factors, then calculate:

  1. a) $3\sqrt{8} - 5\sqrt{2} + \sqrt{50}$
  2. b) $\sqrt{12} + \sqrt{75} - \sqrt{27}$
  3. c) $2\sqrt[3]{16} - \sqrt[3]{54}$
Solve
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Fully simplify the following numerical expression. To do this, prime factorise the radicands, take factors out of the root and work with fractions. The final answer must…

Fully simplify the following numerical expression. To do this, prime factorise the radicands, take factors out of the root and work with fractions. The final answer must be expressed using a single irreducible radical.

$$ A = 2\sqrt{75} - \sqrt{\frac{147}{4}} + \frac{5}{2}\sqrt{12} - \sqrt{300} $$
Solve

Pulling factors out of a radical

To add radicals that don't look like they are like radicals, you have to pull factors out of the root. We break the radicand into prime factors, and every factor whose exponent is greater than or equal to the index comes out.

For example, $\sqrt{2^5} = \sqrt{2^4 \cdot 2} = 2^2\sqrt{2} = 4\sqrt{2}$. With index 3: $\sqrt[3]{2^4} = 2\sqrt[3]{2}$.

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Sometimes the numbers inside the root have factors left over that can come out. Extract all possible factors from the following radicals. $\sqrt{2^5}$ $\sqrt{3^3}$…

Sometimes the numbers inside the root have factors left over that can come out. Extract all possible factors from the following radicals.

  • $\sqrt{2^5}$

  • $\sqrt{3^3}$

  • $\sqrt{5^4}$

  • $\sqrt[3]{2^4}$

Solve
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Extract all possible factors from the following radicals. Take into account the index of the root and the exponents of the radicands. a) $\sqrt{2 \times 3^2 \times 5^5}$…

Extract all possible factors from the following radicals. Take into account the index of the root and the exponents of the radicands.

  1. a) $\sqrt{2 \times 3^2 \times 5^5}$
  2. b) $\sqrt[3]{81}$
  3. c) $\sqrt{12x^3 y^4}$
  4. d) $\sqrt[4]{32}$
Solve

Multiplying and dividing radicals

With the same index, the radicands are multiplied (or divided) inside a single root:

The area of a rectangle with sides $\sqrt{5}$ and $\sqrt{3}$ is $\sqrt{15}$ m²:

Rectangle with sides square root of 5 and square root of 3 whose area is square root of 15. √5 ≈ 2.24 √3 ≈ 1.73 √15 area = √5 · √3 = √15 ≈ 3.87 m² perimeter = 2√5 + 2√3 (it can't be combined further)

Radicals with different indices

They are rewritten with fractional exponents and reduced to a common index (the least common multiple of the indices): $\sqrt{2} \times \sqrt[3]{2} = 2^{1/2} \cdot 2^{1/3} = 2^{5/6} = \sqrt[6]{2^5}$.

It also works for powers of $x$: $\dfrac{\sqrt[4]{x^3}}{\sqrt[6]{x}} = \dfrac{x^{3/4}}{x^{1/6}} = x^{3/4 - 1/6} = x^{7/12} = \sqrt[12]{x^7}$.

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Use the property of the product of roots with the same index ($\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}$) to group these operations into a single root and,…

Use the property of the product of roots with the same index ($\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}$) to group these operations into a single root and, if possible, work out the exact final result:

  • $\sqrt{2} \times \sqrt{32}$

  • $\sqrt[3]{2} \times \sqrt[3]{4}$

  • $\sqrt{5} \times \sqrt{20}$

  • $\sqrt{3} \times \sqrt{27}$

Solve
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Carry out the following multiplications and divisions of radicals. Remember that they must have the same index to operate. If possible, simplify the final result by…

Carry out the following multiplications and divisions of radicals. Remember that they must have the same index to operate. If possible, simplify the final result by extracting factors from the root.

  1. a) $\sqrt{18} \times \sqrt{2}$
  2. b) $\sqrt[3]{4} \times \sqrt[3]{16}$
  3. c) $\frac{\sqrt{75}}{\sqrt{3}}$
  4. d) $\sqrt{2x} \times \sqrt{8x^3}$
Solve
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Perform the following operations, grouping the terms under a single root. Remember that to multiply or divide radicals with different indices, you must first convert…

Perform the following operations, grouping the terms under a single root. Remember that to multiply or divide radicals with different indices, you must first convert them to a common index (lowest common multiple of the indices).

  1. a) $ \sqrt{2} \times \sqrt[3]{4} \times \sqrt[6]{8} $
  1. b) $ \frac{\sqrt[4]{x^3}}{\sqrt[6]{x}} $
Solve

Root of a root and power of a root

It all makes sense with fractional exponents: $\sqrt{\sqrt[3]{a}} = \left(a^{\frac13}\right)^{\frac12} = a^{\frac16}$. Likewise, $a^{m/n} = \sqrt[n]{a^m}$: for example, $5^{3/4} = \sqrt[4]{5^3}$.

Square root of the cube root of 64: the indices are multiplied and the result is the sixth root of 64, which is 2. √ ( ∛64 ) =⁶√64 =2 2 · 3 = 6: the indices are multiplied (2⁶ = 64)
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When we have a root inside another root, we can simplify it by multiplying their indices ($\sqrt[n]{\sqrt[m]{a}} = \sqrt[n \times m]{a}$). Simplify the following…

When we have a root inside another root, we can simplify it by multiplying their indices ($\sqrt[n]{\sqrt[m]{a}} = \sqrt[n \times m]{a}$). Simplify the following expressions to a single root:

  • $\sqrt{\sqrt{81}}$

  • $\sqrt[3]{\sqrt{64}}$

  • $\sqrt{\sqrt[3]{x}}$

Solve
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Fractional powers are another way of writing radicals. Use this relationship to simplify the following expressions and give the final answer in radical form: a) Write…

Fractional powers are another way of writing radicals. Use this relationship to simplify the following expressions and give the final answer in radical form:

  1. a) Write $5^{3/4}$ in radical form.
  2. b) Write $\sqrt[5]{2^3}$ in index form.
  3. c) Calculate by first expressing as a power: $\sqrt[3]{\sqrt{64}}$
  4. d) Simplify: $\frac{\sqrt[4]{x^3}}{\sqrt{x}}$
Solve
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Apply the rules of radicals (root of a root and power of a root) to simplify the following expressions to a single irreducible radical: a) $\sqrt{\sqrt[3]{64}}$ b)…

Apply the rules of radicals (root of a root and power of a root) to simplify the following expressions to a single irreducible radical:

  1. a) $\sqrt{\sqrt[3]{64}}$
  2. b) $(\sqrt[3]{2})^6$
  3. c) $\sqrt{2 \times \sqrt{2}}$ (Hint: Move the first 2 inside the second square root)
Solve
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Express the result of the following operation as a single power with a fractional exponent. To do this, convert all radicals to powers, apply the index laws (product and…

Express the result of the following operation as a single power with a fractional exponent. To do this, convert all radicals to powers, apply the index laws (product and quotient of powers with the same base), and simplify the final exponent.

$$ \frac{\sqrt[4]{a^3 \times \sqrt{a}}}{\sqrt{a \times \sqrt[3]{a^2}}} $$
Solve

Radicals in problems

In geometry, the Pythagorean theorem and the area and volume formulas almost always give roots. The usual practice is to give the simplified exact value and, if asked, the approximate one.

For volumes: a cubic tank of $128\ \text{m}^3$ has edge $\sqrt[3]{128} = \sqrt[3]{2^7} = 4\sqrt[3]{2}$ m.

Radicals also appear when checking solutions. To see whether $x = 1 + \sqrt{5}$ satisfies $x^2 - 2x - 4 = 0$, you use $(1+\sqrt{5})^2 = 1 + 2\sqrt{5} + 5$ and then operate.

Roots with powers of 10

To take the root of a number in scientific notation, you split it into two roots: $\sqrt{a \cdot 10^n} = \sqrt{a} \cdot \sqrt{10^n}$. If $n$ is even, $\sqrt{10^n} = 10^{n/2}$. If $n$ is odd, it doesn't come out exact: first move a factor of 10 into the decimal part so the exponent becomes even.

If the result has to be given in another unit, it is converted at the end: $1.5 \cdot 10^{-5}$ m $= 1.5 \cdot 10^{-5} \cdot 10^{3}$ mm $= 1.5 \cdot 10^{-2}$ mm.

Back to the beginning: Wilkin gets $\sqrt{20} = 2\sqrt{5} \approx 4.47$ m, so he buys about 4.5 m of wire.

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We want to fence a square plot of land with a total surface area of $225 \text{ m}^2$. To find out how many meters of fencing we need, we must first calculate the length…

We want to fence a square plot of land with a total surface area of $225 \text{ m}^2$. To find out how many meters of fencing we need, we must first calculate the length of the side of the square.

  1. Find the length of the side ($l$) knowing that the area is $l^2 = 225$.

  2. Find the total perimeter of the plot.

Total area 225 m² l = ? l = ?
Solve
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You are going to buy a new television, and the dimensions are given in inches along the diagonal. The screen is rectangular, with a width of 40 cm and a height of 30 cm.…

You are going to buy a new television, and the dimensions are given in inches along the diagonal. The screen is rectangular, with a width of 40 cm and a height of 30 cm. Using the Pythagorean theorem ($h = \sqrt{a^2 + b^2}$), calculate the length of the screen's diagonal in centimeters.

Note: The result is an exact root.

h = √(a² + b²) a = 40 cm b = 30 cm h = ?
Solve
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Calculate the perimeter and area of a rectangular plot of land whose dimensions are given by radicals. The base measures $\sqrt{27}$ meters and the height $\sqrt{3}$…

Calculate the perimeter and area of a rectangular plot of land whose dimensions are given by radicals. The base measures $\sqrt{27}$ meters and the height $\sqrt{3}$ meters. Simplify the results as much as possible.

√27 m √3 m Area = ? Perimeter = ?
Solve
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We want to attach a guy wire to support a vertical post 4 meters high. The wire will be anchored to the ground at a distance of $\sqrt{20}$ meters from the base of the…

We want to attach a guy wire to support a vertical post 4 meters high. The wire will be anchored to the ground at a distance of $\sqrt{20}$ meters from the base of the post. Calculate the exact length of cable needed using the Pythagorean theorem. Express the answer as a simplified radical.

4 m √20 m Cable c = ?
Solve
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We have a cubic water tank. We know that its total volume is $128 \text{ m}^3$. Calculate the length of the edge of the tank. Express the answer as a simplified radical…

We have a cubic water tank. We know that its total volume is $128 \text{ m}^3$. Calculate the length of the edge of the tank. Express the answer as a simplified radical (by taking factors out of the root) and do not use decimals.

(Hint: Remember that the volume of a cube is $V = \text{arista}^3$)

edge = ? a a V = 128 m³
Solve
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An architectural firm has designed a decorative triangular piece for a facade. The piece is an isosceles triangle (two equal sides and one different side). We know that…

An architectural firm has designed a decorative triangular piece for a facade. The piece is an isosceles triangle (two equal sides and one different side).

We know that the two equal sides measure $\sqrt{45}$ meters each, and the base (the unequal side) measures $\sqrt{72}$ meters.

Using the Pythagorean theorem and the rules of radicals (taking factors out and simplifying), calculate the exact height ($h$) of the triangle. Express the answer as an integer or a fully simplified radical.

√72 / 2 m Base = √72 m √45 m √45 m h
Solve
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We have three water tanks with different cubic shapes. Tank A has a capacity of $2$ cubic meters. Tank B has an edge length that is exactly double that of Tank A. Tank C…

We have three water tanks with different cubic shapes.

  • Tank A has a capacity of $2$ cubic meters.

  • Tank B has an edge length that is exactly double that of Tank A.

  • Tank C has an edge length that is half that of Tank A.

  • Calculate the exact edge length of Tank A, expressing it as a radical.

  • Calculate the exact volume of Tank B and Tank C using laws of exponents and rules of radicals. Do not use decimals.

a/2 C a A V = 2 m³ 2a B
Solve
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Check whether the irrational number $\phi = 1 + \sqrt{5}$ is a solution to the quadratic equation: $$ x^2 - 2x - 4 = 0 $$ To do this, substitute $x$ with…

Check whether the irrational number $\phi = 1 + \sqrt{5}$ is a solution to the quadratic equation:

$$ x^2 - 2x - 4 = 0 $$

To do this, substitute $x$ with $(1 + \sqrt{5})$, expand the square of the binomial (algebraic identity) and collect like terms to see if the final result is zero.

Solve
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The volume of a giant sphere used in a planetarium is $500 \pi$ cubic meters. Given that the formula for the volume of a sphere is $V = \frac{4}{3}\pi r^3$: 1. Rearrange…

The volume of a giant sphere used in a planetarium is $500 \pi$ cubic meters.

Given that the formula for the volume of a sphere is $V = \frac{4}{3}\pi r^3$:

  1. Rearrange the formula to make the radius $r$ the subject in terms of the volume.

  2. Substitute the given volume and calculate the exact value of the radius, fully simplifying the radical (taking factors out of the cube root).

r V = 500π m³
Solve
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A bacterium is square in shape and has an area of $2.25 \times 10^{-10}$ square meters. Calculate the side length of the bacterium. Express the final answer in…

A bacterium is square in shape and has an area of $2.25 \times 10^{-10}$ square meters.

Calculate the side length of the bacterium. Express the final answer in scientific notation and in millimeters. (Remember that $\sqrt{a \times 10^n} = \sqrt{a} \times \sqrt{10^n}$).

Solve

Summary

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