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Interaction · Forces and pressure in fluids

Pressure and hydrostatic pressure

You can push a thumbtack into a bulletin board in your school hallway with no effort, but if you pressed your flat finger against the same board, however hard you pushed, it would not go in. The force from your hand can be exactly the same in both cases, measured with the same spring scale. The only thing that changes is the area over which that force is spread. That simple idea is what turns a moderate force into something capable of cutting, piercing or holding back a whole reservoir of water behind a dam.

What pressure is

Two blocks bear the same force of 200 N: the one with the small base exerts a greater pressure on the floor and the one with the large base exerts a smaller pressure. F = 200 N small A → large P F = 200 N large A → small P

With the same force, the smaller the area, the greater the pressure. That is why a thumbtack goes in easily and a flat finger against the board does not: in both cases the force can be identical, but the area it acts on changes by several orders of magnitude.

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A crate of books pushes against the floor with a force of $200\ \text{N}$ distributed over a base of $0.5\ \text{m}^2$, as shown in the figure. Calculate the pressure it…

A crate of books pushes against the floor with a force of $200\ \text{N}$ distributed over a base of $0.5\ \text{m}^2$, as shown in the figure.

F = 200 N S = 0.5 m² p = ?

Calculate the pressure it exerts on the floor, in pascals, using $p = \frac{F}{S}$.

Solve
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In what unit is pressure measured in the International System of Units? Write its equivalence in units of force and area, and state after which scientist it is named.

In what unit is pressure measured in the International System of Units? Write its equivalence in units of force and area, and state after which scientist it is named.

Solve
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The snow accumulated on a flat roof exerts a pressure of $600\ \text{Pa}$ over an area of $30\ \text{m}^2$. Calculate the total force supported by the roof.

The snow accumulated on a flat roof exerts a pressure of $600\ \text{Pa}$ over an area of $30\ \text{m}^2$. Calculate the total force supported by the roof.

Solve
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A workshop punch pushes against a metal sheet with a force of $20\ \text{N}$ and its tip has a surface area of $4\ \text{mm}^2$. a) Express the surface area of the tip…

A workshop punch pushes against a metal sheet with a force of $20\ \text{N}$ and its tip has a surface area of $4\ \text{mm}^2$.

  1. a) Express the surface area of the tip in $\text{m}^2$.
  2. b) Calculate the pressure exerted by the punch on the metal sheet.
Solve

The role of the contact area

A hiker of the same weight, 600 N, standing on snow: in boots, with a small area, she sinks in; on skis, with a much larger area, she receives less pressure and does not sink. F = 600 N In boots A₁ = 0.02 m² p₁ = 30,000 Pa small A: sinks in hollow in the snow F = 600 N On skis A₂ = 0.6 m² p₂ = 1,000 Pa larger A: does not sink ski on the snow Same weight F: 30 times more A → 30 times less P
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A hiker walks through freshly fallen snow in boots and sinks up to her ankle; the next day she goes through the same place on skis and leaves hardly a footprint, as…

A hiker walks through freshly fallen snow in boots and sinks up to her ankle; the next day she goes through the same place on skis and leaves hardly a footprint, as shown in the figure.

P boots P skis

If her weight is the same in both cases, explain using the concept of pressure why she does not sink when wearing skis.

Solve
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To cut a loaf of bread we use the sharp edge of the knife and not the back of the blade, even if we apply the same force with our hand. Explain what the contact area of…

To cut a loaf of bread we use the sharp edge of the knife and not the back of the blade, even if we apply the same force with our hand. Explain what the contact area of the sharp edge has to do with the pressure received by the bread.

Solve
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A skier of $60\ \text{kg}$ is standing on the snow. Take $g = 10\ \text{m/s}^2$. a) Calculate her weight. b) Wearing boots, she rests on two soles of…

A skier of $60\ \text{kg}$ is standing on the snow. Take $g = 10\ \text{m/s}^2$.

  1. a) Calculate her weight.
  2. b) Wearing boots, she rests on two soles of $25\ \text{cm} \times 10\ \text{cm}$ each. Calculate the pressure she exerts on the snow (be careful with unit conversions).
  3. c) Wearing skis, she rests on two skis of $1.5\ \text{m} \times 0.2\ \text{m}$ each. Calculate the pressure now.
  4. d) Compare the two results and explain why she does not sink when wearing skis.
Solve
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A manufacturer wants to design a snowboard so that a $70\ \text{kg}$ person does not exert a pressure greater than $2\,000\ \text{Pa}$ on the snow. Take…

A manufacturer wants to design a snowboard so that a $70\ \text{kg}$ person does not exert a pressure greater than $2\,000\ \text{Pa}$ on the snow. Take $g = 10\ \text{m/s}^2$.

  1. a) Calculate the person's weight.
  2. b) What is the minimum surface area the snowboard must have so as not to exceed that pressure?
  3. c) If the snowboard is $1.75\ \text{m}$ long, what minimum width must it have? Express the result in centimeters.
Solve

Pressure inside a liquid: hydrostatic pressure

If you pierce a plastic bottle of water at three different heights, say on a lab bench, the jet from the lowest hole shoots out with much more speed and range than the one from the highest: why does the liquid push harder at the bottom if the water is exactly the same?

Tank of water at rest with three points at depths h₁, h₂ and h₃ measured from the free surface. At each point, arrows show that the pressure acts in all directions and that it is greater the deeper the point is. On the right, a triangle shows that pressure increases in proportion to depth according to p = hρg. free surface of the liquid h₁ h₂ h₃ h₁: lower p h₂: medium p h₃: higher p P = P₀ + ρgh P grows with depth
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A swimming pool is $2\ \text{m}$ deep, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$. Calculate the pressure exerted by…

A swimming pool is $2\ \text{m}$ deep, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ h = 2 m p = ?

Calculate the pressure exerted by the water on the bottom using $p = d\times g\times h$.

Solve
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When swimming down to the bottom of a pool, you feel pressure in your ears, and the deeper you go, the more uncomfortable it becomes. Explain which quantity is changing…

When swimming down to the bottom of a pool, you feel pressure in your ears, and the deeper you go, the more uncomfortable it becomes. Explain which quantity is changing with depth and why.

Solve
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The water tank of a housing development is at the top of a tower, $12\ \text{m}$ above the faucet of a house, as shown in the figure. Given:…

The water tank of a housing development is at the top of a tower, $12\ \text{m}$ above the faucet of a house, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 9.8\ \text{m/s}^2$.

p₁ = ? p₂ = ? 12 m 3 m
  1. a) Calculate the pressure due to the column of water reaching the faucet.
  2. b) What will that pressure be at the faucet on the first floor, located $3\ \text{m}$ lower down?
Solve
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To what depth must you descend in the water of a swimming pool for the pressure due to the water to be $49\,000\ \text{Pa}$? First rearrange for depth in the expression…

To what depth must you descend in the water of a swimming pool for the pressure due to the water to be $49\,000\ \text{Pa}$? First rearrange for depth in the expression $p = d\times g\times h$. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 9.8\ \text{m/s}^2$.

Solve
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A dam holds back water in a reservoir with a maximum depth of $40\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take…

A dam holds back water in a reservoir with a maximum depth of $40\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ 40 m 10 m p(10 m) = ? p(40 m) = ?
  1. a) What pressure does the wall withstand at its base?
  2. b) What about at a depth of $10\ \text{m}$?
  3. c) With those two results, explain why dams are built much thicker at their base than at the top.
Solve
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A building's water tank is on the roof, $15\ \text{m}$ above a faucet on the third floor. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 9.8\ \text{m/s}^2$. a)…

A building's water tank is on the roof, $15\ \text{m}$ above a faucet on the third floor. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 9.8\ \text{m/s}^2$.

  1. a) Calculate the water pressure at that faucet.
  2. b) When closed, the faucet has a cross-sectional area of $1\ \text{cm}^2$: with what force does the water push against it?
  3. c) A neighbor on the first floor has their faucet $9\ \text{m}$ lower down: calculate the pressure at their faucet and explain the difference compared to the third floor.
Solve

Density: the other quantity in $\rho g h$

In $P = \rho g h$ the symbol $\rho$ is the density of the liquid. How do you find it for a liquid, or for a solid with an odd shape?

Total pressure and atmospheric pressure

When an object is submerged in a liquid open to the atmosphere, the pressure it bears is not only the hydrostatic pressure: you have to add the pressure of the air pushing on the free surface of the liquid.

A container of liquid open to the air: atmospheric pressure pushes down on the surface and the total pressure at depth h is P₀ plus ρgh. P₀ h P = P₀ + ρgh
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What is atmospheric pressure? Name the instrument used to measure it and write down its approximate value at sea level, in pascals.

What is atmospheric pressure? Name the instrument used to measure it and write down its approximate value at sea level, in pascals.

Solve
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A scuba diver dives at a depth of $10\ \text{m}$ in a lake, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take…

A scuba diver dives at a depth of $10\ \text{m}$ in a lake, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ atmospheric pressure 101 300 Pa 10 m p = ?
  1. a) Calculate the pressure due solely to the water above him.
  2. b) Calculate the total pressure he experiences, adding atmospheric pressure.
  3. c) How many times atmospheric pressure is that total pressure? Comment on the result.
Solve
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On the weather map, a low-pressure system has a pressure at its center of $990\ \text{hPa}$ and a high-pressure system, of $1\,030\ \text{hPa}$. a) Express both…

On the weather map, a low-pressure system has a pressure at its center of $990\ \text{hPa}$ and a high-pressure system, of $1\,030\ \text{hPa}$.

  1. a) Express both pressures in pascals (remember: $1\ \text{hPa} = 100\ \text{Pa}$).
  2. b) The normal value of atmospheric pressure at sea level is $1\,013\ \text{hPa}$: which of the two systems is closer to that value?
  3. c) Given that low-pressure systems usually bring clouds and rain and high-pressure systems bring settled weather, indicate in which of the two you would expect bad weather and give reasons for your answer.
Solve
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The atmosphere pushes down on your tabletop with a pressure of about $101\,300\ \text{Pa}$. The tabletop measures $1.2\ \text{m} \times 0.6\ \text{m}$. a) Calculate the…

The atmosphere pushes down on your tabletop with a pressure of about $101\,300\ \text{Pa}$. The tabletop measures $1.2\ \text{m} \times 0.6\ \text{m}$.

  1. a) Calculate the surface area of the tabletop.
  2. b) Calculate the force with which the atmosphere crushes it.
  3. c) If the force is so huge, why does the table not break or collapse? Think about the air underneath the tabletop.
Solve
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A scuba diver descends to a depth of $20\ \text{m}$ in the ocean. Data: $d_{mar} = 1\,025\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take $g = 10\ \text{m/s}^2$.…

A scuba diver descends to a depth of $20\ \text{m}$ in the ocean. Data: $d_{mar} = 1\,025\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take $g = 10\ \text{m/s}^2$.

  1. a) Calculate the pressure exerted by the water at that depth.
  2. b) Calculate the total pressure experienced by the diver, adding atmospheric pressure.
  3. c) How many times the atmospheric pressure is this total pressure?
  4. d) Using the previous result, explain why divers must plan their dives and control their ascent.
Solve
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In Torricelli's experiment, a glass tube is filled with mercury and inverted over a trough containing mercury: the column falls until it reaches a height of…

In Torricelli's experiment, a glass tube is filled with mercury and inverted over a trough containing mercury: the column falls until it reaches a height of $76\ \text{cm}$ above the surface of the trough, as shown in the figure. Data: $d_{Hg} = 13\,600\ \text{kg/m}^3$; take $g = 9.8\ \text{m/s}^2$.

d(Hg) = 13 600 kg/m³ vacuum 76 cm atmospheric pressure p = ?
  1. a) Calculate the pressure exerted by this mercury column on its base.
  2. b) Compare the result with the value of atmospheric pressure at sea level and explain what the experiment demonstrates and what is at the top of the tube.
  3. c) What height should the column be if the experiment were carried out with water instead of mercury?
Solve

Back to the start: If you push with a force of $30\ \text{N}$, the tip of your flat finger ($A \approx 1.5\ \text{cm}^2 = 1.5 \times 10^{-4}\ \text{m}^2$) exerts $200{,}000\ \text{Pa}$, whereas the point of the thumbtack ($A \approx 0.1\ \text{mm}^2 = 10^{-7}\ \text{m}^2$) concentrates that same force and produces $300{,}000{,}000\ \text{Pa}$: fifteen hundred times more pressure with the same effort!

Summary

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