Interpreting x-t and v-t graphs
Picture your morning: you walk to the school bus stop at a steady pace, speed up when you realize you are late, and slow down as you reach the stop. That story can be drawn without writing a single word, using a graph. And from a graph you can tell at a glance what the motion is in each stage: constant speed, speeding up, slowing down or rest.
The x-t graph: position and slope
We measure the position of a ball in a corridor: at $0\ \text{s}$ it is at $0\ \text{m}$, at $2\ \text{s}$ at $4\ \text{m}$ and at $4\ \text{s}$ at $8\ \text{m}$; how can we see at a glance whether it is moving fast or slowly without relying on a table of numbers?
In the first graph ($x(t)$) look at the slope of the line; in the second ($v(t)$) check that it is a horizontal line, because the velocity does not change.
In a position-time (x-t) graph, the line of a moving object is horizontal for $10\ \text{s}$, as shown in the figure. What is the moving object doing during that time?…
In a position-time (x-t) graph, the line of a moving object is horizontal for $10\ \text{s}$, as shown in the figure.
What is the moving object doing during that time? Justify your answer.
On the same x-t graph, Ana and Luis appear as two straight lines, and Ana's line rises more steeply than Luis's, as shown in the figure. Who is traveling faster? What…
On the same x-t graph, Ana and Luis appear as two straight lines, and Ana's line rises more steeply than Luis's, as shown in the figure.
Who is traveling faster? What physical quantity does the slope of an x-t graph give us?
The x-t graph of a walker is a straight line passing through the points $(0\ \text{s},\ 0\ \text{m})$ and $(10\ \text{s},\ 50\ \text{m})$, as shown in the figure.…
The x-t graph of a walker is a straight line passing through the points $(0\ \text{s},\ 0\ \text{m})$ and $(10\ \text{s},\ 50\ \text{m})$, as shown in the figure.
Calculate their speed.
The v-t graph: slope = acceleration
The speedometer of a motorcycle reads $0\ \text{m/s}$ at the start, rises to $10\ \text{m/s}$ after $2\ \text{s}$ and reaches $20\ \text{m/s}$ after $4\ \text{s}$; how can we draw how quickly that velocity changes?
Notice how, since $a \neq 0$, the $v(t)$ graph is no longer horizontal: it is a sloping line, and the $x(t)$ graph curves.
The sign of the slope tells you the direction of the change. A line sloping up means the speed is increasing (positive acceleration). A line sloping down means the object is slowing down (negative acceleration, opposite to the velocity). A line below the axis means negative velocity: the object is moving in the opposite direction. To match a story to a graph, follow the stages in order: speeding up, constant speed, slowing to a stop.
The v-t graph of a motorcycle is a straight line passing through the points $(0\ \text{s},\ 0\ \text{m/s})$ and $(4\ \text{s},\ 12\ \text{m/s})$, as shown in the figure.…
The v-t graph of a motorcycle is a straight line passing through the points $(0\ \text{s},\ 0\ \text{m/s})$ and $(4\ \text{s},\ 12\ \text{m/s})$, as shown in the figure.
Calculate its acceleration.
What information does the slope of a position-time graph give? And that of a velocity-time graph? Answer in your own words and provide a numerical example for each.
What information does the slope of a position-time graph give? And that of a velocity-time graph? Answer in your own words and provide a numerical example for each.
The v-t graph of a car has three sections, as shown in the figure: from $(0\ \text{s},\ 0\ \text{m/s})$ to $(10\ \text{s},\ 20\ \text{m/s})$; horizontal at…
The v-t graph of a car has three sections, as shown in the figure: from $(0\ \text{s},\ 0\ \text{m/s})$ to $(10\ \text{s},\ 20\ \text{m/s})$; horizontal at $20\ \text{m/s}$ up to $t = 30\ \text{s}$; and from $(30\ \text{s},\ 20\ \text{m/s})$ to $(35\ \text{s},\ 0\ \text{m/s})$.
- a) Calculate the acceleration of each section.
- b) Describe in words what the car does throughout the entire trip.
The v-t graph of a cyclist is a straight line going from $(0\ \text{s},\ 12\ \text{m/s})$ to $(6\ \text{s},\ 0\ \text{m/s})$, as shown in the figure. a) Calculate their…
The v-t graph of a cyclist is a straight line going from $(0\ \text{s},\ 12\ \text{m/s})$ to $(6\ \text{s},\ 0\ \text{m/s})$, as shown in the figure.
- a) Calculate their acceleration.
- b) What does the sign of this acceleration mean?
- c) What would it mean if the line continued below the axis, with negative velocities?
A car waits stationary at a traffic light; when it turns green, it pulls away gaining speed uniformly, travels for a while at constant speed and finally brakes to a…
A car waits stationary at a traffic light; when it turns green, it pulls away gaining speed uniformly, travels for a while at constant speed and finally brakes to a stop. Which of these descriptions of v-t graphs corresponds to the car? Justify your choice and explain why the others are ruled out:
- a) A horizontal line above zero at all times.
- b) Starting from zero: a line that rises, then a horizontal section, and then a line that falls to zero.
- c) A line that falls from a high value to zero and stays at zero.
Area under a v-t graph: distance traveled
When the velocity is constant, the distance is $d = v \cdot t$. On a v-t graph, that is the area of the rectangle between the line and the time axis.
If $v<0$, the area contributes a negative displacement. For the distance, add up the absolute values of the areas, separating the stages in which the sign of $v$ changes. For example, $v=4\ \text{m/s}$ for $3\ \text{s}$ and $v=-2\ \text{m/s}$ for $2\ \text{s}$ give $\Delta x=12-4=8\ \text{m}$, but $d=12+4=16\ \text{m}$. In the following examples the velocities are positive, which is why distance and displacement coincide.
The velocity-time (v-t) graph of a cruising aircraft is a horizontal line at $v = 250\ \text{m/s}$ for $10\ \text{s}$, as shown in the figure. What type of motion does…
The velocity-time (v-t) graph of a cruising aircraft is a horizontal line at $v = 250\ \text{m/s}$ for $10\ \text{s}$, as shown in the figure.
What type of motion does it have in this section? What distance does it travel in those $10\ \text{s}$?
The v-t graph of a streetcar is horizontal at $10\ \text{m/s}$ between $t = 0\ \text{s}$ and $t = 20\ \text{s}$, and horizontal at $5\ \text{m/s}$ between…
The v-t graph of a streetcar is horizontal at $10\ \text{m/s}$ between $t = 0\ \text{s}$ and $t = 20\ \text{s}$, and horizontal at $5\ \text{m/s}$ between $t = 20\ \text{s}$ and $t = 40\ \text{s}$, as shown in the figure.
- a) What distance does it travel in the first section? And in the second?
- b) What total distance does it travel in $40\ \text{s}$?
- c) What is its average speed over the entire journey?
The x-t graph of a school bus trip has these straight sections, as shown in the figure: from $(0\ \text{min},\ 0\ \text{km})$ to $(10\ \text{min},\ 6\ \text{km})$;…
The x-t graph of a school bus trip has these straight sections, as shown in the figure: from $(0\ \text{min},\ 0\ \text{km})$ to $(10\ \text{min},\ 6\ \text{km})$; horizontal up to $t = 15\ \text{min}$, while picking up students; from $(15\ \text{min},\ 6\ \text{km})$ to $(35\ \text{min},\ 16\ \text{km})$; and finally from $(35\ \text{min},\ 16\ \text{km})$ to $(55\ \text{min},\ 0\ \text{km})$.
- a) Calculate the speed of each section, in $\text{km/min}$.
- b) What does the last section mean, whose slope is negative?
- c) In which section is the bus traveling fastest? Justify it by comparing the slopes.
The v-t graph of a car has these sections, as shown in the figure: it rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to $(5\ \text{s},\ 10\ \text{m/s})$;…
The v-t graph of a car has these sections, as shown in the figure: it rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to $(5\ \text{s},\ 10\ \text{m/s})$; remains at $10\ \text{m/s}$ up to $t = 25\ \text{s}$; and falls in a straight line to $(35\ \text{s},\ 0\ \text{m/s})$.
- a) Calculate the acceleration of each section.
- b) Calculate the distance traveled in the constant speed section.
- c) In the sections with acceleration, the distance corresponds to the area of the triangle under the graph. Calculate the distance of the first and third sections using this idea and find the total distance of the trip.
The v-t graph of a rising elevator has these sections, as shown in the figure: from $(0\ \text{s},\ 0\ \text{m/s})$ to $(2\ \text{s},\ 4\ \text{m/s})$; horizontal at…
The v-t graph of a rising elevator has these sections, as shown in the figure: from $(0\ \text{s},\ 0\ \text{m/s})$ to $(2\ \text{s},\ 4\ \text{m/s})$; horizontal at $4\ \text{m/s}$ up to $t = 8\ \text{s}$; and from $(8\ \text{s},\ 4\ \text{m/s})$ to $(10\ \text{s},\ 0\ \text{m/s})$.
- a) Calculate the acceleration of each section.
- b) Calculate the distance for each section from the area under the graph, and the total height the elevator ascends.
- c) Describe in words what the x-t graph of this elevator would look like: in which sections would it be a curve and in which a straight line? How does its slope change? Justify your answer.
Combined stages and curves
On an x-t graph, a curve that gets steeper means the object is speeding up; a curve that flattens out means it is slowing down. Time always moves forward, so an x-t graph can never go backward in $t$: to return toward the start, the line slopes down as time moves to the right. You can also sketch an x-t graph from a v-t graph: where the speed is constant the x-t line is straight, and where the speed changes it is a curve.
Match each description of an x-t graph with the corresponding motion and justify your choices: a) A horizontal straight line. b) A sloped straight line rising upward. c)…
Match each description of an x-t graph with the corresponding motion and justify your choices:
- a) A horizontal straight line.
- b) A sloped straight line rising upward.
- c) A curve getting progressively steeper.
Motions: it is stationary; it moves at a constant speed; it moves faster and faster.
The x-t graph of a skater has two straight sections: the first goes from $(0\ \text{s},\ 0\ \text{m})$ to $(10\ \text{s},\ 100\ \text{m})$ and the second from…
The x-t graph of a skater has two straight sections: the first goes from $(0\ \text{s},\ 0\ \text{m})$ to $(10\ \text{s},\ 100\ \text{m})$ and the second from $(10\ \text{s},\ 100\ \text{m})$ to $(30\ \text{s},\ 200\ \text{m})$, as shown in the figure.
Calculate their speed in each section and state in which one they are going faster.
The x-t graph of a bike ride has three straight sections, as shown in the figure: from $(0\ \text{min},\ 0\ \text{km})$ to $(20\ \text{min},\ 10\ \text{km})$; horizontal…
The x-t graph of a bike ride has three straight sections, as shown in the figure: from $(0\ \text{min},\ 0\ \text{km})$ to $(20\ \text{min},\ 10\ \text{km})$; horizontal from there to $t = 30\ \text{min}$; and from $(30\ \text{min},\ 10\ \text{km})$ to $(60\ \text{min},\ 16\ \text{km})$.
- a) Calculate the speed of each section, in $\text{km/min}$.
- b) What happens in the middle section? What do you think the cyclists did during that time?
The x-t graph of a car starting off is a curve that starts with a gentle slope and becomes progressively steeper, as shown in the figure. a) Does its speed increase,…
The x-t graph of a car starting off is a curve that starts with a gentle slope and becomes progressively steeper, as shown in the figure.
- a) Does its speed increase, decrease or stay constant? Reason your answer based on how the slope changes.
- b) What would the curve look like if, instead, the car braked to a stop? Describe it in words.
A classmate draws the x-t graph of a runner with these two sections, as shown in the figure: first a straight line from $(0\ \text{s},\ 0\ \text{m})$ to…
A classmate draws the x-t graph of a runner with these two sections, as shown in the figure: first a straight line from $(0\ \text{s},\ 0\ \text{m})$ to $(10\ \text{s},\ 40\ \text{m})$ and then a straight line going from $(10\ \text{s},\ 40\ \text{m})$ to $(5\ \text{s},\ 20\ \text{m})$.
- a) Calculate the speed of the first section.
- b) Explain why the second section is impossible in reality: notice how time progresses.
- c) What should a section look like where the runner actually returns toward the starting point? Describe it and give a numerical example.
You can do it on paper and send a photo with your answer.
Two moving objects on the same graph
To see who is ahead using v-t graphs, compare the areas under the lines: the larger area means the greater distance traveled.
On the same x-t graph, Emma's line starts at $(0\ \text{s},\ 30\ \text{m})$ and passes through $(10\ \text{s},\ 60\ \text{m})$, and Liam's line starts at…
On the same x-t graph, Emma's line starts at $(0\ \text{s},\ 30\ \text{m})$ and passes through $(10\ \text{s},\ 60\ \text{m})$, and Liam's line starts at $(0\ \text{s},\ 0\ \text{m})$ and passes through $(10\ \text{s},\ 60\ \text{m})$, as shown in the figure.
- a) Calculate each person's speed.
- b) Who started ahead? Who runs faster?
- c) Do they cross paths at any point? Where can this be seen on the graph?
On an x-t graph, the line of one train passes through $(0\ \text{s},\ 0\ \text{m})$ and $(20\ \text{s},\ 400\ \text{m})$, and that of another train, coming from the…
On an x-t graph, the line of one train passes through $(0\ \text{s},\ 0\ \text{m})$ and $(20\ \text{s},\ 400\ \text{m})$, and that of another train, coming from the opposite direction, passes through $(0\ \text{s},\ 800\ \text{m})$ and $(40\ \text{s},\ 0\ \text{m})$, as shown in the figure.
- a) Calculate the velocity of each train, including its sign.
- b) The two lines intersect at a point: explain what this point means.
- c) Calculate the time and position at which the trains pass each other.
Two cars leave a traffic light at the same time. The v-t graph for car A rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to…
Two cars leave a traffic light at the same time. The v-t graph for car A rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to $(10\ \text{s},\ 20\ \text{m/s})$. That of car B rises from $(0\ \text{s},\ 0\ \text{m/s})$ to $(5\ \text{s},\ 20\ \text{m/s})$ and then remains at $20\ \text{m/s}$ up to $t = 10\ \text{s}$, as shown in the figure.
- a) Calculate the acceleration of each car as it starts moving.
- b) By calculating the area under each graph, find the distance traveled by each car in those $10\ \text{s}$.
- c) Which one is ahead upon reaching $10\ \text{s}$? Justify this using your results.
The v-t graph of a $100\ \text{m}$ final shows two athletes, as shown in the figure: Vera rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to…
The v-t graph of a $100\ \text{m}$ final shows two athletes, as shown in the figure: Vera rises in a straight line from $(0\ \text{s},\ 0\ \text{m/s})$ to $(4\ \text{s},\ 10\ \text{m/s})$ and then maintains $10\ \text{m/s}$ until the end; Hugo rises from $(0\ \text{s},\ 0\ \text{m/s})$ to $(2\ \text{s},\ 10\ \text{m/s})$ and also maintains $10\ \text{m/s}$.
- a) Calculate the initial acceleration of each athlete.
- b) Calculate the distance traveled by each at $10\ \text{s}$ (areas under the graph).
- c) If both maintain that maximum speed, who crosses the $100\ \text{m}$ finish line first and at what time? Show reasoning for all calculations.
Back to the beginning: On a $v$-$t$ graph, your morning corresponds to a horizontal line (constant speed at a steady pace), a stage sloping upward (you speed up) and a stage sloping downward to the time axis (you slow down until you stop at the bus stop).