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Secondary 2 · Science II (Physics)
Energy · Electrical circuits

Series and Parallel Circuits

In an old string of holiday lights, if one bulb burns out, they all go dark. In the light bulbs in your house, if one burns out, the others stay on. The difference is in how they are connected: in series or in parallel. By the end of this page you will be able to explain it and calculate it.

Before we start: voltage, current, and resistance

To do calculations in a circuit you need three quantities. Think of water flowing down a pipe: the voltage is the "push" the battery gives, the current is how much charge passes per second, and the resistance is how much the element (a bulb, a thin wire) gets in the way of the current.

Why does this make sense? With the same voltage, if the resistance is greater the current is smaller; if the voltage is greater, the current grows.

Series circuit: a single path

If you connect one bulb to a battery, it shines brightly. But if you put a second bulb right after it, on the same wire, both shine less brightly. Why does putting elements in a row reduce the current in the whole circuit?

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Two light bulbs are connected in series, one after the other, to a battery, as shown in the figure. Through which of the two does more current flow? Justify your answer.

Two light bulbs are connected in series, one after the other, to a battery, as shown in the figure.

battery

Through which of the two does more current flow? Justify your answer.

Solve
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Two resistors of $2\ \Omega$ and $3\ \Omega$ are connected in series, as shown in the figure. What is the total (equivalent) resistance of the combination?

Two resistors of $2\ \Omega$ and $3\ \Omega$ are connected in series, as shown in the figure.

R₁ = 2 ΩR₂ = 3 Ω R total = ?

What is the total (equivalent) resistance of the combination?

Solve
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Two resistors, $R_1 = 2\ \Omega$ and $R_2 = 4\ \Omega$, are connected in series to a $12\ \text{V}$ battery, as shown in the figure. a) Calculate the equivalent…

Two resistors, $R_1 = 2\ \Omega$ and $R_2 = 4\ \Omega$, are connected in series to a $12\ \text{V}$ battery, as shown in the figure.

12 VR₁ = 2 ΩR₂ = 4 Ω I = ?
  1. a) Calculate the equivalent resistance.
  2. b) Calculate the current flowing through the circuit.
  3. c) Find the voltage across each resistor using Ohm's law and verify that the two voltages add up to the $12\ \text{V}$ of the battery.
Solve

Parallel circuit: several paths

If you have one bulb on and you connect another identical one directly to the same terminals of the battery, with its own wires, both shine just as brightly as before. Why, when you add new paths, does each bulb still get the full voltage?

How to measure current: the ammeter

Current is measured with an ammeter, which is always connected in series with whatever you want to measure: the current has to pass through the device. It measures the current that passes through the point where you place it.

  • If you place it next to the battery, before the path splits, it measures the total current.

  • If you place it in a branch, it measures only the current in that branch.

In a parallel circuit, the total current is the sum of the currents in the branches, so the ammeter at the battery reads more than the one in any branch.

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Two light bulbs are connected in parallel to the same battery, each along its own path, as shown in the figure. What do they have in common electrically: the current…

Two light bulbs are connected in parallel to the same battery, each along its own path, as shown in the figure.

battery

What do they have in common electrically: the current passing through them or the voltage across their ends? Explain.

Solve
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In which type of connection does current have only one possible path, series or parallel? And in which can it be split among several branches?

In which type of connection does current have only one possible path, series or parallel? And in which can it be split among several branches?

Solve
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Two resistors, $R_1 = 6\ \Omega$ and $R_2 = 12\ \Omega$, are connected in parallel to a $12\ \text{V}$ battery. a) What voltage is across the ends of each one? b)…

Two resistors, $R_1 = 6\ \Omega$ and $R_2 = 12\ \Omega$, are connected in parallel to a $12\ \text{V}$ battery.

Circuit diagram with two resistors in parallel connected to a batteryV = 12 V+−ItotalI1R1 = 6 ΩI2R2 = 12 Ω
  1. a) What voltage is across the ends of each one?
  2. b) Calculate the current flowing through each branch.
  3. c) What is the total current supplied by the battery?
Solve
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Two resistors of $4\ \Omega$ and $12\ \Omega$ are in parallel. Knowing that in this setup $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$ holds, calculate the…

Two resistors of $4\ \Omega$ and $12\ \Omega$ are in parallel. Knowing that in this setup $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$ holds, calculate the equivalent resistance of the combination.

Solve
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We want to measure the total current supplied by a battery in a circuit with two light bulbs in parallel, as shown in the figure. a) Where should we place the ammeter:…

We want to measure the total current supplied by a battery in a circuit with two light bulbs in parallel, as shown in the figure.

ABbattery
  1. a) Where should we place the ammeter: in one of the branches or next to the battery, before the path divides?
  2. b) What would the device measure in each of those two positions?
Solve

What happens if a bulb burns out

Failure comparison: in series, if one bulb burns out both go off because the circuit is left open; in parallel, the other bulb stays on because its branch remains closed. SERIES: one burns out PARALLEL: one burns out open circuit both go off the other stays on broken branch closed branch
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In an old set of fairy lights, the bulbs are connected in series, as shown in the figure. If one bulb blows and its filament breaks, what happens to the others? Explain…

In an old set of fairy lights, the bulbs are connected in series, as shown in the figure.

blownbattery

If one bulb blows and its filament breaks, what happens to the others? Explain thinking about the path followed by the current.

Solve
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In a scale model, two light bulbs are connected in parallel to a battery. If you unscrew one of them, what happens to the other? Justify your answer.

In a scale model, two light bulbs are connected in parallel to a battery. If you unscrew one of them, what happens to the other? Justify your answer.

Diagram of two light bulbs connected in parallel to a batteryPARALLEL CIRCUITBattery+−Light bulb 1What happens to it?Light bulb 2Unscrewed
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A simple torch has a battery, a switch and a light bulb. a) Are they connected in series or in parallel? b) What happens to the current when we open the switch?

A simple torch has a battery, a switch and a light bulb.

  1. a) Are they connected in series or in parallel?
  2. b) What happens to the current when we open the switch?
Solve
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In the classroom there are six LED tubes, and when one breaks down, the others remain on. a) Are they connected in series or in parallel? b) Justify your answer by…

In the classroom there are six LED tubes, and when one breaks down, the others remain on.

  1. a) Are they connected in series or in parallel?
  2. b) Justify your answer by explaining what happens to the current when one fails.
Solve

Why the wiring in a house is in parallel

In Mexico, the outlets and lamps in a house receive about $127\ \text{V}$ from the CFE. Each appliance is on its own branch, connected to the same two conductors. (Some exercises use another value, such as $230\ \text{V}$: work with the data you are given.)

Wiring of a house in parallel: from two conductors come three independent branches, living room and kitchen on and bedroom off, each with its own switch and bulb. live wire neutral living room: on kitchen: on bedroom: off
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In homes, sockets and lamps are connected in parallel and not in series. Give a reason thinking about what would happen when switching off an appliance or if one breaks…

In homes, sockets and lamps are connected in parallel and not in series. Give a reason thinking about what would happen when switching off an appliance or if one breaks down.

Solve
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The two headlights of a car are connected in parallel to the $12\ \text{V}$ battery, and each one has a resistance of $6\ \Omega$. a) What current flows through each…

The two headlights of a car are connected in parallel to the $12\ \text{V}$ battery, and each one has a resistance of $6\ \Omega$.

Circuit diagram of two car headlights connected in parallel to a 12 V battery+−Battery12 VHeadlight 1R₁ = 6 ΩHeadlight 2R₂ = 6 ΩItotal = ?I₁ = ?I₂ = ?
  1. a) What current flows through each headlight?
  2. b) What is the total current supplied by the battery with both headlights on?
  3. c) If one headlight burns out, what happens to the other? Justify your answer considering the type of connection.
Solve
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In a home, the oven ($23\ \Omega$) and the microwave ($46\ \Omega$) are connected in parallel to the $230\ \text{V}$ mains. a) Calculate the current flowing through each…

In a home, the oven ($23\ \Omega$) and the microwave ($46\ \Omega$) are connected in parallel to the $230\ \text{V}$ mains.

Circuit diagram in parallel with oven and microwave connected to the 230 V mains230 VPower mainsItotal = ?I1 = ?OvenR₁ = 23 ΩI2 = ?MicrowaveR₂ = 46 Ω
  1. a) Calculate the current flowing through each appliance when they operate simultaneously.
  2. b) What total current enters through the kitchen circuit?
  3. c) Reason why it is convenient for them to be in parallel rather than in series, considering the voltage that each appliance requires.
Solve

Combining several resistors

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Three light bulbs of $2\ \Omega$ each are connected in series to a $12\ \text{V}$ battery, as shown in the figure. a) Calculate the total resistance. b) What current…

Three light bulbs of $2\ \Omega$ each are connected in series to a $12\ \text{V}$ battery, as shown in the figure.

12 V2 Ω2 Ω2 Ω I = ?
  1. a) Calculate the total resistance.
  2. b) What current passes through them?
  3. c) What voltage is across each light bulb?
Solve
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You have a $6\ \text{V}$ battery and two identical $6\ \Omega$ light bulbs, as shown in the figure. a) If you connect them in series, what current flows through each…

You have a $6\ \text{V}$ battery and two identical $6\ \Omega$ light bulbs, as shown in the figure.

Circuit diagrams with two light bulbs connected in series and in parallel 6 V 6 Ω 6 Ω a) 6 V 6 Ω 6 Ω b)
  1. a) If you connect them in series, what current flows through each one?
  2. b) If you connect them in parallel, what current flows through each one?
  3. c) In which setup do they shine brighter? Justify your answer using the results.
Solve
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Two identical light bulbs in series are connected to a $9\ \text{V}$ battery. a) Without knowing their resistance, reason how the voltage is shared between them. b) How…

Two identical light bulbs in series are connected to a $9\ \text{V}$ battery.

  1. a) Without knowing their resistance, reason how the voltage is shared between them.
  2. b) How many volts are across each one?
  3. c) How would the sharing change if the bulbs were different?
Solve
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We connect identical $3\ \Omega$ light bulbs in series to a $9\ \text{V}$ battery, adding one at a time. a) Calculate the circuit current with one, with two and with…

We connect identical $3\ \Omega$ light bulbs in series to a $9\ \text{V}$ battery, adding one at a time.

  1. a) Calculate the circuit current with one, with two and with three light bulbs.
  2. b) What happens to the brightness of the bulbs as we add more in series?
  3. c) Explain the result using equivalent resistance and Ohm's law.
Solve
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Now we connect identical $12\ \Omega$ light bulbs in parallel to a $6\ \text{V}$ battery, adding one at a time. a) What current passes through each bulb when there are…

Now we connect identical $12\ \Omega$ light bulbs in parallel to a $6\ \text{V}$ battery, adding one at a time.

  1. a) What current passes through each bulb when there are one, two or three?
  2. b) Calculate the total current supplied by the battery in each case.
  3. c) Reason why the battery runs out faster the more bulbs we connect in parallel.
Solve
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Three resistors of $2\ \Omega$, $4\ \Omega$ and $4\ \Omega$ are in parallel, as shown in the figure. a) Calculate the equivalent resistance using…

Three resistors of $2\ \Omega$, $4\ \Omega$ and $4\ \Omega$ are in parallel, as shown in the figure.

6 VR₁ = 2 ΩR₂ = 4 ΩR₃ = 4 Ω
  1. a) Calculate the equivalent resistance using $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$.
  2. b) If the combination is connected to a $6\ \text{V}$ battery, what total current flows?
  3. c) Calculate the current in each branch and check that the three sum to the total current.
Solve
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A resistor of $6\ \Omega$ and another of $3\ \Omega$ are connected in parallel. a) Calculate the equivalent resistance. b) Verify that it is even smaller than the…

A resistor of $6\ \Omega$ and another of $3\ \Omega$ are connected in parallel.

  1. a) Calculate the equivalent resistance.
  2. b) Verify that it is even smaller than the smaller of the two.
  3. c) Explain, thinking about the paths available for the current, why adding a branch in parallel always makes it easier for current to flow.
Solve
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A classmate states: "In series, the current from the battery is shared between the bulbs." a) Is he right? b) With a $12\ \text{V}$ battery and two $3\ \Omega$ light…

A classmate states: "In series, the current from the battery is shared between the bulbs."

  1. a) Is he right?
  2. b) With a $12\ \text{V}$ battery and two $3\ \Omega$ light bulbs in series, calculate the current passing through each one and the voltage across each one.
  3. c) Correct your classmate's statement: what is actually shared in a series circuit?
Solve
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You are going to illuminate two scale models with one bulb each, and they must be able to be switched on and off separately using a single battery. a) Would you connect…

You are going to illuminate two scale models with one bulb each, and they must be able to be switched on and off separately using a single battery.

  1. a) Would you connect them in series or in parallel? Why?
  2. b) What advantage does your choice have if a bulb blows?
  3. c) What disadvantage does it pose for the battery life? Relate this to the total current supplied.
Solve

Summary

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