The concept of the derivative
Aoife checks every night how many followers her camogie club's channel has gained. That figure, "followers per day", is an average: it says nothing about whether today the channel has grown faster than yesterday. To find out what is happening right now, at this very instant, we need another tool: the derivative. This section builds that tool from something you already know, the average rate of change, and turns it into a number that describes change at an exact point.
From the average rate of change to instantaneous change
To find out what happens at an exact instant, for example at $t=1$, we have to shrink the interval as much as possible: calculate the ARC on $[1, 1+h]$ and see what happens as $h$ gets smaller and smaller.
A content creator analyses the growth of their followers on a social network over the past week. The number of followers $S$ as a function of day $t$ is given by the…
A content creator analyses the growth of their followers on a social network over the past week. The number of followers $S$ as a function of day $t$ is given by the expression $S(t) = t^2 + 10t + 500$. Calculate the Average Rate of Change (ARC) of their followers between day $t=1$ and day $t=4$. Explain in your own words what the result obtained means in the context of the problem.
Look at the following graph, which represents the change in the price of a cryptocurrency over a morning. Read from it the values of $f(1)$ and $f(5)$ and calculate the…
Look at the following graph, which represents the change in the price of a cryptocurrency over a morning. Read from it the values of $f(1)$ and $f(5)$ and calculate the Average Rate of Change over the interval $[1, 5]$, interpreting it as the slope of the secant line that passes through those two points.
A streaming platform has analysed the growth of its subscribers during the first months of the year. The function estimating the number of subscribers (in thousands) is…
A streaming platform has analysed the growth of its subscribers during the first months of the year. The function estimating the number of subscribers (in thousands) is given by $S(t) = t^2 + 2t + 10$, where $t$ is the time measured in months from the beginning of the year ($t=0$ is 1 January).
- a) Calculate the Average Rate of Change (ARC) of the number of subscribers between the second month ($t=2$) and the fifth month ($t=5$).
- b) Explain the meaning of the result obtained in the context of the problem.
- c) Would it be correct to state that the platform gained exactly that number of subscribers each month during that period? Reason your answer.
The derivative as a limit
Given the linear function $f(x) = 4x - 3$, use the definition of a derivative at a point using the limit: $$f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$$ to calculate…
Given the linear function $f(x) = 4x - 3$, use the definition of a derivative at a point using the limit:
$$f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$$to calculate the value of the derivative at the point $x=2$. Check whether the result coincides with the gradient of the line.
Calculate, using strictly the definition of a derivative at a point (using the limit as $h \to 0$), the value of $f'(3)$ for the function: $$f(x) = 2x^2 - 5x + 1$$
Calculate, using strictly the definition of a derivative at a point (using the limit as $h \to 0$), the value of $f'(3)$ for the function:
$$f(x) = 2x^2 - 5x + 1$$Given the function $f(x) = \frac{4}{x}$: a) Find the Instantaneous Rate of Change (IRC) at the point with x-coordinate $x = 2$ using the limit of the Average Rate of…
Given the function $f(x) = \frac{4}{x}$:
- a) Find the Instantaneous Rate of Change (IRC) at the point with x-coordinate $x = 2$ using the limit of the Average Rate of Change.
- b) Determine the equation of the tangent line to the graph of the function at that point $x = 2$.
The tangent line
Find the equation of the tangent line to the graph of the function $f(x) = x^2 + 1$ at the point with x-coordinate $x=1$, knowing that the value of the derivative at…
Find the equation of the tangent line to the graph of the function $f(x) = x^2 + 1$ at the point with x-coordinate $x=1$, knowing that the value of the derivative at that point is $f'(1) = 2$.
(Remember that the equation of the tangent line is $y - f(a) = f'(a)(x - a)$).
The concept of a derivative allows us to approximate the value of a function near a known point. Observe the following diagram showing a function and its tangent line at…
The concept of a derivative allows us to approximate the value of a function near a known point. Observe the following diagram showing a function and its tangent line at the point $P(1, 2)$.
If we know that the equation of the orange tangent line is $y = 3x - 1$:
- a) What is the value of the derivative of the function at $x = 1$? Justify your answer.
- b) If we wanted to know the value of the function at $x = 1.1$, what value would we obtain if we used the tangent line to approximate it?
- c) Do you think that for $x = 5$ the tangent line would still be a good approximation of the function? Explain why.
At a ballooning festival, the height of a hot-air balloon (in meters) with respect to time (in seconds) since it begins its ascent is given by the function…
At a ballooning festival, the height of a hot-air balloon (in meters) with respect to time (in seconds) since it begins its ascent is given by the function $H(t) = \sqrt{t + 4}$. The figure shows its graph during the first 12 seconds.
- a) Calculate the derivative $H'(t)$ using the limit definition.
- b) Find the equation of the tangent line to the trajectory at the instant $t = 5$.
- c) For safety, the festival regulations require that the balloon not exceed an ascent speed of $0.25$ m/s. Determine at what instant the instantaneous velocity is exactly that value.
One-sided derivatives and continuity
Just as with limits, if the difference quotient is calculated only with $h\to0^+$ or $h\to0^-$ we obtain the one-sided derivatives. Both are needed for the derivative to exist.
A function is said to be "differentiable" at a point if its graph does not have any jumps or sharp points at that location. Analyse the following piecewise function:…
A function is said to be "differentiable" at a point if its graph does not have any jumps or sharp points at that location. Analyse the following piecewise function:
$$f(x) = \begin{cases} x^2 + x & \text{if } x \le 1 \\ 3x - 1 & \text{if } x > 1 \end{cases}$$- a) Check whether the function is continuous at $x = 1$.
- b) Calculate the one-sided derivatives at $x = 1$ (that is, the derivative of each section at that point).
- c) From the previous results, is the function differentiable at $x = 1$? Justify your answer by relating continuity and the existence of one-sided derivatives.
Given the function $f(x) = |x^2 - 4|$, analyse its differentiability at the points $x = 2$ and $x = -2$. The figure shows its graph. a) Express the function as a…
Given the function $f(x) = |x^2 - 4|$, analyse its differentiability at the points $x = 2$ and $x = -2$. The figure shows its graph.
- a) Express the function as a piecewise-defined function.
- b) Calculate the one-sided derivatives at $x = 2$ using the limit definition. (At $x = -2$ the reasoning is analogous, by the symmetry of the graph.)
- c) Explain graphically what happens at those points (the concept of a "corner point") and why the derivative does not exist even though the function is continuous.
The sign of the derivative: a first reading
The derivative does not just give a number: its sign already tells you something important about the graph. If $f'(a) > 0$, the function is rising at $a$; if $f'(a) < 0$, it is falling; if $f'(a) = 0$, the tangent is horizontal.
Differentiating by rule
At Ordinary Level you do not use limits every time. For $f(x) = ax^n$ (with $n \le 3$) you use the rule:
A small clothing shop has estimated that its daily profits (in euros) depend on the number of discounted items ($x$) according to the function $B(x) = -x^2 + 40x - 300$.…
A small clothing shop has estimated that its daily profits (in euros) depend on the number of discounted items ($x$) according to the function $B(x) = -x^2 + 40x - 300$.
- a) Calculate the derivative function $B'(x)$ using differentiation rules.
- b) Calculate $B'(15)$ and $B'(25)$.
- c) Interpret the results from the previous section: Is it advantageous for the shopkeeper to increase the number of discounted items if they currently have 15? What if they have 25? Reason your answer using the concept of instantaneous change.
Find the points on the graph of the function $f(x) = x^3 - 3x^2 + 5$ where the tangent line is horizontal. Hint: Remember what value the gradient (and therefore the…
Find the points on the graph of the function $f(x) = x^3 - 3x^2 + 5$ where the tangent line is horizontal.
Hint: Remember what value the gradient (and therefore the derivative) must have for a line to be horizontal.
Find the points of the curve $y = x^3 - 3x^2 - 9x + 2$ at which the tangent line is parallel to the x-axis. Once you have found them, use the interpretation of the…
Find the points of the curve $y = x^3 - 3x^2 - 9x + 2$ at which the tangent line is parallel to the x-axis. Once you have found them, use the interpretation of the derivative to reason whether at those points the function has a relative maximum, a relative minimum, or an inflection point, by analyzing the sign of the derivative near those points.
It is known that the revenue function of an agricultural cooperative is $I(x) = -x^2 + 12x$, where $x$ are the tonnes of product sold. a) Calculate the derivative…
It is known that the revenue function of an agricultural cooperative is $I(x) = -x^2 + 12x$, where $x$ are the tonnes of product sold.
- a) Calculate the derivative function $I'(x)$ and interpret it as the "Marginal Revenue" (the approximate revenue from selling one additional unit).
- b) Show that the revenue is maximum when the Marginal Revenue is equal to zero.
- c) What happens to the revenue function if the derivative is negative? Justify your answer in terms of increasing and decreasing.
Consider the function $f(x) = ax^2 + bx + c$. Determine the values of $a$, $b$ and $c$ knowing that: 1. The graph of $f(x)$ passes through the point $(0, 5)$. 2. The…
Consider the function $f(x) = ax^2 + bx + c$. Determine the values of $a$, $b$ and $c$ knowing that:
-
The graph of $f(x)$ passes through the point $(0, 5)$.
-
The tangent line to the curve at the point with x-coordinate $x = 1$ is the line $y = 2x + 1$.
-
Use the derivative to check whether the vertex of the resulting parabola lies to the left or to the right of the $Y$-axis.
Match each of the points marked on the graph ($A$, $B$ and $C$) with the sign of the derivative of the function at that point (positive, negative or zero). Justify your…
Match each of the points marked on the graph ($A$, $B$ and $C$) with the sign of the derivative of the function at that point (positive, negative or zero). Justify your answer by mentally drawing the tangent line at each point.
The following graph shows the profile of a roller coaster on a specific section. It is known that the slope of the track at a point determines the passengers' sensation…
The following graph shows the profile of a roller coaster on a specific section. It is known that the slope of the track at a point determines the passengers' sensation of acceleration.
Based on the geometric concept of the derivative:
- a) Is the derivative zero at any of the three marked points ($A$, $B$, or $C$)? What does it mean for the derivative to be zero with respect to the slope of the track?
- b) State whether the derivative at point $B$ is positive or negative. Justify whether the roller coaster car is ascending or descending at that moment.
- c) Order the values of the derivatives at points $A, B$, and $C$ from lowest to highest.
Back to the beginning: to find out how fast the club's channel was growing at the exact instant $t=1$, we calculate the derivative $S'(t) = 2t + 10$, so $S'(1) = 12\text{ followers/day}$, compared with the average of $15$ it obtained over the first four days.