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5th Year OL · Physics
Energy · Basic thermodynamics

Energy transfers with the surroundings

A kettle on a cold morning in Galway boils away on the hob; an ice cube melts in your glass without the drink warming up while it does; a power station on the Shannon converts part of the heat from its fuel into electricity and gives off the rest to the river. In all these cases we need a quantitative energy balance, with signs that state precisely what enters and what leaves the system. That is the tool you are going to master in this section, and at the end we will come back to the power station.

The focus for the Leaving Certificate is on heat, specific heat capacity, specific latent heat and efficiency. The sign convention for the first law and the calculations with heat engines and refrigerators go beyond the syllabus, and are marked below.

The first law with a sign convention

When you repeatedly operate a hand pump to inflate a bicycle tyre, the metal lower part of the pump gets very hot even though it is nowhere near a flame: you have exerted a force over a displacement on the air, and that compression has increased its internal energy. How are the heat transferred and the mechanical work combined to determine exactly whether a gas gains or loses internal energy?

First law of thermodynamics: the system, with change in internal energy ΔU, receives heat Q (positive if it enters) and work W (positive if the surroundings do it on the system, negative if the system does it). Surroundings ΔU system Q W Q > 0: the system absorbs heat W > 0: the surroundings compress the system ΔU = Q + W

Work done by a gas and special processes

When a gas changes volume at constant pressure $p$, the work exchanged is $W = -p \cdot \Delta V$. If the gas expands, $\Delta V > 0$ and $W < 0$. If the volume does not change, $\Delta V = 0$ and $W = 0$, so $\Delta U = Q$. For an ideal gas at constant temperature, $\Delta U = 0$, so $Q = -W$: all the heat absorbed leaves again as work done by the gas.

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State the first law of thermodynamics in your own words. a) Explain what each of the three terms in the expression $\Delta U = Q + W$ represents. b) Reason why this law…

State the first law of thermodynamics in your own words.

  1. a) Explain what each of the three terms in the expression $\Delta U = Q + W$ represents.
  2. b) Reason why this law is, at heart, the principle of conservation of energy applied to thermodynamic systems.
Solve
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In thermodynamics we will use the following sign convention: $Q > 0$ when the system absorbs heat from the surroundings and $Q < 0$ when it gives off heat; $W > 0$ when…

In thermodynamics we will use the following sign convention: $Q > 0$ when the system absorbs heat from the surroundings and $Q < 0$ when it gives off heat; $W > 0$ when the surroundings do work on the system (compression) and $W < 0$ when the system does work on the surroundings (expansion). With this convention, the first law is written as $\Delta U = Q + W$.

Write with its sign the value of $Q$ or $W$ in each case:

  1. a) The system absorbs $400\ \text{J}$ of heat.
  2. b) The system gives off $250\ \text{J}$ of heat to the surroundings.
  3. c) The surroundings compress the system, doing $100\ \text{J}$ of work.
  4. d) The system expands and does $150\ \text{J}$ of work on the piston.
Solve
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A gas inside a cylinder absorbs heat $Q = +600\ \text{J}$ from a flame while the piston compresses it, doing work $W = +150\ \text{J}$ on it. The diagram shows the…

A gas inside a cylinder absorbs heat $Q = +600\ \text{J}$ from a flame while the piston compresses it, doing work $W = +150\ \text{J}$ on it. The diagram shows the energy transfers to the gas.

gas ΔU = ? Q = +600 J from the flame W = +150 J from the piston
  1. a) Calculate the change in internal energy $\Delta U$ of the gas.
  2. b) Interpret the result: has the internal energy of the gas increased or decreased?
Solve
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The hot water in a home heating circuit passes through a radiator and gives off $500\ \text{J}$ of heat to the room, without any work being done. a) Write the values of…

The hot water in a home heating circuit passes through a radiator and gives off $500\ \text{J}$ of heat to the room, without any work being done.

  1. a) Write the values of $Q$ and $W$ with their sign according to the standard convention.
  2. b) Calculate $\Delta U$ of the water in that section and interpret its sign.
Solve
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A gas gives off $300\ \text{J}$ of heat to the surroundings while a piston compresses it, doing work of $150\ \text{J}$ on it. a) Write $Q$ and $W$ with their sign…

A gas gives off $300\ \text{J}$ of heat to the surroundings while a piston compresses it, doing work of $150\ \text{J}$ on it.

  1. a) Write $Q$ and $W$ with their sign according to the standard convention.
  2. b) Calculate $\Delta U$ and interpret the result: despite the compression, does the gas gain or lose internal energy?
  3. c) For a gas whose internal energy increases with temperature, predict whether its temperature will have risen or fallen.
Solve
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A closed pressure cooker, before its valve opens, maintains the volume of steam practically constant while receiving heat $Q = +4000\ \text{J}$ from the hob. a) Justify…

A closed pressure cooker, before its valve opens, maintains the volume of steam practically constant while receiving heat $Q = +4000\ \text{J}$ from the hob.

  1. a) Justify why the work exchanged is zero in this stage (think about the expression $W = -p \times \Delta V$).
  2. b) Calculate the change in internal energy $\Delta U$ of the contents in that stage.
  3. c) Generalise the result by completing the sentence: "in any isochoric process, the change in internal energy is equal to $\dots$".
Solve
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An ideal gas expands very slowly inside a thermostatic bath (isothermal process) and absorbs heat $Q = +500\ \text{J}$ from the bath. Remember that, in an ideal gas,…

An ideal gas expands very slowly inside a thermostatic bath (isothermal process) and absorbs heat $Q = +500\ \text{J}$ from the bath. Remember that, in an ideal gas, internal energy depends only on temperature.

  1. a) State the value of $\Delta U$ in this process and justify your answer.
  2. b) Calculate the work $W$ exchanged, with its sign, and interpret it.
  3. c) Explain, using the energy balance, what the absorbed heat has been converted into.
Solve
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A gas expands at constant pressure $p = 1\times10^{5}\ \text{Pa}$ from $V_1 = 1\times10^{-3}\ \text{m}^3$ to $V_2 = 3\times10^{-3}\ \text{m}^3$ and, during the…

A gas expands at constant pressure $p = 1\times10^{5}\ \text{Pa}$ from $V_1 = 1\times10^{-3}\ \text{m}^3$ to $V_2 = 3\times10^{-3}\ \text{m}^3$ and, during the expansion, absorbs heat $Q = +700\ \text{J}$ from a burner.

  1. a) Calculate the work $W = -p \times \Delta V$ with its sign.
  2. b) Calculate the change in internal energy $\Delta U$ of the gas.
  3. c) Verify that the heat absorbed is divided between the increase in internal energy and the work done by the gas.
Solve

Specific heat capacity: $Q = m c \Delta\theta$

Temperature, thermometers and heat transfer

Temperature measures how vigorously the particles of a substance move on average: the hotter it is, the greater their average kinetic energy. A thermometer uses a thermometric property, a property that changes steadily with temperature, such as the length of a liquid column in a glass tube or the resistance of a thermistor. Temperature is given in degrees Celsius ($\theta$, in °C) or in kelvin ($T$, in K), where $T = \theta + 273$. A change of 1 °C equals a change of 1 K, so $\Delta\theta$ and $\Delta T$ have the same value.

Heat flows from hot to cold in three ways. In conduction, vibrating particles pass energy to their neighbours (metals are good conductors). In convection, a warmed fluid expands, becomes less dense and rises, while cooler fluid sinks. Radiation needs no medium at all.

In a laboratory investigation, heat a known mass of water with an immersion heater of known power $P$ for a time $t$, recording the temperature every minute in a table. Then $Q = Pt$, and the gradient of a graph of $\Delta\theta$ against $Q$ gives $1/(mc)$, so you can find $c$ from your own data.

One kilogram of water and one kilogram of aluminium receive the same heat Q: the aluminium's thermometer rises much more (greater ΔT) because its specific heat capacity is lower. Water c = 4180 J kg⁻¹ K⁻¹ Aluminium lower c m = 1 kg m = 1 kg ΔT ΔT Q Q same heat same heat
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An electric kettle heats $m = 2\ \text{kg}$ of water and raises its temperature by $\Delta T = 10\ \celsius$. The specific heat capacity of water is…

An electric kettle heats $m = 2\ \text{kg}$ of water and raises its temperature by $\Delta T = 10\ \celsius$. The specific heat capacity of water is $c = 4180\ \text{J}/(\text{kg}\times\celsius)$.

Calculate the heat absorbed by the water using the expression $Q = m \times c \times \Delta T$.

Solve
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The specific heat capacity of water is $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$ and that of ethanol is…

The specific heat capacity of water is $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$ and that of ethanol is $c_{\text{etanol}} = 2400\ \text{J}/(\text{kg}\times\celsius)$.

  1. a) Explain in your own words what the value $4180\ \text{J}/(\text{kg}\times\celsius)$ means: how many joules are needed and to achieve what, exactly.
  2. b) For equal masses and the same temperature increase, reason using formula $Q = m \times c \times \Delta T$ which of the two substances requires more heat.
Solve
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In the laboratory, $750\ \text{mL}$ of water is heated from $20\ \celsius$ to $60\ \celsius$. Data: the density of water is $1\ \text{kg/L}$ and its specific heat…

In the laboratory, $750\ \text{mL}$ of water is heated from $20\ \celsius$ to $60\ \celsius$. Data: the density of water is $1\ \text{kg/L}$ and its specific heat capacity is $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$.

  1. a) Express the mass of water in kilograms and calculate the temperature change.
  2. b) Calculate the heat absorbed by the water and express it in standard form.
Solve
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Heat $Q = 11\,500\ \text{J}$ is supplied to a metal block of $m = 0.5\ \text{kg}$, initially at $20\ \celsius$, and its temperature rises to $70\ \celsius$. a) Rearrange…

Heat $Q = 11\,500\ \text{J}$ is supplied to a metal block of $m = 0.5\ \text{kg}$, initially at $20\ \celsius$, and its temperature rises to $70\ \celsius$.

  1. a) Rearrange the formula $Q = m \times c \times \Delta T$ for the specific heat capacity $c$.
  2. b) Calculate its value in $\text{J}/(\text{kg}\times\celsius)$.
  3. c) By checking the values $c_{\text{plomo}} = 130\ \text{J}/(\text{kg}\times\celsius)$, $c_{\text{hierro}} = 460\ \text{J}/(\text{kg}\times\celsius)$ and $c_{\text{aluminio}} = 900\ \text{J}/(\text{kg}\times\celsius)$, identify which metal it could be.
Solve
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On a clear day, the Sun transfers the same energy $Q = 4180\ \text{J}$ to $1\ \text{kg}$ of sea water ($c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$) and…

On a clear day, the Sun transfers the same energy $Q = 4180\ \text{J}$ to $1\ \text{kg}$ of sea water ($c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$) and to $1\ \text{kg}$ of beach sand ($c_{\text{arena}} = 836\ \text{J}/(\text{kg}\times\celsius)$).

  1. a) Calculate the temperature increase of the water.
  2. b) Calculate the temperature increase of the sand.
  3. c) Use the results to explain why the sand is burning hot at midday while the sea water is barely lukewarm.
  4. d) Relate this to daytime sea breezes: reason over which surface the air heats up first and in which direction the breeze blows.
Solve

Latent heat and changes of state

If you heat a mixture of liquid water and ice cubes on a cooker hob at full power, a thermometer steadily reads $0\ ^\circ\text{C}$ for several minutes until the last piece of ice disappears completely, despite the incessant flow of heat coming in from the flame. Why does the temperature of the system not rise while the two phases coexist?

To find $l_v$ in the laboratory, pass steam at 100 °C into a known mass of cold water in an insulated calorimeter and record the rise in temperature. Weigh the calorimeter before and after to find the mass of steam that condensed. Heat lost by the steam (condensing, then cooling to the final temperature) equals heat gained by the water and calorimeter, which gives $l_v$.

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An ice pack containing $m = 0.5\ \text{kg}$ of ice at $0\ \celsius$ is applied to a sports injury until all the ice melts, remaining at $0\ \celsius$ throughout the…

An ice pack containing $m = 0.5\ \text{kg}$ of ice at $0\ \celsius$ is applied to a sports injury until all the ice melts, remaining at $0\ \celsius$ throughout the process. The latent heat of fusion of ice is $L_{\text{f}} = 3.34\times10^{5}\ \text{J/kg}$.

  1. a) Calculate the heat absorbed by the ice using $Q = m \times L_{\text{f}}$ and express the result in standard form.
  2. b) State where that heat comes from and, therefore, explain the cooling effect on the treated area.
Solve
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A pot of boiling water remains on the hob, but the thermometer reads $100\ \celsius$ throughout the process, even though the flame continues to supply energy. The graph…

A pot of boiling water remains on the hob, but the thermometer reads $100\ \celsius$ throughout the process, even though the flame continues to supply energy. The graph shows how the temperature of the water changes over time.

t T (°C) 100 heats up boils: T = 100 °C
  1. a) Does the water continue to receive energy while it is boiling? Justify your answer.
  2. b) If the temperature does not rise, what is that energy being used for at a microscopic level?
  3. c) Explain, using the concept of latent heat, why the temperature remains constant during a change of state.
Solve
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In an industrial boiler, $m = 0.2\ \text{kg}$ of water is heated from $80\ \celsius$ to $100\ \celsius$ and then that mass is completely vaporised at $100\ \celsius$.…

In an industrial boiler, $m = 0.2\ \text{kg}$ of water is heated from $80\ \celsius$ to $100\ \celsius$ and then that mass is completely vaporised at $100\ \celsius$. Data: $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$ and $L_{\text{v}} = 2.26\times10^{6}\ \text{J/kg}$.

  1. a) Calculate the heat required for the first stage (heating the water).
  2. b) Calculate the heat required for complete vaporisation using $Q = m \times L_{\text{v}}$.
  3. c) Calculate the total heat of the process and comment on which of the two stages turned out to be much more costly in terms of energy.
Solve

Heat engines, refrigerators and efficiency

A petrol car engine on the M50 releases energy by burning fuel to move the vehicle, but more than half of that thermal energy inevitably leaves through the exhaust pipe or is dissipated in the radiator. The same is true of a power station on the Shannon. Why is it physically impossible to design a machine that converts one hundred per cent of the available heat into useful work?

Diagram of the flow of heat absorbed, useful work delivered and waste heat given off in a heat engine between two reservoirs. hot reservoir Q₁ engine W Q₂ cold reservoir

Back to the start: a power station that takes in $Q_1 = 4000\ \text{J}$ and delivers $1200\ \text{J}$ of electrical work has efficiency $1200/4000 = 30\%$, and gives off $2800\ \text{J}$ as heat to the river water. The heat released to the cold reservoir is simply the input minus the useful output.

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In a thermal power plant, the engine driving the generator absorbs heat $Q_1 = 2000\ \text{J}$ per cycle from the hot reservoir (the boiler) and gives off heat…

In a thermal power plant, the engine driving the generator absorbs heat $Q_1 = 2000\ \text{J}$ per cycle from the hot reservoir (the boiler) and gives off heat $Q_2 = 1200\ \text{J}$ to the cold reservoir (the cooling water). In a complete cycle, the change in internal energy of the engine is zero. The heat engine diagram is shown in the figure.

hot reservoir Q₁ = 2000 J engine heat useful W = ? efficiency = ? Q₂ = 1200 J cold reservoir
  1. a) Calculate the useful work $W_{\text{useful}}$ delivered by the engine in each cycle from the energy balance.
  2. b) The efficiency of a heat engine is defined as $\eta = W_{\text{useful}}/Q_1$. Calculate the efficiency of this engine and express it as a percentage.
  3. c) Interpret the result by completing the sentence: "for every $100\ \text{J}$ of heat absorbed, the engine uses $\dots$ and transfers $\dots$ to the cold reservoir".
Solve
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A heat engine undergoes closed cycles. In each cycle it absorbs heat $Q_1 = +3000\ \text{J}$ from the hot reservoir and delivers work of $900\ \text{J}$ to the…

A heat engine undergoes closed cycles. In each cycle it absorbs heat $Q_1 = +3000\ \text{J}$ from the hot reservoir and delivers work of $900\ \text{J}$ to the surroundings, that is, $W = -900\ \text{J}$ with the standard sign convention. The diagram of the engine is shown in the figure.

hot reservoir Q₁ = 3000 J engine heat W = 900 J efficiency = ? Q₂ = ? cold reservoir
  1. a) Justify why the change in internal energy of the engine in a complete cycle is zero.
  2. b) Apply $\Delta U = Q + W$ to the cycle and calculate the net heat $Q$ exchanged per cycle.
  3. c) Taking into account that $Q = Q_1 + Q_2$, calculate the heat $Q_2$ exchanged with the cold reservoir, with its sign, and interpret it.
  4. d) Calculate the efficiency $\eta = W_{\text{useful}}/Q_1$ of the engine.
Solve
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A refrigerator operates as a heat engine in reverse: in each cycle, it extracts heat $Q_2 = +600\ \text{J}$ from the inside and the electric motor does work…

A refrigerator operates as a heat engine in reverse: in each cycle, it extracts heat $Q_2 = +600\ \text{J}$ from the inside and the electric motor does work $W = +200\ \text{J}$ on the system. In a complete cycle, $\Delta U = 0$. The diagram of the refrigerator is shown in the figure.

kitchen Q₁ = ? refrigerator W = +200 J electric motor Q₂ = +600 J inside (cold reservoir)
  1. a) Apply the first law of thermodynamics to the cycle and calculate the net heat $Q$ exchanged.
  2. b) Calculate the heat $Q_1$ that the refrigerator releases to the kitchen, including its sign, and interpret it: why is it greater than the heat extracted from the inside?
  3. c) Use the result to explain why leaving the refrigerator door open does not serve to cool down the kitchen, but actually ends up heating it up.
Solve
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Two heat engines work between the same reservoirs. Engine A absorbs $Q_1 = 5000\ \text{J}$ from the hot reservoir and delivers useful work of $1500\ \text{J}$. Engine B…

Two heat engines work between the same reservoirs. Engine A absorbs $Q_1 = 5000\ \text{J}$ from the hot reservoir and delivers useful work of $1500\ \text{J}$. Engine B absorbs the same $5000\ \text{J}$ and releases heat of $2500\ \text{J}$ to the cold reservoir.

  1. a) Calculate the efficiency of engine A.
  2. b) Calculate the useful work of engine B from its energy balance and then its efficiency.
  3. c) Compare both engines: which one makes better use of the fuel's heat?
  4. d) An inventor claims that they can build an engine with an efficiency of $100\ \%$, which releases no heat to the cold reservoir. Using the energy balance and the concept that every real heat engine must release heat to a cold reservoir, explain why such an engine is not possible.
Solve
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A thermal power station receives $5\times10^{6}\ \text{J}$ of energy from combustion per unit of time considered and delivers $1.5\times10^{6}\ \text{J}$ in the form of…

A thermal power station receives $5\times10^{6}\ \text{J}$ of energy from combustion per unit of time considered and delivers $1.5\times10^{6}\ \text{J}$ in the form of electrical work; the rest is released as heat to the cooling water of a river.

  1. a) Calculate the heat released to the cooling water.
  2. b) Calculate the current efficiency of the power station.
  3. c) Following a technological upgrade, the power station achieves an efficiency of $45\ \%$ with the same combustion input. Calculate the new work delivered and the new heat released to the river.
  4. d) Using your results to support your answer, explain why increasing the efficiency of power stations reduces the environmental impact of thermal pollution on river ecosystems.
Solve

Energy balances in mixed problems

Heating curve of water showing the sloping stages due to specific heat capacity and the constant-temperature plateau (melting) due to latent heat. Q θ (°C) ice 0 melting (constant T) liquid water

Determining $c$ and $l$ and cooling data

In the laboratory you can find $c$ by heating a known mass of water with an immersion heater and measuring the temperature rise, or by the method of mixtures: heat lost by the hot body equals heat gained by the cold one (if no heat escapes). To find $l_f$, drop ice at 0 °C into warm water and use the fall in temperature to find the heat needed to melt it. In cooling experiments, such as a mug of tea left on a table, record the temperature at regular times and plot temperature against time. Measure the mass with a scale, repeat readings, and note random errors (the spread of readings) and systematic errors (a thermometer that always reads high). The mug cools faster when it is much hotter than the room, so the curve is steepest at the start.

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We want to convert $m = 0.5\ \text{kg}$ of ice at $-10\ \celsius$ into liquid water at $40\ \celsius$. Data:…

We want to convert $m = 0.5\ \text{kg}$ of ice at $-10\ \celsius$ into liquid water at $40\ \celsius$. Data: $c_{\text{hielo}} = 2100\ \text{J}/(\text{kg}\times\celsius)$, $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$ and $L_{\text{f}} = 3.34\times10^{5}\ \text{J/kg}$.

  1. a) Calculate the heat required to heat the ice from $-10\ \celsius$ to $0\ \celsius$.
  2. b) Calculate the heat required to melt all the ice at $0\ \celsius$.
  3. c) Calculate the heat required to heat the resulting water from $0\ \celsius$ to $40\ \celsius$.
  4. d) Calculate the total heat of the process, express it in standard form and draw the graph of temperature as a function of heat supplied in your notebook, marking the different stages.
Solve
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In an insulated container there is $0.3\ \text{kg}$ of water at $60\ \celsius$ and $0.3\ \text{kg}$ of ice at $0\ \celsius$ is added. Data:…

In an insulated container there is $0.3\ \text{kg}$ of water at $60\ \celsius$ and $0.3\ \text{kg}$ of ice at $0\ \celsius$ is added. Data: $c_{\text{agua}} = 4180\ \text{J}/(\text{kg}\times\celsius)$ and $L_{\text{f}} = 3.34\times10^{5}\ \text{J/kg}$.

  1. a) Calculate the maximum heat that the hot water can give off if it cooled down to $0\ \celsius$.
  2. b) Calculate the heat needed to melt all the ice.
  3. c) Comparing both results, predict whether all the ice will melt and deduce the final temperature of the mixture.
  4. d) Calculate the mass of ice that melts and the mass that remains unmelted.
Solve
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A gas absorbs heat $Q = +1000\ \text{J}$ from a burner and its internal energy increases by $600\ \text{J}$ while pushing the piston of a mechanism. a) Calculate the…

A gas absorbs heat $Q = +1000\ \text{J}$ from a burner and its internal energy increases by $600\ \text{J}$ while pushing the piston of a mechanism.

  1. a) Calculate the work $W$ exchanged by the gas, including its sign, and state how much work the gas has done.
  2. b) The piston experiences friction, so out of that work only $300\ \text{J}$ is delivered as useful work to the external mechanism. Explain what happened to the rest.
  3. c) Verify that the balance $\Delta U = Q + W$ still holds and explain why friction does not "break" the conservation of energy even though it reduces useful work.
Solve
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Unit Challenge. How does your breakfast mug lose energy? You will experimentally analyze the heat transfers from an everyday thermodynamic system to its surroundings. 1.…

Unit Challenge. How does your breakfast mug lose energy? You will experimentally analyze the heat transfers from an everyday thermodynamic system to its surroundings.

  1. System definition: Identify the boundaries of the system (water) and measure the mass of water $m = (200 \pm 2)\text{ g}$ with a kitchen scale, as well as the ambient temperature $T_{\text{surr}} = (21.0 \pm 0.5)\text{ }^\circ\text{C}$.

  2. Experimental recording: Heat the water to about $80\text{ }^\circ\text{C}$, pour it into the mug, and record its temperature every $2\text{ min}$ for $14\text{ min}$, considering the instrumental uncertainty of the thermometer (e.g., $\pm 0.5\text{ }^\circ\text{C}$).

  3. Data processing: Construct a table with your measurements ($t, T$) and plot the cooling curve $T(t)$. From it, calculate the total heat dissipated to the surroundings using $Q = m \times c \times \Delta T$ (using $c = 4184\text{ J/(kg}\times\text{K)}$) and estimate the average power transferred ($P = Q/\Delta t$).

  4. Reasoned proposal: Write a brief report characterizing the state variables ($P, V, T$) of the system and propose two well-founded measures (lid, insulating material) to minimize energy losses.

The following will be evaluated:

  • Rigor in empirical data collection and correct expression of uncertainties.

  • Technical quality of the table, plot, and suitability of the transferred energy calculation ($Q$).

  • Coherent physical justification of the thermodynamic variables and the insulation proposal.

Solve

Summary

See all the exercises in this section