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5th Year OL · Physics
Vibrations and waves · Wave phenomena

Sound waves and their properties

The human ear is an extraordinarily sensitive sensor: it detects variations in air pressure thousands of times smaller than atmospheric pressure. To describe precisely what we perceive as "loud", "high-pitched" or "having a recognisable timbre", we have to carefully separate the physical quantities of the sound wave from the physiological sensations they produce.

The nature of sound and the audible range

If you gently rest your fingers on your throat while you speak, or touch the membrane of a loudspeaker that is switched on, you will feel a clear mechanical vibration: how does that oscillation travel through the air until it makes the eardrum of the listener vibrate?

Acoustic spectrum: infrasound below 20 Hz, audible range between 20 Hz and 20 000 Hz, and ultrasound above 20 000 Hz, with an arrow indicating increasing frequency. infra- sound ultra- sound 20 Hz – 20 000 Hz 20 Hz 20 000 Hz increasing frequency audible
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The three physiological properties of sound are pitch, intensity and timbre. a) Associate each property with the physical quantity of the wave that determines it:…

The three physiological properties of sound are pitch, intensity and timbre.

  1. a) Associate each property with the physical quantity of the wave that determines it: frequency, amplitude (energy transported) or wave shape.
  2. b) Give a musical example of each: two sounds that differ only in pitch, only in intensity, and only in timbre.
Solve
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The human ear perceives frequencies roughly between $20\ \text{Hz}$ and $20\ \text{kHz}$. The diagram shows the three regions of the acoustic spectrum: Classify the…

The human ear perceives frequencies roughly between $20\ \text{Hz}$ and $20\ \text{kHz}$. The diagram shows the three regions of the acoustic spectrum:

infrasound audible ultrasound 20 Hz 20 kHz f

Classify the following sound waves into infrasound, audible sound or ultrasound, and justify the classification:

  1. a) $15\ \text{Hz}$ (communication between elephants).
  2. b) $440\ \text{Hz}$ (the note "A" of a tuning fork).
  3. c) $45\ \text{kHz}$ (echolocation of a bat).
  4. d) $3\ \text{MHz}$ (medical ultrasound scan).
Solve
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A tuning fork vibrates at $440\ \text{Hz}$ (speed of sound in air: $340\ \text{m/s}$). a) Calculate the period of the sound wave generated. b) Calculate its wavelength…

A tuning fork vibrates at $440\ \text{Hz}$ (speed of sound in air: $340\ \text{m/s}$).

  1. a) Calculate the period of the sound wave generated.
  2. b) Calculate its wavelength in air.
Solve
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An ultrasound scanner emits ultrasound waves at $3\ \text{MHz}$ that propagate through soft tissues at $1540\ \text{m/s}$. The diagram shows the path of the pulse. a)…

An ultrasound scanner emits ultrasound waves at $3\ \text{MHz}$ that propagate through soft tissues at $1540\ \text{m/s}$. The diagram shows the path of the pulse.

probe f = 3 MHz pulse and echo back wall h = ? v = 1540 m/s · t = 0.00013 s (round trip)
  1. a) Calculate the wavelength of the ultrasound in the tissue.
  2. b) The echo from the back wall of an organ returns $1.3 \times 10^{-4}\ \text{s}$ after emission: calculate the depth at which it is located, bearing in mind the round trip of the pulse.
Solve

Qualities of sound: pitch, loudness and timbre

Increase the frequency and watch the green dot: it moves up and down more quickly, and that is what distinguishes a high-pitched sound from a low-pitched one. In air the speed of sound is fixed, so if you double $f$ you must halve $\lambda$ so that $v$ does not change: you will then see the crests more "tightly packed". Change the amplitude and you will see, in a similar way, what distinguishes a loud sound from a quiet one (the ear does not "see" this wave, but the eardrum membrane vibrates in exactly this way). Remember that in Physics, "loudness" is linked to amplitude and "pitch" to frequency.

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A violin and a flute play the same note ($440\ \text{Hz}$) with the same intensity, and yet they can be distinguished perfectly. a) Which property of sound allows this,…

A violin and a flute play the same note ($440\ \text{Hz}$) with the same intensity, and yet they can be distinguished perfectly.

  1. a) Which property of sound allows this, and with which wave quantity is it related?
  2. b) Explain the role of harmonics (frequency components that are multiples of the fundamental frequency) in this difference.
  3. c) Draw in your notebook, qualitatively, the expected waveform for each instrument and compare it with that of a pure tone.

You can do it on paper and send a photo with your answer.

Solve
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A fan produces an intensity level of $70\ \text{dB}$ at a point (given: $\log 2 \approx 0.3$). a) When a second identical fan is turned on, the total intensity at that…

A fan produces an intensity level of $70\ \text{dB}$ at a point (given: $\log 2 \approx 0.3$).

  1. a) When a second identical fan is turned on, the total intensity at that point doubles: calculate the new intensity level.
  2. b) Reason why the result is not $140\ \text{dB}$ and explain how decibels are 'added'.
Solve
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An industrial machine produces a level of $75\ \text{dB}$ in the machine room. a) Reason, using the logarithmic definition of intensity level, how many identical…

An industrial machine produces a level of $75\ \text{dB}$ in the machine room.

  1. a) Reason, using the logarithmic definition of intensity level, how many identical machines operating at the same time would be needed to reach $85\ \text{dB}$ at the same point.
  2. b) And to reach $95\ \text{dB}$?
  3. c) Explain why doubling the number of machines does not double the decibel level.
Solve

Sound intensity and sound intensity level in decibels

Bar chart of the sound intensity level in decibels: five bars of 20, 40, 60, 80 and 100 dB whose height grows in proportion to the level; each 20 dB step means 100 times more intensity. sound level 20 dB 40 60 80 100 dB
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The sound intensity level is defined as $\beta = 10 \times \log \frac{I}{I_0}$, measured in decibels ($\text{dB}$), where $I_0 = 10^{-12}\ \text{W/m}^2$ is the threshold…

The sound intensity level is defined as $\beta = 10 \times \log \frac{I}{I_0}$, measured in decibels ($\text{dB}$), where $I_0 = 10^{-12}\ \text{W/m}^2$ is the threshold intensity of hearing.

Calculate the intensity level of a sound of $I = 10^{-5}\ \text{W/m}^2$.

Solve
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A loud conversation has an intensity of $I = 5 \times 10^{-6}\ \text{W/m}^2$ (data: $I_0 = 10^{-12}\ \text{W/m}^2$; $\log 5 \approx 0.7$). Calculate its intensity level…

A loud conversation has an intensity of $I = 5 \times 10^{-6}\ \text{W/m}^2$ (data: $I_0 = 10^{-12}\ \text{W/m}^2$; $\log 5 \approx 0.7$).

Calculate its intensity level in decibels using $\beta = 10 \times \log \frac{I}{I_0}$.

Solve
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A passing lorry produces a level of $80\ \text{dB}$ and a quiet library is at $40\ \text{dB}$. a) Without using a calculator, use the logarithmic definition of intensity…

A passing lorry produces a level of $80\ \text{dB}$ and a quiet library is at $40\ \text{dB}$.

  1. a) Without using a calculator, use the logarithmic definition of intensity level to reason how many times more intense (in $\text{W/m}^2$) the sound of the lorry is compared to that of the library.
  2. b) Generalise the result: by what factor is the intensity multiplied for every additional $10\ \text{dB}$?
Solve
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The intensity level of a normal conversation is $60\ \text{dB}$ (given: $I_0 = 10^{-12}\ \text{W/m}^2$). a) Rearrange $\beta = 10 \times \log \frac{I}{I_0}$ for $I$ and…

The intensity level of a normal conversation is $60\ \text{dB}$ (given: $I_0 = 10^{-12}\ \text{W/m}^2$).

  1. a) Rearrange $\beta = 10 \times \log \frac{I}{I_0}$ for $I$ and calculate the intensity of that sound.
  2. b) How many times greater than the threshold of hearing is this intensity?
Solve

Attenuation with distance

In front of the stage at a concert in Marlay Park the sound is deafening, but you only need to move back a few tens of metres for the volume to become bearable: what mathematical relationship governs how sound energy decreases as the distance from the source increases?

Concentric spherical wavefronts of radii r, 2r and 3r around a point source: the same energy is spread over an ever larger area and the intensity decreases with the square of the distance. source r 2r 3r spread over more area the same energy P at each wavefront A = 4πr² area ×4 .

Back to the concert: at twice the distance from the stage, the intensity is a quarter and the level is about $6\ \text{dB}$ lower, which is why moving back helps.

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A point sound source emits with power $P = 0.5\ \text{W}$ uniformly in all directions. The intensity at a distance $r$ is $I = \frac{P}{4 \times \pi \times r^2}$ (take…

A point sound source emits with power $P = 0.5\ \text{W}$ uniformly in all directions. The intensity at a distance $r$ is $I = \frac{P}{4 \times \pi \times r^2}$ (take $\pi = 3.14$). The diagram represents isotropic emission.

source P = 0.5 W r = 5 m I = ?

Calculate the intensity at $5\ \text{m}$ from the source.

Solve
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A public address loudspeaker emits sound with a power of $P = 3\ \text{W}$ (data: $\pi = 3.14$; $I_0 = 10^{-12}\ \text{W/m}^2$; $\log 2.4 \approx 0.38$). a) Calculate…

A public address loudspeaker emits sound with a power of $P = 3\ \text{W}$ (data: $\pi = 3.14$; $I_0 = 10^{-12}\ \text{W/m}^2$; $\log 2.4 \approx 0.38$).

  1. a) Calculate the intensity at $10\ \text{m}$ from the loudspeaker using $I = \frac{P}{4 \times \pi \times r^2}$.
  2. b) Calculate the intensity level at that point, in decibels.
Solve
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At $2\ \text{m}$ from a drill, the intensity level is $90\ \text{dB}$ (given: $\log 2 \approx 0.3$). a) Moving away to $4\ \text{m}$, the intensity is divided by $4$:…

At $2\ \text{m}$ from a drill, the intensity level is $90\ \text{dB}$ (given: $\log 2 \approx 0.3$).

  1. a) Moving away to $4\ \text{m}$, the intensity is divided by $4$: calculate by how many decibels the level decreases and its new value.
  2. b) Repeat the calculation for $8\ \text{m}$.
  3. c) State the rule of thumb that can be deduced: how many decibels are lost each time the distance to the source is doubled?
Solve

Summary

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