Rectilinear and circular motion
You already know the difference between displacement and distance, and between speed and velocity. This section applies those ideas to the most common types of motion: those that follow a straight line (with or without acceleration) and those that trace a circle at a constant rate. Think of a Garda speed van on the M50 measuring cars, or a sliotar whirled on a string: both follow these rules.
Constant velocity and constant acceleration in a straight line
Imagine an Intercity train covering equal distances every second, compared with a car pulling away from traffic lights and steadily gaining speed: how can we describe these two ways of moving in a straight line with equations? And how far does a car travel before it stops when the driver brakes?
Move the sliders for the starting displacement, the initial velocity $u$ and $a$. The widget uses its own labels: its $x_0$ is our starting displacement $s_0$, and its $v$ is our initial velocity $u$. With $a=0$ you recover constant velocity from Junior Cycle Science: a straight line on the displacement–time graph. With $a \neq 0$, that graph curves and the velocity–time graph stops being horizontal, with gradient $a$.
A commuter train travels in a straight line at a constant velocity of $\vec{v} = 20\,\vec{i}\ \text{m/s}$. When $t = 0$, it passes through position…
A commuter train travels in a straight line at a constant velocity of $\vec{v} = 20\,\vec{i}\ \text{m/s}$. When $t = 0$, it passes through position $x_0 = 100\ \text{m}$.
- a) Write the equation for its position $x(t)$.
- b) Calculate its position when $t = 8\ \text{s}$.
An aircraft starts from rest on the runway and accelerates uniformly with $\vec{a} = 3\,\vec{i}\ \text{m/s}^2$. a) Write the equation for its velocity $v(t)$. b)…
An aircraft starts from rest on the runway and accelerates uniformly with $\vec{a} = 3\,\vec{i}\ \text{m/s}^2$.
- a) Write the equation for its velocity $v(t)$.
- b) Calculate its velocity after $10\ \text{s}$.
- c) Explain in your own words what an acceleration of $3\ \text{m/s}^2$ means.
A cyclist moves in a straight line with uniform acceleration (MRUA), with $x_0 = 0$, $v_0 = 4\ \text{m/s}$ and $a = 1\ \text{m/s}^2$. a) Write its position equation…
A cyclist moves in a straight line with uniform acceleration (MRUA), with $x_0 = 0$, $v_0 = 4\ \text{m/s}$ and $a = 1\ \text{m/s}^2$.
- a) Write its position equation $x(t)$.
- b) Calculate its position when $t = 6\ \text{s}$ using $x = x_0 + v_0 \times t + \frac{1}{2} \times a \times t^2$.
A bus travelling at $72\ \text{km/h}$ brakes uniformly at $a = -2\ \text{m/s}^2$ until it comes to a stop. a) Express its initial velocity in $\text{m/s}$. b) Calculate…
A bus travelling at $72\ \text{km/h}$ brakes uniformly at $a = -2\ \text{m/s}^2$ until it comes to a stop.
- a) Express its initial velocity in $\text{m/s}$.
- b) Calculate the time it takes to stop.
- c) Calculate the braking distance.
A tube train starts from rest and accelerates uniformly at $0.5\ \text{m/s}^2$ over $400\ \text{m}$. a) Calculate the velocity it reaches using…
A tube train starts from rest and accelerates uniformly at $0.5\ \text{m/s}^2$ over $400\ \text{m}$.
- a) Calculate the velocity it reaches using $v^2 = v_0^2 + 2 \times a \times \Delta x$.
- b) Calculate the time it takes to cover those $400\ \text{m}$.
A driver travels at $90\ \text{km/h}$, takes $0.8\ \text{s}$ to react to an obstacle and then brakes at $a = -5\ \text{m/s}^2$. The diagram shows the two stages of…
A driver travels at $90\ \text{km/h}$, takes $0.8\ \text{s}$ to react to an obstacle and then brakes at $a = -5\ \text{m/s}^2$. The diagram shows the two stages of stopping.
- a) Express the speed in $\text{m/s}$ and calculate the distance travelled during the reaction time.
- b) Calculate the braking time and braking distance.
- c) Calculate the total stopping distance, which is the sum of the previous two.
A car travels at $108\ \text{km/h}$. a) Express this speed in $\text{m/s}$. b) Calculate the braking distance on a dry road surface, with $a = -6\ \text{m/s}^2$. c)…
A car travels at $108\ \text{km/h}$.
- a) Express this speed in $\text{m/s}$.
- b) Calculate the braking distance on a dry road surface, with $a = -6\ \text{m/s}^2$.
- c) Calculate the braking distance on a wet road surface, with $a = -3\ \text{m/s}^2$.
- d) If the driver's reaction time is $0.5\ \text{s}$, calculate the total stopping distance in both cases and explain why it is advisable to increase the safe distance when it rains.
Free fall and vertical projection
If you throw a sliotar vertically upwards, you see it lose speed until it stops in mid-air and then falls back down faster and faster: how does a single equation describe both the rise and the fall under the invisible action of gravity? We will also see how to measure $g$ ourselves.
A coin is dropped from the top of a $20\ \text{m}$ tower. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the time it takes to reach the ground. b) Calculate the…
A coin is dropped from the top of a $20\ \text{m}$ tower. Take $g \approx 10\ \text{m/s}^2$.
- a) Calculate the time it takes to reach the ground.
- b) Calculate the velocity with which it arrives.
A stone is thrown vertically downwards at $v_0 = 10\ \text{m/s}$ from a bridge $15\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$. Look at the diagram: a) Set up the…
A stone is thrown vertically downwards at $v_0 = 10\ \text{m/s}$ from a bridge $15\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$. Look at the diagram:
- a) Set up the position equation taking the water surface as the origin and calculate the time it takes to reach the water.
- b) Calculate the velocity with which it arrives.
A juggler throws a ball vertically upwards at $v_0 = 30\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$. Look at the launch diagram: a) Calculate the time it takes to…
A juggler throws a ball vertically upwards at $v_0 = 30\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$. Look at the launch diagram:
- a) Calculate the time it takes to reach maximum height.
- b) Calculate this maximum height.
- c) How much time passes until the ball returns to his hand and with what velocity does it arrive? Justify your answer using the symmetry of the motion.
A ball is thrown vertically upwards at $v_0 = 10\ \text{m/s}$ from a balcony $15\ \text{m}$ above the ground. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the maximum…
A ball is thrown vertically upwards at $v_0 = 10\ \text{m/s}$ from a balcony $15\ \text{m}$ above the ground. Take $g \approx 10\ \text{m/s}^2$.
- a) Calculate the maximum height it reaches, measured from the ground.
- b) Set up the position equation taking the ground as the origin and calculate the total flight time until it reaches the ground.
- c) Calculate the velocity with which it hits the ground.
- d) Compare this flight time with the time it would take if it were simply dropped from the balcony, and explain the difference.
A hot-air balloon ascends at a constant velocity of $8\ \text{m/s}$. When it is at a height of $48\ \text{m}$, a ballast bag becomes detached. Take…
A hot-air balloon ascends at a constant velocity of $8\ \text{m/s}$. When it is at a height of $48\ \text{m}$, a ballast bag becomes detached. Take $g \approx 10\ \text{m/s}^2$. Look at the diagram of the situation:
- a) Explain why the bag, upon release, continues to rise for a few moments instead of falling immediately.
- b) Set up the position equation of the bag taking the ground as the origin, and calculate the time it takes to reach the ground.
- c) Calculate the velocity with which it hits the ground.
- d) Calculate the height of the balloon at the moment the bag touches the ground.
Uniform circular motion: period, frequency and velocities
The blades of a ceiling fan take $0.5\ \text{s}$ to complete one full revolution. a) What are the period $T$ and the frequency $f$ of the rotation? b) Calculate the…
The blades of a ceiling fan take $0.5\ \text{s}$ to complete one full revolution.
- a) What are the period $T$ and the frequency $f$ of the rotation?
- b) Calculate the angular velocity $\omega = \frac{2\pi}{T}$, in $\text{rad/s}$, and round it to one decimal place.
A Ferris wheel rotates with constant angular velocity $\omega = 0.5\ \text{rad/s}$ and its radius is $r = 10\ \text{m}$. The diagram shows one car on the rim and another…
A Ferris wheel rotates with constant angular velocity $\omega = 0.5\ \text{rad/s}$ and its radius is $r = 10\ \text{m}$. The diagram shows one car on the rim and another closer to the axle.
- a) Calculate the linear velocity $v = \omega \times r$ of a car located on the rim.
- b) Explain why a car located closer to the axle would move more slowly, even though the angular velocity is the same.
A bicycle moves forward at $7\ \text{m/s}$ and its wheels have a radius of $0.35\ \text{m}$. a) Calculate the angular velocity of the wheels, given that at the rim…
A bicycle moves forward at $7\ \text{m/s}$ and its wheels have a radius of $0.35\ \text{m}$.
- a) Calculate the angular velocity of the wheels, given that at the rim $v = \omega \times r$.
- b) Calculate the period of rotation of the wheel.
- c) Calculate the distance the bicycle moves forward per complete revolution of the wheel, and explain why it equals the circumference.
Centripetal acceleration and centripetal force
When riding on a merry-go-round that turns at a steady rate, a speedometer would show a constant speed, but you feel your body tending to continue in a straight line and needing a force to avoid being flung off: if the value of the speed does not change, why do you experience an acceleration? Which force provides it?
A skater takes a bend of radius $8\ \text{m}$ at $4\ \text{m/s}$. The diagram shows the bend and the velocity vector. a) Calculate their normal acceleration…
A skater takes a bend of radius $8\ \text{m}$ at $4\ \text{m/s}$. The diagram shows the bend and the velocity vector.
- a) Calculate their normal acceleration $a_n = \frac{v^2}{r}$.
- b) State its direction and sense.
Beyond the syllabus: accelerated circular motion
A cyclist on a bend of radius $50\ \text{m}$ at $10\ \mathrm{m\,s^{-1}}$ has a centripetal acceleration $a_c=v^2/r=2\ \mathrm{m\,s^{-2}}$. If the cyclist is also speeding up at $a_t=1.5\ \mathrm{m\,s^{-2}}$, the two components are perpendicular, so the total acceleration is $\sqrt{2^2+1.5^2}=2.5\ \mathrm{m\,s^{-2}}$.