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Change · The laws of chemical reactions

Law of definite proportions (Proust)

If you analyse tap water from your home in Cork and water from a stream in the Wicklow Mountains, will they have the same proportion of hydrogen and oxygen? The answer is yes, always, and that very simple fact is one of the most useful laws in chemistry.

Proust's discovery

At the end of the 18th century, the French chemist Joseph Louis Proust analysed the same compound obtained from very different sources (natural minerals, laboratory reactions...) and found something surprising: the proportion between the elements that made it up was always identical. This is what separates a compound from a mixture: in a mixture, such as sand and salt, you can mix the parts in any proportion, but a compound like water has a fixed composition.

Three samples of water from different origins (rain, laboratory and a mountain stream) have the same composition by mass: 1 g of hydrogen for every 8 g of oxygen. rainwater laboratory water stream water 1 g H 8 g O 1 g H 8 g O 1 g H 8 g O in all three: 1 g of H for every 8 g of O
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We analyse distilled water from a laboratory and collected, purified rainwater. In what ratio do hydrogen and oxygen combine in each? What does Proust's law say about…

We analyse distilled water from a laboratory and collected, purified rainwater. In what ratio do hydrogen and oxygen combine in each? What does Proust's law say about the origin of the samples?

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Complete the sentence with the missing words: "When two or more elements combine to form a specific $\dots$, they always do so in the same proportion by $\dots$,…

Complete the sentence with the missing words: "When two or more elements combine to form a specific $\dots$, they always do so in the same proportion by $\dots$, regardless of the amount of $\dots$ or its origin."

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Calculating with a fixed proportion

If you know the proportion of a compound, you can calculate the mass of one element from the mass of the other, just as you would with a cooking recipe.

Notice that the more hydrogen you add, the more oxygen you need to keep exactly the same $1:8$ proportion.

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In water, hydrogen and oxygen combine in the ratio of $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen. How many grams of oxygen will combine with…

In water, hydrogen and oxygen combine in the ratio of $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen. How many grams of oxygen will combine with $4\ \text{g}$ of hydrogen?

Solve
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To form carbon dioxide, carbon and oxygen combine in the ratio of $3\ \text{g}$ of carbon for every $8\ \text{g}$ of oxygen. What mass of oxygen do you need to…

To form carbon dioxide, carbon and oxygen combine in the ratio of $3\ \text{g}$ of carbon for every $8\ \text{g}$ of oxygen. What mass of oxygen do you need to completely burn $9\ \text{g}$ of carbon?

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We completely decompose $90\ \text{g}$ of water into its elements (ratio $1:8$ between hydrogen and oxygen). What mass of hydrogen and what mass of oxygen are obtained?

We completely decompose $90\ \text{g}$ of water into its elements (ratio $1:8$ between hydrogen and oxygen). What mass of hydrogen and what mass of oxygen are obtained?

Solve

Are they the same compound?

Proust's law also works the other way round: if you are given two samples with different masses of the same elements, you can check whether they are consistent with the same compound by calculating the proportion for each one.

Comparison of two samples of iron and oxygen with different masses: the quotient of the masses of Fe and O is 2.33 in both, so they are consistent with the same compound. masses of each sample quotient m(Fe) / m(O) sample A 14 g Fe + 6 g O sample B 21 g Fe + 9 g O 14 / 6 ≈ 2.33 21 / 9 ≈ 2.33 same proportion: consistent with the same compound (the masses differ, but the quotient is the same)
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One sample contains $3\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen, and another contains $3\ \text{g}$ of carbon and $4\ \text{g}$ of oxygen. Could they be the same…

One sample contains $3\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen, and another contains $3\ \text{g}$ of carbon and $4\ \text{g}$ of oxygen. Could they be the same compound? Justify your answer using Proust's law.

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Real measurements and impure samples

Real measurements are never perfect. A balance has limited precision, and samples may contain impurities. So you compare the measured ratio with the expected one and decide whether the gap is small or large.

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One water sample contains $2\ \text{g}$ of hydrogen and $16\ \text{g}$ of oxygen; another sample contains $5\ \text{g}$ of hydrogen and $40\ \text{g}$ of oxygen. The…

One water sample contains $2\ \text{g}$ of hydrogen and $16\ \text{g}$ of oxygen; another sample contains $5\ \text{g}$ of hydrogen and $40\ \text{g}$ of oxygen. The figure compares the composition of the two samples.

hydrogen oxygen 16 g 2 g sample A 40 g 5 g sample B

Calculate the ratio between hydrogen and oxygen in each sample and reason whether they could be the same compound.

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A class measures the composition of water and obtains $10.2\ \text{g}$ of hydrogen and $79.8\ \text{g}$ of oxygen. a) Calculate the oxygen/hydrogen ratio (to one decimal…

A class measures the composition of water and obtains $10.2\ \text{g}$ of hydrogen and $79.8\ \text{g}$ of oxygen.

  1. a) Calculate the oxygen/hydrogen ratio (to one decimal place) and compare it with the theoretical ratio $8:1$.
  2. b) Should we conclude that Proust's law fails? Reason your answer.
  3. c) Point out two possible causes for the slight discrepancy with the theoretical value.
Solve
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A laboratory receives $250\ \text{g}$ of a white mineral that the supplier claims is pure calcium oxide (calcium:oxygen ratio $5:2$). Analysis reveals $175\ \text{g}$ of…

A laboratory receives $250\ \text{g}$ of a white mineral that the supplier claims is pure calcium oxide (calcium:oxygen ratio $5:2$). Analysis reveals $175\ \text{g}$ of calcium and $75\ \text{g}$ of oxygen.

  1. a) Check whether the mineral could be pure calcium oxide.
  2. b) What mass of oxygen should accompany $175\ \text{g}$ of calcium if it were?
  3. c) Propose an explanation for the result of the analysis.
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Two elements, more than one compound

Sometimes two elements combine in more than one fixed proportion, and each proportion gives rise to a different compound, with different properties.

Atomic diagram of two different oxides of copper: one with two copper atoms for each oxygen atom and one with one copper atom for each oxygen atom. CuCuO Oxide 1 2 Cu atoms for 1 O atom(by mass: 8 g Cu : 1 g O, sample 2) CuO Oxide 2 1 Cu atom for 1 O atom(by mass: 4 g Cu : 1 g O, sample 1)
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Copper can form two different oxides. In one sample, $8\ \text{g}$ of copper combine with $2\ \text{g}$ of oxygen; in another sample, $8\ \text{g}$ of copper combine…

Copper can form two different oxides. In one sample, $8\ \text{g}$ of copper combine with $2\ \text{g}$ of oxygen; in another sample, $8\ \text{g}$ of copper combine with $1\ \text{g}$ of oxygen. The figure compares the composition of the two samples.

sample 1 8 g 2 g sample 2 8 g 1 g copper oxygen

Is it the same oxide? How do you know?

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We analyse three samples of "iron oxide". Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B, $14\ \text{g}$ of iron and $4\ \text{g}$ of…

We analyse three samples of "iron oxide". Sample A contains $14\ \text{g}$ of iron and $6\ \text{g}$ of oxygen; sample B, $14\ \text{g}$ of iron and $4\ \text{g}$ of oxygen; sample C, $21\ \text{g}$ of iron and $9\ \text{g}$ of oxygen.

  1. a) Calculate the iron:oxygen ratio for each sample.
  2. b) Which of them are the same compound?
  3. c) Explain why iron can give rise to more than one different oxide.
Solve
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Carbon and oxygen can form two different gases. In sample A, there are $6\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen; in sample B, there are $6\ \text{g}$ of…

Carbon and oxygen can form two different gases. In sample A, there are $6\ \text{g}$ of carbon and $8\ \text{g}$ of oxygen; in sample B, there are $6\ \text{g}$ of carbon and $16\ \text{g}$ of oxygen. The figure shows the model of each molecule.

sample A C O 6 g of C 8 g of O sample B O C O 6 g of C 16 g of O
  1. a) Calculate the carbon:oxygen ratio for each sample.
  2. b) Are they the same compound?
  3. c) Given that one of the gases is carbon monoxide (highly toxic) and the other is carbon dioxide, explain why Proust's law allows us to distinguish between them even though they are made of the same elements.
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When there is reactant left over

If you mix two elements without respecting their exact proportion, not everything reacts: the one in excess is left over without combining.

Bars of 10 g of hydrogen and 64 g of oxygen, drawn so that 1 g of hydrogen has the same length as 8 g of oxygen: the oxygen is only enough for 8 g of hydrogen; the remaining 2 g of hydrogen are left over without reacting. Drawn so that 1 g of H has the same length as 8 g of O Hydrogen (10 g) 8 g react 2 g of H left over Oxygen (64 g) 64 g O (≙ 8 g H) equivalent to only 8 g of H Reacts Left over (excess)
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In a sealed container, we place $10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen and cause them to react (the combination ratio is $1:8$). The figure shows the…

In a sealed container, we place $10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen and cause them to react (the combination ratio is $1:8$). The figure shows the container before the reaction.

hydrogen 10 g oxygen 64 g
  1. a) Does all the hydrogen react?
  2. b) What mass of water is formed?
  3. c) Is there any gas left over? What mass?
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We mix $16\ \text{g}$ of hydrogen with $100\ \text{g}$ of oxygen and trigger the reaction (ratio $1:8$). a) What mass of each gas reacts? b) What mass of water is…

We mix $16\ \text{g}$ of hydrogen with $100\ \text{g}$ of oxygen and trigger the reaction (ratio $1:8$).

  1. a) What mass of each gas reacts?
  2. b) What mass of water is formed?
  3. c) What mass of hydrogen is left over?
Solve
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A student claims: "If I add twice as much oxygen, the water that forms will contain twice as much oxygen." To test this, we combine $4\ \text{g}$ of hydrogen with…

A student claims: "If I add twice as much oxygen, the water that forms will contain twice as much oxygen." To test this, we combine $4\ \text{g}$ of hydrogen with $64\ \text{g}$ of oxygen (twice as much as necessary).

  1. a) Calculate the mass of water formed and the mass of oxygen left over.
  2. b) Use Proust's law to explain why the student is mistaken.
Solve

Back to the start: tap water in Cork and water from a Wicklow stream both contain exactly $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen, because pure water is the same compound wherever it comes from.

Summary

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