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ESO Y4B · Mathematics
Functions · Functions

Rate of change, average rate of change and growth rate

A speedometer does not measure the average speed of a whole journey, but the speed at each particular instant. Until now you have only known how to calculate an average: how much a function changes, on average, between two points. In this section that idea is made precise with its geometric interpretation (the gradient of a secant line) and we begin to answer a finer question: what happens to the function exactly at one point, rather than on average over a stretch? That question is the entry point to the concept of the derivative, which will be formalised later on.

Rate of change and average rate of change

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The following table shows the temperature $T$ (in $^{\circ}C$) of a chemical reaction as a function of time $t$ (in minutes). For $t = 0$, $T = 15$ For $t = 1$, $T = 18$…

The following table shows the temperature $T$ (in $^{\circ}C$) of a chemical reaction as a function of time $t$ (in minutes).

  • For $t = 0$, $T = 15$

  • For $t = 1$, $T = 18$

  • For $t = 2$, $T = 24$

  • For $t = 3$, $T = 32$

  • For $t = 4$, $T = 45$

  • For $t = 5$, $T = 60$

Calculate the Rate of Change (RC), that is, the total change in temperature $T(5) - T(2)$, and the Average Rate of Change (ARC) on the interval $[2, 5]$.

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Given the linear function $f(x) = 4x - 5$, calculate its average rate of change on the intervals $[-2, 1]$ and $[3, 6]$. What conclusion can you draw about the average…

Given the linear function $f(x) = 4x - 5$, calculate its average rate of change on the intervals $[-2, 1]$ and $[3, 6]$. What conclusion can you draw about the average rate of change of linear functions?

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Calculate the average rate of change of the quadratic function $f(x) = x^2 - 6x + 8$ on the interval $[1, 4]$.

Calculate the average rate of change of the quadratic function $f(x) = x^2 - 6x + 8$ on the interval $[1, 4]$.

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Geometric interpretation: the secant line

Graph of a function with a secant line joining two points A and B, highlighting the horizontal and vertical increases that determine its gradient. A(a, f(a))B(b, f(b)) Δx = b − aΔy = f(b) − f(a) secant line AB, gradient = ARC[a,b]
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The graph shows the growth of a plant, where $h(t)$ is the height in centimetres and $t$ is the time in weeks. From the graph, calculate the average rate of change of…

The graph shows the growth of a plant, where $h(t)$ is the height in centimetres and $t$ is the time in weeks. From the graph, calculate the average rate of change of the height on the interval $[1, 4]$.

t (weeks) h (cm) 1 2 3 4 5 20 40 60 80 100
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The following graph shows the number of viewers $V(t)$, in thousands, of the broadcasts of an e-sports tournament during the first $5$ months of the season. Calculate…

The following graph shows the number of viewers $V(t)$, in thousands, of the broadcasts of an e-sports tournament during the first $5$ months of the season. Calculate the average rate of change in the intervals $[1, 3]$ and $[3, 5]$. Interpret the meaning of the signs obtained in each case.

t (months) V (thousands) 0 1 2 3 4 5 6 5 10 15 20 25
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Consider the quadratic function $f(x) = x^2 - 3x + 2$. Calculate the average rate of change in the interval $[2, 5]$ and use this value to write the equation of the…

Consider the quadratic function $f(x) = x^2 - 3x + 2$. Calculate the average rate of change in the interval $[2, 5]$ and use this value to write the equation of the secant line to the graph of $f(x)$ passing through the points with x-coordinates $x = 2$ and $x = 5$.

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Growth rate: relative and percentage change

Comparative graph of two quantities with the same absolute increase but different starting values, to illustrate the percentage growth rate. f(a) = 2000 f(b) = 2500 +25 %
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The number of active users of a mobile app went from $2000$ to $2500$ over the course of a month. Calculate the percentage growth rate.

The number of active users of a mobile app went from $2000$ to $2500$ over the course of a month. Calculate the percentage growth rate.

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The value of a car depreciates according to the function $V(t) = 24000 \cdot 0,85^t$, where $t$ is the number of years since its purchase and $V(t)$ is the price in…

The value of a car depreciates according to the function $V(t) = 24000 \cdot 0,85^t$, where $t$ is the number of years since its purchase and $V(t)$ is the price in euros. Calculate the percentage growth rate in the first year (interval $[0, 1]$) and explain the practical meaning of its sign.

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The price of a tech product was $800$ € at launch. Two months later, its price dropped to $640$ €. Assuming a linear decrease model, calculate the monthly average rate…

The price of a tech product was $800$ € at launch. Two months later, its price dropped to $640$ €. Assuming a linear decrease model, calculate the monthly average rate of change and the total percentage growth rate in those first two months.

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Instantaneous rate of change: narrowing the interval

The idea is simple: you fix the endpoint $a$ and let the other endpoint $b$ get closer and closer to $a$. The secant joining $A(a,f(a))$ with $B(b,f(b))$ keeps rotating and, when $b$ is very close to $a$, it approaches a line that "touches" the graph exactly at $A$ without crossing it: the tangent line.

Animation: point B moves along the curve towards point A and the secant line joining them rotates about A; the earlier positions of b fade out and in the end the secant merges with the tangent line. b far away b closer b almost at a: tangent A(a, f(a))
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The views of a viral video grow according to the mathematical model $N(t) = 100 \cdot 2^t$, where $N$ is the number of views in thousands and $t$ is measured in days.…

The views of a viral video grow according to the mathematical model $N(t) = 100 \cdot 2^t$, where $N$ is the number of views in thousands and $t$ is measured in days. Calculate the average rate of change in the intervals $[1, 3]$ and $[3, 5]$. Compare the results and explain what they indicate about the video's rate of growth.

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Obtain the simplified algebraic expression for the average rate of change of the function $f(x) = 2x^2 - 5x + 1$ in the generic interval $[a, a+h]$, where $h > 0$.

Obtain the simplified algebraic expression for the average rate of change of the function $f(x) = 2x^2 - 5x + 1$ in the generic interval $[a, a+h]$, where $h > 0$.

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The position of an object in free fall is given by $e(t) = 5t^2$ (where $e$ is measured in metres and $t$ in seconds). Find the exact instant in time $t > 1$ for which…

The position of an object in free fall is given by $e(t) = 5t^2$ (where $e$ is measured in metres and $t$ in seconds). Find the exact instant in time $t > 1$ for which the average velocity (which coincides with the average rate of change) in the interval $[1, t]$ is exactly $25$ m/s.

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Comparing rates of change over different stretches

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A stone is dropped from a high bridge. The height $h$ (in metres) above the water surface as a function of time $t$ (in seconds) is given by the equation…

A stone is dropped from a high bridge. The height $h$ (in metres) above the water surface as a function of time $t$ (in seconds) is given by the equation $h(t) = 45 - 5t^2$. Calculate the average rate of change in the interval $[1; 2,5]$. What physical quantity does this value represent, and why does it have a negative sign?

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The volume $V$ (in litres) of water in an industrial tank being emptied is given by the function $V(t) = 500 - 10t - t^2$, where $t$ is measured in minutes. Calculate…

The volume $V$ (in litres) of water in an industrial tank being emptied is given by the function $V(t) = 500 - 10t - t^2$, where $t$ is measured in minutes. Calculate the average rate of change in the intervals $[0, 5]$ and $[5, 10]$. In which time interval does the tank empty faster?

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The stopping distance $d$ (in metres) of a vehicle as a function of its speed $v$ (in km/h) is modelled by the function $d(v) = 0,005v^2 + 0,2v$. Calculate the average…

The stopping distance $d$ (in metres) of a vehicle as a function of its speed $v$ (in km/h) is modelled by the function $d(v) = 0,005v^2 + 0,2v$. Calculate the average rate of change in the intervals $[40, 60]$ and $[100, 120]$. Give reasons why the average increase in stopping distance is much greater at high speeds.

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Given the rational function $f(x) = \frac{x^2 + 4}{x}$, calculate and compare the average rate of change in the intervals $[1, 2]$ and $[-2, -1]$. Justify analytically…

Given the rational function $f(x) = \frac{x^2 + 4}{x}$, calculate and compare the average rate of change in the intervals $[1, 2]$ and $[-2, -1]$. Justify analytically why the same result is obtained by using the odd symmetry of the function.

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Back to the beginning: The speedometer measures the instantaneous rate of change: the average speed calculated over such a tiny time interval that it practically coincides with the gradient of the tangent line at that exact second.

Summary

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