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ESO Y4B · Physics and Chemistry
Interaction · Forces and pressure in fluids

Pressure and hydrostatic pressure

You can push a drawing pin into a wall with no effort, but if you pressed your flat finger against the same wall, however hard you pushed, it would not go in. The force from your hand can be exactly the same in both cases, measured with the same newton meter. The only thing that changes is the area over which that force is spread. That simple idea is what turns a moderate force into something capable of cutting, piercing or supporting kilometres of water.

Before you start, make sure you know: Density (2nd ESO)
Before you start, make sure you know: Surface area (1st ESO)

What pressure is

Two blocks bear the same force of 200 N: the one with the small base exerts a greater pressure on the floor and the one with the large base exerts a smaller pressure. F = 200 N small S → large p F = 200 N large S → small p

With the same force, the smaller the area, the greater the pressure. That is why a drawing pin goes in easily and a flat finger against the wall does not: in both cases the force can be identical, but the area it acts on changes by several orders of magnitude.

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A crate of books pushes against the floor with a force of $200\ \text{N}$ distributed over a base of $0,5\ \text{m}^2$, as shown in the figure. Calculate the pressure it…

A crate of books pushes against the floor with a force of $200\ \text{N}$ distributed over a base of $0,5\ \text{m}^2$, as shown in the figure.

F = 200 N S = 0,5 m² p = ?

Calculate the pressure it exerts on the floor, in pascals, using $p = \frac{F}{S}$.

Solve
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In what unit is pressure measured in the International System of Units? Write its equivalence in units of force and surface area, and state after which scientist it is…

In what unit is pressure measured in the International System of Units? Write its equivalence in units of force and surface area, and state after which scientist it is named.

Solve
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A workshop punch pushes against a metal sheet with a force of $20\ \text{N}$ and its tip has a surface area of $4\ \text{mm}^2$. a) Express the surface area of the tip…

A workshop punch pushes against a metal sheet with a force of $20\ \text{N}$ and its tip has a surface area of $4\ \text{mm}^2$.

  1. a) Express the surface area of the tip in $\text{m}^2$.
  2. b) Calculate the pressure exerted by the punch on the metal sheet.
Solve

The role of the contact area

A hiker of the same weight, 600 N, standing on snow: in boots, with a small area, she sinks in; on skis, with a much larger area, she receives less pressure and does not sink. F = 600 N In boots S₁ = 0,02 m² p₁ = 30 000 Pa small S: sinks in hollow in the snow F = 600 N On skis S₂ = 0,6 m² p₂ = 1 000 Pa larger S: does not sink ski on the snow Same weight F: 30 times more S → 30 times less pressure
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A hiker walks through freshly fallen snow in boots and sinks up to her ankle; the next day she goes through the same place on skis and leaves hardly a footprint, as…

A hiker walks through freshly fallen snow in boots and sinks up to her ankle; the next day she goes through the same place on skis and leaves hardly a footprint, as shown in the figure.

P boots P skis

If her weight is the same in both cases, explain using the concept of pressure why she does not sink when wearing skis.

Solve
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A skier of $60\ \text{kg}$ is standing on the snow. Take $g = 10\ \text{m/s}^2$. a) Calculate her weight. b) Wearing boots, she rests on two soles of…

A skier of $60\ \text{kg}$ is standing on the snow. Take $g = 10\ \text{m/s}^2$.

  1. a) Calculate her weight.
  2. b) Wearing boots, she rests on two soles of $25\ \text{cm} \times 10\ \text{cm}$ each. Calculate the pressure she exerts on the snow (take care with unit conversions).
  3. c) Wearing skis, she rests on two skis of $1,5\ \text{m} \times 0,2\ \text{m}$ each. Calculate the pressure now.
  4. d) Compare the two results and explain why she does not sink when wearing skis.
Solve
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Compare the following two situations, shown in the figure. Take $g = 10\ \text{m/s}^2$. a) A $55\ \text{kg}$ person rests all their weight on two stiletto heels of…

Compare the following two situations, shown in the figure. Take $g = 10\ \text{m/s}^2$.

55 kg S = 2 × 1 cm² 5 000 kg S = 4 × 0,1 m²
  1. a) A $55\ \text{kg}$ person rests all their weight on two stiletto heels of $1\ \text{cm}^2$ each: calculate the pressure exerted on the ground (take care with unit conversions).
  2. b) A $5\,000\ \text{kg}$ elephant rests on its four feet, of $0,1\ \text{m}^2$ each: calculate the pressure it exerts.
  3. c) Who exerts more pressure on the ground? Compare the results and explain the role played by the contact area.
Solve

Pressure inside a liquid: hydrostatic pressure

If you pierce a plastic bottle of water at three different heights, the jet from the lowest hole shoots out with much more speed and range than the one from the highest: why does the liquid push harder at the bottom if the water is exactly the same?

Tank of water at rest with three points at depths h₁, h₂ and h₃ measured from the free surface. At each point, arrows show that the pressure acts in all directions and that it is greater the deeper the point is. On the right, a triangle shows that pressure increases in proportion to depth according to p = d·g·h. free surface of the liquid h₁ h₂ h₃ h₁: lower p h₂: medium p h₃: higher p p = d · g · h pressure increases with depth
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A swimming pool is $2\ \text{m}$ deep, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$. Calculate the pressure exerted by…

A swimming pool is $2\ \text{m}$ deep, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ h = 2 m p = ?

Calculate the pressure exerted by the water on the bottom using $p = d\cdot g\cdot h$.

Solve
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The water tank of a housing estate is at the top of a tower, $12\ \text{m}$ above the tap of a house, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$;…

The water tank of a housing estate is at the top of a tower, $12\ \text{m}$ above the tap of a house, as shown in the figure. Given: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 9,8\ \text{m/s}^2$.

p₁ = ? p₂ = ? 12 m 3 m
  1. a) Calculate the pressure due to the column of water reaching the tap.
  2. b) What will that pressure be at the tap on the ground floor, located $3\ \text{m}$ lower down?
Solve
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A dam holds back water in a reservoir that reaches a depth of $30\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take…

A dam holds back water in a reservoir that reaches a depth of $30\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ 30 m p = ? S = 2 m² F = ?
  1. a) What pressure does the water exert on the base of the dam?
  2. b) A small sluice gate at the bottom has a surface area of $2\ \text{m}^2$; assume that the whole gate is subject to the pressure found in part a). With what force does the water push against that sluice gate?
Solve
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A dam holds back water in a reservoir with a maximum depth of $40\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take…

A dam holds back water in a reservoir with a maximum depth of $40\ \text{m}$ next to the wall, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ 40 m 10 m p(10 m) = ? p(40 m) = ?
  1. a) What pressure does the wall withstand at its base?
  2. b) What about at a depth of $10\ \text{m}$?
  3. c) With those two results, explain why dams are built much thicker at their base than at the top.
Solve

Total pressure and atmospheric pressure

When an object is submerged in a liquid open to the atmosphere, the pressure it bears is not only the hydrostatic pressure: you have to add the pressure of the air pushing on the free surface of the liquid.

Open tank with liquid: atmospheric pressure acts on the free surface and, at a depth h, the total pressure is the sum p(total) = p(atm) + d·g·h. p(atm) h p(total) = p(atm) + d·g·h
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What is atmospheric pressure? Name the instrument used to measure it and write down its approximate value at sea level, in pascals.

What is atmospheric pressure? Name the instrument used to measure it and write down its approximate value at sea level, in pascals.

Solve
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A scuba diver dives at a depth of $10\ \text{m}$ in a lake, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take…

A scuba diver dives at a depth of $10\ \text{m}$ in a lake, as shown in the figure. Data: $d_{agua} = 1\,000\ \text{kg/m}^3$, $p_{atm} = 101\,300\ \text{Pa}$; take $g = 10\ \text{m/s}^2$.

d = 1 000 kg/m³ atmospheric pressure 101 300 Pa 10 m p = ?
  1. a) Calculate the pressure due solely to the water above him.
  2. b) Calculate the total pressure he experiences, adding atmospheric pressure.
  3. c) How many times atmospheric pressure is that total pressure? Comment on the result.
Solve
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In Torricelli's experiment, a glass tube is filled with mercury and inverted over a trough containing mercury: the column falls until it reaches a height of…

In Torricelli's experiment, a glass tube is filled with mercury and inverted over a trough containing mercury: the column falls until it reaches a height of $76\ \text{cm}$ above the surface of the trough, as shown in the figure. Data: $d_{Hg} = 13\,600\ \text{kg/m}^3$; take $g = 9,8\ \text{m/s}^2$.

d(Hg) = 13 600 kg/m³ vacuum 76 cm atmospheric pressure p = ?
  1. a) Calculate the pressure exerted by this mercury column on its base.
  2. b) Compare the result with the value of atmospheric pressure at sea level and explain what the experiment demonstrates and what is at the top of the tube.
  3. c) What height should the column be if the experiment were carried out with water instead of mercury?
Solve
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A mountaineer climbs Mulhacén ($3\,479\ \text{m}$) and their barometer reads $670\ \text{hPa}$; before setting off, at sea level, it read $1\,013\ \text{hPa}$. a)…

A mountaineer climbs Mulhacén ($3\,479\ \text{m}$) and their barometer reads $670\ \text{hPa}$; before setting off, at sea level, it read $1\,013\ \text{hPa}$.

  1. a) Express both pressures in pascals.
  2. b) What percentage of the sea-level pressure remains at the summit?
  3. c) Explain why atmospheric pressure decreases with altitude (think about how much air remains above you) and explain why water boils below $100\ \celsius$ at the summit.
Solve

Back to the start: If you push with a force of $30\ \text{N}$, the tip of your flat finger ($S \approx 1{,}5\ \text{cm}^2 = 1{,}5 \cdot 10^{-4}\ \text{m}^2$) exerts $200\,000\ \text{Pa}$, whereas the point of the drawing pin ($S \approx 0{,}1\ \text{mm}^2 = 10^{-7}\ \text{m}^2$) concentrates that same force and produces $300\,000\,000\ \text{Pa}$: fifteen hundred times more pressure with the same effort!

Summary

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