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ESO Y4B · Physics and Chemistry
Chemical change · Chemical reactions of interest

Neutralisation reactions

Heartburn is relieved with an antacid; a soil that is too acidic is corrected with lime; a wasp sting is treated with a little vinegar. All three cases are the same type of reaction: an acid meets a base and they "cancel" each other out, with a precision that stoichiometry lets us calculate to the gram.

Before you start, make sure you know: Chemical equations and how to balance them (3rd ESO)
Before you start, make sure you know: Solutions and concentration (2nd ESO)

Acids, bases and the pH scale

Lemon juice tastes sour and corrodes marble, whereas soap is slippery and turns red cabbage extract green: how can we order and quantify these differences using a single numerical scale?

pH scale graduated from 0 to 14: acidic zone below 7, neutral point at 7 and basic zone above 7, with an arrow showing the direction in which the pH increases. neutral acidic pH < 7 basic pH > 7 0 7 14 pH the lower, the more acidic the higher, the more basic
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Classify each of these substances as an acid, a base or a salt: a) $HNO_3$ (nitric acid) b) $KOH$ (potassium hydroxide) c) $NaCl$ (sodium chloride) d) $H_2SO_4$…

Classify each of these substances as an acid, a base or a salt:

  1. a) $HNO_3$ (nitric acid)
  2. b) $KOH$ (potassium hydroxide)
  3. c) $NaCl$ (sodium chloride)
  4. d) $H_2SO_4$ (sulfuric acid)
  5. e) $Ca(OH)_2$ (calcium hydroxide)
Solve
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pH measures how acidic or basic a solution is. These are the positions of the four solutions on the pH scale: State whether each of these solutions is acidic, neutral or…

pH measures how acidic or basic a solution is. These are the positions of the four solutions on the pH scale:

pH 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 lemon juice crushed tomato pure water hand soap

State whether each of these solutions is acidic, neutral or basic:

  1. a) lemon juice, $pH = 2,5$
  2. b) pure water, $pH = 7$
  3. c) hand soap, $pH = 10$
  4. d) crushed tomato, $pH = 4,5$
Solve

The heart of neutralisation: $\text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O}$

When hydrochloric acid and caustic soda, two enormously corrosive substances on their own, are carefully mixed, the result is harmless salty water that gives off heat: what transformation takes place at the level of particles for both compounds to lose their aggressiveness?

An H⁺ ion and a hydroxide ion OH⁻ combine to form a neutral water molecule H₂O, with the oxygen bonded to two hydrogens at an angle of about 104.5 degrees. + H⁺ + O H OH⁻ O H H H₂O neutral, pH = 7
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Complete the general scheme of a neutralisation reaction with the missing words: "An $\dots$ reacts with a $\dots$ to form a $\dots$ and $\dots$". Then give an example…

Complete the general scheme of a neutralisation reaction with the missing words: "An $\dots$ reacts with a $\dots$ to form a $\dots$ and $\dots$". Then give an example using the reaction between hydrochloric acid and sodium hydroxide.

Solve
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In the laboratory, hydrochloric acid ($HCl$) is mixed with sodium hydroxide ($NaOH$) to form sodium chloride ($NaCl$), common salt, and water. Write the reaction…

In the laboratory, hydrochloric acid ($HCl$) is mixed with sodium hydroxide ($NaOH$) to form sodium chloride ($NaCl$), common salt, and water. Write the reaction equation and check by counting atoms that it is balanced.

Solve

Balancing neutralisations with polyprotic acids and bases

When the acid provides more than one $\text{H}^+$ per molecule, or the base more than one $\text{OH}^-$, we need to balance carefully so that every ion finds a partner. The rule is the same as always: metals and non-metals first, H and O last.

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Sulfuric acid ($H_2SO_4$) reacts with calcium hydroxide ($Ca(OH)2$) to form calcium sulfate ($CaSO_4$) and water. Write the equation and balance it; pay close attention…

Sulfuric acid ($H_2SO_4$) reacts with calcium hydroxide ($Ca(OH)_2$) to form calcium sulfate ($CaSO_4$) and water. Write the equation and balance it; pay close attention to how many water molecules are formed for each calcium sulfate.

Solve
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Write and balance the equation for the neutralisation between hydrochloric acid ($HCl$) and calcium hydroxide ($Ca(OH)2$), forming calcium chloride ($CaCl_2$) and water.

Write and balance the equation for the neutralisation between hydrochloric acid ($HCl$) and calcium hydroxide ($Ca(OH)_2$), forming calcium chloride ($CaCl_2$) and water.

Solve
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Phosphoric acid ($H_3PO_4$), present in some cola soft drinks, reacts with calcium hydroxide to form calcium phosphate ($Ca_3(PO_4)2$) and water. a) Write and balance…

Phosphoric acid ($H_3PO_4$), present in some cola soft drinks, reacts with calcium hydroxide to form calcium phosphate ($Ca_3(PO_4)_2$) and water.

  1. a) Write and balance the equation (you will need the coefficients $2$, $3$ and $6$).
  2. b) How many moles of water are formed per mole of phosphoric acid?
  3. c) Explain why, when balancing this equation, it is not enough to look at a single element, and why it is advisable to start by balancing calcium and phosphorus before hydrogen and oxygen.
Solve

The titration curve: why the pH "jumps" suddenly

Graph of an acid-base titration curve showing how the pH changes with the volume of base added, highlighting the vertical jump at the equivalence point. V equivalence pH V (mL)
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In the laboratory, a solution of $NaOH$ is added slowly to $25\ \text{mL}$ of a solution of $HCl$ while measuring the pH, as shown in the diagram. This is what is…

In the laboratory, a solution of $NaOH$ is added slowly to $25\ \text{mL}$ of a solution of $HCl$ while measuring the pH, as shown in the diagram.

NaOH HCl 25 mL pH

This is what is observed: at first, the pH is $1$ and hardly increases during the first $20\ \text{mL}$ added; between $24$ and $26\ \text{mL}$, the pH jumps from $3$ to $11$; from then on, it rises slowly, approaching $13$.

  1. a) Draw in your notebook the graph of pH against the volume of $NaOH$ added, marking those three sections.
  2. b) For what added volume is the neutralisation exactly complete? What is the pH of the solution at that point?
  3. c) Explain, using the reaction $H^+ + OH^- \rightarrow H_2O$, why the pH changes so rapidly around that exact point.

You can do it on paper and send a photo with your answer.

Solve
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We mix $0,1\ \text{mol}$ of sulphuric acid ($H_2SO_4$) with $0,1\ \text{mol}$ of sodium hydroxide ($NaOH$). a) Write the balanced equation for the neutralisation, which…

We mix $0,1\ \text{mol}$ of sulphuric acid ($H_2SO_4$) with $0,1\ \text{mol}$ of sodium hydroxide ($NaOH$).

  1. a) Write the balanced equation for the neutralisation, which produces sodium sulphate ($Na_2SO_4$) and water.
  2. b) Reason which of the two reactants is used up first and how many moles of the other remain unreacted.
  3. c) Will the final pH be acidic, basic or neutral? What if we mix $0,1\ \text{mol}$ of $H_2SO_4$ with $0,2\ \text{mol}$ of $NaOH$? Justify both answers.
Solve

Antacids, bicarbonate and efficiency per gram

Front view of a stomach, with the oesophagus at the top and the duodenum at the bottom left. Gastric juice containing hydrochloric acid collects in its lower part. An antacid arrives through the oesophagus, reacts in the juice, gives off CO₂ bubbles and neutralises the excess acid. + antacid CO₂ H⁺ H⁺ H⁺ gastric acid (HCl) oesophagus duodenum stomach the excess acid is neutralised
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Gastric juice in the stomach contains hydrochloric acid. In cases of heartburn, antacids from the pharmacy, which contain bases such as magnesium hydroxide, relieve it.…

Gastric juice in the stomach contains hydrochloric acid. In cases of heartburn, antacids from the pharmacy, which contain bases such as magnesium hydroxide, relieve it. Explain, using the concept of neutralisation, how an antacid works in the stomach.

Solve
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Litmus paper turns red in acidic conditions and blue in basic conditions. a) What colour will it turn in a solution of $HCl$? b) And in a solution of $NaOH$? c) We mix…

Litmus paper turns red in acidic conditions and blue in basic conditions.

  1. a) What colour will it turn in a solution of $HCl$?
  2. b) And in a solution of $NaOH$?
  3. c) We mix the two solutions in exact amounts for complete neutralisation: explain why the litmus paper no longer indicates acid or base in the resulting mixture.
Solve
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Which antacid makes the best use of every gram? These are the reactions of three antacids with stomach acid: a) magnesium hydroxide ($58\ \text{g/mol}$):…

Which antacid makes the best use of every gram? These are the reactions of three antacids with stomach acid:

  1. a) magnesium hydroxide ($58\ \text{g/mol}$): $Mg(OH)_2 + 2\ HCl \rightarrow MgCl_2 + 2\ H_2O$
  2. b) calcium carbonate ($100\ \text{g/mol}$): $CaCO_3 + 2\ HCl \rightarrow CaCl_2 + H_2O + CO_2$
  3. c) sodium hydrogen carbonate ($84\ \text{g/mol}$): $NaHCO_3 + HCl \rightarrow NaCl + H_2O + CO_2$

Calculate the moles of $HCl$ neutralised by $1\ \text{g}$ of each antacid (you can give your answer as a fraction or rounded to three decimal places), order them from highest to lowest capacity per gram and explain why calcium carbonate neutralises less acid per gram than magnesium hydroxide, even though both neutralise the same amount of acid per mole.

Solve

Calculating with neutralisations

Two beakers: on the left 0.1 mol of HCl dissolved, with H⁺ and Cl⁻ ions; on the right 0.05 mol of Mg(OH)₂, with Mg²⁺ and OH⁻ ions. An arrow labelled «÷ 2» shows that half as many moles of base as of acid are needed. 0.1 mol HCl ÷ 2 0.05 mol Mg(OH)₂ H⁺ Cl⁻ Mg²⁺ OH⁻
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Milk of magnesia is a suspension of magnesium hydroxide ($Mg(OH)2$) taken for heartburn. Its reaction with stomach acid is…

Milk of magnesia is a suspension of magnesium hydroxide ($Mg(OH)_2$) taken for heartburn. Its reaction with stomach acid is $Mg(OH)_2 + 2\ HCl \rightarrow MgCl_2 + 2\ H_2O$.

  1. a) How many moles of $HCl$ does $1\ \text{mol}$ of $Mg(OH)_2$ neutralise?
  2. b) If the stomach has an excess of $0,1\ \text{mol}$ of $HCl$, how many moles of $Mg(OH)_2$ are needed to neutralise it?
Solve
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In a laboratory flask, there are $0,2\ \text{mol}$ of sulphuric acid ($H_2SO_4$). a) Write the balanced equation for its neutralisation with sodium hydroxide ($NaOH$),…

In a laboratory flask, there are $0,2\ \text{mol}$ of sulphuric acid ($H_2SO_4$).

  1. a) Write the balanced equation for its neutralisation with sodium hydroxide ($NaOH$), which produces sodium sulphate ($Na_2SO_4$) and water.
  2. b) Calculate how many moles of $NaOH$ are needed to neutralise all the acid.
  3. c) If we were to add only $0,2\ \text{mol}$ of $NaOH$, would the solution be acidic, neutral or basic? Justify your answer using stoichiometry.
Solve
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Marble facades and statues (calcium carbonate, $CaCO_3$) deteriorate with acid rain, which contains sulphuric acid ($H_2SO_4$). a) Write and balance the equation for the…

Marble facades and statues (calcium carbonate, $CaCO_3$) deteriorate with acid rain, which contains sulphuric acid ($H_2SO_4$).

  1. a) Write and balance the equation for the reaction between sulphuric acid and calcium carbonate, in which calcium sulphate ($CaSO_4$), water and carbon dioxide are formed.
  2. b) Explain why this reaction gradually "eats away at" statues.
  3. c) Granite does not contain carbonates: reason why granite buildings withstand acid rain better than marble ones.
Solve

Back to the beginning: Wasp venom is basic; that is why vinegar (which provides acetic acid) neutralises it and soothes the sting, whereas in the stomach the opposite happens: you take a basic antacid to neutralise the excess hydrochloric acid.

Summary

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