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ESO Y4A · Biology and Geology
Genetics and evolution · Hereditary material

Gene expression

Having a recipe written down is no use if nobody cooks it. DNA stores the information, but that information only has an effect when it is "read" and used to make proteins: this process is called gene expression, and it has two stages, transcription and translation.

Before you start, make sure you know: The cell, the unit of living things (1st ESO)

Transcription: from DNA to messenger RNA

The cell's DNA keeps all the master instructions in the nucleus and never leaves it, so that it is not damaged, but the protein factories are outside, in the cytoplasm: how does the cell carry the genetic information out of the nucleus without moving the original?

Transcription in the nucleus: RNA polymerase opens up the DNA and, using the template strand 3'-TACGGA-5', makes the mRNA 5'-AUGCCU-3'. The finished mRNA leaves through a nuclear pore into the cytoplasm. T A C G G A A U G C C U 3' 5' 5' 3' RNA polymerase (enzyme) DNA not copied template strand mRNA being formed 3' 5' nuclear pore complete mRNA leaves the nucleus nuclear envelope nucleus cytoplasm
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Explain in your own words what it means when a cell "expresses a gene", and why the final result of this expression is a protein.

Explain in your own words what it means when a cell "expresses a gene", and why the final result of this expression is a protein.

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Look at the diagram of a eukaryotic cell representing gene expression: labels ?1 and ?2 show where transcription and translation take place, without indicating which is…

Look at the diagram of a eukaryotic cell representing gene expression: labels ?1 and ?2 show where transcription and translation take place, without indicating which is which. State which process occurs at each labelled point and where in the cell it takes place.

Cytoplasm Nucleus DNA mRNA Ribosome Protein ?1 ?2
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State two differences between transcription and translation: the molecule produced in each process and the location where it occurs.

State two differences between transcription and translation: the molecule produced in each process and the location where it occurs.

Solve

The genetic code and triplets

The AUG codon of messenger RNA, made up of the bases A, U and G, codes for the amino acid methionine, which is the first amino acid of the protein. mRNA 5' 3' A U G AUG codon (triplet) codes for methionine (first amino acid)
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What is the genetic code? Explain what a codon is and how many bases make it up.

What is the genetic code? Explain what a codon is and how many bases make it up.

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The template strand of a gene has the sequence 3'-TAC GGA TTT-5'. Write the sequence of the messenger RNA synthesised from it, keeping in mind that in RNA, thymine is…

The template strand of a gene has the sequence 3'-TAC GGA TTT-5'. Write the sequence of the messenger RNA synthesised from it, keeping in mind that in RNA, thymine is replaced by uracil.

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Explain the role of the ribosome and transfer RNA (tRNA) during translation: where does each bind and what does tRNA transport?

Explain the role of the ribosome and transfer RNA (tRNA) during translation: where does each bind and what does tRNA transport?

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Translation: from mRNA to protein

The mRNA reaches the cytoplasm carrying a message written with only 4 types of nucleotide (A, U, C, G), but proteins are built by combining 20 different types of amino acid: how is a 4-letter code translated into a chain of 20 different components?

Animation of the ribosome reading the messenger RNA: the mRNA slides one codon to the left through the reading window and, at each step, a new amino acid is added to the chain that forms the protein. ribosome mRNA chain of amino acids = protein
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A messenger RNA carries the sequence 5'-AUG GCU CAA-3'. Reconstruct the sequence of the DNA template strand from which it was transcribed, indicating its direction.

A messenger RNA carries the sequence 5'-AUG GCU CAA-3'. Reconstruct the sequence of the DNA template strand from which it was transcribed, indicating its direction.

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Two patients with point mutations in the same codon of their mature mRNA are analyzed; the original codon was GAA (encodes glutamic acid): In patient A, the codon…

Two patients with point mutations in the same codon of their mature mRNA are analyzed; the original codon was GAA (encodes glutamic acid):

  • In patient A, the codon mutates to GAG (encodes glutamic acid).

  • In patient B, it mutates to GUA (encodes valine).

  1. a) Based on the properties of the genetic code, justify why patient A shows no alteration while patient B presents a non-functional enzyme.
  2. b) Could a "silent mutation" like the one in patient A exist if the genetic code were not degenerate? Justify your answer by deducing what consequences mutations would have in a hypothetical code with only one codon per amino acid.
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A bacterium synthesizes an oligopeptide from the following mature mRNA fragment: 5'-... AUG GCC UUU UAA ...-3' A mutagenic agent causes the deletion (loss) of the first…

A bacterium synthesizes an oligopeptide from the following mature mRNA fragment:

5'-... AUG GCC UUU UAA ...-3'

A mutagenic agent causes the deletion (loss) of the first nucleotide of the codon GCC (the first cytosine), resulting in the sequence: 5'-... AUG GCU UUU AA...-3'.

Given that:

  • AUG = Methionine (start)

  • GCC = Alanine; GCU = Alanine; UUU = Phenylalanine; UUA = Leucine

  • UAA = Stop (termination)

  1. a) Write the resulting amino acid sequence before and after the mutation.
  2. b) Justify why a reading frameshift mutation (deletion or insertion) usually has much more severe consequences for protein function than a single base substitution mutation.
Solve

Back to the beginning: DNA is the recipe book kept in the library of the nucleus, transcription makes a photocopy in the form of mRNA, and the ribosomes are the cooks who read that copy to prepare the final dish: the protein.

Summary

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