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Math III · Mathematics
Equations · Inequalities and systems of inequalities

Solving Linear Inequalities in One Variable

Before you start, make sure you know: Inequalities with one unknown (Integrated Math I)
Before you start, make sure you know: Intervals, half-lines and neighborhoods (Integrated Math II)

Emma wants a pair of sneakers that cost $\$120$. She has $\$45$ saved and earns $\$12$ an hour at her part-time job. How many hours does she have to work? "Exactly enough" is not the real question. She needs at least enough, and that is an inequality. Solving one works almost exactly like solving an equation, with one rule that changes everything: multiplying or dividing by a negative number flips the inequality sign.

Solving by isolating the variable

You can picture a solution set on a number line. A closed circle means the endpoint is included ($\le$ or $\ge$, written with a bracket). An open circle means it is not included ($<$ or $>$, written with a parenthesis). Infinity always gets a parenthesis.

Two number lines: x ≥ −3 drawn with a closed circle at −3 and a ray to the right, and x < 2 drawn with an open circle at 2 and a ray to the left. x ≥ −3 → [−3, ∞) closed circle: ≥ or ≤ −5 −3 0 5 x < 2 → (−∞, 2) open circle: < or > −5 0 2 5

To test whether a number belongs to the solution set, substitute it into the original inequality and see if the statement is true. For $4x - 7 \ge 2x + 1$, try $x = 5$: $13 \ge 11$ is true, so 5 is in the solution set. Try $x = 0$: $-7 \ge 1$ is false, so 0 is not.

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Solve the following linear inequality: $3x - 5 < 2x + 4$

Solve the following linear inequality:

$3x - 5 < 2x + 4$

Solve
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Find the values of $x$ that satisfy the inequality: $4 - 3x > 10$

Find the values of $x$ that satisfy the inequality:

$4 - 3x > 10$

Solve
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Given the inequality $4x - 7 \ge 2x + 1$, check which of the following values belong to its solution set: $x = -2$, $x = 0$, $x = 4$, $x = 5$.

Given the inequality $4x - 7 \ge 2x + 1$, check which of the following values belong to its solution set: $x = -2$, $x = 0$, $x = 4$, $x = 5$.

Solve

Parentheses, fractions, and decimals

Clean the inequality up first. Distribute to remove parentheses, then combine like terms on each side. If there are fractions, multiply every term by the least common denominator (LCD). The LCD is positive, so the sign does not flip in that step. For decimals, multiply by 10, 100, and so on, to make them whole numbers.

Clearing denominators: multiplying every term of x/3 − 1/2 ≥ x/2 + 1 by the LCD 6 gives 2x − 3 ≥ 3x + 6 without changing the inequality sign. x/3 − 1/2 ≥ x/2 + 1 multiply every term by the LCD, 6 (positive: no flip) 2x − 3 ≥ 3x + 6

When the variable disappears

Sometimes the $x$ terms cancel. Then you are left with a statement made only of numbers, and it is either always true or always false.

Each step in these solutions turns the inequality into an equivalent one (same solutions). That is exactly how you justify an answer analytically: list the steps and say why each is allowed.

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Find the solution set of the inequality by first removing parentheses: $2(x - 3) + 4 \ge 5x - 1$

Find the solution set of the inequality by first removing parentheses:

$2(x - 3) + 4 \ge 5x - 1$

Solve
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Solve the following inequality combining the use of parentheses and denominators: $\frac{2(x-1)}{3} - \frac{3x+1}{4} \le \frac{5-x}{6}$

Solve the following inequality combining the use of parentheses and denominators:

$\frac{2(x-1)}{3} - \frac{3x+1}{4} \le \frac{5-x}{6}$

Solve
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Solve the following inequality by first working with decimal numbers: $0.5(x - 2) + 0.25x \ge 1.5x - 0.75$

Solve the following inequality by first working with decimal numbers:

$0.5(x - 2) + 0.25x \ge 1.5x - 0.75$

Solve

Translating words into inequalities

Most real problems give you a sentence, not a symbol. Learn the key phrases:

Words Symbol
at least, a minimum of, no less than $\ge$
at most, a maximum of, no more than, cannot exceed $\le$
more than, greater than, exceeds, over $>$
fewer than, less than, under, below $<$

"Between 48 and 76 inclusive" means two conditions at once: $48 \le x \le 76$.

Follow four steps: (1) define the variable, (2) translate the sentence into an inequality, (3) solve it, (4) interpret the answer in context (units, whole numbers, impossible values).

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Translate into algebraic language and solve: "Twice a number minus three is strictly less than the number itself plus five."

Translate into algebraic language and solve: "Twice a number minus three is strictly less than the number itself plus five."

Solve
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A small company manufactures cell phone cases. The fixed monthly costs are $\$500$ and producing each case costs $\$2$. If each case is sold for $\$5…

A small company manufactures cell phone cases. The fixed monthly costs are $\$500$ and producing each case costs $\$2$. If each case is sold for $\$5$, set up an inequality and determine the minimum number of cases that must be sold per month to obtain a profit of at least $\$1000$.

Solve
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A freight elevator has a maximum capacity of $800$ pounds. A worker weighing $75$ pounds must take up boxes of building materials weighing $22$ pounds each. If the…

A freight elevator has a maximum capacity of $800$ pounds. A worker weighing $75$ pounds must take up boxes of building materials weighing $22$ pounds each. If the worker must always accompany the load in the elevator, set up and solve an inequality to determine the maximum number of whole boxes they can transport in a single trip.

Solve

Comparing plans, averages, and mixtures

Three more situations show up again and again. For two plans, write each cost as an expression in the same variable, then ask which is smaller. For an average, remember that the average of $n$ numbers is their sum divided by $n$. For mixtures and interest, the amount of the substance is percent × total.

Here is the ride-share comparison below as a graph. Where one line is below the other, that plan is cheaper.

When a plan charges for extra units (for example, extra gigabytes), the extra cost is rate × (amount used − amount included), and it only applies when the amount used is above the included amount.

Interest problems work the same way. If you split $\$5{,}000$ between a 3% account and a 5% account, and $x$ goes into the 5% account, then $5000 - x$ is in the 3% account. The total interest after one year is $0.05x + 0.03(5000 - x)$.

Back to Emma: she needs $45 + 12h \ge 120$. Subtract 45: $12h \ge 75$. Divide by 12: $h \ge 6.25$. She has to work at least 6.25 hours, which is 6 hours 15 minutes.

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A high school student has obtained the following grades on their first three math exams: $6.5$, $7.0$, and $8.2$. What minimum grade must they get on the fourth exam for…

A high school student has obtained the following grades on their first three math exams: $6.5$, $7.0$, and $8.2$. What minimum grade must they get on the fourth exam for their average grade to be greater than or equal to $7.5$?

Solve
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A car rental company (Co. A) charges a flat fee of $\$30$ plus $\$0.15$ per mile traveled. Another competing company (Co. B) charges a flat $\$15$ plus $\$0.20$ per…

A car rental company (Co. A) charges a flat fee of $\$30$ plus $\$0.15$ per mile traveled. Another competing company (Co. B) charges a flat $\$15$ plus $\$0.20$ per mile. Set up an inequality to find out at how many miles it becomes cheaper to rent the car from Co. A and interpret the result using the following graph.

miles (x) Cost ($) 100 200 300 400 30 60 90 Co. A Co. B
Solve
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A telecommunications company offers two data plans. The Standard Plan costs $\$10$ per month and includes $2$ GB of data, charging $\$2$ for each additional GB. The Plus…

A telecommunications company offers two data plans. The Standard Plan costs $\$10$ per month and includes $2$ GB of data, charging $\$2$ for each additional GB. The Plus Plan costs $\$20$ per month and includes $5$ GB of data, charging $\$1.5$ for each additional GB. If a user knows they always consume more than $5$ GB per month, what is the minimum number of gigabytes they must consume for the Plus Plan to be strictly cheaper than the Standard Plan?

Solve

Inequalities with a parameter

Sometimes an inequality has another letter besides $x$, called a parameter (like $k$ or $m$). After you collect the $x$ terms, the coefficient of $x$ may involve the parameter. Its sign decides whether you flip, so you must treat each case separately.

Discussion of (k − 3)x < 6 in three cases: k > 3, k < 3 and k = 3. (k − 3)x < 6 k > 3 (coefficient positive) → x < 6/(k − 3) k < 3 (coefficient negative) → x > 6/(k − 3) (sign flips) k = 3 (coefficient zero) → 0 < 6 is true: all real numbers
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Analyze and solve the inequality $kx - 3 \le 2x + k$ in terms of the possible values of the real parameter $k$.

Analyze and solve the inequality $kx - 3 \le 2x + k$ in terms of the possible values of the real parameter $k$.

Solve

Finding a parameter and literal inequalities

Sometimes the problem goes backward. You are told what the solution set is, and you must find the parameter. The plan: solve for $x$ in terms of the parameter, set the endpoint equal to the given number, solve for the parameter, and check.

A literal inequality uses letters for all the numbers. You solve it the same way, as long as the conditions you are given tell you the signs.

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Consider the inequality $3x - a > 2x + 5$, where $a$ is a real parameter. Calculate the value of $a$ knowing that the solution set of the inequality is the interval…

Consider the inequality $3x - a > 2x + 5$, where $a$ is a real parameter. Calculate the value of $a$ knowing that the solution set of the inequality is the interval $(8, \infty)$.

Solve
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Determine the value of the parameter $m$ so that the solution set of the inequality $\frac{mx - 1}{2} - \frac{x + m}{3} > 1$ is exactly the interval $(4, \infty)$.

Determine the value of the parameter $m$ so that the solution set of the inequality

$\frac{mx - 1}{2} - \frac{x + m}{3} > 1$

is exactly the interval $(4, \infty)$.

Solve
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Solve the following literal inequality for the unknown $x$, assuming that the parameters satisfy the condition $a > b > 0$:…

Solve the following literal inequality for the unknown $x$, assuming that the parameters satisfy the condition $a > b > 0$:

$\frac{x}{a} - \frac{x}{b} \ge \frac{a^2 - b^2}{ab}$

Solve

Summary

See all the exercises in this section