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Photons, Mass Spectrometry, and Separation Methods · Spectrometry and Light

Photoelectron Spectroscopy

How do chemists "weigh" the energy that holds each electron in an atom, one subshell at a time? They can't open an atom and look, but they can knock electrons out with light and measure how hard it was to do. That is photoelectron spectroscopy (PES), and the graph it produces is like a fingerprint of an atom's electron configuration.

How PES works

In PES, a sample of gas-phase atoms is hit with high-energy photons (UV or X-ray) of a known energy. A photon knocks an electron out of an atom. The electron flies away with some kinetic energy, and the instrument measures it.

Energy is conserved, so the photon energy is split between the energy needed to remove the electron and the kinetic energy it carries away:

$$E_{\text{photon}} = \text{BE} + \text{KE}$$

BE is the binding energy: how much energy it takes to pull that electron out of the atom. Since $E_{\text{photon}}$ is known and KE is measured, you get $\text{BE} = E_{\text{photon}} - \text{KE}$.

Photoelectron spectrum of neon with three peaks: 1s at high binding energy with height 2, 2s with height 2, and 2p with height 6. 1s 2s 2p 84.0 4.68 2.08 Binding energy (MJ/mol) Relative number of electrons Neon lower energy →

Notice how the axis is drawn: PES graphs conventionally have binding energy increasing to the left. The 1s electrons, held most tightly, sit at the far left. The spectrum above is a simplified sketch with the peaks spaced for readability, not to scale.

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In a photoelectron spectrum, what do the horizontal axis and the vertical axis represent? Which electrons, those in the 1s subshell or those in the 2p subshell of the…

In a photoelectron spectrum, what do the horizontal axis and the vertical axis represent? Which electrons, those in the 1s subshell or those in the 2p subshell of the same atom, appear at higher binding energy, and why?

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Reading a spectrum: configuration and element

Each peak is a subshell. Count the peaks, read their heights, and you have the electron configuration.

  • Peaks go in order from the highest binding energy (1s) to the lowest.

  • A height of 2 is an s subshell (full), 6 is a p subshell (full), and 10 would be d.

  • A height of 1, 3, 4, or 5 is a partly filled subshell.

  • Add up all heights to get the total number of electrons. For a neutral atom, that number is the atomic number $Z$.

You can predict the number of peaks directly from the configuration. Hydrogen and helium each have just one peak (1s). Hydrogen's has height 1 and helium's has height 2. Lithium has two peaks (1s with height 2 and 2s with height 1).

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A photoelectron spectrum of an element shows three peaks with relative heights 2 : 2 : 1. Assuming the peaks are the 1s, 2s, and 2p subshells, write the electron…

A photoelectron spectrum of an element shows three peaks with relative heights 2 : 2 : 1. Assuming the peaks are the 1s, 2s, and 2p subshells, write the electron configuration and identify the element.

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Practice★☆☆Not started
Explain why a photoelectron spectrum of helium has one peak and a spectrum of lithium has two peaks.

Explain why a photoelectron spectrum of helium has one peak and a spectrum of lithium has two peaks.

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Practice★★☆Not started
The photoelectron spectrum of an element shows peaks at binding energies of 104 MJ/mol, 8.68 MJ/mol, 6.51 MJ/mol, and 0.58 MJ/mol with relative heights 2, 2, 6, and 2 in…

The photoelectron spectrum of an element shows peaks at binding energies of 104 MJ/mol, 8.68 MJ/mol, 6.51 MJ/mol, and 0.58 MJ/mol with relative heights 2, 2, 6, and 2 in order from highest to lowest energy. Write the electron configuration of the element and identify it.

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Why peaks sit where they do

The position of a peak comes from Coulomb's law: the attraction between the nucleus and an electron grows with the charges and weakens with distance.

$$F \propto \frac{q_1 q_2}{r^2}$$

Two things control how tightly an electron is held:

  1. Nuclear charge. More protons pull harder. This shifts all peaks of an atom to higher binding energy as $Z$ increases. The 1s peak moves dramatically: carbon's is near 29 MJ/mol and neon's is near 84 MJ/mol, because neon's nucleus has 10 protons versus 6.

  2. Distance and shielding. Electrons in a lower shell (smaller $n$) are closer to the nucleus. Inner electrons also shield outer electrons from the full nuclear charge, so outer electrons feel a smaller effective nuclear charge.

That is why, in any one atom, the order of binding energy is 1s > 2s > 2p > 3s > 3p. Within the same shell, 2s is held a bit more tightly than 2p because 2s electrons spend more time close to the nucleus.

Comparison of 1s peak positions for carbon and neon: neon's 1s peak is at a much higher binding energy than carbon's. Neon 1s Carbon 1s ≈ 84 ≈ 29 Binding energy (MJ/mol) ← higher energy

Moving down a group works the other way. The outermost electrons of potassium are in the 4th shell, farther away and shielded by more inner electrons than sodium's 3s electron, so potassium's outer peak is at lower binding energy. Yet potassium's 1s peak is at much higher binding energy than sodium's, because the 1s electrons feel a nucleus with 19 protons instead of 11, with nothing between them and the nucleus.

Practice★★☆Not started
The 1s peak of neon appears near 84 MJ/mol, while the 1s peak of carbon appears near 29 MJ/mol. Explain this difference in terms of nuclear charge and Coulomb's law.

The 1s peak of neon appears near 84 MJ/mol, while the 1s peak of carbon appears near 29 MJ/mol. Explain this difference in terms of nuclear charge and Coulomb's law.

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Practice★★☆Not started
A photoelectron spectrum of an atom shows the following peaks: 1s at 309 MJ/mol (height 2), and four more peaks at lower energy with heights 2, 6, 2, and 6. Write the…

A photoelectron spectrum of an atom shows the following peaks: 1s at 309 MJ/mol (height 2), and four more peaks at lower energy with heights 2, 6, 2, and 6. Write the electron configuration that matches these heights through the 3p subshell, assuming no further peaks, and identify the element.

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Practice★★★Not started
Compare the photoelectron spectra of sodium and potassium. (a) Give the expected number of peaks and their relative heights for each. (b) Explain which element has the…

Compare the photoelectron spectra of sodium and potassium. (a) Give the expected number of peaks and their relative heights for each. (b) Explain which element has the lower binding energy for its outermost electrons, using atomic radius and shielding. (c) Explain why the 1s peak of potassium is at a much higher binding energy than the 1s peak of sodium.

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Writing a full explanation

On the AP® exam you must justify claims, not just state them. A strong PES explanation has three parts:

  1. Claim: which peak or element is higher or lower.

  2. Evidence: the relevant numbers or heights.

  3. Reasoning: Coulomb's law with nuclear charge, distance, and shielding.

Successive ionization energies

PES peaks show how many valence electrons an atom has: the lowest-binding-energy peaks belong to the valence shell. The same idea shows up in successive ionization energies, the energies needed to remove the 1st, 2nd, 3rd electron, and so on, from one atom.

There is a big jump after the last valence electron is removed, because the next electron comes from an inner shell that is closer to the nucleus and less shielded. For example, if the 3rd ionization energy of an element is much larger than its 2nd, the atom has 2 valence electrons, which matches a PES with two electrons in the outermost peak.

Practice★★★Not started
A student claims that the photoelectron spectrum of magnesium has peaks with relative heights 2, 2, 6, 2, and that of aluminum has relative heights 2, 2, 6, 2, 1. (a)…

A student claims that the photoelectron spectrum of magnesium has peaks with relative heights 2, 2, 6, 2, and that of aluminum has relative heights 2, 2, 6, 2, 1. (a) Verify or correct each claim. (b) Explain why the 3s peak of aluminum is at a slightly higher binding energy than the 3s peak of magnesium. (c) Predict how the position and height of the 3p peak of aluminum compare with its 3s peak, and justify your prediction.

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Summary

Back to the start: the spectrum is a fingerprint because every element has its own set of peak positions and heights, which you can now read as an electron configuration.

See all the exercises in this section