Models and conjugate pairs
Vinegar on your french fries is an acid you can eat. The acid in a car battery will burn your skin. Both are "acids", so calling something acidic is not enough: we need a model that explains what happens at the particle level, and that model must separate how strong an acid is from how concentrated it is.
From Arrhenius to Brønsted–Lowry
Hold an open bottle of concentrated ammonia near an open bottle of concentrated hydrochloric acid in a lab fume hood and a dense white smoke of solid ammonium chloride forms in the air. There is no liquid water and no solution to release ions. How can we call this a neutralization?
The first modern theory was proposed by Svante Arrhenius in 1884. It defines acids and bases by what they release when dissolved in water.
This works well for "classic" acids and bases, but it leaves out obvious cases. Ammonia, $\mathrm{NH_3}$, has no $\mathrm{OH^-}$ in its formula, yet it is a well-known base. In 1923 Johannes Brønsted and Thomas Lowry independently proposed a wider model based on the transfer of a proton.
This is why Brønsted–Lowry is the more extensive model: it covers everything Arrhenius does, and reactions in other solvents or in the gas phase as well.
Everyday acids and bases
Acids and bases are all around you. Vinegar (acetic acid) and citrus juices are acids. Antacid tablets and toothpaste contain bases. Indicators such as litmus change color with the type of solution. Neutralization is used in practice: Corn Belt farmers spread agricultural lime on acidic fields, and an antacid tablet neutralizes excess stomach acid.
Acids also have characteristic reactions. Each of these gives a salt:
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Acid + base → salt + water: $\mathrm{HCl + NaOH \rightarrow NaCl + H_2O}$
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Acid + metal → salt + hydrogen: $\mathrm{Mg + 2HCl \rightarrow MgCl_2 + H_2}$
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Acid + carbonate → salt + water + carbon dioxide: $\mathrm{CaCO_3 + 2HCl \rightarrow CaCl_2 + H_2O + CO_2}$
The last one is why buttermilk pancakes rise: the acid in buttermilk reacts with baking soda and releases $\mathrm{CO_2}$.
Understanding of the behavior of acids and bases developed decisively in the late 19th and early 20th centuries. Consider the substances $\mathrm{HCl}$ and…
Understanding of the behavior of acids and bases developed decisively in the late 19th and early 20th centuries. Consider the substances $\mathrm{HCl}$ and $\mathrm{NH}_3$ at $25\,^{\circ}\mathrm{C}$.
- a) Justify why hydrogen chloride behaves as an acid according to both Arrhenius's theory and the Brønsted-Lowry theory, writing the corresponding chemical equation in aqueous solution.
- b) Explain, with reasoning, why a strict historical interpretation based only on the dissociation of hydroxides does not directly describe ammonia. Write its reaction with water and explain how proton transfer produces hydroxide ions, consistent with the extended aqueous definition of a base.
The concept of neutralization has complementary interpretations depending on the theoretical framework used. a) Describe the neutralization reaction in aqueous solution…
The concept of neutralization has complementary interpretations depending on the theoretical framework used.
- a) Describe the neutralization reaction in aqueous solution between solutions of sodium hydroxide, $\mathrm{NaOH}$, and nitric acid, $\mathrm{HNO}_3$, writing the net ionic equation and justifying the process according to Arrhenius's definition.
- b) Now consider the reaction between the gases ammonia, $\mathrm{NH}_3(\mathrm{g})$, and hydrogen chloride, $\mathrm{HCl}(\mathrm{g})$, to form the white solid ammonium chloride, $\mathrm{NH}_4\mathrm{Cl}(\mathrm{s})$, in the complete absence of solvent. Explain whether this process is a neutralization according to Arrhenius and according to Brønsted-Lowry, indicating the acid, the base and the proton transferred.
Conjugate acid–base pairs
In the Brønsted-Lowry framework, two chemical species form a conjugate acid-base pair if they are related by the transfer of exactly one proton ($\mathrm{H}^+$), which…
In the Brønsted-Lowry framework, two chemical species form a conjugate acid-base pair if they are related by the transfer of exactly one proton ($\mathrm{H}^+$), which involves a change of one unit in their net electric charge.
- a) Write the molecular or ionic formula of the conjugate base of each of the following acidic chemical species: hydrogen sulfate ion, $\mathrm{HSO}_4^-$, and hydronium ion, $\mathrm{H}_3\mathrm{O}^+$.
- b) Write the molecular or ionic formula of the conjugate acid corresponding to each of the following bases: hydrogen phosphate ion, $\mathrm{HPO}_4^{2-}$, and methylamine, $\mathrm{CH}_3\mathrm{NH}_2$.
At $25\,^{\circ}\mathrm{C}$, hydrocyanic acid, $\mathrm{HCN}$, has an acidity constant $K_a = 4.9\times 10^{-10}$, while hydrofluoric acid, $\mathrm{HF}$, has…
At $25\,^{\circ}\mathrm{C}$, hydrocyanic acid, $\mathrm{HCN}$, has an acidity constant $K_a = 4.9\times 10^{-10}$, while hydrofluoric acid, $\mathrm{HF}$, has $K_a = 6.8\times 10^{-4}$. Sodium fluoride, $\mathrm{NaF}$, is reacted with hydrocyanic acid in homogeneous aqueous solution.
- a) Set out the Brønsted-Lowry proton transfer equation between the fluoride ion, $\mathrm{F}^-$, and $\mathrm{HCN}$, identify the two conjugate acid-base pairs and deduce whether the constant of this reaction will be greater or less than one.
- b) Calculate the exact numerical value of the equilibrium constant of this reaction at $25\,^{\circ}\mathrm{C}$ and relate the result to the standard thermodynamic preference, distinguishing it from the direction in which a particular mixture will evolve, which requires knowing its reaction quotient. Use the ideal model and neglect the autoprotolysis of water where that approximation is valid.
Amphiprotic species and the self-ionization of water
Add baking soda to vinegar and it fizzes, because it neutralizes the acid. Mix it with a strong base and it reacts again, this time acting as an acid. How can one substance behave as a base towards some reagents and as an acid towards others?
Water itself is amphiprotic, and this has a major consequence: two water molecules can react with each other.
In the self-ionization, one water molecule acts as an acid (donating $\mathrm{H^+}$) and the other as a base (accepting it). The two conjugate pairs are $\mathrm{H_3O^+/H_2O}$ and $\mathrm{H_2O/OH^-}$.
Amphiprotic substances are those that can donate or accept protons depending on the chemical species they react with. The bicarbonate ion, $\mathrm{HCO}3^-$, is an…
Amphiprotic substances are those that can donate or accept protons depending on the chemical species they react with. The bicarbonate ion, $\mathrm{HCO}_3^-$, is an amphiprotic species of great importance in aqueous solution at $25\,^{\circ}\mathrm{C}$.
- a) Write the balanced reaction in which the bicarbonate ion acts as a Brønsted-Lowry acid toward the hydroxide anion, $\mathrm{OH}^-$, identifying the two conjugate acid-base pairs.
- b) Write the balanced reaction in which the bicarbonate ion acts as a Brønsted-Lowry base toward the hydronium ion, $\mathrm{H}_3\mathrm{O}^+$, likewise identifying the two conjugate pairs.
Pure water at $25\,^{\circ}\mathrm{C}$ undergoes self-ionization according to the equilibrium…
Pure water at $25\,^{\circ}\mathrm{C}$ undergoes self-ionization according to the equilibrium $2\,\mathrm{H}_2\mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_3\mathrm{O}^+(\mathrm{aq}) + \mathrm{OH}^-(\mathrm{aq})$, with $K_w = 1.0\times 10^{-14}$ and a standard enthalpy of dissociation $\Delta H^0 > 0$.
- a) Explain the amphiprotic behavior of water, indicating the role played by each of the two water molecules in the autoprotolysis reaction, and state the two conjugate acid-base pairs generated.
- b) Given that at $60\,^{\circ}\mathrm{C}$ the ionic product of water increases to $K_w = 9.6\times 10^{-14}$, justify using Le Chatelier's principle why this value increases, calculate the pH of neutral water at $60\,^{\circ}\mathrm{C}$ and explain in detail whether water at that temperature is still strictly neutral even though its pH is lower than $7.00$. Use the ideal model to relate concentrations to pH.
Molecular structure and acid strength
Why is HI a much stronger acid than HF, even though fluorine is far more electronegative? Two factors control how easily an H–X bond gives up its proton: how polar the bond is, and how strong the bond is.
The terms "strong" and "concentrated" are often confused when describing an acidic solution. Consider at $25\,^{\circ}\mathrm{C}$ the following two solutions: solution 1…
The terms "strong" and "concentrated" are often confused when describing an acidic solution. Consider at $25\,^{\circ}\mathrm{C}$ the following two solutions: solution 1 of hydrochloric acid, $\mathrm{HCl}$, with concentration $c_1 = 1.0\times 10^{-4}\,\mathrm{mol\times L^{-1}}$ (a strong, fully ionized acid), and solution 2 of acetic acid, $\mathrm{CH}_3\mathrm{COOH}$, with concentration $c_2 = 2.0\,\mathrm{mol\times L^{-1}}$ ($K_a = 1.8\times 10^{-5}$).
- a) Calculate the concentration of $\mathrm{H}_3\mathrm{O}^+$ ions in both solutions, neglecting the autoprotolysis of water.
- b) Classify each solution according to its intrinsic acid strength and according to its concentration, and explain why the weak acid solution can have a higher concentration of $\mathrm{H}_3\mathrm{O}^+$ ions than the strong acid. Use the ideal model and neglect the autoprotolysis of water where that approximation is valid.
Acid strength and concentration: two different things
For a weak acid, $K_a = \dfrac{[\mathrm{H_3O^+}][\mathrm{A^-}]}{[\mathrm{HA}]}$. The larger $K_a$ is, the greater the percent ionization. For a weak base, $K_b = \dfrac{[\mathrm{BH^+}][\mathrm{OH^-}]}{[\mathrm{B}]}$.
Two independent aqueous solutions of two monoprotic acids, $\mathrm{HA}$ and $\mathrm{HB}$, are prepared at the same initial analytical concentration…
Two independent aqueous solutions of two monoprotic acids, $\mathrm{HA}$ and $\mathrm{HB}$, are prepared at the same initial analytical concentration $c_0 = 0.10\,\mathrm{mol\times L^{-1}}$ and at $25\,^{\circ}\mathrm{C}$. The diagram shows a microscopic sample of identical volume for both containers, in which a total equivalent of $6$ acid molecules was initially introduced into each solution. Observe the distribution of particles at equilibrium illustrated below:
- a) From the count of species present at equilibrium (undissociated molecules and ions produced), determine the percentage or degree of dissociation of each acid.
- b) Deduce, with reasoning, which of the two acids is stronger, justifying whether two solutions with exactly the same initial molar concentration of solute necessarily have the same acidity. Use the ideal model and neglect the autoprotolysis of water where that approximation is valid.
The terms "strong" and "concentrated" are often confused when describing an acidic solution. Consider at $25\,^{\circ}\mathrm{C}$ the following two solutions: solution 1…
The terms "strong" and "concentrated" are often confused when describing an acidic solution. Consider at $25\,^{\circ}\mathrm{C}$ the following two solutions: solution 1 of hydrochloric acid, $\mathrm{HCl}$, with concentration $c_1 = 1.0\times 10^{-4}\,\mathrm{mol\times L^{-1}}$ (a strong, fully ionized acid), and solution 2 of acetic acid, $\mathrm{CH}_3\mathrm{COOH}$, with concentration $c_2 = 2.0\,\mathrm{mol\times L^{-1}}$ ($K_a = 1.8\times 10^{-5}$).
- a) Calculate the concentration of $\mathrm{H}_3\mathrm{O}^+$ ions in both solutions, neglecting the autoprotolysis of water.
- b) Classify each solution according to its intrinsic acid strength and according to its concentration, and explain why the weak acid solution can have a higher concentration of $\mathrm{H}_3\mathrm{O}^+$ ions than the strong acid. Use the ideal model and neglect the autoprotolysis of water where that approximation is valid.
In the laboratory there are two bottles labeled $\mathrm{X}$ and $\mathrm{Y}$. It is known that one contains formic acid, $\mathrm{HCOOH}$ ($K_a = 1.8\times 10^{-4}$ at…
In the laboratory there are two bottles labeled $\mathrm{X}$ and $\mathrm{Y}$. It is known that one contains formic acid, $\mathrm{HCOOH}$ ($K_a = 1.8\times 10^{-4}$ at $25\,^{\circ}\mathrm{C}$), and the other contains hypochlorous acid, $\mathrm{HClO}$ ($K_a = 3.0\times 10^{-8}$ at $25\,^{\circ}\mathrm{C}$). Two students prepare a $0.050\,\mathrm{mol\times L^{-1}}$ solution from bottle $\mathrm{X}$ and a $0.050\,\mathrm{mol\times L^{-1}}$ solution from bottle $\mathrm{Y}$. The electrical conductivity and pH are measured at $25\,^{\circ}\mathrm{C}$, finding that solution $\mathrm{X}$ has a $\mathrm{pH} = 2.53$, while solution $\mathrm{Y}$ has a $\mathrm{pH} = 4.41$.
- a) Identify, with reasoning, which acid corresponds to each bottle by calculating the experimental acidity constant of each.
- b) Taking the conjugate bases of both acids in aqueous solution at equal molar concentration, justify which of the two anions will undergo more pronounced basic hydrolysis and calculate its corresponding basicity constant $K_b$ at $25\,^{\circ}\mathrm{C}$, given that $K_w = 1.0\times 10^{-14}$. Use the ideal model and neglect the autoprotolysis of water where that approximation is valid.
Back to the start: Vinegar is safe to sprinkle on fries because it contains a weak acid ($\mathrm{CH_3COOH}$) that is only slightly dissociated and at low concentration. Battery acid burns the skin because it combines a strong acid ($\mathrm{H_2SO_4}$ dissociates fully in its first step) with a very high concentration.