Back to homePhysics · 6th Year OL · Change subject
Start for free
6th Year OL · Physics
Relativistic, quantum, nuclear, and particle physics · Nuclear physics

Atomic nuclei and the stability of isotopes

Inside any nucleus with more than one proton there is a constant battle: the electrical repulsion between protons, confined to a distance of barely $10^{-15}\ \text{m}$, should blow the nucleus apart in a fraction of a second. The fact that most of the matter in the universe is stable shows that there is another force, even stronger at those distances, capable of winning that battle. Understanding when it wins and when it loses is understanding why some nuclei are stable and others radioactive. In 1932 Ernest Walton from Dungarvan and John Cockcroft were the first to split the nucleus using artificially accelerated particles, and the process released energy: by the end of this page you will see why.

Composition of the nucleus: protons, neutrons and isotopes

When Joseph John Thomson measured pure samples of neon gas in the laboratory, he discovered that they were made up of atoms that were chemically identical but had two different masses ($20\ \text{u}$ and $22\ \text{u}$): how is it possible for atoms of the same element not to weigh the same?

Nuclei with the same $A$ but a different $Z$ are called isobars, and nuclei with the same $N$ but a different $Z$ are called isotones.

Carbon-14 nucleus drawn as a cluster of 6 protons and 8 neutrons, next to its nuclear notation with mass number 14 and atomic number 6, and the relationships Z = 6, N = A − Z = 8 and A = Z + N = 14. Carbon-14 nucleus + + + + + + + proton (p⁺) neutron (n) 14 6 C mass number (A) atomic number (Z) element (carbon) Z = 6 protons N = A − Z = 8 neutrons A = Z + N = 14 nucleons
Practice★☆☆Not started
The potassium in bananas contains a small fraction of the isotope potassium-40, whose nucleus has atomic number $Z = 19$ and mass number $A = 40$. a) State how many…

The potassium in bananas contains a small fraction of the isotope potassium-40, whose nucleus has atomic number $Z = 19$ and mass number $A = 40$.

  1. a) State how many protons and how many neutrons this nucleus has.
  2. b) Write its symbol using ${}^{A}_{Z}\text{X}$ notation.
  3. c) How many electrons does a neutral atom of potassium-40 have? Justify your answer.
Solve
Practice★☆☆Not started
Carbon has three natural isotopes: carbon-12, carbon-13 and carbon-14, all with $Z = 6$. a) Explain what it means for two nuclei to be isotopes. b) Calculate the number…

Carbon has three natural isotopes: carbon-12, carbon-13 and carbon-14, all with $Z = 6$.

  1. a) Explain what it means for two nuclei to be isotopes.
  2. b) Calculate the number of neutrons in the nucleus of each of the three isotopes.
  3. c) Do all three isotopes have the same chemical properties? Reason your answer considering their electrons.
Solve
Practice★★☆Not started
Consider these five nuclides: ${}^{14}{6}\text{C}$, ${}^{14}{7}\text{N}$, ${}^{12}{6}\text{C}$, ${}^{16}{8}\text{O}$ and ${}^{15}{7}\text{N}$. a) Calculate the number of…

Consider these five nuclides: ${}^{14}_{6}\text{C}$, ${}^{14}_{7}\text{N}$, ${}^{12}_{6}\text{C}$, ${}^{16}_{8}\text{O}$ and ${}^{15}_{7}\text{N}$.

  1. a) Calculate the number of protons and neutrons in each one.
  2. b) State which pairs are isotopes (same $Z$) and which pair is isobars (same $A$).
  3. c) Identify two nuclides that have the same number of neutrons (isotones).
Solve

Sizes, units and nuclear density

A hurling sliotar fits in your hand, yet a teaspoon of nuclear matter would outweigh a mountain: how can the nucleus be so small and so heavy?

Practice★☆☆Not started
The atomic mass unit (u) is defined as one twelfth of the mass of a carbon-12 atom, and is equivalent to $1\ \text{u} = 1.66 \times 10^{-27}\ \text{kg}$. a) The mass of…

The atomic mass unit (u) is defined as one twelfth of the mass of a carbon-12 atom, and is equivalent to $1\ \text{u} = 1.66 \times 10^{-27}\ \text{kg}$.

  1. a) The mass of the oxygen-16 nucleus is about $16\ \text{u}$: express it in kilograms, in standard form.
  2. b) Reason why in nuclear physics it is more convenient to work in units of u than in kilograms.
Solve
Practice★☆☆Not started
The radius of an atom is on the order of $10^{-10}\ \text{m}$, while that of its nucleus is on the order of $10^{-15}\ \text{m}$, as shown in the figure. a) Calculate…

The radius of an atom is on the order of $10^{-10}\ \text{m}$, while that of its nucleus is on the order of $10^{-15}\ \text{m}$, as shown in the figure.

r atom ≈ 0.1 nm atom nucleus r ≈ 1 fm diagram not to scale r atom / r nucleus = ?
  1. a) Calculate how many times larger the radius of the atom is than that of the nucleus.
  2. b) The volume of a sphere is proportional to the cube of the radius: estimate how many times larger the volume of the atom is than that of the nucleus.
  3. c) In light of the result, explain why it is said that the atom is mostly empty space.
Solve
Practice★★☆Not started
Marie Curie isolated radium in $1898$, and for decades the activity of $1\ \text{g}$ of radium-226 served as a unit of measurement, the curie. Data:…

Marie Curie isolated radium in $1898$, and for decades the activity of $1\ \text{g}$ of radium-226 served as a unit of measurement, the curie. Data: $N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}$ and molar mass of radium-226: $226\ \text{g/mol}$.

  1. a) Calculate how many radium-226 nuclei are in a sample of $1\ \text{mg}$.
  2. b) Calculate how many nuclei are in $1\ \text{g}$, the quantity that defined the curie.
Solve
Practice★★★Not started
The radius of a nucleus can be estimated using the expression $R = R_0 \times A^{1/3}$, where $R_0 = 1.2 \times 10^{-15}\ \text{m}$ and $A$ is the mass number. For…

The radius of a nucleus can be estimated using the expression $R = R_0 \times A^{1/3}$, where $R_0 = 1.2 \times 10^{-15}\ \text{m}$ and $A$ is the mass number. For iron-56 take $A^{1/3} \approx 3.8$ and a nuclear mass of $9.3 \times 10^{-26}\ \text{kg}$. The volume of a sphere is $V = \frac{4}{3} \times \pi \times R^3$, with $\pi \approx 3.14$.

  1. a) Calculate the radius of the iron-56 nucleus.
  2. b) Calculate its volume and density, in $\text{kg/m}^3$.
  3. c) The matter of a neutron star has a density similar to nuclear density: calculate the mass that a teaspoon of $5\ \text{cm}^3$ of this matter would have and comment on the result.
Solve

The strong interaction and the band of stability

If you bring two protons together to nuclear distances ($10^{-15}\ \text{m}$), the electrical force of mutual repulsion is around $230\ \text{N}$, a gigantic value for subatomic particles: how can dozens of them live packed together in such a tiny space without the nucleus flying into pieces?

Graph of the number of neutrons against the number of protons: the line N = Z and the band of stability, which moves away from it upwards until it reaches N/Z close to 1.5 in heavy nuclei. Z (protons) N (neutrons) N = Z band of stability N/Z ≈ 1 N/Z ≈ 1.5 (heavy nuclei)
Practice★☆☆Not started
In a helium nucleus, two protons are confined in a region about $10^{-15}\ \text{m}$ in diameter. As both have positive charge, they repel each other electrically with…

In a helium nucleus, two protons are confined in a region about $10^{-15}\ \text{m}$ in diameter. As both have positive charge, they repel each other electrically with considerable force; however, the nucleus does not break apart.

  1. a) Explain what the strong nuclear force is and why it manages to keep the nucleus bound together.
  2. b) Reason why, even with that force existing, nuclei with too many protons end up being unstable.
Solve
Practice★☆☆Not started
Of the nearly $3000$ known nuclides, barely $250$ are stable; the rest end up decaying sooner or later. a) Explain what it means for a nucleus to be stable and what…

Of the nearly $3000$ known nuclides, barely $250$ are stable; the rest end up decaying sooner or later.

  1. a) Explain what it means for a nucleus to be stable and what happens to an unstable nucleus.
  2. b) In light stable nuclei, the number of neutrons $N$ and the number of protons $Z$ are almost equal: state the approximate value of the ratio $\frac{N}{Z}$ in these nuclei.
Solve
Practice★★☆Not started
Two protons inside a nucleus are separated by a distance of $10^{-15}\ \text{m}$, as shown in the figure. Data: Coulomb constant…

Two protons inside a nucleus are separated by a distance of $10^{-15}\ \text{m}$, as shown in the figure. Data: Coulomb constant $K = 9 \times 10^{9}\ \text{N}\times\text{m}^2/\text{C}^2$ and proton charge $e = 1.6 \times 10^{-19}\ \text{C}$.

+ + F F r F = ?
  1. a) Calculate the repulsive electrostatic force between them using Coulomb's law, $F = K \times \frac{e^2}{r^2}$.
  2. b) The value obtained is huge for a force between particles: explain what conclusion can be drawn about the strength of the strong nuclear force that holds them together.
Solve
Practice★★☆Not started
The $\frac{N}{Z}$ ratio of stable nuclei is approximately $1$ for light nuclei and increases to about $1.5$ for the heaviest ones, as shown in the figure. Calculate the…

The $\frac{N}{Z}$ ratio of stable nuclei is approximately $1$ for light nuclei and increases to about $1.5$ for the heaviest ones, as shown in the figure.

Z (protons) N (neutrons) N = Z belt of stability

Calculate the $\frac{N}{Z}$ ratio for each of these nuclides and predict, by comparing with this trend, whether they are expected to be stable or unstable:

  1. a) ${}^{12}_{6}\text{C}$
  2. b) ${}^{14}_{6}\text{C}$
  3. c) ${}^{206}_{82}\text{Pb}$
  4. d) ${}^{238}_{92}\text{U}$
Solve
Practice★★★Not started
Oxygen has only three stable isotopes: ${}^{16}{8}\text{O}$, ${}^{17}{8}\text{O}$ and ${}^{18}{8}\text{O}$. Isotopes with a neutron excess tend to decay by beta-minus…

Oxygen has only three stable isotopes: ${}^{16}_{8}\text{O}$, ${}^{17}_{8}\text{O}$ and ${}^{18}_{8}\text{O}$. Isotopes with a neutron excess tend to decay by beta-minus emission ($\beta^{-}$: a neutron converts into a proton), and those with a neutron deficit, by beta-plus emission ($\beta^{+}$: a proton converts into a neutron).

  1. a) Calculate the $\frac{N}{Z}$ ratio of ${}^{14}_{8}\text{O}$ and ${}^{21}_{8}\text{O}$ and compare it with that of ${}^{16}_{8}\text{O}$.
  2. b) Predict which type of decay each of these two unstable isotopes will undergo, justifying your answer.
  3. c) Write the equation for each process and identify the daughter nuclide formed in each case.
Solve

Mass defect and binding energy

If you weigh a helium-4 nucleus in a mass spectrometer you get $4.0015\ \text{u}$, but if you add up the masses of its nucleons separately (two free protons and two free neutrons) you get $4.0320\ \text{u}$: where has the missing mass gone when they join together?

Comparison of masses: two loose protons and two loose neutrons add up to 4.0320 u, whereas the helium-4 nucleus they form weighs 4.0015 u; the difference is released as binding energy. 2 p⁺ + 2 n separate p⁺ p⁺ n n sum = 4.0320 u they join He-4 nucleus 4.0015 u + energy released Δm = 0.0305 u
Practice★☆☆Not started
Precision measurements show that the mass of a helium-4 nucleus is less than the sum of the masses of its two protons and two neutrons measured separately. a) Explain…

Precision measurements show that the mass of a helium-4 nucleus is less than the sum of the masses of its two protons and two neutrons measured separately.

  1. a) Explain what the mass defect of a nucleus is.
  2. b) What has the "missing" mass been transformed into? Mention Einstein's relation $E = \Delta m \times c^2$ in your explanation.
Solve
Practice★★☆Not started
Data: mass of proton $m_p = 1.0073\ \text{u}$, mass of neutron $m_n = 1.0087\ \text{u}$, mass of helium-4 nucleus $m_{\alpha} = 4.0015\ \text{u}$ and…

Data: mass of proton $m_p = 1.0073\ \text{u}$, mass of neutron $m_n = 1.0087\ \text{u}$, mass of helium-4 nucleus $m_{\alpha} = 4.0015\ \text{u}$ and $1\ \text{u} = 1.66 \times 10^{-27}\ \text{kg}$.

  1. a) Calculate the sum of the masses of the two protons and two neutrons that form the helium-4 nucleus, measured separately.
  2. b) Calculate the mass defect $\Delta m$ of the nucleus, in u units.
  3. c) Express this mass defect in kilograms, in standard form.
Solve
Practice★★☆Not started
The mass defect of the helium-4 nucleus is $\Delta m = 0.0305\ \text{u}$, equivalent to $5.06 \times 10^{-29}\ \text{kg}$. Data: $c = 3 \times 10^{8}\ \text{m/s}$ and…

The mass defect of the helium-4 nucleus is $\Delta m = 0.0305\ \text{u}$, equivalent to $5.06 \times 10^{-29}\ \text{kg}$. Data: $c = 3 \times 10^{8}\ \text{m/s}$ and $1\ \text{eV} = 1.6 \times 10^{-19}\ \text{J}$.

  1. a) Calculate the binding energy of the nucleus using Einstein's relation, $E = \Delta m \times c^2$, expressed in joules.
  2. b) Convert the result to $\text{MeV}$ (note that $1\ \text{MeV} = 10^{6}\ \text{eV}$).
  3. c) Calculate the binding energy per nucleon of helium-4.
Solve
Practice★★☆Not started
In nuclear physics, the mass–energy equivalence $1\ \text{u} \times c^2 = 931.5\ \text{MeV}$ is used. a) The mass defect of deuterium (hydrogen-2 nucleus) is…

In nuclear physics, the mass–energy equivalence $1\ \text{u} \times c^2 = 931.5\ \text{MeV}$ is used.

  1. a) The mass defect of deuterium (hydrogen-2 nucleus) is $\Delta m = 0.0024\ \text{u}$: calculate its binding energy in $\text{MeV}$.
  2. b) Calculate its binding energy per nucleon and compare it with that of iron-56 ($8.8\ \text{MeV}$ per nucleon): reason which of the two nuclei is more stable.
Solve
Practice★★★Not started
Shortly after the Big Bang, protons and neutrons in the early universe joined together to form deuterium, and in each union a gamma photon was emitted. Data:…

Shortly after the Big Bang, protons and neutrons in the early universe joined together to form deuterium, and in each union a gamma photon was emitted. Data: $m_p = 1.0073\ \text{u}$, $m_n = 1.0087\ \text{u}$, mass of deuterium nucleus $m_d = 2.0136\ \text{u}$ and $1\ \text{u} \times c^2 = 931.5\ \text{MeV}$.

  1. a) Calculate the mass defect of the process in which a proton and a neutron form a deuterium nucleus.
  2. b) Calculate the energy released in the formation of each deuterium nucleus, in $\text{MeV}$.
  3. c) Where does this energy go? Explain the role of the emitted gamma photon.
Solve
Practice★★★Not started
All the electricity consumed in Ireland in a year is of the order of $9 \times 10^{17}\ \text{J}$. Data: $c = 3 \times 10^{8}\ \text{m/s}$. a) Suppose that this energy…

All the electricity consumed in Ireland in a year is of the order of $9 \times 10^{17}\ \text{J}$. Data: $c = 3 \times 10^{8}\ \text{m/s}$.

  1. a) Suppose that this energy were obtained by converting mass directly into energy, with an efficiency of $100\ \%$: calculate, using $E = \Delta m \times c^2$, the mass that would have to be converted.
  2. b) Comment on the result: does it seem like a lot or a little mass to supply electricity to an entire country for a year?
  3. c) A student states: "in nuclear reactions mass is conserved, just as in chemical reactions". Correct their statement and explain what actually is conserved in a nuclear reaction.
Solve

The stability curve: the peak at iron

Curve of binding energy per nucleon against mass number A, highlighting the maximum at iron-56 and the regions of energy release by nuclear fusion and fission. A (mass number) Binding energy / nucleon (MeV) Fe-56 (maximum, 8.8 MeV) U-235 (7.6 MeV)
Practice★☆☆Not started
The binding energy per nucleon is the average energy required to remove a nucleon from a nucleus. a) Define the binding energy of a nucleus. b) The binding energy per…

The binding energy per nucleon is the average energy required to remove a nucleon from a nucleus.

  1. a) Define the binding energy of a nucleus.
  2. b) The binding energy per nucleon is maximum in intermediate-mass nuclei, such as iron, and lower in very light and very heavy nuclei: reason which nuclei will be the most stable.
Solve
Practice★★☆Not started
In nuclide tables, the binding energy per nucleon of iron-56 is given as $8.8\ \text{MeV}$ and that of uranium-235 as $7.6\ \text{MeV}$, as shown in the figure. a)…

In nuclide tables, the binding energy per nucleon of iron-56 is given as $8.8\ \text{MeV}$ and that of uranium-235 as $7.6\ \text{MeV}$, as shown in the figure.

A (mass number) Binding energy per nucleon (MeV) Fe-56 8.8 56 U-235 7.6 235
  1. a) Calculate the total binding energy of each of these two nuclei.
  2. b) Explain why iron-56 is more stable than uranium-235 even though its total binding energy is smaller.
  3. c) Relate the result to the fact that uranium-235 releases energy when undergoing fission.
Solve
Practice★★★Not started
Data: mass of proton $m_p = 1.0073\ \text{u}$, mass of neutron $m_n = 1.0087\ \text{u}$, mass of iron-56 nucleus $m(\text{Fe}) = 55.9207\ \text{u}$ and…

Data: mass of proton $m_p = 1.0073\ \text{u}$, mass of neutron $m_n = 1.0087\ \text{u}$, mass of iron-56 nucleus $m(\text{Fe}) = 55.9207\ \text{u}$ and $1\ \text{u} \times c^2 = 931.5\ \text{MeV}$.

  1. a) Iron-56 has $Z = 26$: state how many protons and how many neutrons its nucleus contains.
  2. b) Calculate its mass defect, in u units.
  3. c) Calculate its total binding energy and its binding energy per nucleon, in $\text{MeV}$.
  4. d) Given that the binding energy per nucleon of carbon-12 is $7.7\ \text{MeV}$, reason which of the two nuclei is more stable and which process, fusion or fission, could release energy starting from each one.
Solve

Back to the beginning: The strong nuclear interaction wins the battle when the $N/Z$ ratio lies within the band of stability (between $1$ and $1.5$); if a nucleus accumulates too many protons ($Z > 83$; bismuth-209 is only very nearly stable, with an enormous half-life) or departs from that ratio, the electrical repulsion or the energy imbalance destabilises the nucleus and it emits radiation to reach a more tightly bound configuration. Walton's accelerated protons split lithium into two helium nuclei, which lie nearer the peak of the curve, so the mass lost was released as energy.

Summary

See all the exercises in this section