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6th Year OL · Physics
Electromagnetic field · Electromagnetic induction

Motors, generators and transformers

Before you start, make sure you know: Rigid bodies and the moment of a force (5th Year, Leaving Certificate)
Before you start, make sure you know: Power, energy consumption and efficiency (5th Year, Leaving Certificate)

The electricity in your home has travelled a very long way: it may have been born in an alternator turned by water at Ardnacrusha on the Shannon, or by steam at Moneypoint, travelled hundreds of kilometres at very high voltage through the National Grid, and reached your socket after passing through several transformers. Motor, generator and transformer are three sides of the same coin: electromagnetic induction.

The electric motor: a couple that turns

If you connect a loop of copper wire to a cell and place it between the poles of a magnet, the loop gives a sudden jerk and lines up towards the centre: how do we make it keep turning continuously instead of stopping there, so that it can drive machinery?

Direct-current motor: a loop between the north and south poles of a magnet. On each side of the loop perpendicular to the field B there acts a force F, upwards on one side and downwards on the other. This couple makes the loop turn about its axis. The current I comes from the cell through the brushes and the split-ring commutator. N S B shaft loop I − + split-ring commutator brush F F couple → rotation

Back emf

Once the loop spins, its coils cut the field and an induced emf appears. By Lenz's law it opposes the supply voltage, so it is called the back emf, $\varepsilon'$. The current in the motor is then $I = \dfrac{V - \varepsilon'}{R}$. At start-up $\varepsilon' = 0$, so the current is largest.

You can investigate the motor effect in the lab: place a wire in a magnetic field, vary the current $I$ (or the length $l$ of wire in the field) and measure the force with a balance. A graph of force against current is a straight line through the origin, which supports $F = BIl$, and reversing the current or the field reverses the force, as Fleming's left-hand rule predicts.

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The rectangular loop of a DC motor is between the poles of a magnet and carries a current. a) Draw the magnetic forces on the two sides of the loop perpendicular to the…

The rectangular loop of a DC motor is between the poles of a magnet and carries a current.

  1. a) Draw the magnetic forces on the two sides of the loop perpendicular to the field in your notebook and explain why they form a couple that makes the loop rotate.
  2. b) What role does the split-ring commutator play? What would happen to the loop upon reaching the dead centre if it did not exist?

You can do it on paper and send a photo with your answer.

Solve
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The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$…

The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$ perpendicular to its axis of rotation, as shown in the figure.

N S B = 0.4 T long side l = 10 cm I I = 3 A × F = ? · F = ?
  1. a) Calculate the magnetic force on each of the long sides of the loop, $F = I \times l \times B$.
  2. b) Explain why these two forces, acting in opposite directions, form a couple that rotates the loop instead of translating it.
  3. c) What happens to the couple when the plane of the loop is perpendicular to the field (dead centre) and how does the split-ring commutator solve this?
Solve

Generators: a.c. and d.c. generators

Animation of a loop rotating in a uniform magnetic field: its projected ellipse widens and narrows until it is seen almost edge-on, twice per revolution, with constant angular velocity, to generate alternating current. rotation alternating emf, E(t) = E₀·sin(ω·t)

Faraday's law and rms values

The induced emf, $E$, in a coil of $N$ turns is $E = -N\dfrac{\Delta\Phi}{\Delta t}$, where the minus sign is Lenz's law: the induced current opposes the change that causes it (this is why pedalling a bicycle dynamo feels harder when the bulb is on: the energy comes from you). For an a.c. supply the effective (rms) values are $V_{rms} = \dfrac{V_0}{\sqrt2}$ and $I_{rms} = \dfrac{I_0}{\sqrt2}$. Irish mains, $230\ \text{V}$ at $50\ \text{Hz}$, is an rms value.

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a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring…
  1. a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring commutator) determines it.
  2. b) What physical phenomenon are both devices based on?
Solve
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When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure. a) Explain, based on how the…

When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure.

N S B loop uniform rotation emf = ?
  1. a) Explain, based on how the magnetic flux through the loop varies, why the emf continually changes value.
  2. b) Reason why the emf changes sign every half turn.
Solve
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The alternator of a small power plant is equivalent to a coil of $200$ turns of $100\ \text{cm}^2$ rotating at a frequency of $50\ \text{Hz}$ in a field of…

The alternator of a small power plant is equivalent to a coil of $200$ turns of $100\ \text{cm}^2$ rotating at a frequency of $50\ \text{Hz}$ in a field of $0.5\ \text{T}$ (take $\pi \approx 3.14$).

  1. a) Calculate the angular speed of rotation, $\omega = 2 \times \pi \times f$.
  2. b) Calculate the maximum generated emf, $\varepsilon_0 = N \times B \times S \times \omega$.
  3. c) Write the expression $\varepsilon(t)$ assuming that at $t = 0$ the flux is maximum and the emf is zero.
Solve
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In a hydroelectric power plant, water rotates the turbine, which drives the alternator rotor at a frequency of $25\ \text{Hz}$ (take $\pi \approx 3.14$). The alternator…

In a hydroelectric power plant, water rotates the turbine, which drives the alternator rotor at a frequency of $25\ \text{Hz}$ (take $\pi \approx 3.14$). The alternator winding is equivalent to $100$ turns of $0.2\ \text{m}^2$ rotating in a field of $0.8\ \text{T}$.

  1. a) Calculate the angular speed of the rotor.
  2. b) Calculate the maximum generated emf, $\varepsilon_0 = N \times B \times S \times \omega$.
  3. c) Describe the chain of energy transformations from the dammed water to the electrical energy leaving the power plant.
Solve
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The domestic voltage of $230\ \text{V}$ is the rms value of an alternating current of $50\ \text{Hz}$ whose maximum value is $325\ \text{V}$ (take $\pi \approx 3.14$ and…

The domestic voltage of $230\ \text{V}$ is the rms value of an alternating current of $50\ \text{Hz}$ whose maximum value is $325\ \text{V}$ (take $\pi \approx 3.14$ and $\sqrt{2} \approx 1.41$). The graph of voltage against time is shown in the figure.

t emf (V) 0 maximum = 325 V rms = 230 V T = 0.02 s
  1. a) Calculate the angular frequency $\omega$ and write the expression for emf as a function of time, $\varepsilon(t) = \varepsilon_0 \times \sen(\omega \times t)$.
  2. b) Verify that the rms value satisfies the relationship $\varepsilon_{\text{ef}} = \frac{\varepsilon_0}{\sqrt{2}}$.
  3. c) If the power station alternator works with a field of $0.6\ \text{T}$ and turns of $0.05\ \text{m}^2$, calculate how many turns its winding needs to generate that maximum emf, $\varepsilon_0 = N \times B \times S \times \omega$.
Solve

The transformer

If you wind two separate coils around the same iron ring and connect one of them to the alternating current of the mains, the second coil lights a lamp with no electrical contact between the two: how does the energy travel, and what does the voltage received by the lamp depend on?

The two coils are linked by mutual induction: the changing flux from the primary induces an emf in the secondary. This is mutual inductance: the changing current in the primary coil produces a changing magnetic flux in the core, and that changing flux induces an emf in the secondary coil. Because some energy is lost, the efficiency of a real transformer is found by measuring the input power $I_pV_p$ and the output power $I_sV_s$ (see the worked example below).

Real transformers are not perfect. The efficiency is $\text{efficiency} = \dfrac{P_{out}}{P_{in}}\times 100\%$. Energy is lost as heat in the windings ($I^2R$) and as eddy currents in the core, which is why the core is made of insulated laminations. The same definition gives the efficiency of a motor.

National Grid data (secondary sources such as EirGrid reports, which you can look up online to investigate generation and induced emf in real alternators) show that transmission losses are only a few per cent of the energy carried, because of the high voltage used.

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A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in…

A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in the secondary, whereas connecting it to alternating current does.

Solve
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The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns. a) Write the turns ratio,…

The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns.

  1. a) Write the turns ratio, $\frac{V_1}{N_1} = \frac{V_2}{N_2}$.
  2. b) Calculate the secondary voltage and state whether the transformer is step-up or step-down.
Solve
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An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram: a) Calculate…

An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram:

primary secondary ∼ N₁ = 460 V₁ = 230 V N₂ = 40 V₂ = ?
  1. a) Calculate the secondary voltage.
  2. b) A current of $2.3\ \text{A}$ flows through the secondary circuit: calculate the power delivered by the transformer.
  3. c) In an ideal transformer, the primary power is equal to the secondary power: calculate the current drawn by the transformer from the mains.
Solve
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A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ mains. a) Calculate the…

A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ mains.

  1. a) Calculate the turns ratio of the transformer.
  2. b) Calculate the power consumed by the train.
  3. c) Calculate the current drawn by the transformer from the mains.
Solve
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A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the…

A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the $230\ \text{V}$ mains.

  1. a) Calculate the current flowing through the secondary.
  2. b) Calculate the power drawn by the charger from the mains and the corresponding primary current.
  3. c) Calculate the power lost inside the charger.
  4. d) Explain the two main causes of losses in a real transformer: eddy currents in the core (which is why it is made of stacked, insulated laminations) and the Joule effect in the windings.
Solve

Transmitting energy: why at high voltage

The National Grid, run by EirGrid, carries electricity from wind farms in Mayo and Cork and from the East–West Interconnector to Dublin and beyond, losing only a few per cent on the way: what physical trick makes that possible?

Electrical energy transmission: at the power station a step-up transformer raises the voltage, the high-voltage line on pylons carries a low current for hundreds of kilometres with few losses, and next to the city a step-down transformer lowers the voltage for consumption. G high voltage, low I → few losses (I²·R) power station transformer step-up transformer step-down city hundreds of km

That is why at a power station the voltage is stepped up before transmission (with a step-up transformer next to the generators) and stepped down again close to where it is consumed (with a step-down transformer next to the city): the combination of alternating current and transformers is what makes it feasible to transmit electricity hundreds of kilometres with reasonable losses.

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Electricity companies transport energy at voltages of hundreds of kilovolts. a) Write the relationship between power, voltage and current, $P = V \times I$, and explain…

Electricity companies transport energy at voltages of hundreds of kilovolts.

  1. a) Write the relationship between power, voltage and current, $P = V \times I$, and explain why, to transport the same power, a high voltage implies a low current.
  2. b) The power lost due to the Joule effect in the cables is $I^2 \times R$: explain why it is so important for the transported current to be small.
Solve
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A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$. a) Calculate the electrical power it…

A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$.

  1. a) Calculate the electrical power it absorbs from the mains.
  2. b) Calculate its efficiency, as a percentage.
  3. c) Name two mechanisms by which a real motor loses energy and briefly explain them.
Solve
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A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$. a) If transmission were carried out at $1000\ \text{V}$, calculate…

A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$.

  1. a) If transmission were carried out at $1000\ \text{V}$, calculate the current through the line and the power lost in it, and express this loss as a percentage of the transmitted power.
  2. b) Repeat the calculations assuming transmission is carried out at $10\ \text{kV}$.
  3. c) Draw a conclusion as to why it is advantageous to transmit energy at high voltage.
Solve
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A power station generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer…

A power station generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer steps it down to $230\ \text{V}$ for consumption. Observe the diagram:

power station 6 kV step-up 132 kV step-down consumption 230 V
  1. a) Calculate the turns ratio $\frac{N_2}{N_1}$ of the step-up transformer.
  2. b) Calculate the turns ratio $\frac{N_1}{N_2}$ of the city step-down transformer.
  3. c) Explain why the step-up transformer is installed next to the power station and the step-down transformer next to the points of consumption, and not the other way round.
Solve
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A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$. a) Calculate the current flowing through…

A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$.

  1. a) Calculate the current flowing through the line.
  2. b) Calculate the power dissipated in the line and express it as a percentage of the generated power.
  3. c) Repeat the calculations assuming transmission were carried out at $25\ \text{kV}$.
  4. d) Explain the dual role played by transformers (and therefore alternating current) in making long-distance electrical power transmission viable.
Solve
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A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and…

A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and the line would have a resistance of $1\ \Omega$.

  1. a) Calculate the current that would have to be transmitted.
  2. b) Calculate the power that would be lost in the line and compare it with the power intended for transmission.
  3. c) In light of the result, explain why the proposal is unfeasible and how the combination of alternating current and transformers solves the problem.
Solve
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Unit challenge. How does electromagnetic induction transform our daily lives, from the power grid to medicine? Become a technical consultant and prepare a report…

Unit challenge. How does electromagnetic induction transform our daily lives, from the power grid to medicine? Become a technical consultant and prepare a report addressing the following stages:

  1. Generation in the grid: Access the official website of Red Eléctrica de España (RedOS), check the wind and hydroelectric power in real time, and explain how the induced emf ($\varepsilon = -\mathrm{d}\Phi/\mathrm{d}t$) is generated in their alternators.

  2. Home laboratory: Use a magnetometer app (such as Phyphox) on your smartphone to measure the magnetic field $B$ emitted by a transformer or induction hob at distances $d$ between $5.0$ and $25.0\text{ cm}$ (intervals of $5.0\text{ cm}$). Assign reasonable uncertainties (e.g., $\Delta d = \pm 0.2\text{ cm}$ and $\Delta B$). Present a table with your measurements and plot $B$ versus $d$.

  3. Technological applications and health: Analyse the role of eddy currents in induction cooking and compare it with the physical principle of magnetic resonance imaging (MRI). Propose a well-founded safety recommendation for people with pacemakers.

  4. Final proposal: Write a short report (maximum two pages) integrating your calculations, the graph, and your conclusions on electromagnetic safety.

Assessment criteria:

  • Conceptual rigour when stating and applying Faraday's and Lenz's laws.

  • Technical quality of the home experiment (uncertainty estimation, table, and graph).

  • Precise physical justification of the technological applications and health warnings.

Solve

For the unit challenge, use EirGrid's website (not Red Eléctrica de España) to check wind and hydroelectric generation in real time. Explain how an induced emf, $E = -\dfrac{d\Phi}{dt}$, is produced in the alternators that generate this power: the rotating coil changes the flux linkage, as in the section on generators.

Summary

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