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Molecular genetics · From DNA to protein

DNA replication

Every time a cell divides, it must give each daughter cell a complete and exact copy of its genome. Think of the cells lining your skin or gut: they divide every day, and each new cell needs a full set of instructions. That copy is produced by a mechanism that invents nothing: it reads an existing strand and builds its complementary strand by applying, with chemical precision, the base-pairing rule. This section details the molecular machinery that makes this copying possible — which enzymes are involved, why the two new strands are not synthesised in the same way, and how an almost perfect fidelity is guaranteed — taking the prokaryotic model, which is better understood, as a reference, and then pointing out what changes in a eukaryotic cell. At the end we return to a puzzle: how can a human cell copy about two metres of DNA in a matter of hours?

Replication is semi-conservative

In a university lab in Ireland, as in Meselson and Stahl's lab, researchers can follow DNA copies with isotopes. When the DNA of bacteria labelled with $^{15}\text{N}$ is centrifuged after a single division in a medium containing $^{14}\text{N}$, neither fully heavy nor fully light DNA is observed, but a single band of intermediate density. How is the original material shared so that each daughter molecule keeps one complete original strand and receives one new strand, with no mixing within a strand?

Semi-conservative model: a double-stranded DNA molecule replicates and gives rise to two daughter molecules, each with one conserved parental strand and one new strand. Parental DNA (2 strands) replication molecule 1: 1 old strand + 1 new molecule 2: 1 old strand + 1 new original strand (conserved) new strand (synthesised)

When does replication happen?

DNA is replicated during the S phase of interphase, before mitosis begins. If a cell divided without copying its DNA first, each daughter cell would receive only half the genetic information. After replication, each chromosome consists of two identical sister chromatids, joined at the centromere. They carry identical DNA sequences (each is a copy of the same original molecule) and separate during anaphase of mitosis, so each daughter cell gets one.

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What does it mean that DNA replication is semi-conservative? Explain it in your own words, indicating how the two daughter DNA molecules are formed.

What does it mean that DNA replication is semi-conservative? Explain it in your own words, indicating how the two daughter DNA molecules are formed.

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At what point in the cell cycle is DNA replicated and why is it essential for replication to occur before cell division begins?

At what point in the cell cycle is DNA replicated and why is it essential for replication to occur before cell division begins?

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After replication, each chromosome is made up of two sister chromatids. Explain what relationship the DNA sequences of both chromatids bear to each other, why they…

After replication, each chromosome is made up of two sister chromatids. Explain what relationship the DNA sequences of both chromatids bear to each other, why they remain joined for a time and at what moment of cell division they separate.

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Before the famous Meselson and Stahl experiment, there were three theoretical models to explain DNA replication: semiconservative, conservative, and dispersive. Imagine…

Before the famous Meselson and Stahl experiment, there were three theoretical models to explain DNA replication: semiconservative, conservative, and dispersive. Imagine that you perform this experiment by culturing E. coli bacteria for many generations in a medium with heavy nitrogen ($^{15}\text{N}$) until all their DNA is labelled, and then you transfer them to a medium with light nitrogen ($^{14}\text{N}$).

  1. a) Deduce what types of DNA molecules (heavy $^{15}\text{N}\text{-}^{15}\text{N}$, hybrid $^{15}\text{N}\text{-}^{14}\text{N}$, or light $^{14}\text{N}\text{-}^{14}\text{N}$) and in what percentages would appear in the density gradient after one and after two generations if replication were:
  1. Strictly conservative.

  2. Strictly dispersive.

  1. b) Reason in a justified manner which of these two alternative models was ruled out already with the analysis of the first-generation DNA and which obligatorily required waiting for the second generation to be refuted.
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The replication fork

Replication fork. On the left is the original double helix, with a topoisomerase ahead of the fork. At the vertex of the Y, helicase separates the two template strands. On the right, primase synthesises RNA primers and, starting from them, the new DNA strands grow in the 5'→3' direction. 5' 3' 3' 5' Original DNA (double helix) advance of the fork topoisomerase relaxes the supercoiling helicase template strand RNA primer new DNA strand primase new DNA strand template strand RNA primer replication fork

Try it: in the interactive below, complete the complementary strand for the sequence ATGCCA by pairing A with T and G with C.

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Name the main enzyme that synthesises the new strand of DNA during replication and explain its basic function and in which direction (5'→3' or 3'→5') it adds nucleotides.

Name the main enzyme that synthesises the new strand of DNA during replication and explain its basic function and in which direction (5'→3' or 3'→5') it adds nucleotides.

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Name the enzyme that opens the DNA double helix at the replication fork and explain what mechanical problem appears in the molecule ahead of the fork (supercoiling) and…

Name the enzyme that opens the DNA double helix at the replication fork and explain what mechanical problem appears in the molecule ahead of the fork (supercoiling) and what type of enzyme solves it.

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Explain the role of the RNA primer at the start of replication and reason why DNA polymerase cannot initiate a new strand from scratch.

Explain the role of the RNA primer at the start of replication and reason why DNA polymerase cannot initiate a new strand from scratch.

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The leading strand and the lagging strand

If dividing cells are given a very short radioactive pulse, much of the labelled DNA appears in short fragments of about 1,000 nucleotides. If the fork advances continuously in a single direction, why is one of the two strands made in pieces?

Animation of the replication fork: the fork advances to the left, the leading strand grows continuously behind it, the Okazaki fragments of the lagging strand appear one by one growing to the right, in the direction opposite to the advance of the fork, and at the end the gaps are sealed. fork leading strand: continuous lagging strand: Okazaki fragments
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The nucleotides incorporated into the new strand arrive as triphosphates (dATP, dGTP, dCTP, dTTP). Explain where the cell obtains the energy needed to form the bonds of…

The nucleotides incorporated into the new strand arrive as triphosphates (dATP, dGTP, dCTP, dTTP). Explain where the cell obtains the energy needed to form the bonds of the growing chain.

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At a replication fork, one of the new strands (A) is synthesized continuously, moving toward the fork, while the other (B) is synthesized in fragments, moving away from…

At a replication fork, one of the new strands (A) is synthesized continuously, moving toward the fork, while the other (B) is synthesized in fragments, moving away from it. Indicate which of the new strands (A or B) is the leading strand and which is the lagging strand, and explain why one is synthesized continuously and the other in Okazaki fragments, referring to the direction in which DNA polymerase operates.

Diagram of a DNA replication fork with continuous and fragmented synthesisTemplate DNANew strand ANew strand BPrimer (RNA)5'3'3'5'HelicaseFork movementStrand AStrand B
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Place the following stages of replication in order and justify the chosen order: joining of fragments by DNA ligase, unwinding of the double helix by helicase, synthesis…

Place the following stages of replication in order and justify the chosen order: joining of fragments by DNA ligase, unwinding of the double helix by helicase, synthesis of nucleotides by DNA polymerase, removal of primers, formation of Okazaki fragments.

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Name the enzyme that synthesises the RNA primers during replication and explain why each Okazaki fragment needs its own primer while the leading strand only needs one at…

Name the enzyme that synthesises the RNA primers during replication and explain why each Okazaki fragment needs its own primer while the leading strand only needs one at the start.

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Once the RNA primers of the lagging strand have been removed, what are the gaps filled with and which enzyme then seals the chain? Explain why the lagging strand takes…

Once the RNA primers of the lagging strand have been removed, what are the gaps filled with and which enzyme then seals the chain? Explain why the lagging strand takes longer to be completed than the leading strand.

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To analyze the synthesis of new DNA strands during replication, a pulse-chase assay is performed in a bacterial culture: cells are exposed to radioactive thymidine…

To analyze the synthesis of new DNA strands during replication, a pulse-chase assay is performed in a bacterial culture: cells are exposed to radioactive thymidine ($[^3\text{H}]\text{-thymidine}$) during an ultrashort pulse of $5$ seconds and then transferred to a medium with an excess of non-radioactive thymidine (chase) for $5$ minutes. Following alkaline lysis and denaturation, the DNA strands are separated by density gradient centrifugation. a) Predict and justify what size pattern of radioactive fragments (small ones of about $1000$-$2000$ nucleotides or high-molecular-weight ones) will be observed at the end of the pulse ($5$ s) and how it will change after the chase ($5$ min). b) If the same assay is performed in a mutant strain with thermally blocked DNA ligase, predict the result after the $5$-minute chase and justify your answer. c) Reason why this experiment refutes the hypothesis that both strands are synthesized continuously.

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A thermosensitive yeast mutant for the gene encoding DNA ligase I is isolated. At $25\text{ }^\circ\text{C}$ the yeast divides normally, but when cultured at…

A thermosensitive yeast mutant for the gene encoding DNA ligase I is isolated. At $25\text{ }^\circ\text{C}$ the yeast divides normally, but when cultured at $37\text{ }^\circ\text{C}$ the enzyme is inactivated and the cell arrests its cell cycle before entering mitosis. a) A student claims: "At $37\text{ }^\circ\text{C}$, only the lagging strand will have breaks because Okazaki fragments are formed on it; the leading strand will be a single, perfectly continuous chain from one end of the chromosome to the other." Refute this statement, taking into account the presence of multiple replication origins (replicons) per linear chromosome. b) Specify the exact type of chemical bond that cannot be sealed in the absence of ligase (indicating the terminal $3'$ and $5'$ chemical groups) and reason why DNA polymerases cannot carry out this sealing reaction on their own. c) Justify why the presence of unsealed breaks in the double helix activates a cell cycle checkpoint, preventing mitosis.

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To verify whether replication is continuous or discontinuous, researchers carry out pulse labelling with tritiated thymidine for $5$, $15$, and $60$ seconds in bacteria.…

To verify whether replication is continuous or discontinuous, researchers carry out pulse labelling with tritiated thymidine for $5$, $15$, and $60$ seconds in bacteria. After denaturing the DNA, they analyse the size of the radioactive strands by centrifugation. At $5$ seconds, they only detect short fragments ($1000$–$2000$ nucleotides), but as the labelling time increases, the radioactivity progressively shifts toward high-molecular-weight fragments. a) Reason why this result supports that replication occurs in a semi-discontinuous manner rather than continuously on both strands. b) Predict and justify what result would have been obtained in the three measurements if both strands were synthesised continuously from the replication origin. c) Explain the unavoidable molecular cause (structural and enzymatic) why the cell is forced to synthesise one of the two strands based on small fragments.

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Copying fidelity

Proofreading in three steps: DNA polymerase incorporates a mismatched nucleotide (G opposite T), steps back and removes it with its 3'→5' exonuclease activity, and then inserts the correct nucleotide (A opposite T) and continues synthesis. 1 · A mismatched nucleotide is incorporated G ATGCCT TACGGATCTGCAAG 5'3'5' new strand template strand wrong nucleotide (G opposite T) DNA polymerase 2 · It steps back and removes it: 3'→5' exonuclease ATGCCT TACGGATCTGCAAG 5'3'5' G wrong nucleotide removed steps back 3 · It inserts the correct nucleotide and continues ATGCCTA TACGGATCTGCAAG 5'3'5' corrected nucleotide (A opposite T) synthesis continues
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During replication, which nucleotide will be inserted opposite an adenine of the template strand? And opposite a guanine? Explain which property of the DNA structure…

During replication, which nucleotide will be inserted opposite an adenine of the template strand? And opposite a guanine? Explain which property of the DNA structure makes it possible for the copy to be faithful.

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Chemical analysis of the DNA of a species shows that $30\ \%$ of its bases are adenine. State, with reasoning, the percentages of thymine, guanine and cytosine, and…

Chemical analysis of the DNA of a species shows that $30\ \%$ of its bases are adenine. State, with reasoning, the percentages of thymine, guanine and cytosine, and explain what consequence this complementarity relationship has for DNA replication.

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In a laboratory, a mutant strain of Escherichia coli* is obtained that has an alteration in DNA polymerase III: its polymerization rate in the $5'\to 3'$ direction…

In a laboratory, a mutant strain of Escherichia coli is obtained that has an alteration in DNA polymerase III: its polymerization rate in the $5'\to 3'$ direction remains intact, but it has completely lost its $3'\to 5'$ exonuclease activity. a) Predict and justify what effect this mutation will have on copying fidelity and on the spontaneous mutation rate per cell division. b) If this strain is cultured in the presence of 2-aminopurine (a base analog that can mispair with cytosine), reason whether the mutation fixation rate will be higher, lower, or equal to that of the wild-type strain. c) Justify at the molecular level why the proofreading activity must remove the mismatched nucleotide in the $3'\to 5'$ direction before continuing with the addition of the next nucleotide.

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DNA replication achieves extraordinary fidelity thanks to three successive barriers: the pairing specificity of DNA polymerase (an error of $1$ in every $10^5$…

DNA replication achieves extraordinary fidelity thanks to three successive barriers: the pairing specificity of DNA polymerase (an error of $1$ in every $10^5$ nucleotides), $3'\to 5'$ exonuclease proofreading (final error of $1$ in every $10^7$), and the post-replicative mismatch repair system (final error of $1$ in every $10^9$). a) A cell line from hereditary colorectal cancer (Lynch syndrome) exhibits a mutation rate $100$ times higher than normal, even though its DNA polymerases have intact polymerase and exonuclease activities. Deduce and justify what mechanism is failing in these cells. b) To correct an error after the passage of the fork, the repair system must distinguish the template (old) strand from the newly synthesized one. Reason how the cellular machinery discriminates between both strands to avoid replacing the base on the original strand. c) If a mismatch error (for example, a guanine incorrectly paired with a thymine) escapes all correction systems and the cell goes through two complete rounds of cell division, deduce what proportion of the final daughter DNA molecules will carry the permanently fixed mutation.

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Particularities of eukaryotic replication

The DNA of a human cell is almost two metres long and its polymerases move about twenty times more slowly than those of a bacterium, yet the cell replicates its whole genome in only about eight hours instead of taking weeks or months. What organisational strategy allows linear chromosomes to duplicate so quickly without degrading at their ends?

Diagram of a linear eukaryotic chromosome with three origins of replication active at the same time and the telomeres in pink at both ends. multiple origins of replication telomeres: they shorten unless telomerase acts

Back to the start: the answer is that a human cell opens up thousands of origins at once, so the work is shared along every chromosome.

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How many replication forks are formed from a single origin of replication and in which direction do they advance? Explain the advantage of eukaryotic chromosomes having…

How many replication forks are formed from a single origin of replication and in which direction do they advance? Explain the advantage of eukaryotic chromosomes having many origins of replication.

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State two differences between the replication of a bacterial chromosome and that of a human chromosome, considering the shape of the DNA and the number of origins of…

State two differences between the replication of a bacterial chromosome and that of a human chromosome, considering the shape of the DNA and the number of origins of replication.

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The DNA polymerase of E. coli adds about $1000$ nucleotides per second at each fork. Calculate how long it will take, at a minimum, to replicate its circular chromosome…

The DNA polymerase of E. coli adds about $1000$ nucleotides per second at each fork. Calculate how long it will take, at a minimum, to replicate its circular chromosome of $4.6$ million base pairs if it is replicated from a single origin bidirectionally, and comment on the result by comparing it with the generation time of the bacterium (about $20$ minutes).

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Two human cell cultures are compared in the laboratory: normal dermal fibroblasts and cancer cells from a lung carcinoma cell line. Average telomere length is monitored…

Two human cell cultures are compared in the laboratory: normal dermal fibroblasts and cancer cells from a lung carcinoma cell line. Average telomere length is monitored over the course of $60$ population doublings. The fibroblasts enter replicative senescence at doubling $40$ with progressive telomeric shortening, whereas the cancer cells proliferate continuously and maintain their telomere length intact. a) Justify at the molecular level why conventional replication machinery cannot complete the $5'$ end of the lagging strand after the removal of the last RNA primer (the "end replication problem"). b) A therapy is designed that introduces into the tumor cells a synthetic oligonucleotide complementary to the template RNA of human telomerase ribonucleoprotein (hTR). Predict and justify what effect this treatment will have on telomerase activity, telomere length, and the long-term viability of the tumor cells.

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In early embryos of the insect Drosophila melanogaster*, the S phase lasts only $5$ minutes, whereas in adult somatic cells it lasts for about $8$ hours. However, the…

In early embryos of the insect Drosophila melanogaster, the S phase lasts only $5$ minutes, whereas in adult somatic cells it lasts for about $8$ hours. However, the replication fork progression rate is identical at both stages: about $40$ nucleotides per second. a) If the haploid genome of Drosophila has $1.8 \times 10^8$ base pairs, calculate the maximum average distance (in base pairs) that can exist between two adjacent active replication origins in the embryo to complete replication in $5$ minutes, assuming bidirectional replication. b) Interpret what accounts for the difference in S-phase duration between the embryo and the adult if the polymerization rate does not change. c) Reason what genomic risk it would pose to a eukaryotic cell if the same replication origin were activated ("fired") twice within the same S phase, and how the cell prevents this event.

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Summary

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