Evaluating Limits Algebraically
Plug $x = 3$ into $h(x) = \dfrac{x^2 - 9}{x - 3}$ and you get $\dfrac{0}{0}$, which tells you nothing. Yet on a graphing calculator the graph looks like a clean line with one tiny hole. How high is the hole? In this section you will build a toolkit of moves (factor, use a conjugate, compare growth, use special limits, apply L'Hôpital) so that $\frac{0}{0}$ and its relatives stop being scary.
Reading limits: one-sided and infinite
A limit describes where $f(x)$ is heading as $x$ gets close to $a$. It does not care what happens exactly at $x = a$. To decide if the heading is the same from both directions, look at each side separately.
Infinite limits and vertical asymptotes
When the denominator shrinks to $0$ but the numerator does not, the quotient blows up. Use signs to decide whether it goes to $+\infty$ or $-\infty$.
Given the graph of the function $f(x)$ shown below, visually identify the value of the following limits: a) $\lim_{x \to 2^-} f(x)$ b) $\lim_{x \to 2^+} f(x)$ c)…
Given the graph of the function $f(x)$ shown below, visually identify the value of the following limits:
- a) $\lim_{x \to 2^-} f(x)$
- b) $\lim_{x \to 2^+} f(x)$
- c) $\lim_{x \to +\infty} f(x)$
Calculate the one-sided limits of the function $f(x) = \frac{3}{x - 5}$ at the point where the denominator equals zero. To do this, complete the study of the trend from…
Calculate the one-sided limits of the function $f(x) = \frac{3}{x - 5}$ at the point where the denominator equals zero. To do this, complete the study of the trend from the left and from the right:
- a) $\lim_{x \to 5^-} \frac{3}{x - 5}$
- b) $\lim_{x \to 5^+} \frac{3}{x - 5}$
Use the representation of the vertical asymptote to help you:
Factoring and canceling
Always start with direct substitution: plug in $x = a$. If you get a number, that's the limit (for polynomials, rational functions with a nonzero denominator, roots, $\sin$, $\cos$, $e^x$, $\ln x$ inside their domains). If you get $\frac{\text{nonzero}}{0}$, use the sign analysis from the last section. If you get $\frac{0}{0}$, it is an indeterminate form: it means a common factor $(x - a)$ is hiding in both numerator and denominator.
Canceling is legal because a limit only looks at $x$ near $a$, never at $a$ itself. So $\frac{x-3}{x-3} = 1$ for every $x$ the limit looks at.
That answers the opening question: the graph of $h$ is the line $y = x + 3$ with a hole at $(3, 6)$, so the hole is at height $6$.
For higher-degree polynomials you need to find the factor first. If $x = a$ makes the polynomial $0$, then $(x - a)$ is a factor, and synthetic division finds the rest. Some problems call this Ruffini's rule: it is the same as synthetic division.
The altitude of a reconnaissance drone (in feet) with respect to the horizontal distance $x$ traveled is given by the function $h(x) = \frac{x^2 - 9}{x - 3}$. Although…
The altitude of a reconnaissance drone (in feet) with respect to the horizontal distance $x$ traveled is given by the function $h(x) = \frac{x^2 - 9}{x - 3}$. Although the drone cannot physically be at position $x = 3$ due to a software restriction, calculate the limit of the altitude as it approaches this point:
$$\lim_{x \to 3} \frac{x^2 - 9}{x - 3}$$Resolve the indeterminate form of type $\frac{0}{0}$ by simplifying the fraction through the factorization of the polynomials (you can use algebraic identities or…
Resolve the indeterminate form of type $\frac{0}{0}$ by simplifying the fraction through the factorization of the polynomials (you can use algebraic identities or Ruffini's rule):
$$\lim_{x \to 2} \frac{x^2 - 4}{x^2 - 2x}$$Radicals: multiply by the conjugate
When the $\frac{0}{0}$ comes from a square root, factoring won't help. Use the conjugate: the same expression with the opposite sign in the middle. The product of conjugates removes the root:
$$(\sqrt{A} - B)(\sqrt{A} + B) = A - B^2.$$You multiply the numerator and the denominator by the conjugate, which is the same as multiplying by $1$, so the value does not change.
The graph shows the hole at height $\frac{1}{4}$ when $x = 0$.
A precision sensor in a nanotechnology laboratory measures the force of attraction between two particles. The signal strength $S$ as a function of the distance $x$ (in…
A precision sensor in a nanotechnology laboratory measures the force of attraction between two particles. The signal strength $S$ as a function of the distance $x$ (in nanometers) is expressed by the following function:
$$S(x) = \frac{\sqrt{x+5} - 3}{x-4}$$Calculate the value to which the signal tends as the distance $x$ approaches $4$ nanometer. Explain what mathematical technique you have used to resolve the indeterminate form.
Polynomials and rational functions at infinity
As $x \to \pm\infty$, the term with the highest power is so much bigger than the rest that it controls everything. To see this, factor it out.
$$-2x^3 + 50x^2 - 100 = x^3\left(-2 + \frac{50}{x} - \frac{100}{x^3}\right).$$The fractions inside the parentheses go to $0$, so the parentheses tend to $-2$ while $x^3 \to +\infty$. The sign of the leading coefficient therefore decides the answer. For example, $5x^3 - 40x^2 + 7 \to +\infty$ as $x \to +\infty$ but $\to -\infty$ as $x \to -\infty$ (odd degree flips the sign).
For a quotient, divide the numerator and denominator by the highest power of $x$ in the denominator.
Calculate the limit at infinity of the following polynomial function, which represents the evolution of the profits of a tech startup (in thousands of dollars) over time…
Calculate the limit at infinity of the following polynomial function, which represents the evolution of the profits of a tech startup (in thousands of dollars) over time $x$:
$$\lim_{x \to +\infty} ( -2x^3 + 50x^2 - 100 )$$Indicate which is the dominant term and justify why the sign of the leading coefficient determines the final behavior of the function.
A video game server manages the number of connected players using the function $P(x) = \frac{6x^2 + 20}{2x^2 + 5}$, where $x$ is the time in hours since the launch of an…
A video game server manages the number of connected players using the function $P(x) = \frac{6x^2 + 20}{2x^2 + 5}$, where $x$ is the time in hours since the launch of an event. Calculate the limit of players as time tends to infinity:
$$\lim_{x \to +\infty} \frac{6x^2 + 20}{2x^2 + 5}$$In a chemistry laboratory, the concentration of a reactant in a mixture (in mg/l) follows the function $C(t) = \frac{5t + 8}{t^2 + 2}$, where $t$ is the time in minutes.…
In a chemistry laboratory, the concentration of a reactant in a mixture (in mg/l) follows the function $C(t) = \frac{5t + 8}{t^2 + 2}$, where $t$ is the time in minutes. Determine what value the concentration tends to in the long term by calculating:
$$\lim_{t \to +\infty} \frac{5t + 8}{t^2 + 2}$$Radicals at infinity and $\infty - \infty$
A square root of a polynomial also has a dominant term. For large positive $x$, $\sqrt{x^4 + x} \approx \sqrt{x^4} = x^2$ and $\sqrt{x^2 + 6x} \approx x$. To handle it exactly, divide by the right power of $x$ and move it inside the root.
When you get $\infty - \infty$, such as $\sqrt{x^2 + 4x} - x$, the conjugate is again the tool. It turns the difference into a quotient.
What does the answer $2$ mean on a graph? The vertical gap between the curve $y = \sqrt{x^2 + 4x}$ and the line $y = x$ tends to $2$. The curve hugs the line $y = x + 2$ (a slant asymptote).
In the study of the spread of news on social media, it is estimated that the number of users reached $U$ (in thousands) after $t$ hours follows the expression: $$U(t) =…
In the study of the spread of news on social media, it is estimated that the number of users reached $U$ (in thousands) after $t$ hours follows the expression:
$$U(t) = \frac{5t^2 - 3t + 2}{2t^2 + \sqrt{t^4 + 1}}$$Calculate the limit of users reached as time increases indefinitely ($t \to +\infty$). Does the function have any horizontal asymptotes? Justify your answer by comparing the degrees of the dominant terms.
Calculate the following limit by resolving the indeterminate form of type $\infty - \infty$ using the conjugate expression: $$\lim_{x \to +\infty} \left( \sqrt{x^2 + 6x}…
Calculate the following limit by resolving the indeterminate form of type $\infty - \infty$ using the conjugate expression:
$$\lim_{x \to +\infty} \left( \sqrt{x^2 + 6x} - x \right)$$Graphically represent in a schematic way what this result means regarding the distance between the radical function and the line $y = x$.
A satellite follows a trajectory whose radial distance to the center of a planet, in thousands of miles, is given by $d(x) = \sqrt{x^2 + ax} - \sqrt{x^2 - 1}$, where $x$…
A satellite follows a trajectory whose radial distance to the center of a planet, in thousands of miles, is given by $d(x) = \sqrt{x^2 + ax} - \sqrt{x^2 - 1}$, where $x$ represents the mission time. Knowing that after a long time ($x \to +\infty$) the distance stabilizes at $4$ thousand miles, determine the value of the orbital constant $a$.
Comparing growth: logs, powers, exponentials
For quotients like $\frac{\infty}{\infty}$ that mix $\ln x$, powers $x^k$ and exponentials $a^x$, you can decide by asking "who grows faster?"
The graph shows $x^3$ staying ahead for a while, but $2^x$ overtakes it near $x = 10$ and then runs away. Among exponentials, the bigger base wins. For example $\dfrac{2^x}{3^x} = \left(\dfrac{2}{3}\right)^x \to 0$, while $\dfrac{3^x}{2^x} \to +\infty$. Also $\ln(x^{10} + 5)$ behaves like $10 \ln x$, so it is still a logarithm.
To evaluate a limit with several kinds of terms, divide top and bottom by the dominant term of the denominator (or the biggest one overall).
Based on the comparison of orders of infinity, determine the value of the following limits without performing complex operations: a)…
Based on the comparison of orders of infinity, determine the value of the following limits without performing complex operations:
- a) $\lim_{x \to +\infty} \frac{e^x}{x^{10}}$
- b) $\lim_{x \to +\infty} \frac{\ln(x)}{x^2}$
- c) $\lim_{x \to +\infty} \frac{2^x}{3^x}$
Calculate the value of the following limits by comparing the orders of infinity of the functions involved (exponentials, powers and logarithms): a)…
Calculate the value of the following limits by comparing the orders of infinity of the functions involved (exponentials, powers and logarithms):
- a) $\lim_{x \to +\infty} \frac{\ln(x^{10} + 5)}{x}$
- b) $\lim_{x \to +\infty} \frac{3^x}{x^2 + 100x}$
- c) $\lim_{x \to +\infty} \frac{e^x + x^5}{2e^x - \sqrt{x}}$
Calculate the value of the following limit by applying the comparison of infinities or L'Hôpital's Rule, analysing in detail the order of magnitude of each term:…
Calculate the value of the following limit by applying the comparison of infinities or L'Hôpital's Rule, analysing in detail the order of magnitude of each term:
$$\lim_{x \to +\infty} \frac{e^x + x^{10}}{2e^x - \ln(x^5 + 1)}$$Which term dominates the growth of the function in the numerator and which in the denominator?
Special trig limits
Plugging $x = 0$ into $\dfrac{\sin x}{x}$ gives $\frac{0}{0}$, and there is nothing to factor. This limit is so important that you simply memorize it, along with its cousins.
The graph of $\frac{\sin x}{x}$ has a hole at $x = 0$ at height $1$, exactly where the limit says it should be.
Some problems call this idea equivalent infinitesimals: near $0$, $\sin x \approx x$, $\tan x \approx x$ and $1 - \cos x \approx \frac{x^2}{2}$. That is the same set of facts as above, so use whichever way of writing it you prefer.
Calculate the limit at the point $x = 0$ of the following trigonometric expression, using equivalent infinitesimals or known trigonometric identities: $$\lim_{x \to 0}…
Calculate the limit at the point $x = 0$ of the following trigonometric expression, using equivalent infinitesimals or known trigonometric identities:
$$\lim_{x \to 0} \frac{x \cdot \text{tg}(3x)}{\cos(x) - 1}$$Hint: Remember that for very small values of $x$, $\text{tg}(ax) \approx ax$ and $1 - \cos(x) \approx \frac{x^2}{2}$.
L'Hôpital's Rule
Some $\frac{0}{0}$ limits resist factoring and conjugates, and some mix exponentials, logs and polynomials. L'Hôpital's Rule handles them using derivatives.
Powers: take the natural log
For forms like $0^0$, $\infty^0$ or $1^\infty$, set $y = f(x)^{g(x)}$, so that $\ln y = g(x) \ln f(x)$. That turns the power into a product. Find the limit of $\ln y$, then undo the log with $e^{(\cdot)}$.
The next problems all use this section. Remember from the first section that a two-sided limit exists only if both one-sided limits agree.
In the design of a new ramp for a skatepark, engineers need to ensure that the transition between two sections of the track is smooth (continuous). The height of the…
In the design of a new ramp for a skatepark, engineers need to ensure that the transition between two sections of the track is smooth (continuous). The height of the ramp $h(x)$ in feet is given by the following function:
$$h(x) = \begin{cases} \dfrac{\ln(1 + kx)}{x} & \text{if } x > 0 \\ \cos(x) + a & \text{if } x \le 0 \end{cases}$$Determine the values of the parameters $k$ and $a$ so that $\displaystyle \lim_{x \to 0} h(x)$ exists and is equal to the initial height of the ramp, which is $2$ feet.
Determine with reasoning the value of the parameters $a$ and $b$ (where $a, b \in \mathbb{R}$) so that the following equality of limits holds: $$\lim_{x \to 0}…
Determine with reasoning the value of the parameters $a$ and $b$ (where $a, b \in \mathbb{R}$) so that the following equality of limits holds:
$$\lim_{x \to 0} \frac{ax^2 + bx + 1 - e^x}{x^2} = 3$$Hint: Note that for the limit to be finite, the numerator must equal zero at the point in the same way as the denominator.
Study the behavior of the function $f(x) = \left( \cos x \right)^{1/x^2}$ as $x$ approaches zero. To do this, calculate: $$\lim_{x \to 0} (\cos x)^{1/x^2}$$ Explain why…
Study the behavior of the function $f(x) = \left( \cos x \right)^{1/x^2}$ as $x$ approaches zero. To do this, calculate:
$$\lim_{x \to 0} (\cos x)^{1/x^2}$$Explain why this limit results in an indeterminate form of the type $1^\infty$ and solve using natural logarithms or the specific formula for this type of limit.
The number e and the form $1^\infty$
A base that tends to $1$ raised to a power that tends to infinity is not automatically $1$. The base is slightly off $1$, and a huge exponent magnifies that. The outcome depends on the race between the two.
The graph of $\left(1 + \frac{1}{x}\right)^x$ climbs toward $e \approx 2.718$, not toward $1$ and not toward infinity.
The growth of a bird population in a protected nature reserve is governed by the following idealised continuous compound interest law: $$P(t) = \left( \frac{3t + 5}{3t -…
The growth of a bird population in a protected nature reserve is governed by the following idealised continuous compound interest law:
$$P(t) = \left( \frac{3t + 5}{3t - 2} \right)^{2t}$$Calculate the limit of the population as time $t$ tends to infinity. Express the result in terms of the number $e$.
A multiplayer video game server has detected that the number of active users, $N(t)$, in thousands, follows an exponential growth model as a function of time $t$ (in…
A multiplayer video game server has detected that the number of active users, $N(t)$, in thousands, follows an exponential growth model as a function of time $t$ (in months) defined by the expression:
$$N(t) = \left( \frac{3t^2 + 5t + 1}{3t^2 + 2t} \right)^{2t}$$Calculate the limit of active users as time tends to infinity ($t \to +\infty$). Does the player population stabilise at a finite value or grow indefinitely?
Calculate the value of the limit of the following sequence, which frequently appears in continuous compound interest and probability problems: $$\lim_{n \to \infty}…
Calculate the value of the limit of the following sequence, which frequently appears in continuous compound interest and probability problems:
$$\lim_{n \to \infty} \left( \sqrt{n^2 + n} - n \right)^n$$Note: This exercise requires careful treatment of the internal indeterminate form before evaluating the overall power.
Parameters, piecewise functions, and discontinuities
Two kinds of questions come up all the time: "find the constant so that the limit is finite (or two pieces match)" and "what kind of discontinuity is this?"
Given the rational function depending on a parameter $k \in \mathbb{R}$: $$f(x) = \frac{x^3 - kx^2 + 4}{x-2}$$ Find the value of $k$ so that the limit…
Given the rational function depending on a parameter $k \in \mathbb{R}$:
$$f(x) = \frac{x^3 - kx^2 + 4}{x-2}$$Find the value of $k$ so that the limit $\lim_{x \to 2} f(x)$ is finite. Once this value is found, calculate the value of the limit.
Consider the piecewise function $f(x)$: $$f(x) = \begin{cases} \frac{x^2 - 9}{x - 3} & \text{if } x < 3 \\ \sqrt{2x + a} & \text{if } x \ge 3 \end{cases}$$ Calculate the…
Consider the piecewise function $f(x)$:
$$f(x) = \begin{cases} \frac{x^2 - 9}{x - 3} & \text{if } x < 3 \\ \sqrt{2x + a} & \text{if } x \ge 3 \end{cases}$$Calculate the value of the parameter $a$ so that the limit of the function exists at the point $x = 3$. What is the value of this limit?
Let the function be $g(x) = \dfrac{x^3 - 2x^2 + k}{x^2 - 4}$. Calculate the value of $k$ so that the limit of the function as $x \to 2$ is finite. Once $k$ is found,…
Let the function be $g(x) = \dfrac{x^3 - 2x^2 + k}{x^2 - 4}$. Calculate the value of $k$ so that the limit of the function as $x \to 2$ is finite. Once $k$ is found, calculate this limit and classify the type of discontinuity the function presents at $x = 2$ and at $x = -2$.