Ideal gases
A 12.3 L diving cylinder used off the Kerry coast at 200 atm, a $\text{CO}_2$ fire extinguisher in your school corridor, a hot-air balloon that rises because the hot air inside it is less dense than the air outside: all three cases are solved with a single equation, the same for any gas in any conditions. You may have met the relationships between pressure, volume and temperature of gases before; now you are going to bring them together into one tool, which can also link pressure and volume to the real amount of substance, in moles.
The ideal gas equation of state
In a laboratory, the behaviour of a gas enclosed in a cylinder with a piston is studied. The state of the gas is described by four variables: pressure, volume,…
In a laboratory, the behaviour of a gas enclosed in a cylinder with a piston is studied. The state of the gas is described by four variables: pressure, volume, temperature and amount of substance. The diagram shows the gas enclosed in the cylinder with its four variables.
- a) Explain in your own words what each of these variables indicates.
- b) State the SI unit for each one.
- c) When applying the ideal gas equation, $p\times V=n\times R\times T$, with $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$, in which units should pressure, volume, temperature and amount of substance be expressed?
A rigid laboratory container contains a gas at $2\ \text{atm}$ and $27\ \celsius$, and occupies a volume of $24.6\ \text{L}$. Data:…
A rigid laboratory container contains a gas at $2\ \text{atm}$ and $27\ \celsius$, and occupies a volume of $24.6\ \text{L}$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Express the temperature in kelvin.
- b) Apply the ideal gas equation, $p\times V=n\times R\times T$, and calculate how many moles of gas are in the container.
A cylinder with a piston contains $2\ \text{mol}$ of nitrogen at $300\ \text{K}$, subjected to a pressure of $4\ \text{atm}$. Data:…
A cylinder with a piston contains $2\ \text{mol}$ of nitrogen at $300\ \text{K}$, subjected to a pressure of $4\ \text{atm}$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Write down the ideal gas equation and rearrange for volume.
- b) Calculate the volume occupied by the gas.
A factory boiler contains $4\ \text{mol}$ of water vapour in a volume of $16.4\ \text{L}$ at a pressure of $10\ \text{atm}$. Data:…
A factory boiler contains $4\ \text{mol}$ of water vapour in a volume of $16.4\ \text{L}$ at a pressure of $10\ \text{atm}$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Calculate the temperature of the vapour in kelvin.
- b) Express it in degrees Celsius.
- c) Explain why it is essential to use kelvin and not degrees Celsius in the ideal gas equation: what would happen to the result if you used the temperature in $\celsius$?
Standard temperature and pressure and molar volume
If you measure in the laboratory the volume of $1\ \text{mol}$ of helium ($4\ \text{g}$), $1\ \text{mol}$ of nitrogen ($28\ \text{g}$) and $1\ \text{mol}$ of carbon dioxide ($44\ \text{g}$) at $0\ ^\circ\text{C}$ and $1\ \text{atm}$, you get exactly $22.4\ \text{L}$ in all three cases: why do gases whose molecules have such different masses and sizes occupy exactly the same space in those conditions?
In an experiment, exactly $1\ \text{mol}$ of an ideal gas is enclosed in a $22.4\ \text{L}$ container kept at $273\ \text{K}$. Data:…
In an experiment, exactly $1\ \text{mol}$ of an ideal gas is enclosed in a $22.4\ \text{L}$ container kept at $273\ \text{K}$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Calculate the pressure of the gas, in atmospheres.
- b) Which known value does the result approximate? What are these pressure and temperature conditions called?
In chemistry, standard temperature and pressure (STP) are used as reference conditions. a) Which values of pressure and temperature define standard conditions (STP)?…
In chemistry, standard temperature and pressure (STP) are used as reference conditions.
- a) Which values of pressure and temperature define standard conditions (STP)? Express the temperature in kelvin as well.
- b) Use the ideal gas equation, $p\times V=n\times R\times T$ with $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$, to calculate the volume occupied by $1\ \text{mol}$ of any ideal gas at standard temperature and pressure.
- c) What is this reference volume called?
In a laboratory, $32\ \text{g}$ of oxygen, $\text{O}2$, is weighed. Data: molar mass of $\text{O}2$, $32\ \text{g/mol}$; molar volume at standard temperature and…
In a laboratory, $32\ \text{g}$ of oxygen, $\text{O}_2$, is weighed. Data: molar mass of $\text{O}_2$, $32\ \text{g/mol}$; molar volume at standard temperature and pressure, $22.4\ \text{L/mol}$.
- a) How many moles of oxygen is this?
- b) What volume would this gas occupy at standard temperature and pressure?
Two identical $11.2\ \text{L}$ containers are both at STP ($1\ \text{atm}$ and $273\ \text{K}$): one contains nitrogen, $\text{N}2$, and the other hydrogen, $\text{H}2$.…
Two identical $11.2\ \text{L}$ containers are both at STP ($1\ \text{atm}$ and $273\ \text{K}$): one contains nitrogen, $\text{N}_2$, and the other hydrogen, $\text{H}_2$. Data: molar masses of $\text{N}_2$ and $\text{H}_2$, $28\ \text{g/mol}$ and $2\ \text{g/mol}$; molar volume at STP, $22.4\ \text{L/mol}$.
- a) How many moles of gas are in each container?
- b) Calculate the mass of gas in each one.
- c) Which of the two containers weighs more? Does it therefore contain more particles? Give reasons for your answers.
The density of a gas
At a birthday party in Galway, a helium balloon rises quickly to the ceiling, whereas if you inflate it with carbon dioxide from a cartridge it falls to the floor immediately, even though both are at the same pressure and temperature: how does the mass of each molecule determine whether a gas floats or sinks in air?
The kinetic theory explains why gases have such low densities: in a gas the particles are very far apart and mostly empty space lies between them, whereas in a liquid they are packed close together.
A $5\ \text{L}$ cylinder contains $10\ \text{g}$ of nitrogen gas. The figure compares this cylinder with the same volume of water using the particle model. a) Calculate…
A $5\ \text{L}$ cylinder contains $10\ \text{g}$ of nitrogen gas. The figure compares this cylinder with the same volume of water using the particle model.
- a) Calculate the density of the gas in $\text{g/L}$ (mass divided by volume).
- b) The density of water is $1000\ \text{g/L}$: how many times denser is water than this gas?
- c) Explain, using the particle model, why gases have such low densities compared to liquids.
$\text{CO}2$ is denser than air, which explains why it can accumulate at the bottom of wells and poorly ventilated cellars. Data: molar mass of $\text{CO}2$,…
$\text{CO}_2$ is denser than air, which explains why it can accumulate at the bottom of wells and poorly ventilated cellars. Data: molar mass of $\text{CO}_2$, $44\ \text{g/mol}$; $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$; density of air at STP, $1.29\ \text{g/L}$.
- a) Calculate the mass of $1\ \text{mol}$ of $\text{CO}_2$ and the volume it occupies at STP ($1\ \text{atm}$ and $273\ \text{K}$).
- b) Calculate the density of $\text{CO}_2$ at STP, to one decimal place.
- c) Compare it with that of air and explain why $\text{CO}_2$ accumulates in low areas.
A cylinder containing an unknown gas is received in a laboratory. Measuring its mass and volume gives a density of $1.43\ \text{g/L}$ at STP. Data: molar volume at STP,…
A cylinder containing an unknown gas is received in a laboratory. Measuring its mass and volume gives a density of $1.43\ \text{g/L}$ at STP. Data: molar volume at STP, $22.4\ \text{L/mol}$.
- a) Calculate the mass of $22.4\ \text{L}$ of the gas, i.e. its molar mass.
- b) Which gas could it be: $\text{H}_2$ ($2\ \text{g/mol}$), $\text{O}_2$ ($32\ \text{g/mol}$) or $\text{CO}_2$ ($44\ \text{g/mol}$)? Justify your answer.
Mixtures, transfers and balloons: the equation in real situations
When a gas changes conditions but the amount stays the same, $n$ and $R$ are unchanged, so $\dfrac{pV}{T}$ keeps the same value. If $T$ is also constant, $p_1V_1 = p_2V_2$ (Boyle's law). If $V$ and $n$ are constant, $p \propto T$: doubling the temperature in kelvin doubles the pressure. If $V$ and $T$ are constant, $p \propto n$. The kinetic theory explains why: hotter particles move faster and hit the walls harder and more often; more particles means more collisions.
A hot-air balloon rises because of the same equation: if the air inside is heated, its density falls (at the same pressure, which is always atmospheric pressure) and ends up below the density of the cold air outside, just as an object floats in a liquid that is denser than it is. A hot-air balloon over the Wicklow Mountains works the same way.
A diving cylinder of $12.3\ \text{L}$ is filled with air at $200\ \text{atm}$ and $27\ \celsius$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.…
A diving cylinder of $12.3\ \text{L}$ is filled with air at $200\ \text{atm}$ and $27\ \celsius$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$. The pressure-volume graph shows the compressed air in the cylinder and its expansion at constant temperature to surface pressure.
- a) Express the temperature in kelvin and calculate how many moles of air the cylinder contains.
- b) Calculate what volume all that air would occupy at surface pressure, $1\ \text{atm}$, and at the same temperature.
- c) A diver consumes about $60\ \text{L}$ of air per minute measured at the surface: estimate, in minutes, the theoretical duration of the cylinder.
A hot-air balloon is open at the bottom, so that the pressure of the air inside is always atmospheric pressure, $1\ \text{atm}$. The outside air is at $27\ \celsius$ and…
A hot-air balloon is open at the bottom, so that the pressure of the air inside is always atmospheric pressure, $1\ \text{atm}$. The outside air is at $27\ \celsius$ and the burner heats the inside air up to $127\ \celsius$. Data: average molar mass of air, $29\ \text{g/mol}$; $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$. The diagram represents the balloon and the inside and outside air.
- a) Express both temperatures in kelvin and calculate the density of the outside air.
- b) Calculate the density of the hot air inside.
- c) Compare the mass of $1000\ \text{L}$ ($1\ \text{m}^3$) of air inside and outside, and use this difference to explain why the balloon rises.
Two rigid containers, of $10\ \text{L}$ and $30\ \text{L}$, are connected by a tap that is closed. The first contains oxygen at $4\ \text{atm}$ and $300\ \text{K}$; the…
Two rigid containers, of $10\ \text{L}$ and $30\ \text{L}$, are connected by a tap that is closed. The first contains oxygen at $4\ \text{atm}$ and $300\ \text{K}$; the second is empty. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$. The diagram shows the setup with the tap still closed.
- a) Calculate the moles of enclosed oxygen.
- b) The tap is opened and the gas spreads throughout the entire available volume, without the temperature changing. Calculate the final pressure.
- c) Explain, using the kinetic model, why the pressure drops even though not a single particle has left the system.
Ideal and real gases
An ideal gas is a useful model, but when do real gases stop obeying it, and how can we tell which assumptions of the kinetic theory fail?
An illuminated sign contains a pure noble gas. In the laboratory, its density is measured: $1.79\ \text{g/L}$ at $2\ \text{atm}$ and $273\ \text{K}$. Data:…
An illuminated sign contains a pure noble gas. In the laboratory, its density is measured: $1.79\ \text{g/L}$ at $2\ \text{atm}$ and $273\ \text{K}$. Data: $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Calculate the volume that $1\ \text{mol}$ of the gas would occupy at $2\ \text{atm}$ and $273\ \text{K}$.
- b) Use the density to calculate the mass of that volume, i.e. the molar mass of the gas.
- c) Identify it among the noble gases: He ($4\ \text{g/mol}$), Ne ($20\ \text{g/mol}$), Ar ($40\ \text{g/mol}$) and Kr ($84\ \text{g/mol}$).
- d) Give reasons, using the ideal gas equation, why increasing the pressure increases the density of a gas even though its molar mass does not change.
At the summit of Mount Everest, the atmosphere is much less dense than at sea level. Data: average molar mass of air, $29\ \text{g/mol}$;…
At the summit of Mount Everest, the atmosphere is much less dense than at sea level. Data: average molar mass of air, $29\ \text{g/mol}$; $R=0.082\ \text{atm}\times\text{L}/(\text{mol}\times\text{K})$.
- a) Calculate the density of air at sea level, at $1\ \text{atm}$ and $15\ \celsius$ ($288\ \text{K}$).
- b) At the summit, the pressure is $0.33\ \text{atm}$ and the temperature is $-30\ \celsius$ ($243\ \text{K}$): calculate the air density there.
- c) Calculate how many grams of air a climber inhales in each breath of $2\ \text{L}$ at each of the two locations.
- d) Use the results to explain why many climbers need oxygen cylinders at the summit even though the proportion of oxygen in the air is the same at both locations.
Back to the start: In the extinguisher, the $\text{CO}_2$ is stored compressed; when the valve is opened it expands towards atmospheric pressure ($1\ \text{atm}$), occupying hundreds of times its volume and smothering the fire by displacing the oxygen, thanks to its density (about $1.96\ \text{g/L}$) being greater than that of air.