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Exercises: Hypothesis testing

Practice★☆☆
A streaming platform claims that the mean time its users spend watching series is $120$ minutes a day. A group of students suspects that, due to exams, this time has…

A streaming platform claims that the mean time its users spend watching series is $120$ minutes a day. A group of students suspects that, due to exams, this time has decreased. To carry out a hypothesis test on this claim:

  1. a) Clearly define the null hypothesis ($H_0$) and the alternative hypothesis ($H_1$).
  1. b) State whether it is a one-tailed or two-tailed test.
μ = 120 H₀: μ = 120 H₁: μ < 120 One-tailed test
Solve
Practice★☆☆
In the quality control of a potato chip factory, we want to check if the mean weight of the bags is really $150$ ounces, as indicated on the packaging. It is known that…

In the quality control of a potato chip factory, we want to check if the mean weight of the bags is really $150$ ounces, as indicated on the packaging. It is known that the population standard deviation is $\sigma = 5$ ounces. If it is suspected that the bags may weigh both more and less than indicated:

  1. a) Set up the hypotheses $H_0$ and $H_1$.
  1. b) If we set a significance level of $\alpha = 0,05$, calculate the critical values $z_{\alpha/2}$ that delimit the acceptance zone.
Solve
Practice★☆☆
A sociologist claims that $35\%$ of American teenagers prefer physical format to digital for reading books. To test this claim against the suspicion that the proportion…

A sociologist claims that $35\%$ of American teenagers prefer physical format to digital for reading books. To test this claim against the suspicion that the proportion is different, a random sample is chosen. Determine the acceptance region for the sample proportion if a confidence level of $95\%$ is used and the sample size is $n = 400$ people.

p₀ = 0.35 0,3033 0,3967 95% Acceptance Region 2,5% Rejection 2,5% Rejection
Solve
Practice★☆☆
We are carrying out a two-tailed hypothesis test for the mean of a normal population with known $\sigma$. After calculating the test statistic with the data from a…

We are carrying out a two-tailed hypothesis test for the mean of a normal population with known $\sigma$. After calculating the test statistic with the data from a sample, we obtain a value of $z_{exp} = 2,15$.

If the critical values for a significance level of $\alpha = 0,05$ are $-1,96$ and $1,96$, reason whether we should accept or reject the null hypothesis.

Solve
Practice★☆☆
A sports shoe brand claims that $60\%$ of marathon runners use its products. A sports journalist suspects that the proportion is lower. To carry out the test, $100$…

A sports shoe brand claims that $60\%$ of marathon runners use its products. A sports journalist suspects that the proportion is lower. To carry out the test, $100$ runners are surveyed and it is found that $52$ of them use this brand.

  1. a) Calculate the test statistic (sample proportion) $\hat{p}$.
  1. b) Write the expression for the standardised test statistic $Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 \cdot q_0}{n}}}$ for this case.
Solve
Practice★☆☆
We want to check if the mean charging time of a smartphone battery has changed after a software update. The mean time before was $90$ minutes with a population standard…

We want to check if the mean charging time of a smartphone battery has changed after a software update. The mean time before was $90$ minutes with a population standard deviation of $\sigma = 10$ minutes. A sample of $64$ phones is taken and a mean charging time of $93$ minutes is obtained.

For a significance level of $\alpha = 0,01$ (where the critical value is $z_{\alpha/2} = 2,575$), determine the acceptance zone of the two-tailed test for the population mean.

Z 0 −2.575 2.575 x̄ 90 ? ? 93 Acceptance Zone 1 - α = 0.99 Rejection α/2 = 0.005 Rejection α/2 = 0.005 μ = 90 σ = 10 n = 64 x̄ = 93 Acceptance Zone?
Solve
Practice★☆☆
Explain in your own words what it means to commit a Type I Error in the context of a study attempting to prove whether a new study method improves math scores (where…

Explain in your own words what it means to commit a Type I Error in the context of a study attempting to prove whether a new study method improves math scores (where $H_0$ is that the method produces no improvements).

Solve
Practice★☆☆
Given a normal population with standard deviation $\sigma = 12$, we want to test $H_0: \mu = 50$ against $H_1: \mu > 50$ with a significance level of $\alpha = 0,05$.…

Given a normal population with standard deviation $\sigma = 12$, we want to test $H_0: \mu = 50$ against $H_1: \mu > 50$ with a significance level of $\alpha = 0,05$.

Calculate the critical value of the sample mean $\bar{x}_c$ for a sample of size $n = 36$ using the formula $\bar{x}_c = \mu_0 + z_{\alpha} \cdot \frac{\sigma}{\sqrt{n}}$, knowing that for $\alpha = 0,05$ the value of $z_{\alpha} = 1,645$.

Solve
Practice★★☆
A well-known technology influencer* claims in one of their videos that $40\ \%$ of American teenagers prefer to use tablets rather than laptops for studying. A student…

A well-known technology influencer claims in one of their videos that $40\ \%$ of American teenagers prefer to use tablets rather than laptops for studying. A student association decides to test this claim and carries out a random survey of $250$ high school students, of which $85$ state their preference for the tablet.

Using a significance level of $\alpha = 0,05$, set up a two-tailed hypothesis test to determine if the influencer's claim can be considered statistically acceptable or if, on the contrary, the true proportion is different.

p₀ = 0.40 0.339 0.461 Acceptance Zone 1 - α = 0.95 Rejection α/2 = 0.025 Rejection α/2 = 0.025 p̂ = 0.34 Sample
Solve
Practice★★☆
An online shopping courier company claims that the mean delivery time for its parcels in large cities is $48$ hours, with a known standard deviation of $\sigma = 6$…

An online shopping courier company claims that the mean delivery time for its parcels in large cities is $48$ hours, with a known standard deviation of $\sigma = 6$ hours. A group of users suspects that the service is slower than advertised. To check this, they record the delivery times of $36$ randomly chosen orders, obtaining a mean of $50,5$ hours.

State the null and alternative hypotheses for this case and carry out a one-tailed (right-tailed) hypothesis test with a confidence level of $99\ \%$. Is there sufficient evidence to claim that the company takes longer than it claims?

Solve
Practice★★☆
A new model of running shoes designed to increase performance is being tested. The manufacturer sets the null hypothesis $H_0$: "The mean performance with the new model…

A new model of running shoes designed to increase performance is being tested. The manufacturer sets the null hypothesis $H_0$: "The mean performance with the new model is equal to that of the previous model" against the alternative $H_1$: "The mean performance is higher".

Explain with reasoning what it would mean to commit a Type I error and a Type II error in this practical context. Which of the two errors do you think would be more damaging to the company's brand image if discovered later?

Solve
Practice★★☆
In a study on sustainability, it is known that two years ago $30\ \%$ of young people in a town used public transportation to go to school. Following an environmental…

In a study on sustainability, it is known that two years ago $30\ \%$ of young people in a town used public transportation to go to school. Following an environmental awareness campaign, we want to check if this percentage has increased. A random sample of $150$ young people is taken and it is observed that $54$ of them now use public transportation.

From these data, and with a significance level of $5\ \%$, can it be concluded that the campaign has been effective and the proportion of users has increased? Set up the corresponding test.

p₀ = 0.30 z_α = ? α = 5% (Rejection) Sample Data n = 150 x = 54 p̂ = 54/150 = ? Hypotheses H₀: p ≤ 0.30 H₁: p > 0.30 Does p̂ fall in the rejection zone? p̂ = ?
Solve
Practice★★☆
A soft drink manufacturer claims that each can contains, on average, $330$ fl oz of the product. It is known that the filling of the cans follows a normal distribution…

A soft drink manufacturer claims that each can contains, on average, $330$ fl oz of the product. It is known that the filling of the cans follows a normal distribution with a standard deviation of $\sigma = 5$ fl oz. A consumer inspector takes a random sample of $25$ cans and obtains a mean volume of $327,5$ fl oz.

With a significance level of $1\ \%$, carry out a two-tailed test to verify if the mean content of the cans differs significantly from the value advertised by the manufacturer.

Solve
Practice★★☆
A health center claims that the proportion of smokers in the population of young people aged between 16 and 18 is $15\ \%$. To verify this, a study is carried out on a…

A health center claims that the proportion of smokers in the population of young people aged between 16 and 18 is $15\ \%$. To verify this, a study is carried out on a sample of $400$ young people in that age range, resulting in $72$ of them smoking.

Calculate the p-value (probability of obtaining a result as extreme as or more extreme than the one observed under the null hypothesis) for a two-tailed test. In light of the result, would you reject the health center's claim for a standard significance level of $\alpha = 0,05$?

Solve
Practice★★☆
A study has been carried out on the monthly leisure expenditure of college students in a city, assuming it follows a normal distribution with standard deviation…

A study has been carried out on the monthly leisure expenditure of college students in a city, assuming it follows a normal distribution with standard deviation $\$\sigma = 20$. A $95\ \%$ confidence interval of $(75,1; 84,9)$ has been obtained for the mean.

Without performing new standardization calculations, use the relationship between confidence intervals and hypothesis testing to answer: Would the null hypothesis $\$H_0: \mu = 70$ be rejected against $\$H_1: \mu \neq 70$ with a significance level of $\alpha = 0,05$? What if the null hypothesis were $\$H_0: \mu = 80$? Justify your answer.

Solve
Practice★★☆
A streaming platform suspects that the mean daily time its users spend watching content has changed compared to last year, which was $120$ minutes. They assume a normal…

A streaming platform suspects that the mean daily time its users spend watching content has changed compared to last year, which was $120$ minutes. They assume a normal distribution with $\sigma = 30$ minutes. They take a random sample of $100$ users and observe a mean of $126$ minutes.

Determine the acceptance region and the critical region for a two-tailed test with a significance level of $10\ \%$. What decision should the platform make regarding its suspicion?

μ₀ = 120 126 c₁ = ? c₂ = ? Acceptance Region 1 - α = 0.90 Critical Region α/2 = 0.05 Critical Region α/2 = 0.05 H₀: μ = 120 H₁: μ ≠ 120 n = 100 σ = 30 x̄ = 126 Decision?
Solve
Practice★★★
A well-known eSports organization claims that $40\%$ of teenagers who play "League of Legends" in the US have spent money on in-game cosmetics (skins*). However, a…

A well-known eSports organization claims that $40\%$ of teenagers who play "League of Legends" in the US have spent money on in-game cosmetics (skins). However, a consumer association suspects that this figure is different. To test this hypothesis, they carry out a random survey of $600$ players, of which $216$ admit to having made purchases.

  1. a) State the null and alternative hypotheses for a two-tailed test.
  2. b) Using a significance level of $\alpha = 0,05$, determine the critical region.
  3. c) Can the organization's claim be rejected with the data obtained? Justify your answer by calculating the test statistic.
p₀ = 0.40 c₁ = ? c₂ = ? p̂ = 0.36 1 - α = 0.95 Acceptance Region α/2 = 0.025 α/2 = 0.025 n = 600 x = 216 p̂ = 0.36 α = 0.05 H₀: ? H₁: ?
Solve
Practice★★★
A study on youth mental health indicates that the mean daily time that high school seniors spend on TikTok is $120$ minutes, with a standard deviation of $30$ minutes. A…

A study on youth mental health indicates that the mean daily time that high school seniors spend on TikTok is $120$ minutes, with a standard deviation of $30$ minutes. A school counselor believes that in their school, due to the pressure of SAT exams, the mean time is significantly lower. They take a random sample of $50$ students and obtain a mean of $112$ minutes.

  1. a) Define the appropriate hypothesis test for the counselor's belief.
  2. b) Calculate the p-value of the sample obtained.
  3. c) If a significance level of $1\%$ is used, what conclusion should the counselor draw? What if the significance level were $5\%$?
Solve
Practice★★★
A brand of wireless headphones claims that the battery of its new "Pro-Z" model lasts, on average, $24$ hours. It is known that the battery lifespan follows a normal…

A brand of wireless headphones claims that the battery of its new "Pro-Z" model lasts, on average, $24$ hours. It is known that the battery lifespan follows a normal distribution with a standard deviation of $\sigma = 2,5$ hours. A group of technical testers analyzes $100$ headphones and finds a mean lifespan of $23,4$ hours.

  1. a) Carry out a one-tailed hypothesis test to check if the battery lasts less than promised with a significance level of $\alpha = 0,05$.
  2. b) Explain, in the context of the problem, what committing a Type II error would consist of.
  3. c) What should the minimum sample size be so that, with a mean of $23,4$, the result is significant at $1\%$?
μ₀ = 24 z = 0 23,59 z = −1.645 x̄ = 23.4 z = −2.4 Reject H₀ α = 0,05 Accept H₀ 1 - α = 0,95 n = 100 σ = 2,5 σ/√n = 0.25
Solve
Practice★★★
In a debate on sustainability, it is claimed that $75\%$ of young people in a city separate plastic packaging from the rest of the trash. To verify this, a sample of…

In a debate on sustainability, it is claimed that $75\%$ of young people in a city separate plastic packaging from the rest of the trash. To verify this, a sample of $150$ young people is selected and it is observed that $105$ of them recycle correctly.

  1. a) Set up the hypothesis test to check if the true proportion is lower than claimed.
  2. b) Is the initial claim acceptable for a significance level of $10\%$?
  3. c) Suppose the true proportion were $65\%$. What decision would most likely be made with this test if the sample were only $20$ people? Reason about the importance of sample size on the power of the test.
Solve
Practice★★★
A manufacturer of electronic components for smartphones guarantees that the percentage of defective parts in its production is, at most, $2\%$. An external quality…

A manufacturer of electronic components for smartphones guarantees that the percentage of defective parts in its production is, at most, $2\%$. An external quality control decides to sample $2500$ components to verify this guarantee. After the analysis, $62$ defective parts are found.

  1. a) Formulate the hypotheses for a right-tailed test.
  2. b) Calculate the value of the test statistic.
  3. c) Determine the critical significance level (p-value). In light of the result, do you think the manufacturer should review its production process? Justify your answer.
Solve
Practice★★★
We want to investigate whether a new study method improves performance in math. The historical mean score in a region is $6,4$ with a standard deviation of…

We want to investigate whether a new study method improves performance in math. The historical mean score in a region is $6,4$ with a standard deviation of $\sigma = 1,2$. The new method is applied to an experimental group of $36$ students and a mean score of $6,9$ is obtained.

  1. a) Carry out a one-tailed hypothesis test for a significance level of $\alpha = 0,05$.
  2. b) If the $95\%$ confidence interval for the mean of this group were $(6,508 ; 7,292)$, could you have answered the previous section without calculating the test statistic? Explain the relationship between confidence intervals and hypothesis testing.
6.0 6.2 6.6 6.8 7.0 7.2 6.73 Rejection region α = 0.05 μ₀ = 6.4 95% Confidence Interval 6.508 7.292 x̄ = 6.9
Solve
Practice★★★
A trade school claims that the mean starting salary of its graduates is $\$1550…

A trade school claims that the mean starting salary of its graduates is $\$1550$ per month. It is known that salaries follow a normal distribution with standard deviation $\$\sigma = 210$. A trade union selects a sample of $49$ graduates and obtains a mean salary of $\$1480$.

  1. a) Test the school's hypothesis against the union's suspicion that the salary is lower, using $\alpha = 0,01$.
  2. b) Calculate the probability of committing a Type I error if we decide to reject the null hypothesis for any sample mean lower than $\$1500$.
  3. c) How would an increase in the population standard deviation affect the acceptance region?
Solve
Practice★★★
A streaming platform considers a user to be "loyal" if they watch more than $15$ hours of content per month. The company maintains that $60\%$ of its current subscribers…

A streaming platform considers a user to be "loyal" if they watch more than $15$ hours of content per month. The company maintains that $60\%$ of its current subscribers meet this criterion. For a market study, the profiles of $400$ randomly chosen users are analyzed and it is found that $224$ are loyal users.

  1. a) Set up a two-tailed test for the proportion of loyalty with $\alpha = 0,05$.
  2. b) What is the maximum allowable error of the proportion so that the null hypothesis is not rejected with the sample obtained?
  3. c) If we change the significance level to $\alpha = 0,01$, would the decision change? Reason about how the strictness of the test affects the possibility of rejecting a claim.
Solve