Exercises: Motors, generators and transformers
a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring…
- a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring commutator) determines it.
- b) What physical phenomenon are both devices based on?
When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure. a) Explain, based on how the…
When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure.
- a) Explain, based on how the magnetic flux through the loop varies, why the emf continually changes value.
- b) Reason why the emf changes sign every half turn.
In a bicycle with a dynamo, the light turns on when pedalling. a) Explain how the dynamo generates the current that powers the bulb. b) According to Lenz's law, the…
In a bicycle with a dynamo, the light turns on when pedalling.
- a) Explain how the dynamo generates the current that powers the bulb.
- b) According to Lenz's law, the induced current opposes the rotation of the dynamo: explain where the energy consumed by the bulb ultimately comes from, and why more resistance is felt when pedalling with the dynamo connected.
The rectangular loop of a DC motor is between the poles of a magnet and carries a current. a) Draw the magnetic forces on the two sides of the loop perpendicular to the…
The rectangular loop of a DC motor is between the poles of a magnet and carries a current.
- a) Draw the magnetic forces on the two sides of the loop perpendicular to the field in your notebook and explain why they form a couple that makes the loop rotate.
- b) What role does the split-ring commutator play? What would happen to the loop upon reaching the dead center if it did not exist?
A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in…
A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in the secondary, whereas connecting it to alternating current does.
The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns. a) Write the turns ratio,…
The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns.
- a) Write the turns ratio, $\frac{V_1}{N_1} = \frac{V_2}{N_2}$.
- b) Calculate the secondary voltage and state whether the transformer is step-up or step-down.
Mains voltage, $230\ \text{V}$, needs to be transformed to $12\ \text{V}$ to power a model circuit. a) Calculate the required turns ratio, $\frac{N_1}{N_2}$. b) If the…
Mains voltage, $230\ \text{V}$, needs to be transformed to $12\ \text{V}$ to power a model circuit.
- a) Calculate the required turns ratio, $\frac{N_1}{N_2}$.
- b) If the secondary has $30$ turns, how many turns must the primary have?
Electricity companies transport energy at voltages of hundreds of kilovolts. a) Write the relationship between power, voltage and current, $P = V \times I$, and explain…
Electricity companies transport energy at voltages of hundreds of kilovolts.
- a) Write the relationship between power, voltage and current, $P = V \times I$, and explain why, to transport the same power, a high voltage implies a low current.
- b) The power lost due to the Joule effect in the cables is $I^2 \times R$: explain why it is so important for the transported current to be small.
The alternator of a small power plant is equivalent to a coil of $200$ turns of $100\ \text{cm}^2$ rotating at a frequency of $50\ \text{Hz}$ in a field of…
The alternator of a small power plant is equivalent to a coil of $200$ turns of $100\ \text{cm}^2$ rotating at a frequency of $50\ \text{Hz}$ in a field of $0.5\ \text{T}$ (take $\pi \approx 3.14$).
- a) Calculate the angular speed of rotation, $\omega = 2 \times \pi \times f$.
- b) Calculate the maximum generated emf, $\varepsilon_0 = N \times B \times S \times \omega$.
- c) Write the expression $\varepsilon(t)$ assuming that at $t = 0$ the flux is maximum and the emf is zero.
A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$. a) Calculate the electrical power it…
A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$.
- a) Calculate the electrical power it absorbs from the mains.
- b) Calculate its efficiency, as a percentage.
- c) Name two mechanisms by which a real motor loses energy and briefly explain them.
An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram: a) Calculate…
An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram:
- a) Calculate the secondary voltage.
- b) A current of $2.3\ \text{A}$ flows through the secondary circuit: calculate the power delivered by the transformer.
- c) In an ideal transformer, the primary power is equal to the secondary power: calculate the current drawn by the transformer from the mains.
A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ mains. a) Calculate the…
A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ mains.
- a) Calculate the turns ratio of the transformer.
- b) Calculate the power consumed by the train.
- c) Calculate the current drawn by the transformer from the mains.
A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$. a) If transmission were carried out at $1000\ \text{V}$, calculate…
A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$.
- a) If transmission were carried out at $1000\ \text{V}$, calculate the current through the line and the power lost in it, and express this loss as a percentage of the transmitted power.
- b) Repeat the calculations assuming transmission is carried out at $10\ \text{kV}$.
- c) Draw a conclusion as to why it is advantageous to transmit energy at high voltage.
In a hydroelectric power plant, water rotates the turbine, which drives the alternator rotor at a frequency of $25\ \text{Hz}$ (take $\pi \approx 3.14$). The alternator…
In a hydroelectric power plant, water rotates the turbine, which drives the alternator rotor at a frequency of $25\ \text{Hz}$ (take $\pi \approx 3.14$). The alternator winding is equivalent to $100$ turns of $0.2\ \text{m}^2$ rotating in a field of $0.8\ \text{T}$.
- a) Calculate the angular speed of the rotor.
- b) Calculate the maximum generated emf, $\varepsilon_0 = N \times B \times S \times \omega$.
- c) Describe the chain of energy transformations from the dammed water to the electrical energy leaving the power plant.
The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$…
The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$ perpendicular to its axis of rotation, as shown in the figure.
- a) Calculate the magnetic force on each of the long sides of the loop, $F = I \times l \times B$.
- b) Explain why these two forces, acting in opposite directions, form a couple that rotates the loop instead of translating it.
- c) What happens to the couple when the plane of the loop is perpendicular to the field (dead center) and how does the split-ring commutator solve this?
A power station generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer…
A power station generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer steps it down to $230\ \text{V}$ for consumption. Observe the diagram:
- a) Calculate the turns ratio $\frac{N_2}{N_1}$ of the step-up transformer.
- b) Calculate the turns ratio $\frac{N_1}{N_2}$ of the city step-down transformer.
- c) Explain why the step-up transformer is installed next to the power station and the step-down transformer next to the points of consumption, and not the other way round.
A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$. a) Calculate the current flowing through…
A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$.
- a) Calculate the current flowing through the line.
- b) Calculate the power dissipated in the line and express it as a percentage of the generated power.
- c) Repeat the calculations assuming transmission were carried out at $25\ \text{kV}$.
- d) Explain the dual role played by transformers (and therefore alternating current) in making long-distance electrical power transmission viable.
The domestic voltage of $230\ \text{V}$ is the rms value of an alternating current of $50\ \text{Hz}$ whose maximum value is $325\ \text{V}$ (take $\pi \approx 3.14$ and…
The domestic voltage of $230\ \text{V}$ is the rms value of an alternating current of $50\ \text{Hz}$ whose maximum value is $325\ \text{V}$ (take $\pi \approx 3.14$ and $\sqrt{2} \approx 1.41$). The graph of voltage against time is shown in the figure.
- a) Calculate the angular frequency $\omega$ and write the expression for emf as a function of time, $\varepsilon(t) = \varepsilon_0 \times \sen(\omega \times t)$.
- b) Verify that the rms value satisfies the relationship $\varepsilon_{\text{ef}} = \frac{\varepsilon_0}{\sqrt{2}}$.
- c) If the power station alternator works with a field of $0.6\ \text{T}$ and turns of $0.05\ \text{m}^2$, calculate how many turns its winding needs to generate that maximum emf, $\varepsilon_0 = N \times B \times S \times \omega$.
When starting a $12\ \text{V}$ motor whose internal resistance is $0.5\ \Omega$, with the shaft still at rest, the initial current is $24\ \text{A}$. a) Verify this…
When starting a $12\ \text{V}$ motor whose internal resistance is $0.5\ \Omega$, with the shaft still at rest, the initial current is $24\ \text{A}$.
- a) Verify this value by applying Ohm's law and explain why, at startup, the motor behaves as a simple resistor.
- b) When the motor runs at full speed, the rotation of its coils in the field generates an induced emf of $10\ \text{V}$ (back electromotive force): calculate the current at full speed, $I = \frac{V - \varepsilon'}{R}$.
- c) Explain using Lenz's law why this induced emf has the opposite sign to the supply voltage.
- d) In light of the previous sections, explain why it is dangerous to stall the shaft of a running motor and what happens to its winding.
A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the…
A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the $230\ \text{V}$ mains.
- a) Calculate the current flowing through the secondary.
- b) Calculate the power drawn by the charger from the mains and the corresponding primary current.
- c) Calculate the power lost inside the charger.
- d) Explain the two main causes of losses in a real transformer: eddy currents in the core (which is why it is made of stacked, insulated laminations) and the Joule effect in the windings.
A $1500\ \text{kg}$ electric car travels at $72\ \text{km/h}$. On releasing the accelerator, its motor acts as a generator and recharges the battery (regenerative…
A $1500\ \text{kg}$ electric car travels at $72\ \text{km/h}$. On releasing the accelerator, its motor acts as a generator and recharges the battery (regenerative braking).
- a) Express the speed in $\text{m/s}$ and calculate the kinetic energy of the car.
- b) If the system recovers $60\%$ of that energy, how much energy returns to the battery?
- c) During braking, the motor winding ($300$ turns) undergoes a flux variation of $0.4\ \text{Wb/s}$ in each turn: calculate the generated emf.
- d) Explain using Lenz's law why the induced current slows down the car instead of accelerating it.
The pickup of an electric guitar is a small magnet surrounded by a coil of $2000$ turns of $1\times10^{-5}\ \text{m}^2$ each. When the metal string is plucked (A note,…
The pickup of an electric guitar is a small magnet surrounded by a coil of $2000$ turns of $1\times10^{-5}\ \text{m}^2$ each. When the metal string is plucked (A note, $440\ \text{Hz}$), the field through the coil oscillates, with a variation of $1\times10^{-3}\ \text{T}$ in each quarter period. Observe the diagram:
- a) Calculate the duration of a quarter of a period of the vibration.
- b) Calculate the average induced emf during that interval, in millivolts.
- c) Explain qualitatively how the electrical signal reaching the amplifier is generated and reason why the string must be made of a ferromagnetic material.
A wireless charger has a transmitter coil of $20$ turns powered at $12\ \text{V}$ with alternating current of $100\ \text{kHz}$; the phone's coil has $15$ turns. Observe…
A wireless charger has a transmitter coil of $20$ turns powered at $12\ \text{V}$ with alternating current of $100\ \text{kHz}$; the phone's coil has $15$ turns. Observe the diagram:
- a) Calculate the induced voltage in the phone's coil assuming ideal coupling, using the relationship $\frac{V_1}{N_1} = \frac{V_2}{N_2}$.
- b) Explain how this system resembles a transformer and what fundamental difference there is regarding the core compared to a conventional one.
- c) Reason, based on Faraday's law, why such a high frequency is used instead of the $50\ \text{Hz}$ mains frequency: what happens to $\frac{\Delta \Phi}{\Delta t}$ and to the required size of the coils?
A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and…
A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and the line would have a resistance of $1\ \Omega$.
- a) Calculate the current that would have to be transmitted.
- b) Calculate the power that would be lost in the line and compare it with the power intended for transmission.
- c) In light of the result, explain why the proposal is unfeasible and how the combination of alternating current and transformers solves the problem.