Exercises: Exponential and logarithmic equations
Solve the following exponential equations by writing both sides as powers of the same base: a) $2^{x} = 8$ b) $3^{x} = \frac{1}{9}$ c) $5^{x} = 25$ d) $10^{x} = 0.001$
Solve the following exponential equations by writing both sides as powers of the same base:
- a) $2^{x} = 8$
- b) $3^{x} = \frac{1}{9}$
- c) $5^{x} = 25$
- d) $10^{x} = 0.001$
By applying the definition of a logarithm, solve: a) $\log_{2} x = 5$ b) $\log_{3} x = -2$ c) $\log x = 4$ d) $\ln x = 0$
By applying the definition of a logarithm, solve:
- a) $\log_{2} x = 5$
- b) $\log_{3} x = -2$
- c) $\log x = 4$
- d) $\ln x = 0$
Solve the equations: a) $\log_{2} x + \log_{2} 4 = 5$ b) $\log_{5} x - \log_{5} 2 = 2$
Solve the equations:
- a) $\log_{2} x + \log_{2} 4 = 5$
- b) $\log_{5} x - \log_{5} 2 = 2$
Solve the following exponential equations with the unknown in an exponent expression: a) $3^{x + 1} = 27$ b) $2^{3x} = 16$ c) $5^{2 - x} = 125$
Solve the following exponential equations with the unknown in an exponent expression:
- a) $3^{x + 1} = 27$
- b) $2^{3x} = 16$
- c) $5^{2 - x} = 125$
Solve the equations by taking base-10 logarithms on both sides. Express the exact solution as a quotient of logarithms (there is no need to give the decimal value): a)…
Solve the equations by taking base-10 logarithms on both sides. Express the exact solution as a quotient of logarithms (there is no need to give the decimal value):
- a) $2^{x} = 15$
- b) $7^{x} = 100$
Solve by applying the appropriate inverse function: a) $\ln x = 4$ b) $e^{x} = 7$ c) $10^{x} = 45$ d) $\log x = 2.5$
Solve by applying the appropriate inverse function:
- a) $\ln x = 4$
- b) $e^{x} = 7$
- c) $10^{x} = 45$
- d) $\log x = 2.5$
Solve the equation $4^{x} - 5 \times 2^{x} + 4 = 0$ using the substitution $t = 2^{x}$. Check the solutions obtained.
Solve the equation $4^{x} - 5 \times 2^{x} + 4 = 0$ using the substitution $t = 2^{x}$. Check the solutions obtained.
Solve the equation $2^{x + 1} + 2^{x} + 2^{x - 1} = 28$ by factorising out the smallest power. Check the solution.
Solve the equation $2^{x + 1} + 2^{x} + 2^{x - 1} = 28$ by factorising out the smallest power. Check the solution.
Solve the logarithmic equation $\log_{2}(x - 1) + \log_{2}(x + 1) = 3$ and check the validity of each candidate solution.
Solve the logarithmic equation $\log_{2}(x - 1) + \log_{2}(x + 1) = 3$ and check the validity of each candidate solution.
Solve the equation $\log x + \log(x + 3) = 1$, where $\log$ denotes the base-10 logarithm. Why must one of the solutions to the associated quadratic equation be…
Solve the equation $\log x + \log(x + 3) = 1$, where $\log$ denotes the base-10 logarithm. Why must one of the solutions to the associated quadratic equation be discarded?
Solve the equation $3^{x - 1} = 2^{x}$ by taking natural logarithms on both sides. Express the exact solution in terms of logarithms and give its approximate value to…
Solve the equation $3^{x - 1} = 2^{x}$ by taking natural logarithms on both sides. Express the exact solution in terms of logarithms and give its approximate value to two decimal places.
Solve the logarithmic system: $$\begin{cases} \log x + \log y = 3 \\ \log x - \log y = 1 \end{cases}$$ Check that the solution satisfies both equations and that the…
Solve the logarithmic system:
$$\begin{cases} \log x + \log y = 3 \\ \log x - \log y = 1 \end{cases}$$Check that the solution satisfies both equations and that the values are valid for the logarithms.
Solve the exponential system: $$\begin{cases} 3^{x} \times 3^{y} = 27 \\ \frac{2^{x}}{2^{y}} = 4 \end{cases}$$ Hint: convert each equation into a linear equation for the…
Solve the exponential system:
$$\begin{cases} 3^{x} \times 3^{y} = 27 \\ \frac{2^{x}}{2^{y}} = 4 \end{cases}$$Hint: convert each equation into a linear equation for the exponents.
The figure shows the curve $y = 2^{x}$ and the straight line $y = 5$. a) Explain why the solution to the equation $2^{x} = 5$ is the x-coordinate of the intersection…
The figure shows the curve $y = 2^{x}$ and the straight line $y = 5$.
- a) Explain why the solution to the equation $2^{x} = 5$ is the x-coordinate of the intersection point labelled '?'.
- b) Bound the solution between two consecutive integers using the graph or by trial and error.
- c) Express the exact solution using a logarithm and calculate its approximate value to three decimal places.
Solve the exponential equation $9^{x} - 4 \times 3^{x} + 3 = 0$ by following these steps: a) Express $9^{x}$ as a power with base $3$ and use the substitution…
Solve the exponential equation $9^{x} - 4 \times 3^{x} + 3 = 0$ by following these steps:
- a) Express $9^{x}$ as a power with base $3$ and use the substitution $t = 3^{x}$.
- b) Solve the resulting quadratic equation.
- c) Reverse the substitution, check each solution in the original equation, and discard any that are not valid.
Solve the logarithmic equation $\log_{2} x + \log_{4} x = 3$. a) Express $\log_{4} x$ in terms of $\log_{2} x$ using the change of base formula. b) Solve the resulting…
Solve the logarithmic equation $\log_{2} x + \log_{4} x = 3$.
- a) Express $\log_{4} x$ in terms of $\log_{2} x$ using the change of base formula.
- b) Solve the resulting equation and check the solution.
A student solves the equation $\log_{2}(x - 1) + \log_{2}(x - 3) = 3$ as follows: '…
A student solves the equation $\log_{2}(x - 1) + \log_{2}(x - 3) = 3$ as follows:
'$\log_{2}[(x - 1)(x - 3)] = 3 \Rightarrow (x - 1)(x - 3) = 8 \Rightarrow x^{2} - 4x - 5 = 0 \Rightarrow x = 5$ and $x = -1$. Therefore, the equation has two solutions: $x = 5$ and $x = -1$.'
- a) Explain where the error in their conclusion lies, even though the calculations are correct.
- b) Write out the full and correct solution, stating which check is mandatory for every logarithmic equation.
Solve the equation $4^{x} - 3 \times 2^{x + 1} + 8 = 0$. a) Rewrite the equation using only powers of base $2$ and substitute $t = 2^{x}$. b) Solve the quadratic…
Solve the equation $4^{x} - 3 \times 2^{x + 1} + 8 = 0$.
- a) Rewrite the equation using only powers of base $2$ and substitute $t = 2^{x}$.
- b) Solve the quadratic equation in $t$.
- c) Reverse the substitution and check the two solutions.
A family deposits $\$100\,000$ into a savings account at $4 \%$ annual compound interest, so that the capital after $t$ years is $C(t) = 100\,000 \times 1.04^{t}…
A family deposits $\$100\,000$ into a savings account at $4 \%$ annual compound interest, so that the capital after $t$ years is $C(t) = 100\,000 \times 1.04^{t}$.
- a) Set up the exponential equation that determines how many years must pass for the capital to reach $\$160\,000$.
- b) Solve it using logarithms and give the result rounded to the nearest month.
- c) Without doing the full calculation, reason whether with an interest rate of $2 \%$ the time required would be exactly double. Check your conjecture with calculations.
Solve the following equations, in which the unknown appears in unusual places: a) $\log_{x} 8 = \frac{3}{2}$ (the unknown is the base of the logarithm; remember which…
Solve the following equations, in which the unknown appears in unusual places:
- a) $\log_{x} 8 = \frac{3}{2}$ (the unknown is the base of the logarithm; remember which values a base can take).
- b) $\log_{3}(x + 2) - \log_{3}(x - 2) = 1$ (apply the rule for the logarithm of a quotient and check the solution).
A bacterial colony grows at a cumulative rate of $15 \%$ per day. If initially there are $2,000$ bacteria: a) Write the expression for the number of bacteria after $t$…
A bacterial colony grows at a cumulative rate of $15 \%$ per day. If initially there are $2,000$ bacteria:
- a) Write the expression for the number of bacteria after $t$ days and set up the inequality that determines when the population will exceed $10,000$ bacteria.
- b) Solve it using logarithms and deduce the minimum number of full days that must pass.