Back to homeBiology · 2nd Bach. Science · Change subject
Start for free
BAC2 tech · Biology
Metabolism · Cellular metabolism

Energy yield

After studying glycolysis, the Krebs cycle, the respiratory chain and fermentation separately, it is time to do the sums: how much ATP is actually obtained from one glucose molecule, and why is respiring so much more worthwhile than fermenting?

Before you start, make sure you know: A healthy diet (2nd ESO)

The complete balance of aerobic respiration

Per glucose molecule, in a eukaryotic cell, we count each stage separately.

Stage Net direct ATP NADH FADH₂
Glycolysis, cytosol 2 2 0
Oxidation of two pyruvates to acetyl-CoA, matrix 0 2 0
Two turns of the Krebs cycle, matrix 2 equivalents (GTP/ATP) 6 2
Aerobic respiration in the eukaryotic cell: glucose is broken down in the cytosol to pyruvate, enters the Krebs cycle in the mitochondrial matrix, and the NADH and FADH₂ pass electrons to the transport chain and to the ATP synthase of the cristae; 4 direct ATP and 26–28 oxidative ATP are added, about 30–32 ATP in total Cytosol Glucose Glycolysis +2 ATP 2 pyruvate Matrix acetyl-CoA Krebs +2 ATP 10 NADH 2 FADH₂ Transport chain ATP synthase Direct ATP 4 + Chain and ATP synthase 26–28 ATP = Approximate total 30–32 ATP
Practice★☆☆Not started
How many net ATP molecules are obtained in glycolysis per glucose molecule, and how many in total (classic theoretical figure) when completely respired aerobically?

How many net ATP molecules are obtained in glycolysis per glucose molecule, and how many in total (classic theoretical figure) when completely respired aerobically?

Solve
Practice★☆☆Not started
State how many ATP molecules are obtained, according to currently accepted values, for each NADH and for each $\text{FADH}2$ that deliver their electrons to the…

State how many ATP molecules are obtained, according to currently accepted values, for each NADH and for each $\text{FADH}_2$ that deliver their electrons to the respiratory chain.

Solve
Practice★★☆Not started
In aerobic respiration, about $36$-$38\ \text{ATP}$ are obtained per glucose, of which only $2$ come from glycolysis. Calculate what percentage of the total yield is…

In aerobic respiration, about $36$-$38\ \text{ATP}$ are obtained per glucose, of which only $2$ come from glycolysis. Calculate what percentage of the total yield is contributed by the mitochondrial stages (taking $36\ \text{ATP}$ as the total) and comment on the result.

Solve

Respiration versus fermentation

Aerobic respiration oxidises glucose completely and yields approximately 30–32 ATP per molecule in the model above. Fermentation regenerates NAD⁺ to keep glycolysis going: overall it yields 2 net ATP per glucose, which come from glycolysis, not from the conversion of pyruvate into lactate or ethanol.

Comparative diagram: glucose goes through glycolysis (2 ATP) and the pyruvate continues to the mitochondrion with oxygen (respiration, about 30–32 ATP in total) or is fermented to lactate or ethanol without oxygen (2 ATP in total), regenerating NAD⁺ for glycolysis; bars of ATP per glucose. Cytosol Glucose Glycolysis +2 ATP Pyruvate with O₂ Mitochondrion CO₂ + H₂O without O₂ Lactate or ethanol NADH → NAD⁺ regenerates NAD⁺ ATP per glucose Respiration ~30–32 ATP Fermentation 2 ATP
Practice★☆☆Not started
Why is fermentation much less energy-efficient than aerobic respiration, even though both begin with glycolysis? Explain what happens to pyruvate in each case.

Why is fermentation much less energy-efficient than aerobic respiration, even though both begin with glycolysis? Explain what happens to pyruvate in each case.

Solve
Practice★☆☆Not started
Rank from highest to lowest energy yield per glucose molecule: aerobic respiration, lactic acid fermentation, and alcoholic fermentation. Justify the ranking.

Rank from highest to lowest energy yield per glucose molecule: aerobic respiration, lactic acid fermentation, and alcoholic fermentation. Justify the ranking.

Solve
Practice★★☆Not started
Calculate how many glucose molecules a cell needs to break down to obtain $180\ \text{ATP}$ aerobically ($36\ \text{ATP/glucosa}$) and how many by fermentation (…

Calculate how many glucose molecules a cell needs to break down to obtain $180\ \text{ATP}$ aerobically ($36\ \text{ATP/glucosa}$) and how many by fermentation ($2\ \text{ATP/glucosa}$). Comment on the implication of this difference for anaerobic organisms.

Solve

Real yield and its losses

During intense physical exercise, we break out in a sweat and give off a large amount of body heat: how much of the energy in glucose does a cell really use to synthesise ATP, and why is the rest dissipated?

Bar chart illustrating the approximate split of the fuel's chemical energy between useful ATP and dissipated heat illustrative split, not a fixed proportion useful ATP(~40 %) heat(~60 %) part of the heat comes from H⁺ leaks across the mitochondrial membrane
Practice★☆☆Not started
What does it mean that a metabolic pathway has an energy yield of $40\ \%$? Explain what happens to the rest of the energy contained in the food.

What does it mean that a metabolic pathway has an energy yield of $40\ \%$? Explain what happens to the rest of the energy contained in the food.

Solve
Practice★★☆Not started
The combustion of $1\ \text{g}$ of glucose releases about $4\ \text{kcal}$ and that of $1\ \text{g}$ of fat about $9\ \text{kcal}$. Explain what that difference is due…

The combustion of $1\ \text{g}$ of glucose releases about $4\ \text{kcal}$ and that of $1\ \text{g}$ of fat about $9\ \text{kcal}$. Explain what that difference is due to and calculate how many grams of fat provide the same energy as $90\ \text{g}$ of glucose.

Solve
Practice★★★Not started
Under standard biochemical conditions ($\text{pH} = 7{,}0$, $25\ ^\circ\text{C}$), the complete combustion of $1\ \text{mol}$ of glucose yields…

Under standard biochemical conditions ($\text{pH} = 7{,}0$, $25\ ^\circ\text{C}$), the complete combustion of $1\ \text{mol}$ of glucose yields $\Delta G^{\circ\prime} = -2870\ \text{kJ/mol}$ and the hydrolysis of $1\ \text{mol}$ of ATP yields $\Delta G^{\circ\prime} = -30{,}5\ \text{kJ/mol}$. However, in the cytoplasm of a living hepatocyte, the actual concentrations of ATP, ADP, and $\text{P}_\text{i}$ mean that the phosphorylation of ADP requires around $+50{,}0\ \text{kJ/mol}$, with roughly $30\ \text{mol of ATP}$ net per mole of oxidized glucose obtained experimentally.

  1. a) Calculate and compare the theoretical percentage energy efficiency under standard conditions (assuming $36\ \text{ATP/glucose}$) versus the actual intracellular thermodynamic efficiency. Justify the fate of the fraction of free energy that is not stored in the phosphate bonds of ATP and its significance for homeothermic animals.
  2. b) 2,4-Dinitrophenol (DNP) is a lipophilic molecule capable of transporting protons across the inner mitochondrial membrane, dissipating the electrochemical gradient. Predict, with reasoning, how treatment with DNP will affect the net yield of ATP per glucose, the rate of $\text{O}_2$ consumption by the cell, and the body temperature of the organism.
Solve

Energy per gram of fuel

Comparative diagram of the energy content per gram and the storage capacity of carbohydrates versus lipids. kcal/g 4 glucose 9 fat
Practice★★☆Not started
During a marathon, a runner performs about $10000\ \text{kJ}$ of useful work. If their organism has an overall yield of $25\ \%$, calculate how much chemical energy from…

During a marathon, a runner performs about $10000\ \text{kJ}$ of useful work. If their organism has an overall yield of $25\ \%$, calculate how much chemical energy from food they have had to mobilise and reason why their body heats up so much during the race.

Solve
Practice★★★Not started
The adult human brain has a mass of about $1400\ \text{g}$ (around $2\ \%$ of body mass), but at rest it consumes $20\ \%$ of the oxygen and glucose of the entire body,…

The adult human brain has a mass of about $1400\ \text{g}$ (around $2\ \%$ of body mass), but at rest it consumes $20\ \%$ of the oxygen and glucose of the entire body, degrading approximately $120\ \text{g}$ of glucose per day (molar mass $= 180\ \text{g/mol}$).

  1. a) Justify at a molecular and membrane transport level which continuous physiological processes of neurons explain such a basal expenditure of ATP at rest.
  2. b) Calculate the daily moles of ATP produced by the brain assuming a net yield of $30\ \text{mol of ATP}$ per mole of oxidized glucose. If the total intracellular reserve of ATP in brain tissue is $2{,}5\ \mu\text{mol/g}$, calculate how many seconds of activity this reserve would last if oxidative phosphorylation were stopped instantaneously.
  3. c) Based on the results of b), justify why cerebral ischemia causes loss of consciousness in less than $10\ \text{seconds}$, and explain why the brain cannot sustain its energy viability through fermentation from endogenous glycogen, unlike skeletal muscle fibers.
Solve
Practice★★★Not started
A migratory bird weighing $30\ \text{g}$ must face an uninterrupted journey requiring a metabolic energy expenditure equivalent to $2\ \text{mol}$ of ATP. Data: Glucose:…

A migratory bird weighing $30\ \text{g}$ must face an uninterrupted journey requiring a metabolic energy expenditure equivalent to $2\ \text{mol}$ of ATP.

Data:

  • Glucose: $180\ \text{g/mol}$; yield = $36\ \text{mol}$ of ATP per mole of glucose. Glycogen is stored hydrated with $2\ \text{g}$ of water per gram of dry polysaccharide.

  • Palmitic acid: $256\ \text{g/mol}$; yield = $106\ \text{mol}$ of ATP per mole of fatty acid. Triacylglycerols are stored in anhydrous form.

  1. a) Calculate the total reserve mass (in grams) that the bird should incorporate into its body before the journey if it stored that energy exclusively as fat versus if it did so exclusively as hydrated glycogen.
  2. b) Based on the results obtained, interpret the biomechanical impact on flight and predict what would happen to the viability of migration if glycogen were used.
  3. c) Justify biochemically why one dry gram of palmitic acid yields more than double the ATP of one gram of glucose, considering the oxidation state of their carbon atoms.
Solve

Summary

See all the exercises in this section