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Secondary 4 · Mathematics
3D shapes · 3D shapes

Longitude and Latitude

Before you start, make sure you know: Circle and circumference (Secondary Year 1 (first cycle))
Before you start, make sure you know: Round solids (Secondary Year 2 (first cycle))

Wilkin sends his cousin his location from Santo Domingo, and his phone shows something like 18.5° N, 69.9° W. Those are two numbers, and with them you can find any point on Earth, just like $(x, y)$ locates a point on the plane. The difference is that here the "sheet of paper" is a sphere and the coordinates are angles. By the end of this page you will know how to calculate how far that location is from the equator and what time it is where his cousin lives.

Meridians and parallels

We picture the Earth as a sphere that rotates around an axis passing through the North and South Poles.

  • Meridians: semicircles that run from pole to pole. The reference one is the Greenwich meridian (London), the 0° meridian.

  • Parallels: circles perpendicular to the axis. The largest is the equator (0° parallel), which divides the Earth into the Northern Hemisphere and the Southern Hemisphere.

Move the sliders or pick a city. Notice how the parallel changes depending on the latitude:

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Imagine you are a beginner cartographer. On your first map, you must locate the most important reference lines on Earth. Look at the diagram and match each letter with…

Imagine you are a beginner cartographer. On your first map, you must locate the most important reference lines on Earth. Look at the diagram and match each letter with its corresponding name:

  1. Equator.

  2. Greenwich Meridian.

  3. North Pole.

  4. Any parallel.

A B C D
Solve
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Look at the following flat representation (planisphere) of an ocean region. Identify the coordinates (Latitude and Longitude) of point $P$ marked with a star.

Look at the following flat representation (planisphere) of an ocean region. Identify the coordinates (Latitude and Longitude) of point $P$ marked with a star.

P 20ºN 10ºN 0º 10ºS 20ºS 20ºE 30ºE 40ºE 50ºE 60ºE Equator N S E W
Solve

Geographic coordinates

Earth sphere showing the equator, the Greenwich meridian, and the latitude as the angle of a point. lat NS equator: latitude 0° Greenwich: longitude 0° A point: lat and lon First the latitude,then the longitude.

Santo Domingo is at about $18.5°$ N and $69.9°$ W: north of the equator and west of Greenwich.

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State which hemisphere (Northern or Southern for latitude, Eastern or Western for longitude) the following geographical points are located in: Point A: $34^\circ$ N,…

State which hemisphere (Northern or Southern for latitude, Eastern or Western for longitude) the following geographical points are located in:

  • Point A: $34^\circ$ N, $120^\circ$ E

  • Point B: $12^\circ$ S, $45^\circ$ W

  • Point C: $89^\circ$ N, $5^\circ$ W

  • Point D: $40^\circ$ S, $170^\circ$ E

Solve
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An explorer has mistakenly written down the following coordinates in his diary. Explain why these coordinates are geographically impossible: a) Latitude: $105^\circ$ S,…

An explorer has mistakenly written down the following coordinates in his diary. Explain why these coordinates are geographically impossible:

  1. a) Latitude: $105^\circ$ S, Longitude: $20^\circ$ E.
  2. b) Latitude: $45^\circ$ N, Longitude: $210^\circ$ W.
Solve
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Two ships, Alfa and Beta, are sailing across the Atlantic Ocean. Their coordinates are: Ship Alfa: $20^\circ$ N, $30^\circ$ W Ship Beta: $20^\circ$ N, $60^\circ$ W…

Two ships, Alfa and Beta, are sailing across the Atlantic Ocean. Their coordinates are:

  • Ship Alfa: $20^\circ$ N, $30^\circ$ W

  • Ship Beta: $20^\circ$ N, $60^\circ$ W

Answer giving reasons:

  1. a) Are they located on the same parallel or on the same meridian?
  2. b) Which of the two ships is closer to the Greenwich Meridian?
Solve

Antipodes

The antipodes of a point are the point diametrically opposite on the sphere: if you went through the Earth along a line through the center, you would come out there.

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If you travel by plane from Madrid ($40^\circ$ N, $3^\circ$ W) to a city that is exactly at its antipodes (the opposite point on the Earth's sphere): a) What would be…

If you travel by plane from Madrid ($40^\circ$ N, $3^\circ$ W) to a city that is exactly at its antipodes (the opposite point on the Earth's sphere):

  1. a) What would be the latitude of that point? (Same value but opposite direction).
  2. b) If the longitudes of a point and its antipode must sum to $180^\circ$ and be in opposite hemispheres, what would be the longitude of that point?
Solve
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The antipodes of a location are said to be the point on the Earth's surface that is diametrically opposite to it. If the coordinates of your city are $40^\circ$ $25'$ N…

The antipodes of a location are said to be the point on the Earth's surface that is diametrically opposite to it. If the coordinates of your city are $40^\circ$ $25'$ N latitude and $3^\circ$ $41'$ W longitude:

  1. a) What would be the latitude of your antipodes?
  2. b) What would be the longitude of your antipodes?

(Hint: For the latitude, change the hemisphere; for the longitude, find the meridian that completes $180^\circ$ and change the hemisphere E/W).

N S Equator Meridian 3º41'W Opposite meridian City 40º25'N, 3º41'W 40º25' Antipode Lat?, Long?
Solve

Distances along a meridian

Two cities on the same meridian are separated by an arc of a great circle. The radius of the Earth is about $6{,}371$ km, so a full trip around measures $2\pi \times 6{,}371 \approx 40{,}030$ km.

Arc of a meridian between two points and its central angle, used to calculate the distance. P 42° NQ 12° S 54° arc = 54/360 of the full circle
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Two towns, Villa Sol and Villa Luna, are located on the same meridian. If Villa Sol has a latitude of $45^\circ$ N and Villa Luna has a latitude of $20^\circ$ S, how…

Two towns, Villa Sol and Villa Luna, are located on the same meridian. If Villa Sol has a latitude of $45^\circ$ N and Villa Luna has a latitude of $20^\circ$ S, how many degrees of meridian arc separate them?

Equator 45° 20° Villa Sol Villa Luna
Solve
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A humpback whale migrates along exactly the same meridian from a feeding area located at $65^\circ$ N latitude to a breeding area at $15^\circ$ S. If the mean radius of…

A humpback whale migrates along exactly the same meridian from a feeding area located at $65^\circ$ N latitude to a breeding area at $15^\circ$ S. If the mean radius of the Earth is taken to be $6\,371$ km, calculate the total distance in kilometers that the whale travels on its outward journey.

N Pole S Pole Equator R = 6.371 km 65° N 15° S 65° 15°
Solve
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In navigation, the "nautical mile" is used, defined as the arc length of a meridian of $1'$ (one minute of arc). a) Calculate how many kilometers one nautical mile is…

In navigation, the "nautical mile" is used, defined as the arc length of a meridian of $1'$ (one minute of arc).

  1. a) Calculate how many kilometers one nautical mile is equivalent to (Radius of the Earth = $6\,371$ km).
  2. b) If a sailboat has sailed along a meridian from a latitude of $30^\circ$ N to $35^\circ$ N, how many nautical miles has it traveled?
Equator N Pole W R = 6371 km 30°N 35°N Distance traveled 5° 1 Nautical Mile 1' 1 nautical mile R = 6371 km
Solve

Distances along a parallel

A parallel of latitude $\varphi$ is a circle with a radius smaller than $R$. Look at the cross-section of the sphere: the radius of the parallel forms a right triangle with $R$.

Cross-section of the Earth's sphere: the radius of a parallel is R times the cosine of the latitude. lat R r r = R · cos(lat) The parallel is a circleof radius r, smaller than R.
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Two oceanographic research ships are located on the Equator line. Ship A is at a longitude of $12^\circ$ E and ship B is located at a distance of $2\,500$ km to the West…

Two oceanographic research ships are located on the Equator line. Ship A is at a longitude of $12^\circ$ E and ship B is located at a distance of $2\,500$ km to the West of ship A. Determine the exact longitude of ship B, knowing that the radius of the Earth is $6\,371$ km.

Equator R = 6 371 km 0° (Greenwich) 12° ? A (12°E) B (?) 2 500 km North Pole ← WEST EAST →
Solve
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Two cities, P and Q, are situated on the same meridian. City P is at $42^\circ$ N and city Q is at $15^\circ$ N. Another city, R, is situated on the same parallel as Q,…

Two cities, P and Q, are situated on the same meridian. City P is at $42^\circ$ N and city Q is at $15^\circ$ N. Another city, R, is situated on the same parallel as Q, but at a distance of $20^\circ$ longitude to the East.

Calculate, using $R = 6\,371$ km:

  1. a) The distance between P and Q along the meridian.
  2. b) The distance between Q and R along the parallel.

Which of the two distances is greater?

Equator 42°N 15°N P Q d(P,Q) = ? R 20° d(Q,R) = ? R = 6371 km
Solve
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Calculate the shortest distance between two points, P and Q, located on the Earth's surface if their coordinates are: P: $(40^\circ \text{ N}, 10^\circ \text{ O})$ Q:…

Calculate the shortest distance between two points, P and Q, located on the Earth's surface if their coordinates are:

  • P: $(40^\circ \text{ N}, 10^\circ \text{ O})$

  • Q: $(40^\circ \text{ S}, 10^\circ \text{ O})$

Assume that the Earth is a perfect sphere of radius $6371 \text{ km}$. Express the result in kilometers. Does the traveler travel along a meridian or along a parallel? Justify your answer.

Equator N S Meridian 10° W d 40° 40° R = 6.371 km C P Q
Solve

Time zones and the date change

The Earth makes one turn of $360°$ in 24 hours, so it rotates $360° : 24 = 15°$ every hour. That is why it is divided into 24 time zones of $15°$ of longitude each. Toward the east it is later; toward the west, earlier.

Consecutive bands of 15-degree time zones and their correspondence in hours toward the east and west. 10 h11 h12 h 13 h14 h15 h ← westeast → each band: 15° of longitude = 1 hour

The International Date Line

The $180°$ meridian (the antimeridian of Greenwich) is, approximately, the International Date Line. When you cross it toward the east (toward the west on the map) you subtract a day; when you cross it toward the west you add a day. That way the calendar adds up after going all the way around the world.

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We know that the Earth takes 24 hours to complete a rotation of $360^\circ$ on its axis. a) How many degrees of longitude correspond to a time difference of one hour? b)…

We know that the Earth takes 24 hours to complete a rotation of $360^\circ$ on its axis.

  1. a) How many degrees of longitude correspond to a time difference of one hour?
  2. b) If it is 12:00 noon in a city located at $0^\circ$ longitude (Greenwich), what time will it be in a city located at $30^\circ$ E?
Solve
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A group of friends in Madrid (longitude $3^\circ$ $41'$ W) wants to watch live the launch of a space rocket from Cape Canaveral (longitude $80^\circ$ $36'$ W). If the…

A group of friends in Madrid (longitude $3^\circ$ $41'$ W) wants to watch live the launch of a space rocket from Cape Canaveral (longitude $80^\circ$ $36'$ W). If the launch is scheduled for 14:30 Florida local time, and knowing that each time zone of $15^\circ$ is equivalent to a theoretical time difference of one hour, at what time should they tune in to the live broadcast in Spain? Use the theoretical time zone diagram to perform the calculation.

← WEST (W) EAST (E) → 0° Madrid 3°41' W ? h Cape Canaveral 80°36' W 14:30 Δt = ? 1 time zone = 15° = 1 h
Solve
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An aircraft takes off from Tokyo ($35^\circ$ N, $139^\circ$ E) at 08:00 on Monday bound for San Francisco ($37^\circ$ N, $122^\circ$ W). If the flight lasts 10 hours,…

An aircraft takes off from Tokyo ($35^\circ$ N, $139^\circ$ E) at 08:00 on Monday bound for San Francisco ($37^\circ$ N, $122^\circ$ W). If the flight lasts 10 hours, what time and day will it be in San Francisco when the aircraft lands? Take into account the date change when crossing the Greenwich antimeridian ($180^\circ$).

120°E 135°E 150°E 165°E 165°W 150°W 135°W 120°W UTC+8 UTC+9 UTC+10 UTC+11 UTC-11 UTC-10 UTC-9 UTC-8 Antimeridian (180°) Change: −1 day Flight: 10h Tokyo (139°E) Monday 08:00 San Francisco (122°W) Arrival: ?
Solve
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A reconnaissance aircraft takes off from a base located at coordinates $(30^\circ \text{ N}, 15^\circ \text{ O})$ at 08:00 local time. It flies directly East along the…

A reconnaissance aircraft takes off from a base located at coordinates $(30^\circ \text{ N}, 15^\circ \text{ O})$ at 08:00 local time. It flies directly East along the same parallel until it reaches a city located at $60^\circ$ East longitude. The flight has a total duration of 9 hours.

At what local time in the destination city will the aircraft land? Take into account the change in time zones during the journey (assume theoretical time zones of $15^\circ$ each).

Greenwich 30ºW 15ºW 0º 15ºE 30ºE 45ºE 60ºE 75ºE +1h +1h +1h +1h +1h Time zone change: +5 hours Flight: 9 hours Departure 08:00 Arrival ??:??
Solve
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A submarine travels along the seabed from a point X $(0^\circ, 175^\circ \text{ E})$ to a point Y $(0^\circ, 170^\circ \text{ O})$. The figure shows the Equator seen…

A submarine travels along the seabed from a point X $(0^\circ, 175^\circ \text{ E})$ to a point Y $(0^\circ, 170^\circ \text{ O})$. The figure shows the Equator seen from the North Pole, with the two points marked.

Equator seen from the North Pole with the Greenwich meridian at the bottom, the 180º antimeridian at the top and points X (175º E) and Y (170º O) near the antimeridianX (175º E)Y (170º W)180º (antimeridian)0º (Greenwich)90º E90º WNorth PoleEquator
  1. a) How many degrees of longitude has it travelled if it has followed the shortest route along the Equator?
  1. b) If the submarine travels at a constant speed of $20 \text{ nudos}$ ($1 \text{ nudo} \approx 1.85 \text{ km/h}$), how long will it take to complete the journey? (Radius of the Earth: $6371 \text{ km}$).
  1. c) Was there any date change during the journey? Explain why.
Solve

Review of solids for the final problems

Some problems in this section involve polyhedra, frustums, and spheres. Here are the tools you need.

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A truncated octahedron is constructed from a regular octahedron with an edge length of $12 \text{ cm}$. To do this, each of the six vertices is cut off so that small…

A truncated octahedron is constructed from a regular octahedron with an edge length of $12 \text{ cm}$. To do this, each of the six vertices is cut off so that small square-based pyramids are removed, converting each original triangular face into a regular hexagon.

  1. Determine the number of faces, vertices and edges of the resulting polyhedron and check whether it satisfies Euler's formula.

  2. If the edge of the new polyhedron (that of the resulting hexagon) is $4 \text{ cm}$, calculate the total surface area of the truncated octahedron.

hexagon square a = 4 cm F = ? V = ? E = ? F + V = E + 2
Solve
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A perfume company designs a bottle in the shape of an inverted frustum of a cone topped by a hemisphere that fits perfectly onto the upper base. The design data are as…

A perfume company designs a bottle in the shape of an inverted frustum of a cone topped by a hemisphere that fits perfectly onto the upper base. The design data are as follows:

  • Height of the frustum of a cone: $8 \text{ cm}$.

  • Radius of the lower base (where it rests): $3 \text{ cm}$.

  • Radius of the upper base (where the hemisphere fits): $6 \text{ cm}$.

Calculate the total volume of the bottle and determine whether it can hold a standard bottle of $330 \text{ ml}$ of essence. (Take $\pi \approx 3.14$).

h=8 r=3 R=6
Solve
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A water tank is in the shape of a right regular hexagonal prism. It is known that the radius of the circle circumscribing the hexagonal base measures $4 \text{ m}$ and…

A water tank is in the shape of a right regular hexagonal prism. It is known that the radius of the circle circumscribing the hexagonal base measures $4 \text{ m}$ and that the height of the prism is three times the apothem of the base.

Calculate the cost of waterproofing the side walls and the bottom (lower base) if the price of the material is $750 \text{ \text{RD\$}\ /m}^2$. Round the result to two decimal places.

R = 4 m ap H = 3·ap
Solve
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A cylinder has a radius of $R$ and a height of $2R$. Inside it, a sphere of radius $R$ is placed, which fits tangentially against the walls and bases of the cylinder. 1.…

A cylinder has a radius of $R$ and a height of $2R$. Inside it, a sphere of radius $R$ is placed, which fits tangentially against the walls and bases of the cylinder.

  1. Prove analytically the relationship between the volume of the sphere and the volume of the cylinder.

  2. If the volume of the cylinder is $54 \text{ cm}^3$, what volume of air remains free inside the cylinder once the sphere is inserted?

R R 2R
Solve

Summary

Back to the beginning: Wilkin's location, $18.5°$ N, is $18.5 \times 111.2 \approx 2{,}057$ km from the equator, and his time is found using zones of $15°$.

See all the exercises in this section